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I know strings end with '/0' in C. While I'm dynamically allocating memory for a string, how do I handle that?
Also, how would you print out a dynamically allocated string? Because I've tried the regular way to print out a string and it did not work.
For the first question, I tried:
int len;
scanf("%d", &len);
char* str = (char*)malloc(sizeof(char)*len);
for (int i = 0; i<len; ++i){
scanf("%c", (str+i));
}
For the second question, I tried
printf("%s", *str);
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I have some materials showing this code. what does code means by making these assignments?
char inputfilename[128];
inputfilename[0] = 0;
char *argv[128];
*argv[1] = 0;
In C, character arrays are terminated by a null character (value 0). In both cases in your example, the code initializes the strings to "empty" (with a terminator in the first element). This would prove useful in any subsequent string operations (strcat, strcpy, etc.).
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This code prints the array elements, but I can't understand how does k[x-1] gives the array elements.
#include<stdio.h>
int main()
{
int x[]={2,4,6,8,10},k=1;
while (k<=5)
{
printf ("%3d",k[x-1]);
k++;
}
return 0;
}
Array indexes start at 0 in C. An array like int x[]={2,4,6,8,10} will have a value x[0]=2 and so forth. Typically, when iterating through an array, a convention like this is used:
for (int i = 0; i < length; i++)
printf("%3d",x[i]);
Since the code you provided begins the indexing at 1, you have to subtract one to fetch the proper element.
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copy all characters from one character array to another without using strcpy function.
char s1[80],s2[80];
int i;
printf("input s2");
scanf("%s",&s2);
for(i=0;i<=strlen(s2);i++)
s1[i]=s2[i];
printf("s1:%s",s1);
Instead of scanf, using gets function for getting input with spaces.
#include<stdio.h>
int main()
{
char s1[80],s2[80];
int i;
printf("input s2");
// scanf("%c",&s2);
gets(s2);
printf("%d",strlen(s2));
for(i=0;i<strlen(s2);i++)
{
s1[i]=s2[i];
}
printf("s1:%s",s1);
}
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the question is the following: "How do I split a string into 3 parts in C?"
The string is something similar to the following: "Roberta$$$Anna$$$$$$Massimo$$$"
I need to split it exactly after 10 characters (Roberta$$$, Anna$$$$$$, Massimo$$$), and please notice that they aren't separated by a spacebar, so I think I cannot use the strtok function or the library string.h to split them.
char source[] = "Roberta$$$Anna$$$$$$Massimo$$$";
char part1[11];
char part2[11];
char part3[11];
memmove(part1, &source[ 0], 10);
part1[10] = '\0';
memmove(part2, &source[10], 10);
part2[10] = '\0';
memmove(part3, &source[20], 10);
part3[10] = '\0';
You could use strncpy() or memcpy() instead of memmove().
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char string[]="DGS021J0W0S1000.0S20000S3000.0S4000.0S50.00S60.00F";
how to get S[1-5]
thanks!
Use strncpy() standard function
char S[6] = {0};
strncpy(S, string+1 , 5);
If you want to copy from the beginning of the string to the 5th charachter, then your question should be
how to get S[0-4]
and not S[1-5] because array index in C start from 0 and not from 1. and the solution for this case will be
char S[6] = {0};
strncpy(S, string , 5);
I think you are looking for substring methods.
You can do it in two for loops in C.