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I'm looking for a way to create a "variable-function" in C language.
In MATLAB i'm able to create something like:
my_function = (#x) sin(x) + x^2 + x;
so that i'm able to evaluate it for any value of 'x' i like:
my_point = 3.09;
my_function(my_point);
is there anything like that for C language?
That's just a regular C function. The terminology would be: "A function with arguments"
double my_function(double x)
{
return sin(x) + x*x + x;
}
#include <stdio.h>
#include<math.h>
#define my_function(x) sin(x) + pow(x,2) + x
int main()
{
double my_point = 3.09;
printf("%lf",my_function(my_point));
return(0);
}
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Write a C program to convert a number in scientific notation to its equivalent decimal form :
Given
8.3e+2 output = 830
2.E-1 output = 0.2
4.3E2 output = 430
Is there any inbuilt library or function in C/C++ which can do this?
or one will have to write his own code, in that case, any easy way to achieve this?
try this
#include <iostream>
#include <string>
int32_t main(int32_t argc, char *argv[]) {
std::string str = "8.3e+2";
std::cout << std::stod(str) << std::endl;
return EXIT_SUCCESS;
}
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I am trying to research various integer overflow scenarios in C and I was wondering does the C language provide any defenses against numeric errors and are there any additional classes or libraries in the C language that can help with that? Also, can anyone give me an example of code that results in an integer overflow in C?
No, there are no defenses.
This overflows:
#include <limits.h>
#include <stdio.h>
const int a = INT_MAX - 2;
const int b = INT_MAX - 2;
printf("%d + %d = %d\n", a, b, a + b);
When I tested it it printed -6, but anything could happen I guess.
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How can I write 3 cos² 2x with C?
Assuming x is in radians :
3*pow(cos(2*x),2)
Here is a function for your purpose:
#include <math.h>
double f(double x) {
double c = cos(2 * x);
return c * c * 3;
}
First compute cos 2x, then square the result and multiply by 3.
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I just wonder how to find mean of two numbers without using division.
do not use these conditions :
int mean = (a + b) >> 1;
four fundamental arithmetic operations
I think this may be helpful -->
int a,b,i,j;
if (a>b)
{
int temp = a;
a = b;
b = temp;
}
for(i=a,j=b;i<j;i++,j--)
continue;
if(i==j)printf("%d\n", i);
else printf("%lf\n", (double)(i)-0.5);
Add them then multiply by 0.5 , no division involved.
If they're both integers, you can use a right shift:
int median = (a + b) >> 1;
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I am having difficulty getting the real output from a C function. For example:
int max3(int a, int b, int c){
if ((a>b)&&(a>c))
return a;
if ((b>c)&&(b>a))
return b;
return c;
}
Can you give me an idea of how to specify the real output (e.g. tools, algorithms, etc.)?
In this above example, the real output is 6 (in case (a,b,c) = (1,2,6)).
Thank in advance very much.
I'd have probably written it, as it is simple, using the ternary operator:
int max3(int a, int b, int c){
if (a>b)
return (a>c)?a:c;
else
return (b>c)?b:c;
}