I have a C program where I run 3 branches of code: 2 that i started through pthread_create and the normal one.
I am wondering how to correctly protect it if my second thread fails to be created somehow.
Here is my code:
# include <pthread.h>
# include <stdio.h>
# include <stdlib.h>
# include <semaphore.h>
# include <errno.h>
typedef struct s_philo{
sem_t *first;
sem_t *second;
sem_t *stop_A;
sem_t *stop_B;
pthread_t A_thread;
pthread_t B_thread;
} t_philo;
void sem_close_safe(sem_t *sem)
{
if (sem_close(sem) == -1)
printf("Failed to close semaphore\n");
}
int free_philo(t_philo *philo)
{
if (philo->first)
sem_close_safe(philo->first);
if (philo->second)
sem_close_safe(philo->second);
if (philo->stop_A)
sem_close_safe(philo->stop_A);
if (philo->stop_B)
sem_close_safe(philo->stop_B);
free(philo);
return (1);
}
void *check_philo(t_philo *philo)
{
void *check;
check = philo;
if (!philo->first || !philo->second || !philo->stop_A || !philo->stop_B)
check = NULL;
return (check);
}
sem_t *sem_open_new_safe(const char *name, unsigned int value)
{
sem_t *sem;
sem = sem_open(name, O_CREAT | O_EXCL, 0644, value);
if (errno == EEXIST)
{
if (sem_unlink(name) == -1)
return (NULL);
sem = sem_open(name, O_CREAT | O_EXCL, 0644, value);
}
if (sem == SEM_FAILED)
return (NULL);
if (sem_unlink(name) == -1)
{
sem_close_safe(sem);
return (NULL);
}
return (sem);
}
void *A(void *p)
{
t_philo *philo;
philo = (t_philo *) p;
sem_wait(philo->stop_A);
sem_post(philo->stop_A);
return (NULL);
}
void *B(void *p)
{
t_philo *philo;
philo = (t_philo *) p;
sem_wait(philo->stop_B);
sem_post(philo->stop_B);
return (NULL);
}
int main(void)
{
t_philo *philo;
int i;
philo = malloc(sizeof(*philo));
philo->first = sem_open_new_safe("/first", 1);
philo->second = sem_open_new_safe("/second", 1);
philo->stop_A = sem_open_new_safe("/stop_A", 0);
philo->stop_B = sem_open_new_safe("/stop_B", 0);
if (!check_philo(philo))
return (free_philo(philo));
if (pthread_create(&philo->A_thread, NULL, &A, (void *)philo))
return (free_philo(philo));
if (pthread_create(&philo->B_thread, NULL, &B, (void *)philo))
return (free_philo(philo));
i = 0;
while (i++ < 100)
{
if (sem_wait(philo->first) == -1)
sem_post(philo->stop_B);
if (sem_wait(philo->second) == -1)
sem_post(philo->stop_A);
printf("%d\n", i);
sem_post(philo->second);
sem_post(philo->first);
}
sem_post(philo->stop_B);
sem_post(philo->stop_A);
pthread_join(philo->A_thread, NULL);
pthread_join(philo->B_thread, NULL);
free_philo(philo);
return (0);
}
Both of my A and B threads wait for semaphores on their first lines of code so they will never return on their own if I do not post these semaphores.
Should I pthread_join thread A ? Should I manually post some semaphores to force thread A to continue its execution and return ? Or maybe I should use pthread_detach ? I am a bit lost.
Edit: I have been asked to post more code to make it executable, but I have a lot of lines of code and it would just drown the above one. What I am looking for (if it exists) is not a guided code-specific answer, but more of a best practice to gracefully handle pthread_create errors.
Edit 2: I added the least code I could to make it runnable
The general case looks something like this pseudocode:
if (!setup_A()) {
exit(FAILURE);
}
if (!setup_B()) {
teardown_A();
exit(FAILURE);
}
if (!setup_C()) {
teardown_B();
teardown_A();
exit(FAILURE);
}
do_successful_processing();
teardown_C();
teardown_B();
teardown_A();
and you're effectively asking how to write teardown_B().
The general solution (assuming you can't just switch to C++ to use proper destructors and RAII) does not exist. The teardown is just as specific to the details of A, B, C and your application as the setup is.
I am wondering how to correctly protect it if my second thread fails to be created somehow.
The proximate answer is to tell the thread to quit (in some application-specific way), and then to join it.
The actual semantics of requesting a shutdown are specific to your code, since you wrote the function that thread is executing. Here, it should be sufficient to sem_post the semaphone thread A is waiting on.
NB. DO NOT use pthread_kill to shut down threads, if you can possibly avoid it. It's much better to write clean shutdown handling explicitly.
I am wondering how to correctly protect it if my second thread fails to be created somehow.
Easiest would be to simply call exit(1) in the case that thread creation fails. That will terminate the whole process, including all its threads. All resources owned by the process will be cleaned up by the system.
That does create a possible issue if the program wants to clean up any persistent resources, such as files or named semaphores. Often that's not a major issue, for if the program fails then it may be ok for its termination to be less tidy than if it succeeds. Nevertheless, there are ways to reduce that impact.
In particular, you can minimize the program's use of modifiable persistent resources. For example, your program would be all-around cleaner if it used unnamed semaphores instead of named ones. You would not need to watch out for existing ones when you create them, and since they are being used only within a single process, you would not need to worry about failing to clean them up before terminating.
But where you want some kind of affirmative cleanup to happen when the program terminates, you always have the option to use atexit() to register an exit handler to perform that. There are some caveats, but it's good to be aware of this option.
Should I pthread_join thread A ?
In your particular example, I see no reason to do so. It might be more appropriate in other cases.
Should I manually post some semaphores to force thread A to continue its execution and return ?
If you plan to join thread A then you need to ensure that it will, in fact, terminate. In this case, it looks like yes, you could achieve that by semaphore manipulation, but cases where it actually mattered would be more complex. Ensuring A's timely would probably not be so simple in such cases.
Or maybe I should use pthread_detach ?
There is no advantage at all to doing that in this case. Thread A will be terminated when the process terminates, regardless of whether it is detached. And presumably that's what you want in your example, for it would not make progress if it were the only live thread left in the process.
Related
In my destructor I want to destroy a thread cleanly.
My goal is to wait for a thread to finish executing and THEN destroy the thread.
The only thing I found about querying the state of a pthread is pthread_attr_setdetachstate but this only tells you if your thread is:
PTHREAD_CREATE_DETACHED
PTHREAD_CREATE_JOINABLE
Both of those have nothing to do with whether the thread is still running or not.
How do you query a pthread to see if it is still running?
It sounds like you have two questions here:
How can I wait until my thread completes?
Answer: This is directly supported by pthreads -- make your thread-to-be-stopped JOINABLE (when it is first started), and use pthread_join() to block your current thread until the thread-to-be-stopped is no longer running.
How can I tell if my thread is still running?
Answer: You can add a "thread_complete" flag to do the trick:
Scenario: Thread A wants to know if Thread B is still alive.
When Thread B is created, it is given a pointer to the "thread_complete" flag address. The "thread_complete" flag should be initialized to NOT_COMPLETED before the thread is created. Thread B's entry point function should immediately call pthread_cleanup_push() to push a "cleanup handler" which sets the "thread_complete" flag to COMPLETED.
See details about cleanup handlers here: pthread cleanup handlers
You'll want to include a corresponding pthread_cleanup_pop(1) call to ensure that the cleanup handler gets called no matter what (i.e. if the thread exits normally OR due to cancellation, etc.).
Then, Thread A can simply check the "thread_complete" flag to see if Thread B has exited yet.
NOTE: Your "thread_complete" flag should be declared "volatile" and should be an atomic type -- the GNU compilers provide the sig_atomic_t for this purpose. This allows the two threads consistent access the same data without the need for synchronization constructs (mutexes/semaphores).
pthread_kill(tid, 0);
No signal is sent, but error checking is still performed so you can use that to check
existence of tid.
CAUTION: This answer is incorrect. The standard specifically prohibits passing the ID of a thread whose lifetime has ended. That ID might now specify a different thread or, worse, it might refer to memory that has been freed, causing a crash.
I think all you really need is to call pthread_join(). That call won't return until the thread has exited.
If you only want to poll to see whether the thread is still running or not (and note that is usually not what you should be wanting to do!), you could have the thread set a volatile boolean to false just before it exits... then your main-thread could read the boolean and if it's still true, you know the thread is still running. (if it's false, on the other hand, you know the thread is at least almost gone; it may still be running cleanup code that occurs after it sets the boolean to false, though, so even in this case you should still call pthread_join before trying to free any resources the thread might have access to)
There is not fully portable solution, look if your platform supports pthread_tryjoin_np or pthread_timedjoin_np. So you just check if thread can be joined (of course created with PTHREAD_CREATE_JOINABLE).
Let me note on the "winning" answer, which has a huge hidden flaw, and in some contexts it can lead to crashes. Unless you use pthread_join, it will coming up again and again. Assume you are having a process and a shared library. Call the library lib.so.
You dlopen it, you start a thread in it. Assume you don't want it join to it, so you set it detachable.
Process and shared lib's logic doing its work, etc...
You want to load out lib.so, because you don't need it any more.
You call a shutdown on the thread and you say, that you want to read a flag afterwards from your lib.so's thread, that it have finished.
You continue on another thread with dlclose, because you see, that you have saw, that the flag is now showing the thread as "finished"
dlclose will load out all stack and code related memory.
Whops, but dlclose does not stop threads. And you know, even when you are in the last line of the cleanup handler to set the "thread is finished" volatile atomic flag variable, you still have to return from a lot of methods on the stack, giving back values, etc. If a huge thread priority was given to #5+#6's thread, you will receive dlclose before you could REALLY stop on the thread. You will have some nice crashes sometimes.
Let me point out, that this is not a hipothetical problem, I had the same issue on our project.
I believe I've come up with a solution that at least works for Linux. Whenever I create a thread I have it save it's LWP (Light Weight Process ID) and assign it a unique name, eg.
int lwp = syscall(SYS_gettid);
prctl(PR_SET_NAME, (long)"unique name", 0, 0, 0);
Then, to check if the thread exists later I open /proc/pid/task/lwp/comm and read it. If the file exists and it's contents match the unique name I assigned, the thread exists. Note that this does NOT pass a possibly defunct/reused TID to any library function, so no crashes.
#include <stdio.h>
#include <stdlib.h>
#include <stdarg.h>
#include <pthread.h>
#include <sys/prctl.h>
#include <sys/file.h>
#include <stdbool.h>
#include <string.h>
#include <unistd.h>
#include <syscall.h>
pthread_t subthread_tid;
int subthread_lwp;
#define UNIQUE_NAME "unique name"
bool thread_exists (pthread_t thread_id)
{
char path[100];
char thread_name[16];
FILE *fp;
bool thread_exists = false;
// If the /proc/<pid>/task/<lwp>/comm file exists and it's contents match the "unique name" the
// thread exists, and it's the original thread (TID has NOT been reused).
sprintf(path, "/proc/%d/task/%d/comm", getpid(), subthread_lwp);
fp = fopen(path, "r");
if( fp != NULL ) {
fgets(thread_name, 16, fp);
fclose(fp);
// Need to trim off the newline
thread_name[strlen(thread_name)-1] = '\0';
if( strcmp(UNIQUE_NAME, thread_name) == 0 ) {
thread_exists = true;
}
}
if( thread_exists ) {
printf("thread exists\n");
} else {
printf("thread does NOT exist\n");
}
return thread_exists;
}
void *subthread (void *unused)
{
subthread_lwp = syscall(SYS_gettid);
prctl(PR_SET_NAME, (long)UNIQUE_NAME, 0, 0, 0);
sleep(10000);
return NULL;
}
int main (int argc, char *argv[], char *envp[])
{
int error_number;
pthread_create(&subthread_tid, NULL, subthread, NULL);
printf("pthread_create()\n");
sleep(1);
thread_exists(subthread_tid);
pthread_cancel(subthread_tid);
printf("pthread_cancel()\n");
sleep(1);
thread_exists(subthread_tid);
error_number = pthread_join(subthread_tid, NULL);
if( error_number == 0 ) {
printf("pthread_join() successful\n");
} else {
printf("pthread_join() failed, %d\n", error_number);
}
thread_exists(subthread_tid);
exit(0);
}
#include <string.h>
#include <stdio.h>
#include <pthread.h>
#include <signal.h>
#include <unistd.h>
void* thread1 (void* arg);
void* thread2 (void* arg);
int main()
{
pthread_t thr_id;
pthread_create(&thr_id, NULL, thread1, NULL);
sleep(10);
}
void* thread1 (void* arg)
{
pthread_t thr_id = 0;
pthread_create(&thr_id, NULL, thread2, NULL);
sleep(5);
int ret = 0;
if( (ret = pthread_kill(thr_id, 0)) == 0)
{
printf("still running\n");
pthread_join(thr_id, NULL);
}
else
{
printf("RIP Thread = %d\n",ret);
}
}
void* thread2 (void* arg)
{
// sleep(5);
printf("I am done\n");
}
I'm creating a multi-thread program in C and I've some troubles.
There you have the function which create the threads :
void create_thread(t_game_data *game_data)
{
size_t i;
t_args *args = malloc(sizeof(t_args));
i = 0;
args->game = game_data;
while (i < 10)
{
args->initialized = 0;
args->id = i;
printf("%zu CREATION\n", i);//TODO: Debug
pthread_create(&game_data->object[i]->thread_id, NULL, &do_action, args);
i++;
while (args->initialized == 0)
continue;
}
}
Here you have my args struct :
typedef struct s_args
{
t_game_data *object;
size_t id;
int initialized;
}args;
And finally, the function which handle the created threads
void *do_action(void *v_args)
{
t_args *args;
t_game_data *game;
size_t id;
args = v_args;
game = args->game;
id = args->id;
args->initialized = 1;
[...]
return (NULL);
}
The problem is :
The main thread will create new thread faster than the new thread can init his variables :
args = v_args;
game = args->game;
id = args->id;
So, sometime, 2 different threads will get same id from args->id.
To solve that, I use an variable initialized as a bool so make "sleep" the main thread during the new thread's initialization.
But I think that is really sinful.
Maybe there is a way to do that with a mutex? But I heard it wasn't "legal" to unlock a mutex which does not belong his thread.
Thanks for your answers!
The easiest solution to this problem would be to pass a different t_args object to each new thread. To do that, move the allocation inside the loop, and make each thread responsible for freeing its own argument struct:
void create_thread(t_game_data *game_data) {
for (size_t i = 0; i < 10; i++) {
t_args *args = malloc(sizeof(t_args));
if (!args) {
/* ... handle allocation error ... */
} else {
args->game = game_data;
args->id = i;
printf("%zu CREATION\n", i);//TODO: Debug
if (pthread_create(&game_data->object[i]->thread_id, NULL,
&do_action, args) != 0) {
// thread creation failed
free(args);
// ...
}
}
}
}
// ...
void *do_action(void *v_args) {
t_args *args = v_args;
t_game_data *game = args->game;
size_t id = args->id;
free(v_args);
args = v_args = NULL;
// ...
return (NULL);
}
But you also write:
To solve that, I use an variable initialized as a bool so make "sleep"
the main thread during the new thread's initialization.
But I think that is really sinful. Maybe there is a way to do that
with a mutex? But I heard it wasn't "legal" to unlock a mutex which
does not belong his thread.
If you nevertheless wanted one thread to wait for another thread to modify some data, as your original strategy requires, then you must employ either atomic data or some kind of synchronization object. Your code otherwise contains a data race, and therefore has undefined behavior. In practice, you cannot assume in your original code that the main thread will ever see the new thread's write to args->initialized. "Sinful" is an unusual way to describe that, but maybe appropriate if you belong to the Church of the Holy C.
You could solve that problem with a mutex by protecting just the test of args->initialized in your loop -- not the whole loop -- with a mutex, and protecting the threads' write to that object with the same mutex, but that's nasty and ugly. It would be far better to wait for the new thread to increment a semaphore (not a busy wait, and the initialized variable is replaced by the semaphore), or to set up and wait on a condition variable (again not a busy wait, but the initialized variable or an equivalent is still needed).
The problem is that in create_thread you are passing the same t_args structure to each thread. In reality, you probably want to create your own t_args structure for each thread.
What's happening is your 1st thread is starting up with the args passed to it. Before that thread can run do_action the loop is modifying the args structure. Since thread2 and thread1 will both be pointing to the same args structure, when they run do_action they will have the same id.
Oh, and don't forget to not leak your memory
Your solution should work in theory except for a couple of major problems.
The main thread will sit spinning in the while loop that checks the flag using CPU cycles (this is the least bad problem and can be OK if you know it won't have to wait long)
Compiler optimisers can get trigger happy with respect to empty loops. They are also often unaware that a variable may get modified by other threads and can make bad decisions on that basis.
On multi core systems, the main thread may never see the change to args->initiialzed or at least not until much later if the change is in the cache of another core that hasn't been flushed back to main memory yet.
You can use John Bollinger's solution that mallocs a new set of args for each thread and it is fine. The only down side is a malloc/free pair for each thread creation. The alternative is to use "proper" synchronisation functions like Santosh suggests. I would probably consider this except I would use a semaphore as being a bit simpler than a condition variable.
A semaphore is an atomic counter with two operations: wait and signal. The wait operation decrements the semaphore if its value is greater than zero, otherwise it puts the thread into a wait state. The signal operation increments the semaphore, unless there are threads waiting on it. If there are, it wakes one of the threads up.
The solution is therefore to create a semaphore with an initial value of 0, start the thread and wait on the semaphore. The thread then signals the semaphore when it is finished with the initialisation.
#include <semaphore.h>
// other stuff
sem_t semaphore;
void create_thread(t_game_data *game_data)
{
size_t i;
t_args args;
i = 0;
if (sem_init(&semaphore, 0, 0) == -1) // third arg is initial value
{
// error
}
args.game = game_data;
while (i < 10)
{
args.id = i;
printf("%zu CREATION\n", i);//TODO: Debug
pthread_create(&game_data->object[i]->thread_id, NULL, &do_action, args);
sem_wait(&semaphore);
i++;
}
sem_destroy(&semaphore);
}
void *do_action(void *v_args) {
t_args *args = v_args;
t_game_data *game = args->game;
size_t id = args->id;
sem_post(&semaphore);
// Rest of the thread work
return NULL;
}
Because of the synchronisation, I can reuse the args struct safely, in fact, I don't even need to malloc it - it's small so I declare it local to the function.
Having said all that, I still think John Bollinger's solution is better for this use-case but it's useful to be aware of semaphores generally.
You should consider using condition variable for this. You can find an example here http://maxim.int.ru/bookshelf/PthreadsProgram/htm/r_28.html.
Basically wait in the main thread and signal in your other threads.
I was trying to implement a multi-threaded program using binary semaphore. Here is the code:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
#include <semaphore.h>
int g = 0;
sem_t *semaphore;
void *myThreadFun(void *vargp)
{
int myid = (int)vargp;
static int s = 0;
sem_wait(semaphore);
++s; ++g;
printf("Thread ID: %d, Static: %d, Global: %d\n", myid, s, g);
fflush(stdout);
sem_post(semaphore);
pthread_exit(0);
}
int main()
{
int i;
pthread_t tid;
if ((semaphore = sem_open("/semaphore", O_CREAT, 0644, 3))==SEM_FAILED) {
printf("semaphore initialization failed\n");
}
for (i = 0; i < 3; i++) {
pthread_create(&tid, NULL, myThreadFun, (void *)i);
}
pthread_exit(NULL);
return 0;
}
Now, when I opened the sempahore, I made the count 3. I was expecting that this wouldnt work, and I would get race condition, because each thread is now capable of decrementing the count.
Is there something wrong with the implementation? Also, if I make the count 0 during sem_open, wouldnt that initiate a deadlock condition, because all the threads should be blocked on sem_wait.
Now, when I opened the sempahore, I made the count 3. I was expecting that this wouldnt work, and I would get race condition, because each thread is now capable of decrementing the count.
And how do you judge that there isn't any race? Observing output consistent with what you could rely upon in the absence of a data race in no way proves that there isn't a data race. It merely fails provide any evidence of one.
However, you seem to be suggesting that there would be a data race inherent in more than one thread concurrently performing a sem_wait() on a semaphore whose value is initially greater than 1 (otherwise which counter are you talking about?). But that's utter nonsense. You're talking about a semaphore. It's a synchronization object. Such objects and the functions that manipulate them are the basis for thread synchronization. They themselves are either completely thread safe or terminally buggy.
Now, you are correct that you open the semaphore with an initial count sufficient to avoid any of your threads blocking in sem_wait(), and that therefore they can all run concurrently in the whole body of myThreadFun(). You have not established, however, that they in fact do run concurrently. There are several reasons why they might not do. If they do run concurrently, then the incrementing of shared variables s and g is indeed of concern, but again, even if you see no signs of a data race, that doesn't mean there isn't one.
Everything else aside, the fact that your threads all call sem_wait(), sem_post(), and printf() induces some synchronization in the form of memory barriers, which would reduce the likelihood of observing anomalous effects on s and g. sem_wait() and sem_post() must contain memory barriers in order to function correctly, regardless of the semaphore's current count. printf() calls are required to use locking to protect the state of the stream from corruption in multi-threaded programs, and it is reasonable to suppose that this will require a memory barrier.
Is there something wrong with the implementation?
Yes. It is not properly synchronized. Initialize the semaphore with count 1 so that the modifications of s and g occur only while exactly one thread has the semaphore locked.
Also, if I make the count 0 during sem_open, wouldnt that initiate a deadlock condition, because all the threads should be blocked on sem_wait.
If the semaphore has count 0 before any of the additional threads are started, then yes. It is therefore inappropriate to open the semaphore with count 0, unless you also subsequently post to it before starting the threads. But you are using a named semaphore. These persist until removed, and you never remove it. The count you specify to sem_open() has no effect unless a new semaphore needs to be created; when an existing semaphore is opened, its count is unchanged.
Also, do have the main thread join all the others before it terminates. It's not inherently wrong not to do so, but in most cases it's required for the semantics you want.
I'll get to the code in a bit that proves you had a race condition. I'll add a couple of different ways to trigger it so you can see how this works. I'm doing this on Linux and passing -std=gnu99 as a param to gcc ie
gcc -Wall -pedantic -lpthread -std=gnu99 semaphore.c -o semtex
Note. In your original example (assuming Linux) one fatal mistake you had was not removing the semaphore. If you run the following command you might see some of these sitting around on your machine
ls -la /dev/shm/sem.*
You need to make sure that there are no old semaphore sitting on the filesystem before running your program or you end up picking up the last settings from the old semaphore. You need to use sem_unlink to clean up.
To run it please use the following.
rm /dev/shm/sem.semtex;./semtex
I'm deliberately making sure that the semaphore is not there before running because if you have a DEADLOCK it can be left around and that causes all sorts of problems when testing.
Now, when I opened the sempahore, I made the count 3. I was expecting
that this wouldn't work, and I would get race condition, because each
thread is now capable of decrementing the count.
You had a race condition but sometimes C is so damned fast things can appear to work because your program can get everything it needs done in the time the OS has allocated to the thread ie the OS didn't preempt it at an important point.
This is one of those cases, the race condition is there you just need to squint a little bit to see it. In the following code you can tweak some parameters to see the a deadlock, correct usage and Undefined Behavior.
#define INITIAL_SEMAPHORE_VALUE CORRECT
The value INITIAL_SEMAPHORE_VALUE can take three values...
#define DEADLOCK 0
#define CORRECT 1
#define INCORRECT 2
I hope they're self explanatory. You can also use two methods to cause the race condition to blow up the program.
#define METHOD sleep
Set the METHOD to spin and you can play with the SPIN_COUNT and find out how many times the loop can run before you actually see a problem, this is C, it can get a lot done before it gets preempted. The code has most of the rest of the information you need in it.
#include <assert.h>
#include <errno.h>
#include <fcntl.h>
#include <pthread.h>
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/stat.h>
#include <unistd.h>
#define DEADLOCK 0 // DEADLOCK
#define CORRECT 1 // CORRECT
#define INCORRECT 2 // INCORRECT
/*
* Change the following values to observe what happen.
*/
#define INITIAL_SEMAPHORE_VALUE CORRECT
//The next value provides to two different ways to trigger the problem, one
//using a tight loop and the other using a system call.
#define METHOD sleep
#if (METHOD == spin)
/* You need to increase the SPIN_COUNT to a value that's big enough that the
* kernel preempts the thread to see it fail. The value set here worked for me
* in a VM but might not work for you, tweak it. */
#define SPIN_COUNT 1000000
#else
/* The reason we can use such a small time for USLEEP is because we're making
* the kernel preempt the thread by using a system call.*/
#define USLEEP_TIME 1
#endif
#define TOT_THREADS 10
static int g = 0;
static int ret = 1729;
sem_t *semaphore;
void *myThreadFun(void *vargp) {
int myid = (int)vargp;
int w = 0;
static int s = 0;
if((w = sem_wait(semaphore)) != 0) {
fprintf(stderr, "Error: %s\n", strerror(errno));
abort();
};
/* This is the interesting part... Between updating `s` and `g` we add
* a delay using one of two methods. */
s++;
#if ( METHOD == spin )
int spin = 0;
while(spin < SPIN_COUNT) {
spin++;
}
#else
usleep(USLEEP_TIME);
#endif
g++;
if(s != g) {
fprintf(stderr, "Fatal Error: s != g in thread: %d, s: %d, g: %d\n", myid, s, g);
abort();
}
printf("Thread ID: %d, Static: %d, Global: %d\n", myid, s, g);
// It's a false sense of security if you think the assert will fail on a race
// condition when you get the params to sem_open wrong It might not be
// detected.
assert(s == g);
if((w = sem_post(semaphore)) != 0) {
fprintf(stderr, "Error: %s\n", strerror(errno));
abort();
};
return &ret;
}
int main(void){
int i;
void *status;
const char *semaphore_name = "semtex";
pthread_t tids[TOT_THREADS];
if((semaphore = sem_open(semaphore_name, O_CREAT, 0644, INITIAL_SEMAPHORE_VALUE)) == SEM_FAILED) {
fprintf(stderr, "Fatal Error: %s\n", strerror(errno));
abort();
}
for (i = 0; i < TOT_THREADS; i++) {
pthread_create(&tids[i], NULL, myThreadFun, (void *) (intptr_t) i);
}
for (i = 0; i < TOT_THREADS; i++) {
pthread_join(tids[i], &status);
assert(*(int*)status == 1729);
}
/*The following line was missing from your original code*/
sem_unlink(semaphore_name);
pthread_exit(0);
}
I've got some code that currently looks like this (simplified)
/* instance in global var *mystruct, count initialized to 0 */
typedef struct {
volatile unsigned int count;
} mystruct_t;
pthread_mutex_t mymutex; // is initialized
/* one thread, goal: block while mystruct->count == 0 */
void x(void *n) {
while(1) {
pthread_mutex_lock(&mymutex);
if(mystruct->count != 0) break;
pthread_mutex_unlock(&mymutex);
}
pthread_mutex_unlock(&mymutex);
printf("count no longer equals zero");
pthread_exit((void*) 0)
}
/* another thread */
void y(void *n) {
sleep(10);
pthread_mutex_lock(&mymutex);
mystruct->count = 10;
pthread_mutex_unlock(&mymutex);
}
This seems inefficient and wrong to me--but I don't know a better way of doing it. Is there a better way, and if so, what is it?
Condition variables allow you to wait for a certain event, and have a different thread signal that condition variable.
You could have a thread that does this:
for (;;)
{
if (avail() > 0)
do_work();
else
pthread_cond_wait();
}
and a different thread that does this:
for (;;)
{
put_work();
pthread_cond_signal();
}
Very simplified of course. :) You'll need to look up how to use it properly, there are some difficulties working with condition variables due to race conditions.
However, if you are certain that the thread will block for a very short time (in order of µs) and rarely, using a spin loop like that is probably more efficient.
A general solution is to use a POSIX semaphore. These are not part of the pthread library but work with pthreads just the same.
Since semaphores are provided in most other multi-threading APIs, it is a general technique that may be applied perhaps more portably; however perhaps more appropriate in this instance is a condition variable, which allows a thread to pend on the conditional value of a variable without polling, which seems to be exactly what you want.
Condition variables are the solution to this problem. Your code can be fairly easily modified to use them:
pthread_mutex_t mymutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t mycond = PTHREAD_COND_INITIALIZER;
/* one thread, goal: block while mystruct->count == 0 */
void x(void *n) {
pthread_mutex_lock(&mymutex);
while (mystruct->count == 0)
pthread_cond_wait(&mycond, &mymutex);
printf("count no longer equals zero");
pthread_mutex_unlock(&mymutex);
pthread_exit((void*) 0)
}
/* another thread */
void y(void *n) {
sleep(10);
pthread_mutex_lock(&mymutex);
mystruct->count = 10;
pthread_cond_signal(&mycond);
pthread_mutex_unlock(&mymutex);
}
Note that you should generally keep the mutex locked while you act on the result - "consume" the event or similar. That's why I moved the pthread_mutex_unlock() to a point after the printf(), even though it doesn't really matter in this toy case.
(Also, in real code it might well make sense to put the mutex and condition variable inside mystruct).
You could use barriers.
You may also use semaphores to synchronize threads.
In my destructor I want to destroy a thread cleanly.
My goal is to wait for a thread to finish executing and THEN destroy the thread.
The only thing I found about querying the state of a pthread is pthread_attr_setdetachstate but this only tells you if your thread is:
PTHREAD_CREATE_DETACHED
PTHREAD_CREATE_JOINABLE
Both of those have nothing to do with whether the thread is still running or not.
How do you query a pthread to see if it is still running?
It sounds like you have two questions here:
How can I wait until my thread completes?
Answer: This is directly supported by pthreads -- make your thread-to-be-stopped JOINABLE (when it is first started), and use pthread_join() to block your current thread until the thread-to-be-stopped is no longer running.
How can I tell if my thread is still running?
Answer: You can add a "thread_complete" flag to do the trick:
Scenario: Thread A wants to know if Thread B is still alive.
When Thread B is created, it is given a pointer to the "thread_complete" flag address. The "thread_complete" flag should be initialized to NOT_COMPLETED before the thread is created. Thread B's entry point function should immediately call pthread_cleanup_push() to push a "cleanup handler" which sets the "thread_complete" flag to COMPLETED.
See details about cleanup handlers here: pthread cleanup handlers
You'll want to include a corresponding pthread_cleanup_pop(1) call to ensure that the cleanup handler gets called no matter what (i.e. if the thread exits normally OR due to cancellation, etc.).
Then, Thread A can simply check the "thread_complete" flag to see if Thread B has exited yet.
NOTE: Your "thread_complete" flag should be declared "volatile" and should be an atomic type -- the GNU compilers provide the sig_atomic_t for this purpose. This allows the two threads consistent access the same data without the need for synchronization constructs (mutexes/semaphores).
pthread_kill(tid, 0);
No signal is sent, but error checking is still performed so you can use that to check
existence of tid.
CAUTION: This answer is incorrect. The standard specifically prohibits passing the ID of a thread whose lifetime has ended. That ID might now specify a different thread or, worse, it might refer to memory that has been freed, causing a crash.
I think all you really need is to call pthread_join(). That call won't return until the thread has exited.
If you only want to poll to see whether the thread is still running or not (and note that is usually not what you should be wanting to do!), you could have the thread set a volatile boolean to false just before it exits... then your main-thread could read the boolean and if it's still true, you know the thread is still running. (if it's false, on the other hand, you know the thread is at least almost gone; it may still be running cleanup code that occurs after it sets the boolean to false, though, so even in this case you should still call pthread_join before trying to free any resources the thread might have access to)
There is not fully portable solution, look if your platform supports pthread_tryjoin_np or pthread_timedjoin_np. So you just check if thread can be joined (of course created with PTHREAD_CREATE_JOINABLE).
Let me note on the "winning" answer, which has a huge hidden flaw, and in some contexts it can lead to crashes. Unless you use pthread_join, it will coming up again and again. Assume you are having a process and a shared library. Call the library lib.so.
You dlopen it, you start a thread in it. Assume you don't want it join to it, so you set it detachable.
Process and shared lib's logic doing its work, etc...
You want to load out lib.so, because you don't need it any more.
You call a shutdown on the thread and you say, that you want to read a flag afterwards from your lib.so's thread, that it have finished.
You continue on another thread with dlclose, because you see, that you have saw, that the flag is now showing the thread as "finished"
dlclose will load out all stack and code related memory.
Whops, but dlclose does not stop threads. And you know, even when you are in the last line of the cleanup handler to set the "thread is finished" volatile atomic flag variable, you still have to return from a lot of methods on the stack, giving back values, etc. If a huge thread priority was given to #5+#6's thread, you will receive dlclose before you could REALLY stop on the thread. You will have some nice crashes sometimes.
Let me point out, that this is not a hipothetical problem, I had the same issue on our project.
I believe I've come up with a solution that at least works for Linux. Whenever I create a thread I have it save it's LWP (Light Weight Process ID) and assign it a unique name, eg.
int lwp = syscall(SYS_gettid);
prctl(PR_SET_NAME, (long)"unique name", 0, 0, 0);
Then, to check if the thread exists later I open /proc/pid/task/lwp/comm and read it. If the file exists and it's contents match the unique name I assigned, the thread exists. Note that this does NOT pass a possibly defunct/reused TID to any library function, so no crashes.
#include <stdio.h>
#include <stdlib.h>
#include <stdarg.h>
#include <pthread.h>
#include <sys/prctl.h>
#include <sys/file.h>
#include <stdbool.h>
#include <string.h>
#include <unistd.h>
#include <syscall.h>
pthread_t subthread_tid;
int subthread_lwp;
#define UNIQUE_NAME "unique name"
bool thread_exists (pthread_t thread_id)
{
char path[100];
char thread_name[16];
FILE *fp;
bool thread_exists = false;
// If the /proc/<pid>/task/<lwp>/comm file exists and it's contents match the "unique name" the
// thread exists, and it's the original thread (TID has NOT been reused).
sprintf(path, "/proc/%d/task/%d/comm", getpid(), subthread_lwp);
fp = fopen(path, "r");
if( fp != NULL ) {
fgets(thread_name, 16, fp);
fclose(fp);
// Need to trim off the newline
thread_name[strlen(thread_name)-1] = '\0';
if( strcmp(UNIQUE_NAME, thread_name) == 0 ) {
thread_exists = true;
}
}
if( thread_exists ) {
printf("thread exists\n");
} else {
printf("thread does NOT exist\n");
}
return thread_exists;
}
void *subthread (void *unused)
{
subthread_lwp = syscall(SYS_gettid);
prctl(PR_SET_NAME, (long)UNIQUE_NAME, 0, 0, 0);
sleep(10000);
return NULL;
}
int main (int argc, char *argv[], char *envp[])
{
int error_number;
pthread_create(&subthread_tid, NULL, subthread, NULL);
printf("pthread_create()\n");
sleep(1);
thread_exists(subthread_tid);
pthread_cancel(subthread_tid);
printf("pthread_cancel()\n");
sleep(1);
thread_exists(subthread_tid);
error_number = pthread_join(subthread_tid, NULL);
if( error_number == 0 ) {
printf("pthread_join() successful\n");
} else {
printf("pthread_join() failed, %d\n", error_number);
}
thread_exists(subthread_tid);
exit(0);
}
#include <string.h>
#include <stdio.h>
#include <pthread.h>
#include <signal.h>
#include <unistd.h>
void* thread1 (void* arg);
void* thread2 (void* arg);
int main()
{
pthread_t thr_id;
pthread_create(&thr_id, NULL, thread1, NULL);
sleep(10);
}
void* thread1 (void* arg)
{
pthread_t thr_id = 0;
pthread_create(&thr_id, NULL, thread2, NULL);
sleep(5);
int ret = 0;
if( (ret = pthread_kill(thr_id, 0)) == 0)
{
printf("still running\n");
pthread_join(thr_id, NULL);
}
else
{
printf("RIP Thread = %d\n",ret);
}
}
void* thread2 (void* arg)
{
// sleep(5);
printf("I am done\n");
}