Split snowflake db string based on a delimiter - snowflake-cloud-data-platform

Question

got a string
AccountID, ÿþ 23.04.2019 ÿþ ÿþ AccountNum, ÿþ 68 ÿþ ÿþ ActiveDate, ÿþ Jan 1 1900 12:00AM ÿþ ÿþ BankAccount, ÿþ ÿþ ÿþ BankAccountType, ÿþ 0 ÿþ 1 ÿþ BankCIN, ÿþ ÿþ ÿþ BankCodeType, ÿþ 0 ÿþ 0 ÿþ BankConstantSymbol, ÿþ 0 ÿþ ÿþ BankContractAccount, ÿþ ÿþ ÿþ BankGroupID, ÿþ ÿþ ÿþ BankIBAN, ÿþ ÿþ ÿþ CellularPhone, ÿþ 123 ÿþ 321 ÿþ ContactPerson
text format is
[ColumnName], ÿþ [OldValue] ÿþ [NewValue] ÿþ
Required result is
Thanks for any pointers!
Tried replacing the delimiter with split_to_table, tried split_part...keep getting stuck on the time from activedate. Then I assumed since I could split_to_table I'll use LAG or LEAD to get the following index value as a column...but got stuck.

Answer 1

This seems to work:
WITH SPLIT_DATA AS (
SELECT
-- Each group of 3 values will form the same row
ceil(index/3) ROW_ID
-- label each element as to which column in each row it should be assigned to
, case when mod(index,3) = 0 then 3 else mod(index,3) end pos
-- Remove the trailing comma from the column name values
, CASE WHEN RIGHT(TRIM(VALUE),1) = ',' THEN LEFT(TRIM(VALUE),LENGTH(TRIM(VALUE))-1) ELSE TRIM(VALUE) END VALUE
FROM COMPLEX_SPLIT, LATERAL SPLIT_TO_TABLE(LONG_STRING,'ÿþ ')
),
PIVOT_DATA AS (
SELECT *
FROM SPLIT_DATA
PIVOT(MIN(VALUE) FOR POS IN (1, 2, 3))
AS p (ROW_ID, COLUMN_NAME, OLD_VALUE, NEW_VALUE)
)
SELECT COLUMN_NAME, OLD_VALUE, NEW_VALUE
FROM PIVOT_DATA
ORDER BY COLUMN_NAME
;