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Using bash script, I want to count the numbers between zeros only. Is it possible to use awk? Sorry, i am new to this.
5000000000009228247152000000000000000000003
5000000000006338293700000000000000000000001
grep -Po '0+\K[^0]+(?=0)'
gives you:
9228247152
63382937
EDIT
If things could be easily done in a single process (awk here is the case), I won't start 2nd process.
awk one-liner with count and text:
awk -F'0+' 'NF>2{for(i=2;i<NF;i++)printf "text:%s count:%d\n",$i,length($i)}'
gives:
text:9228247152 count:10
text:63382937 count:8
awk one-liner only with count:
awk -F'0+' 'NF>2{for(i=2;i<NF;i++)print length($i)}'
gives:
10
8
With sed:
echo 5000000000009228247152000000000000000000003 | \
sed -n -r -e 's/0+([^0]+)0+/\1/' | wc -m
$ grep -oP '0+\K[1-9]+(?=0+)' file
9228247152
63382937
To count the number of digits,
$ grep -oP '0+\K[1-9]+(?=0+)' file | awk -v FS="" '{print NF}'
10
8
Related
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From my program, I am trying to execute a command using popen` which contains:
sprintf(buff, "echo -n cd %s; ls | awk -F'.' '{print $2"."$3"."$4'#'$5}'"
But compiler says 'stray # in program'.
How to print "#" in C ?
Your # needs to be between quotation marks ("). If you want to have quotation marks as characters in a string you need to escape them with \ (e.g. "\"").
So the string should be "echo -n cd %s; ls | awk -F'.' '{print $2\".\"$3\".\"$4\"#\"$5}'".
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i have this code:
#!/bin/bash
PIDS=$(ls -la /proc | awk '{print $9}' | grep "^[0-9]*$")
PIDLIST=$(echo $PIDS | tr "" "\n")
counter=0
for PID in $PIDLIST; do
KERNEL[$counter]=$(cat "/proc/$PID/stat" | awk '{print $14 }')
counter=$((counter + 1))
done
I'm trying to save the content of cat "/proc/$PID/stat" | awk '{print $14 }' command in a named KERNEL array, given a position by a counter.
I have this error:
mitop.sh: 8: mitop.sh: KERNEL[0]=26: not found
What i'm doing wrong?
sistemas#DyASO:~$ bash --version
GNU bash, versión 4.2.24(1)-release (i686-pc-linux-gnu)
Copyright (C) 2011 Free Software Foundation, Inc.
Licencia GPLv3+: GPL de GNU versión 3 o posterior <http://gnu.org/licenses/gpl.html>
I am using sh ./mitop.sh
That is the problem. You're not executing the script with Bash.
You are executing it with /bin/sh, which is very different.
You need to run it like this:
./mitop.sh
Or like this:
bash ./mitop.sh
This last one is just for sanity check.
The recommended way to run shell scripts is with ./the_script.sh,
to let the first line decide how it should be executed.
Also, the script can be written better, I recommend this way:
#!/bin/bash
kernel=()
for file in /proc/[0-9]*; do
read -a fields < "$file"/stat
kernel+=("${fields[13]}")
done
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I would like to know if there is any way to scan a text file and then run a command. I have tried grep getting nowhere. I have also tried the find . thing, it sounds promising but I can't seem to get a good explanation on how to use it. If you would like to know what this will be used for here is an explanation: I have an iPhone app that sends a word over http, the server side application is listening for the command and when received it runs a command.
The following will cat all files that find finds that contain "needle" and will show their contents. Modify accordingly:
find . -exec grep needle -q {} \; -exec cat {} \;
In bash, you could tail -f the file, and pipe it to this script:
while read LINE; do
grep -q word <<< $LINE && command_to_execute
done
But the best thing would to place this logic in the web server instead of parsing a file (the log file I am guessing).
UPDATE:
The above loop is expensive to run as grep is called at each iteration. This one is better:
tail -f file | grep word | while read LINE; do
command_to_execute
done
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I am looking for a table of language names and codes like the ISO 639-1 set: http://en.wikipedia.org/wiki/List_of_ISO_639-1_codes
Thanks
You'll want ISO 639-3 if you want the up-to-date list.
Enhancing Obalix answer, I have created a bash script that will take a UTF-8 CSV file and insert it into a database.
Note that the file provided by Obalix is in UTF-16 NOT UTF-8. The below script checks for its encoding and advises user on how to convert it.
Of course you will need to modify the insert statement according to your schema.
#!/bin/bash
USAGE="Usage: $0 <csv-file>"
if [ $# -lt 1 ]
then
echo $USAGE
exit 1
fi
csv=$1
if [ ! -f $csv ]; then
echo "$csv: No such file"
exit 1
fi
file $csv | grep -q UTF-8
if [ $? -ne 0 ]
then
echo $csv: must be in UTF-8 format, use the following command to fix this:
echo "cat $csv | iconv -f UTF-16 -t UTF-8 | tr -d \"\r\" > utf8-$csv"
exit 1
fi
mysql=<PATH/TO/mysql/BINARY>
db=<DATABASE_NAME>
user=<USERNAME>
pass=<PASSWORD>
sql=insert-all-langs.sql
echo "-- Inserting all languages generated on `date`" > $sql
printf "Processing CSV file..."
# prepend _ to all lines so that no line starts by whitespace
sed 's/.*/_&/' $csv | while read l; do
iso6391=`echo "$l" | cut -f4`
name=`echo -e "$l" | cut -f3 | tr -d "\"" | sed 's/'\''/\\\\'\''/g'`
echo $iso6391:$name
# insert ignore supresses errors for duplicate locales (row still not inserted)
echo "insert ignore into languages (name, locale, rtl, created_at, updated_at) values ('$name', '$iso6391', 0, now(), now());" >> $sql
done
echo Done
printf "Executing SQL..."
cat $sql | $mysql -u$user -p$pass $db
echo Done
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I have a lots of files with multiple lines, and in most case, one of the lines contain a certain pattern. I would like to list every file that does not have a line with this pattern.
Use the "-L" option in order to have file WITHOUT the pattern. Per the man page:
-L, --files-without-match
Suppress normal output; instead print the name of each input file from which no output would normally have been printed. The scanning will stop on the first match.
Grep returns 0/1 to indicate if there was a match, so you can do something like this:
for f in *.txt; do
if ! grep -q "some expression" $f; then
echo $f
fi
done
EDIT: You can also use the -L option:
grep -L "some expression" *
try "count" and filter where equals ":0":
grep -c [pattern] * | grep ':0$'
(if you use TurboGREP cough, you won't have a -L switch ;))
(EDIT: added '$' to end of regex in case there are files with ":0" in the name)