from java to MIPS assembly for a simple while loop [closed] - loops

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i need to convert a code from java to assembly, but it only prints the first message. but the last two message dosent print neither the message nor the numbers of the result.
the two code in java and assembly are that i wrote as follow :
the code in java:
/**
* this program count how many 10s can be in a givin number the return the extra or the remain that less than 10
*/
Scanner input=new Scanner(System.in);
System.out.println("enter num: ");//print input message
int num=input.nextInt();// user input
int numOf10=0;//counter
while(num>9){ //start of while loop
num-=10;//subtruct 10 from the input number
numOf10++;//add one to the counter
}
System.out.println("number of 10 is: "+numOf10);//print message contain
System.out.println("the remain: "+num);//print message contain
////////////////////////////////////////////////////////////////////////////////////
the code in assembly:
.data
EnterMessage: .asciiz"Enter the number:\n "
ResultMessage: .asciiz"number of 10 is:\n"
remainMessage: .asciiz"the remain:\n "
.text
main:
#ask user to enter input
li $v0,4
la $a0,EnterMessage
syscall
#read user input
li $v0,5
syscall
#save input
move $t0,$v0
#creat variables
#$t2=9
addi $t2,$zero,9
#counter=$t3=0
addi $t3,$zero,0
#jal loop
#while loop
loop:
ble $t1,$t2,exit
subi $t0,$t0,10
addi $t3,$t3,1
j loop
print:
#print ResultMessage num
li $v0,1
move $a0,$t3
syscall
#print ResultMessage
li $v0,4
la $a0,ResultMessage
syscall
#print remainMessage num
li $v0,1
move $a0,$t0
syscall
#print remainMessage
li $v0,4
la $a0,remainMessage
syscall
#close the program
exit:
#end
li $v0,10
syscall

Answer 1

Your problem is here:
ble $t1,$t2,exit
There are a couple of problems here. First, exit leads to:
#close the program
exit:
#end
li $v0,10
syscall
So you've jumped to the end without doing anything.
Second, you've chosen $t1 as one of your registers for the compare, which you never set up. So its value is currently unknown (most likely the kernel or OS or whatever zeroed all your registers prior to main but it's not a good practice to assume that.)
Let's think about what's being asked:
while(num>9){ //start of while loop
num-=10;//subtruct 10 from the input number
numOf10++;//add one to the counter
}
When translating a high-level language to assembly we don't have to do everything the same way it was written in the source language. In terms of goto we can think of this as:
loop_begin:
if (num <= 9) goto loop_exit;
num -= 10;
numOf10++;
goto loop_begin;
loop_exit:
You've got the right idea for the most part. The nice thing about MIPS is that the branching syntax isn't nearly as obtuse as other assembly languages, since you don't have to remember whether carry clear means less than or greater than etc.
loop:
ble $t0,$t2,print # if $t0 (num) <= 9 goto print
subi $t0,$t0,10 # num = num - 10
addi $t3,$t3,1 # counter++
j loop # goto loop
Edit: Fixed typo in comments in last section