C Registry Functions In Windows API - c

Question

RegOpenKeyEx()
I want to printf("Success") or printf("Failure") depending on if the function fails or succeeds
How would I do such a conditional while keeping it neat and legible?
I am wanting to stay away from this :
if (RegOpenKeyEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) != 0 )
{
//CODE
}

Answer 1

Are you asking how to check why it failed?
"A nonzero error code defined in Winerror.h indicates failure. To get a generic description of the error, call FormatMessage with the FORMAT_MESSAGE_FROM_SYSTEM flag set."
So.. ERROR_SUCCESS if succeeded, error code if it fails.

Answer 2

After checking the unedited question, I think the only thing you can do is to break up the statement into multiple statements like this:
const char* regKey = "BIG_STRING......";
DWORD errorCode = RegOpenKeyEx(...);
if(ERROR_SUCCESS == errorCode)
{
//Rest of the code
}
else
{
//Error handling
}

Answer 3

You can use newlines, or name things or both,
LONG result = RegOpenKeyEx(HKEY_LOCAL_MACHINE,
"HUGE LONG KYEY STRUCTURE HERE",
0,KEY_SET_VALUE);
if(result != 0 ) {
...
or perhaps
LPCTSTR keypath = "HUGE LONG KYEY STRUCTURE HERE";
if( RegOpenKeyEx(HKEY_LOCAL_MACHINE,keypath,0,KEY_SET_VALUE) != 0 ) {
...

Answer 4

You could instead use the ternary operator:
bool success = (RegKeyOpenEx(...) == ERROR_SUCCESS);
printf("%s\n", success ? "Success" : "Failure");

Answer 5

It does not return ERROR_SUCCESS when it does not succeed. Is that what you mean?
for multiple checks of error codes use:
LONG errors = 0;
errors += abs( RegKeyOpenEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) );
errors += abs( RegKeyOpenEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) );
errors += abs( RegKeyOpenEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) );
errors += abs( RegKeyOpenEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) );
errors += abs( RegKeyOpenEx(HKEY_LOCAL_MACHINE,"HUGE LONG KYEY STRUCTURE HERE",0,KEY_SET_VALUE) );
if( errors > 0 )
{
print( "OMG It went wrong!\n" );
}
else
{
print( "Hero!\n" );
}