typedef struct{
int number;
char name[100];
} Apple
typedef struct{
Apple *apple;
int bit[2];
} AppleArray;
int main(){
AppleArray *aArray;
loadApple(&aArray);
}
loadApple(AppleArray **aArray){
*aArray = NULL;
for(i=0; i<100; i++){
*aArray = realloc(*aArray, (i+1) * sizeof(AppleArray));
/*SEGFAULT here*/
aArray[i]->apple = NULL;
for(j=0; j<2; j++){
aArray[i]->apple = realloc(aArray[i]->apple, sizeof(Apple) * (j+1))
}
}
}
I want to have an AppleArray with specific size. Each AppleArray will have two Apple. However, I get segfault when i assign NULL to aArray[i]->apple. What is the problem there?
EDIT :
loadApple(AppleArray **aArray){
*aArray = malloc(100 * sizeof(AppleArray));
for(i=0; i<100; i++){
/*SEGFAULT here*/
aArray[i]->apple = NULL;
for(j=0; j<2; j++){
aArray[i]->apple = realloc(aArray[i]->apple, sizeof(Apple) * (j+1))
}
}
}
You can call realloc() only on an address that was returned to you by an prior memory allocation function like malloc()or calloc() otherwise it gives you Undefined Behavior.
C99 Standard 7.20.3.4-3: The realloc function:
void *realloc(void *ptr, size_t size);
If ptr is a null pointer, the realloc function behaves like the malloc function for the
specified size. Otherwise, if ptr does not match a pointer earlier returned by a memory
management function, or if the space has been deallocated by a call to the free or
realloc function, the behavior is undefined.
Apart from what Als has mentioned above, you are also having an array out-of-bounds read problem as after your loop, i value will be 100 and you are trying to access aArray[100] whereas in your logic (though incorrect) your would have allocated memory only till aArray[99].
Your loadApple function can be rewritten as below:
loadApple(AppleArray **aArray)
{
*aArray = NULL;
*aArray = malloc(100 * sizeof(AppleArray));
//I have shown index as 0 here just as an example.
(*aArray)[0].apple = NULL;
(*aArray)[0].apple = malloc(2 * sizeof(Apple));
}
This code should also give the same behavior which the logic of your code is trying to achieve.
<pre>
#include "stdio.h"
#include "stdlib.h"
#define MAX_SIZE 5
#define NAME_SIZE 100
#define APPLE_NUM 2
typedef struct
{
int number;
char name[NAME_SIZE];
}Apple;
typedef struct
{
Apple* apple;
int bit[2];
}AppleArray;
void printApple(AppleArray** aArray)
{
int i;
for (i = 0; i < MAX_SIZE; ++i)
{
fprintf(stderr, "%4d: bit[0] = %d, bit[1] = %d\n", i, (*aArray + i)->bit[0], (*aArray + i)->bit[1]);
int j;
for (j = 0; j < APPLE_NUM; ++j)
{
fprintf(stderr, "\tapple[%d]: number = %d, name = %s\n",
j,
(*aArray + i)->apple[j].number,
(*aArray + i)->apple[j].name);
}
printf("\n");
}
}
void loadApple(AppleArray **aArray)
{
*aArray = NULL;
int i;
for(i = 0; i < MAX_SIZE; i++)
{
AppleArray* tmp = (AppleArray*)realloc(*aArray, (i+1) * sizeof(AppleArray));
if (tmp != NULL)
{
*aArray = tmp;
}
else
{
//error
free(*aArray);
*aArray = NULL;
exit(0);
}
/*SEGFAULT here*/
//aArray[i]->apple = NULL;
(*aArray + i)->apple = NULL;
(*aArray + i)->bit[0] = i;
(*aArray + i)->bit[1] = i + 1;
/*
int j;
for (j = 0; j < 2; j++)
{
(*aArray + i)->apple = realloc(aArray[i]->apple, sizeof(Apple) * (j+1));
}
*/
(*aArray + i)->apple = (Apple*)realloc(NULL, sizeof(Apple) * APPLE_NUM);
int j;
for (j = 0; j < APPLE_NUM; ++j)
{
(*aArray + i)->apple[j].number = j;
snprintf( (*aArray + i)->apple[j].name, NAME_SIZE, "apple_%d_%d", i, j);
}
}//for
}
void destroyApple(AppleArray* thiz)
{
if (thiz == NULL)
{
return;
}
int i;
for (i = 0; i < MAX_SIZE; ++i)
{
free(thiz[i].apple);
thiz[i].apple = NULL;
}
free(thiz);
}
int main()
{
AppleArray *aArray;
loadApple(&aArray);
printApple(&aArray);
destroyApple(aArray);
return 0;
}
Related
We were asked to convert 2D static array to dynamic array. So I will need to create an array of pointers in which every pointer points to a different row. I have written this code but my code breaks when i=1 on line *(dynamicStr[i] + v) = rowStr[v]; Additionally, if I enable free(ptr); section my debugger gets stuck there for 6 or 7 times and then contiunes.
EDIT: In the end, I solved the problem with appying the answers #dodooft and #Viktor Terziev gave.
#include <stdio.h>
#include <stdlib.h>
void toDynamic(int x,int y, char toDyna[x][y]);
void toDynamic2(int x,int y, char toDyna[x][y]);
int main()
{
char toDyna[7][12] = {
"JOHN",
"MARK",
"PIERCEPIERCE",
"20",
"ROSIE",
"ALEX",
"MARLYN"
};
int x = 7;
int y = 12;
toDynamic2(x, y, toDyna);
return 0;
}
void toDynamic2(int x,int y, char toDyna[x][y]){
char *dynamicStr[x];
int rowToCheck = 0;
int size;
char *ptr;
int c;
for(int i = 0; i < x; i++){
printf("i: %d\n",i);
c = 0;
size = strlen(toDyna[rowToCheck]);
ptr = (char*) malloc(size * sizeof(char));
for(int j = 0; j < y; j++){
if(toDyna[i][j] != '\0'){
*(ptr+c) = toDyna[i][j];
c++;
} else{
break;
}
}
*(ptr+size) = '\0';
printf(" ");
char rowStr[size];
for(int v = 0; v < size; v++){
rowStr[v] = *(ptr+v);
printf("Added Char: %c\n", rowStr[v]);
*(dynamicStr[i] + v) = rowStr[v];
}
//free(ptr);
//printf("\n%s\n", rowStr);
//dynamicStr[i] = &rowStr;
rowToCheck++;
}
for(int i = 0; i < x; i++){
printf("%s\n", dynamicStr[i]);
}
}
EDIT: This is the working verion of the code:
#include <stdio.h>
#include <stdlib.h>
char** toDynamic(int x,int y, char toDyna[x][y]);
void free2DArray(int x, char **dynamicStr);
int main()
{
char toDyna[7][12] = {
"JOHN",
"MARK",
"PIERCEPIERCE",
"20",
"ROSIE",
"ALEX",
"MARLYN"
};
int x = 7;
int y = 12;
char **dynamicArr;
dynamicArr = toDynamic(x, y, toDyna);
free2DArray(x, dynamicArr);
return 0;
}
char** toDynamic(int x,int y, char toDyna[x][y]){
printf("Q2\n");
char **dynamicStr;
int rowToCheck = 0;
int size;
int c;
dynamicStr = (char*)malloc(x * sizeof(char*));
for(int i = 0; i < x; i++){
dynamicStr[i] = (char*)malloc(y * sizeof(char));
c = 0;
size = strlen(toDyna[rowToCheck]);
char *ptr = (char*) malloc((size + 1) * sizeof(char));
for(int j = 0; j < y; j++){
if(toDyna[i][j] != '\0'){
*(ptr+c) = toDyna[i][j];
c++;
} else{
break;
}
}
*(ptr+size) = '\0';
dynamicStr[i] = ptr;
rowToCheck++;
}
for(int i = 0; i < x; i++){
printf("%s\n", dynamicStr[i]);
}
printf("----------------------------\n");
return dynamicStr;
}
void free2DArray(int x, char **dynamicStr){
printf("Q3\n");
for(int i = 0; i < x; i++){
free(dynamicStr[i]);
printf("dynamicStr %d freed\n", i);
}
free(dynamicStr);
printf("dynamicStr array freed\n");
printf("----------------------------\n");
}
You define dynamicStr as an array of char pointers, when you are trying to assign a value to it with *(dynamicStr[i] + v) = rowStr[v]; you are basically copying the value of rowStr[v] to the address that is pointed by dynamicStr[i] + v. That address is not defined in your code, so you got a segfault.
If you are trying to fill dynamicStr with pointers to new arrays with dynamic memory, you should try something like
dynamicStr[i] = ptr;
where ptr is the pointer returned by the malloc call to the i-th row. Also, as you are working with strings you can use strcpy to copy the data from the static array to the dynamic one.
Its much easier than you think, please refer to strcpy documentation and strlen documentation, and (if you use my code) don't forget to free your memory.
char * * toDynamic2(size_t n, size_t m, char strings[n][m])
{
char * * arr = malloc(n * sizeof(char*));
for(size_t i = 0; i < n; ++i)
{
size_t size = strlen(strings[i]);
arr[i] = malloc((size + 1) * sizeof(char));
strcpy(arr[i], strings[i]);
}
for(size_t i = 0; i < n; ++i)
{
printf("%s\n", arr[i]);
}
return arr;
}
I am getting the error variable sized object may not be initialized and I don't understand why.
Could someone show me how to fix this line?
int arr[size] = (int *)(augs->one);
Here is my code:
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdlib.h>
#include <pthread.h>
#include <assert.h>
int count = 0;
int cmpfunc(const void *a, const void *b) {
return (*(int*)a - *(int*)b);
}
struct structure {
int two;
int *one;
};
void *sort(void *augments) {
struct structure *augs = (struct structure*)augments;
int i = 0;
int size = 1;
size = augs->two;
int arr[size] = (int *)(augs->one);
//int *arr = (int *)data;
//printf("sizeof:%d\n", sizeof(arr));
qsort(arr, size, sizeof(int), cmpfunc);
printf("finaloutput:\n");
for (i = 0; i < size; i++) {
printf("%d ", arr[i]);
}
printf("\n");
return NULL;
}
int main(int argc, char *argv[]) {
FILE *myFile;
myFile = fopen("data.txt", "r");
// number of lines in file
char charicter;
for (charicter = getc(myFile); charicter != EOF; charicter = getc(myFile)) {
if (charicter == '\n') {
count++;
}
}
printf("count is %d\n", count);
int numberArray[count];
int i = 0;
if ((myFile = fopen("data.txt", "r"))) {
while ((fscanf(myFile, "%d", &numberArray[i]) != EOF)) {
++i;
}
fclose(myFile);
}
assert(argv[1] != NULL);
int num = atoi(argv[1]); //num equals number input
int arrayarray[num - 1][(count / num)];
int idx;
for (i = 0; i < (count); i++) {
printf("numberarray[%d]= %d\n", i, numberArray[i] /*[0],numberArray[i][1]*/);
}
for (i = 1; i < num + 1; i++) {
for (idx = 0; idx < (count / num); idx++) {
arrayarray[i - 1][idx] = numberArray[i * idx];
}
}
///*
for (i = 0; i < ((count / num)); i++) {
printf("arrayarray[0]=%d\n", arrayarray[0][i]);
}
//*/
int lastarray[((count / num) + (count % num))];
for (idx = 0; idx < ((count / num) + (count % num)); idx++) {
lastarray[idx] = numberArray[idx + ((count / num) * (num - 1))];
}
for (i = 0; i < ((((count / num) + (count % num)))); i++) {
printf("lastaray[%d]=%d\n", i, lastarray[i]);
}
//*******************
pthread_t thread_id_arr[num];
for (i = 0; i < num; i++) {
pthread_t tid;
struct structure *augs;
if (i != (num - 1)) {
augs = malloc(sizeof(struct structure) + sizeof(int) + sizeof(int) * num);
(*augs).one = arrayarray[i];
(*augs).two = (count / num);
pthread_create(&tid, NULL, sort, augs);
} else {
(*augs).one = lastarray;
(*augs).two = (count / num) + (count % num);
pthread_create(&tid, NULL, sort, augs);
//pthread_create(&tid, NULL, sort, (void*)lastarray);
}
thread_id_arr[i] = tid;
}
for (i = 0; i < num; i++) {
pthread_join(thread_id_arr[i], NULL);
}
return 0;
}
As others pointed out, you can't initialize a Variable Length Array with a pointer, like you are doing. However, you don't actually need a VLA at all. Use this instead :
int *arr = augs -> one;
You want to act directly on the array that is passed into the thread, not make a copy of it.
That being said, I see another problem. In the loop that spawns the sorting threads, you are not allocating a new args on the last loop iteration, it reuses the allocated args from the previous iteration, which can cause disaster for the 2nd-to-last thread. You need to move the malloc() call above the if.
Also, the malloc() is allocating more memory than your threads actually use. You only need to allocate enough memory for just the struct by itself, not for any integers following the struct.
Also, when each thread is done using the allocated args that it is given, it needs to free() the args to avoid leaking memory.
All the solutions I have seen online has calloc() function used twice, is it possible to do with only using it once?
The below code is not printing the correct array elements
int **ptr;
//To allocate the memory
ptr=(int **)calloc(n,sizeof(int)*m);
printf("\nEnter the elments: ");
//To access the memory
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
scanf("%d",ptr[i][j]);
}
}
Since C99 you can use pointers to VLAs (Variable Length Arrays):
int n, m;
scanf("%d %d", &n, &m);
int (*ptr)[m] = malloc(sizeof(int [n][m]));
for (i = 0; i < n; i++)
{
for (j = 0; j < m; j++)
{
scanf("%d", &ptr[i][j]); // Notice the address of operator (&) for scanf
}
}
free(ptr); // Call free only once
If it's just about minimising the number of calls to memory allocation functions you can created such a jagged array like this:
#include <stdlib.h>
#include <stdio.h>
int ** alloc_jagged_2d_array_of_int(size_t n, size_t m)
{
int ** result = NULL;
size_t t = 0;
t += n * sizeof *result;
t += n*m * sizeof **result;
result = calloc(1, t);
if (NULL != result)
{
for (size_t i = 0; i < n; ++i)
{
result[i] = ((int*) (result + n)) + i*m;
}
}
return result;
}
Use it like this:
#include <stdlib.h>
#include <stdio.h>
int ** alloc_jagged_2d_array_of_int(size_t, size_t);
int main(void)
{
int result = EXIT_SUCCESS;
int ** p = alloc_jagged_2d_array_of_int(2, 3);
if (NULL == p)
{
perror("alloc_jagged_2d_array_of_int() failed");
result = EXIT_FAILURE;
}
else
{
for (size_t i = 0; i < 2; ++i)
{
for (size_t j = 0; j < 3; ++j)
{
p[i][j] = (int) (i*j);
}
}
}
/* Clean up. */
free(p);
return result;
}
I have a problem with dynamic arrays in C. My program was working perfectly, but I was asked to put the creation of dynamic array into a seperate void. I did it, and it still worked great, but then I had to assign a value to a certain point of the created array in void, and make it return the said value, however, what I get is a random value. The function works by sending a pointer and the lenght of required array into void, and then makes the pointer into a dynamic array.
#include <stdio.h>
#include <stdlib.h>
#define MAX 255
void ieskom (int skaiciai[],int n, int *de, int *me, int *n1, int *n2)
{
int i = 0;
int j = 0;
int nr1 = 0;
int nr2 = 0;
int temp = 0;
int temp1 = 0;
int eile = 0;
int eile1 = 0;
int *did;
did = (int*)calloc(n,sizeof(int));
if (did==NULL)
{
printf("Nepriskirta atminties.");
exit(0);
}
int *maz;
maz = (int*)calloc(n,sizeof(int));
if (maz==NULL)
{
printf("Nepriskirta atminties.");
exit(0);
}
i = 0;
for (i = 0; i < n; i++)
{
if (skaiciai[i] < skaiciai[i+1])
{
did[j] = did[j] + 1;
if (did[j] > temp)
{
eile = j;
temp = did[j];
nr1 = i+1;
}
}
else
{
did[j] = did[j] + 1;
if (did[j] > temp)
{
eile = j;
temp = did[j];
nr1 = i+1;
}
j = j + 1;
}
}
j = 0;
for (i = 0; i < n; i++)
{
if (skaiciai[i] > skaiciai[i+1])
{
maz[j] = maz[j] + 1;
if (maz[j] > temp1)
{
eile1 = j;
temp1 = maz[j];
nr2 = i+1;
}
}
else
{
maz[j] = maz[j] + 1;
if (maz[j] > temp1)
{
eile1 = j;
temp1 = maz[j];
nr2 = i+1;
}
j = j + 1;
}
}
*de = did[eile];
*me = maz[eile1];
*n1 = nr1;
*n2 = nr2;
free(did);
free(maz);
}
/*int masyvas(x)
{
int y;
y = (int*)malloc(x*sizeof(int));
return y;
}*/
void *masyvas (int *skaiciai, int n)
{
*skaiciai = (int*)malloc(n*sizeof(int));
skaiciai[2] = 5;
return skaiciai;
}
int main()
{
int n1 = 0;
int n2 = 0;
int de = 0;
int me = 0;
int i = 0;
int n = 0;
int *skaiciai;
scanf("%d", &n);
// skaiciai = masyvas(n); // naudojant int
masyvas(&skaiciai, n);
printf("2 = %d", skaiciai[2]);
if (skaiciai==NULL)
{
printf("Nepriskirta atminties.");
exit(0);
}
for (;i < n; i++)
{
scanf("%d", &skaiciai[i]);
}
ieskom (skaiciai, n, &de, &me, &n1, &n2);
if (de > me)
{
printf("Elementu numeriai:");
printf(" %d", n1-de+1);
printf(" %d\n", n1);
printf("\nAtstumas tarp ju: %d", de-2);
}
else
{
printf("Elementu numeriai:");
printf(" %d", n2-me+1);
printf(" %d\n", n2);
printf("\nAtstumas tarp ju: %d", me-2);
}
free(skaiciai);
getchar();
getchar();
return 0;
}
The problem is in void masyvas and printf skaicia[2] - I assign a certain value to skaiciai[2], yet it prints a random one. How do I fix it?
EDIT: Thank you for your answers and explanations, it really helped me a lot! I know have solved my problem, and most importantly, I know why it was a problem in the first place.
First of all, you should translate variables and texts to english (your code lack of comments, this should apply to them too).
Next your masyvas() function returns a pointer to the allocated array (why void* ?!) but when you call it you don't get the returned value.
You have to choose: either you pass a pointer to your function (an array is a pointer, to if you want an array to be allocated from a function you have to pass a pointer to the pointer, so a int **), or you use the returned value.
Allocating with returned value:
// this function allocates a int* tab of size n and set one value
int *allocate_tab(int n) {
int *tmp;
tmp = malloc(n*sizeof(int));
if (tmp == NULL) {
return(NULL); // failed
}
tmp[2] = 5;
return(tmp);
}
// in main (or other function)
int *mytab;
mytab = alloc_tab(45);
Allocating by passing a pointer to the array:
void alloc_tab(int **tab, int n) {
*tab = malloc(n*sizeof(int));
if (*tab == NULL) {
return;
}
(*tab)[2] = 5;
}
// in main (or other)
int *mytab;
alloc_tab(&mytab, 45);
If you can't understand this stuff I guess you should read more about memory, allocation and pointers.
You need to pass a pointer-to-pointer here and do not need to return anything.
void masyvas (int **skaiciai, int n)
{
*skaiciai = (int*)malloc(n*sizeof(int));
(*skaiciai)[2] = 5;
}
When you declare int *skaiciai, the variable is a pointer to type int. skaiciai holds the address that points to an int. When you pass &skaiciai, you're passing the address of the address that points to an int. So because this is an address of an address, its a double pointer.
I have the following code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
typedef struct _item {
int v, w;
} item;
void printItems(item *t, int n) {
int i;
for(i= 0; i < n; i++)
printf("%4i",t[i].v);
printf("\n");
}
item * newItemSet(int n) {
int i;
item *t = (item*)malloc(sizeof(item));
for (i = 0; i < n; i++){
(t+i)->v = rand()%100;
(t+i)->w = rand()%100;
}
return t;
}
item * mer(item*a, int n, item*b, int m) {
int size = m+n;
item*q = (item*)malloc(sizeof(item)*size);
int i, c;
c = 0;
printf("a----\n");
printItems(a,n);
printf("b----\n");
printItems(b,m);
for(i = 0; i<n; i++) {
q[c] = a[i];
c++;
}
for(i = 0; i<m; i++) {
q[c] = b[i];
c++;
}
printItems(q,size);
return q;
}
int main(void) {
srand(time(NULL));
item * a = newItemSet(6);
item *b = newItemSet(6);
item *c = mer(a,6,b,6);
printItems(c,12);
return 0;
}
At every execution, the first part of c is correct, up to the last two elements of b. What did I miss?
The allocation for newItemSet does not appear correct. It should be:
item *t = malloc(sizeof(item) * n);
item *t = (item*)malloc(sizeof(item));
Should be:
item *t = malloc(n * sizeof(item));
You are allocating space for n items, not one item. Also, there is no need to cast the return value of malloc and it can hide errors.