Split date result sets into columns in sql server - sql-server

Question

can you please assist
I have a query that shows number of teachers, the site the visited and when date they visited. This query looks at all teachers visits for the past week.
I want to split the dateattended field into columns to show daily visit for the past week. Below is how it looks.
EmployeeNumber Name HomeSite Site Attended Day Attended
TP-000322789 Samuel Mohlamnyane Teacher Port Elizabeth 2014-10-18 07:23
TP-000148774 Jean Smoothie Teacher Hennopsview 2014-10-13 08:55
TP-000148774 Jean Smoothie Teacher Hennopsview 2014-10-16 08:43
TP-000148122 Anthony Mike Teacher Tzaneen 2014-10-19 09:19
TP-000148122 Anthony Mike Teacher Tzaneen 2014-10-15 08:26
TP-000328452 Geneve Gorridon Teacher Tzaneen 2014-10-14 07:44
TP-000346529 Edmos Dube Teacher Melrose 2014-10-18 07:47
TP-000321374 Anita Rene Classen Teacher Johannesburg 2014-10-17 07:57
TP-000324511 Anthonysia White Teacher Durbanville 2014-10-15 07:53
TP-000324511 Anthonysia White Teacher Durbanville 2014-10-18 12:26
TP-000327471 Moses Mathebula Teacher Polokwane 2014-10-13 05:50
TP-000148194 Nonhlanhla Ndlovu Teacher Vereeniging 2014-10-15 07:06
TP-000323383 Lerato Manyanka Teacher Bedfordview 2014-10-13 07:26
TP-000323383 Lerato Manyanka Teacher Bedfordview 2014-10-16 06:51
TP-000323384 Lerato Manyanka Teacher Bedfordview 2014-10-17 08:57
Now I want to split Day attended to show date in different columns from yesterday going down to the last seven days.
Below is the code I used to get the above result set. And how the result should look like.
EmployeeNumber Name HomeSite Site Attended Day 1 Day2 Day 3 Day 4 Day 5 Day 6 Day 7
TP-000148194 Nonhlanhla Ndlovu Teacher Vereeniging 2014-10-15 07:06
TP-000323383 Lerato Manyanka Teacher Bedfordview 2014-10-17 08:57 2014-10-16 06:51 2014-10-13 07:26
SELECT mdet.MemRefNo AS 'EmployeeNumber'
, cont.FirstName + ' ' + cont.LastName AS Name
, s.Name AS 'HomeSite'
, Attend.VisitedSite AS 'Site Attended'
, Attend.Weekdays AS 'Day Attended'
FROM MemberDetail mdet
INNER JOIN MembershipHistory mhis ON mdet.CurrentMembershipID = mhis.ID32
INNER JOIN contacts cont ON cont.GUID = mdet.ContactGUID
INNER JOIN Sites s ON s.id = cont.HomeSiteID
INNER JOIN Packages pg ON pg.ID = mhis.PackageID
CROSS APPLY
(
SELECT min(a1.attenddate) AS Weekdays , a1.contactguid, a1.SiteID , s.Name as VisitedSite FROM dbo.attendance a1
INNER JOIN Sites s ON s.id = a1.Siteid
WHERE DATEDIFF(DAY,a1.attenddate,GETDATE()) <= 7
and ContactGuid = mdet.ContactGuid
AND a1.isswipesuccessful = 1
GROUP BY a1.ContactGuid, DATEPART(DW, a1.attenddate),a1.SiteID , s.Name
) Attend
WHERE pg.Description LIKE '%Teacher%'

Answer 1

I think this is the query you want, it uses a pivot with the results from your existing query as source through a common table expression. Ideally the code could be merged into one query, but as you didn't provide any test data from the source tables, but only the output I didn't try to rewrite it. Note that if a person visited the same site more than one time in a single day, only the latest time will be shown.
-- using original query as source
;WITH visits AS (
SELECT mdet.MemRefNo AS 'EmployeeNumber'
, cont.FirstName + ' ' + cont.LastName AS Name
, s.Name AS 'HomeSite'
, Attend.VisitedSite AS 'Site Attended'
, Attend.Weekdays AS 'Day Attended'
FROM MemberDetail mdet
INNER JOIN MembershipHistory mhis ON mdet.CurrentMembershipID = mhis.ID32
INNER JOIN contacts cont ON cont.GUID = mdet.ContactGUID
INNER JOIN Sites s ON s.id = cont.HomeSiteID
INNER JOIN Packages pg ON pg.ID = mhis.PackageID
CROSS APPLY
(
SELECT min(a1.attenddate) AS Weekdays , a1.contactguid, a1.SiteID , s.Name as VisitedSite FROM dbo.attendance a1
INNER JOIN Sites s ON s.id = a1.Siteid
WHERE DATEDIFF(DAY,a1.attenddate,GETDATE()) <= 7
and ContactGuid = mdet.ContactGuid
AND a1.isswipesuccessful = 1
GROUP BY a1.ContactGuid, DATEPART(DW, a1.attenddate),a1.SiteID , s.Name
) Attend
WHERE pg.Description LIKE '%Teacher%'
)
-- query to produce results
SELECT
EmployeeNumber,
Name,
HomeSite,
[Site Attended],
[1] AS 'Day 1',
[2] AS 'Day 2',
[3] AS 'Day 3',
[4] AS 'Day 4',
[5] AS 'Day 5',
[6] AS 'Day 6',
[7] AS 'Day 7'
FROM (
SELECT *, DATEDIFF(day, [Day Attended], GETDATE()) diff
FROM visits
WHERE [Day Attended] > (GETDATE()-7) -- adjust this to limit date range
) a
PIVOT (
MAX([Day Attended]) FOR [diff] in ([1],[2],[3],[4],[5],[6],[7])
) AS Pivoted;
It would probably be trivial to modify the existing query to get the desired results.
Sample SQL Fiddle (using the sample output data as source).
Sample results:
EmployeeNumber Name HomeSite Site Attended Day 1 Day 2 Day 3 Day 4 Day 5 Day 6 Day 7
-------------------- ---------------------------------------- -------------------- -------------------- ----------------------- ----------------------- ----------------------- ----------------------- ----------------------- ----------------------- -----------------------
TP-000148122 Anthony Mike Teacher Tzaneen NULL 2014-10-19 09:19:00.000 NULL NULL NULL 2014-10-15 08:26:00.000 NULL
TP-000148194 Nonhlanhla Ndlovu Teacher Vereeniging NULL NULL NULL NULL NULL 2014-10-15 07:06:00.000 NULL
TP-000148774 Jean Smoothie Teacher Hennopsview NULL NULL NULL NULL 2014-10-16 08:43:00.000 NULL NULL
TP-000321374 Anita Rene Classen Teacher Johannesburg NULL NULL NULL 2014-10-17 07:57:00.000 NULL NULL NULL
TP-000322789 Samuel Mohlamnyane Teacher Port Elizabeth NULL NULL 2014-10-18 07:23:00.000 NULL NULL NULL NULL
TP-000323383 Lerato Manyanka Teacher Bedfordview NULL NULL NULL 2014-10-17 08:57:00.000 2014-10-16 06:51:00.000 NULL NULL
TP-000324511 Anthonysia White Teacher Durbanville NULL NULL 2014-10-18 12:26:00.000 NULL NULL 2014-10-15 07:53:00.000 NULL
TP-000346529 Edmos Dube Teacher Melrose NULL NULL 2014-10-18 07:47:00.000 NULL NULL NULL NULL