Seg fault when using scanf to define the size - arrays

Question

I have a strange issue with my code :
I have a function generating a dynamic array of struct and only takes an int size as parameter.
It's work well until i try to add just a scanf("d";&size); to choose the size of my array, can't understand why i get a seg fault.
Note : There is no issue with compilation if i remove the line containing scanf
pokemon_t * createPkmDatabase( int taille){
printf("taille %d",taille);
pokemon_t *tableau=malloc(sizeof(pokemon_t)*taille);
...
...
}
int main(){
/*"taille" means size in french */
int taille=5;
printf("Saisir taille : ");
scanf("%d",&taille); /* <-- BREAKS EVERYTHING */
printf("valeur de taille : %d\n ",taille);
pokemon_t *database=createPkmDatabase(taille);
}
I don't get why changing the value of "taille" with a simple scanf change anything the value.
It doesn't even seems to enter in the function bc it doesn't even print the value of the size

Answer 1

There are no errors in the code shown.
Some remarks:
Use the correct type for sizes (size_t)
Always check the result of scanf and malloc
typedef struct {
int x,y,z;
}pokemon_t;
pokemon_t * createPkmDatabase(size_t taille){
printf("taille %d",taille);
pokemon_t *tableau=malloc(sizeof(*tableau)*taille);
return tableau;
}
int main(){
/*"taille" means size in french */
size_t taille;
printf("Saisir taille : ");
if(scanf("%zu",&taille) == 1)
{
printf("valeur de taille : %zu\n ",taille);
pokemon_t *database=createPkmDatabase(taille);
if(database)
{
printf("\nAllocation OK\n");
}
else
{
printf("\nAllocation FAILED\n");
}
free(database);
}
}
https://godbolt.org/z/ExjYe5G94