I need to add automatically current weeks first date into a table and a text box of a vba form. could anyone help if any functions are available ??
monday = DateAdd("d", 1 - Weekday(Date, vbMonday), Date)
Use
DateAdd("d", Weekday(Date(), 3) * -1, Date())
I know you said VBA but here's how it can be done in Access database engine SQL and works 'stand alone' i.e. not requiring Access or VBA (of course, the logic can be translated into VBA):
Week beginning Sunday: if run on a Sunday will return the current date:
SELECT DATEADD('WW', DATEDIFF('WW', #1990-01-07 00:00:00#, NOW()), #1990-01-07 00:00:00#)
Week beginning Sunday: if run on a Sunday will return the previous Sunday:
SELECT DATEADD('D', (DATEDIFF('D', #1990-01-08 00:00:00#, NOW()) \ 7) * 7, #1990-01-07 00:00:00#)
Hint: 1990-01-07 00:00:00 is an arbitrary date known to be a Sunday.
Related
I am working with dates so I have created a function that generates a SQL Table Calendar which returns Day, Month, WeekOfMonth, WeekOfYear and so on.
Right now, for the Day of Month field I am using the following function:
-- [WkNo]=Week number
[WkNo] = DATEPART(week,dt.DT),
But the problem is that when I run this on a SQL installed with Language = US English, the week setting is wrong cause the week starts from Sunday.
I need to set the week starting from Monday, is it possible without the use of DATEPART?
Update: based on asker's comment that he cannot use the DATEFIRST approach I am updating answer.
Note:
This answer is generic in nature.
If instead of Monday you want the week to start from Tuesday, you can change the dateadd(dd,-1,dt.DT) to dateadd(dd,-2,dt.DT) and for Wednesday to dateadd(dd,-3,dt.DT).
Basically the formula becomes dateadd(dd,-n,dt.DT) for value of n ranging over 1(Monday) to 6 (Saturday).
SELECT [WkNo]=
ISNULL(DATEPART(week,
case
when Year(dt.DT)>YEAR(dateadd(dd,-1,dt.DT))
then null
else dateadd(dd,-1,dt.DT)
end
),1)
See working fiddle http://sqlfiddle.com/#!6/10a80/14
Old Answer:
See MSDN documentation: https://msdn.microsoft.com/en-us/library/ms174420.aspx
When datepart is week (wk, ww) or weekday (dw), the return value
depends on the value that is set by using SET DATEFIRST. January 1 of
any year defines the starting number for the week datepart, for
example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year.
SET DATEFIRST 1
-- [WkNo]=Week number
[WkNo] = DATEPART(week,dt.DT),
try
SET DATEFIRST {1,2,3,4,5,6,7(default, U.S. English)}
for your Query:
set datefirst 1
select [WkNo]= DATEPART(week,dt.DT)
See Here
I'm trying to pull data that falls in between January 1st, 2014 and today's date last year (ie. August 3rd, 2014). How would I go about using ``dateadd` to get the date 1/1/14? I'm using the following code to get the date 8/3/14.
dateadd (yy, -1, getdate())
I want to avoid explicitly searching for 1/1/14 because in a year's time I'd like the sql query to find 1/1/15 without me having to go back in and rewrite it.
Use DATEFROMPARTS:
DATEFROMPARTS(YEAR(GETDATE()) - 1, 1, 1)
DATEADD(yy, DATEDIFF(yy,0,getdate())-1, 0)
DATEFROMPARTS() is the best way but it requires SQL2012 or later. If you're on an earlier vierion, try this:
You can use GETDATE() to get the current date
You can use the function YEAR() to extract the year from any date
Subtract 1 from it to get last year
Append 1/1/ to the front of it
Convert it back to a date again
select convert(datetime, '1/1/' + convert(varchar(max),year(getdate())-1))
I am making a report that will run on the 1st of every month and on the 16th of every month.
If it is running on the 1st I need the #start_date to be the 16th to the last day of the previous month.
If it is running on the 16th I need #start_date to be the 1st of the month through the 15th of the month.
I can think of a couple ways to do this, but I am curious is SSRS/Report Builder/SQL Data Tools builder has an easy method for setting this up.
My option was to make a SQL query that does what I need then plug that into the Get Balues from a query part of the parameter.
If you run the report in the first part of the month then the parameters should be set to the 16th to the end of the previous month; if run in the second part of the month then the parameters should be set to the 1st to the 15th of the current month.
#start_date Default Value expression:
=IIF(Day(Today) >= 16, DateAdd(DateInterval.Day, 1-Day(Today), Today), DateAdd(DateInterval.Month, -1, (DateAdd(DateInterval.Day, 16-Day(Today), Today))))
#end_date Default Value expression:
=IIF(Day(Today) >= 16, DateAdd(DateInterval.Day, 15-Day(Today), Today), DateAdd(DateInterval.Day, -1, (DateAdd(DateInterval.Day, 1-Day(Today), Today))))
I have the following MSSQL query to return the ending day of the week in MSSQL:
SELECT DateAdd(Day, 0 - DatePart(Weekday, GetDate()), GetDate());
I played around with the =DateAdd function, but it keeps throwing me an error for the Day parameter. Also, when I used DateInterval.Day... I get the same error.
However, when I try placing that query into an SSRS expression, it throws me an error. Does anyone know the direct conversion for that query above in SSRS?
SSRS Uses a dialect of Visual Basic, its Date functions are different from TSQL, you have to use
"d" instead of DAY for day interval
"w" instead of WEEKDAY for weekday
Now() instead of GetDate() for current date.
Try
=DateAdd("d", 0 - DatePart("w", Now()), Now())
Is it possible to create an sql statement that selects the week number (NOT the day of week - or the day number in a week). I'm creating a view to select this extra information along with a couple of other fields and thus can not use a stored procedure. I'm aware that it's possible to create a UDF to do the trick, but if at all possible i'd rather only have to add a view to this database, than both a view and a function.
Any ideas? Also where i come from, the week starts monday and week 1 is the first week of the year with atleast 4 days.
Related:
How do I calculate the week number given a date?
Be aware that there are differences in what is regarded the correct week number, depending on the culture. Week numbers depend on a couple of assumptions that differ from country to country, see Wikipedia article on the matter. There is an ISO standard (ISO 8601) that applies to week numbers.
The SQL server integrated DATEPART() function does not necessarily do The Right Thing. SQL Server assumes day 1 of week 1 would be January 1, for many applications that's wrong.
Calculating week numbers correctly is non-trivial, and different implementations can be found on the web. For example, there's an UDF that calculates the ISO week numbers from 1930-2030, being one among many others. You'll have to check what works for you.
This one is from Books Online (though you probably want to use the one from Jonas Lincoln's answer, the BOL version seems to be incorrect):
CREATE FUNCTION ISOweek (#DATE DATETIME)
RETURNS INT
AS
BEGIN
DECLARE #ISOweek INT
SET #ISOweek = DATEPART(wk,#DATE)
+1
-DATEPART(wk,CAST(DATEPART(yy,#DATE) AS CHAR(4))+'0104')
-- Special cases: Jan 1-3 may belong to the previous year
IF (#ISOweek=0)
SET #ISOweek = dbo.ISOweek(CAST(DATEPART(yy,#DATE) - 1
AS CHAR(4))+'12'+ CAST(24+DATEPART(DAY,#DATE) AS CHAR(2)))+1
-- Special case: Dec 29-31 may belong to the next year
IF ((DATEPART(mm,#DATE)=12) AND
((DATEPART(dd,#DATE)-DATEPART(dw,#DATE))>= 28))
SET #ISOweek=1
RETURN(#ISOweek)
END
GO
You need the ISO week. From http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=60510, here's an implementation:
drop function dbo.F_ISO_WEEK_OF_YEAR
go
create function dbo.F_ISO_WEEK_OF_YEAR
(
#Date datetime
)
returns int
as
/*
Function F_ISO_WEEK_OF_YEAR returns the
ISO 8601 week of the year for the date passed.
*/
begin
declare #WeekOfYear int
select
-- Compute week of year as (days since start of year/7)+1
-- Division by 7 gives whole weeks since start of year.
-- Adding 1 starts week number at 1, instead of zero.
#WeekOfYear =
(datediff(dd,
-- Case finds start of year
case
when NextYrStart <= #date
then NextYrStart
when CurrYrStart <= #date
then CurrYrStart
else PriorYrStart
end,#date)/7)+1
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4 =
dateadd(dd,3,dateadd(yy,datediff(yy,0,#date),0))
) aa
) a
return #WeekOfYear
end
go
Looks like the DATEPART mssql function should help you out with ...
DATEPART(wk, ‘Jan 1, xxxx’) = 1
Well I'll be.. turns out there is a way to set the first day of the week, DATEFIRST
SET DATEFIRST 1 -- for monday
Update: Now I understand better, what the OP wants.. which is custom-logic for this. I don't think MSSQL would have functions with such rich level of customization. But I may be wrong... I think you'll have to roll your own UDF here...sorry
FORGET THE OTHER ANSWERS
The question specifies "the week starts monday and week 1 is the first week of the year with atleast 4 days." This is ISO 8601 standard and what this answer provides. This function is used in production on our site.
This is all you need:
CREATE FUNCTION ISOweek (#DATE DATETIME)
RETURNS INT
AS
BEGIN
RETURN (datepart(DY, datediff(d, 0, #DATE) / 7 * 7 + 3)+6) / 7
END
GO
This will return you the week number of date entered in quotes
SELECT DATEPART( wk, 'enter the date over here' )
Looks like datepart will get you part of the way there, but you'll have to adjust to get your correct week number, based on the day of week of Jan 1 of the given year. I'm not familiar enough with T-SQL to do that, but it should be possible. Pity there isn't a mode argument as in MySQL
have you considered using the WEEK function?
This will get you the week of the year for the specified date that you pass in.
SELECT { fn WEEK(GETDATE()) } AS WeekNumber, { fn WEEK(CONVERT(DATETIME, '2008-01-01 00:00:00', 102)) } AS FirstWeekOfYear, { fn WEEK(CONVERT(DATETIME, '2008-12-31 00:00:00', 102)) } AS LastWeekOfYear
This outputs the following SQL2000 and SQL2005:
WeekNumber: 50
FirstWeekOfYear: 1
LastWeekOfYear: 53
I Hope this helps :)
Why yet again, people make mountains out of mole-hills, it astounds me?
So simple...
select DATEPART(wk, GETDATE())