Printing format with printf - c

Question

I'm doing the past exam and everything has been going well, I've finished the task, but I have some formatting problems.
What I get:
What I want to achieve:
It bothers me and I would be grateful if someone could come up with a solution.
My code for printing the array:
void printArray(int tab[][MAX], int n, int m) {
for (int j = 0; j < m; j++)
{
printf("%5d", j);
}
printf("\n");
for (int k = 0; k < 3 * n + 4; k++)
{
printf("-");
}
printf("\n");
for (int i = 0; i < n; i++)
{
printf("%2d |", i);
for (int j = 0; j < m; j++)
{
printf("%3d", tab[i][j]);
}
printf("\n");
}
}

Answer 1

The offset is off and printf("%5d", j); makes the heading numbers too wide.
Fix it by prepending the first line, but instead of printf("%2d |", i); that you use to prepend each line when printing the values, you can use a blank string, printf("%2s |", "");.
void printArray(int tab[][MAX], int n, int m) {
printf("%2s |", ""); // this fixes the offset
for (int j = 0; j < m; j++)
{
printf("%3d", j); // and use the same width as when printing the values
}
// ...

Answer 2

Here's my solution, with liberal use of width specifiers on the printf statements.
As you change the constant COL_WIDTH, the table should generally automatically adjust.
#include <stdio.h>
void printArray(int tab[][4], int n, int m)
{
const int COL_WIDTH = 4;
printf("%*.*s|", COL_WIDTH, COL_WIDTH, "");
for (int j = 0; j < m; j++)
{
printf("%*d", COL_WIDTH, j);
}
printf("\n%.*s", COL_WIDTH*(n+1)+1, "----------------------------------------");
for (int i = 0; i < n; i++)
{
printf("\n%*d |", COL_WIDTH-1, i);
for (int j = 0; j < m; j++)
{
printf("%*d", COL_WIDTH, tab[i][j]);
}
}
}
int main(void) {
int table[][4] = { { 1, 2, 1, 2}, {2, 2, 3, 2}, {1, 3, 2, 3}, {2, 2, 2, 1} };
printArray(table, 4, 4);
return 0;
}
Output
| 0 1 2 3
---------------------
0 | 1 2 1 2
1 | 2 2 3 2
2 | 1 3 2 3
3 | 2 2 2 1