How do I render this Asymptote code into an image? - asymptote

I don't know anything about asymptote, I asked an AI to generate the code based this geometry problem,
Prove that in a triangle ABC, if the altitudes AD, BE and CF to sides AB, AC and BC respectively, are concurrent, then the triangle is an isosceles triangle.
Here is the Asymptote code it generated,
pointpen = black;
pathpen = black+linewidth(0.7);
pair A=(0,0),B=(1,0),C=IP(CR(A,3),CR(B,2)),D=foot(A,B,C),E=foot(B,A,C),F=foot(C,A,B);
I found this renderer online, When I enter this into the renderer I get this error,
pointpen = black;
workspace_1.asy: 1.1: no matching variable 'pointpen'
Update: OK on further investigation seems like the AI may be using some sort of short-hand mapping or making assumptions about pre-existing variables. I think variables like pointpen don't really exist, and maybe this D stands for draw(). Will keep trying.
I am looking at Asymptote's tutorial here (, and I can't find any of these things like pointpen, pathpen, or these D things here, so this isn't standard Asymptote code? Searched high & low can't really figure out what this is or how to visualize it. Any help would be appreciated thanks!

OK finally figured this out. I think the AI was using some older (or alternative version) of Asymptote.
I think the modern equivalent of the code it generated looks like this,
pair A=(0,0),B=(1,0),C=(0.5,sqrt(3)/2),D=(A+B)/2,E=(B+C)/2,F=(A+C)/2;
draw(A--D); draw(B--E); draw(C--F);
dot("$A$",A,SW); dot("$B$",B,SE); dot("$C$",C,N); dot("$D$",D,S);
dot("$E$",E,S); dot("$F$",F,S);
Of course I can't be 100% sure this is what the AI intended (does it have intentions?) but this graphic looks like it fits what the geometry problem is asking.
Sorry my original question was super vague.


How to search three or more arrays row by row for an optimum value in matlab

I have a few variables and here they are, three variables "R1, R2 and R3" each have a size of [40 x 1].
I have a fourth variable U of the same dimension. For every U(i) I need to search for an optimum value within R1(i), R2(i) and R3(i) which would return a single value solution. I intend to plot the optimum value against U9i).I have been trying to wrap my head around the knnsearch function but no luck.
Any one out there who could please help??
Well when I can't wrap my head around something, I don't come here first.
A lot of people forget this one because we are online, but read a book on the topic. Have your code open so when you see something in the book, test it out.
Draw out any type of diagram. I call these "Napkin Diagrams", because I write it on anything, even a napkin.
I play with code until my keyboard has no letters left on it, then I keep plugging away until the keys fall off
Explore the language API's
Check for public repositories that you can play with
Google, is okay for a quick reference, but google will not teach you anything other than how to google
I talk my code over with myself all the time, people think I'm nuts, but so do I . . It actually works sometimes.
Then if I still can't get it, I come here with a list of things that I have tried, sample code that has not worked, etc.
I used to hate when people told me this, but that was the best thing anyone could have done for me so I tend to do the same now" Thinking about coding is a big part, but u have to get done wht u can. Then we all know what level u are at. Plus it being the end of semester a lot of these types of questions are homework...
Thinking is good, now turn those thoughts into a conceptual design . It's okay to be wrong in this stage, its all just conceptual
If I understood correctly, this might be what you need:
RR = [R1(:) R2(:) R3(:)];
d = bsxfun(#minus,RR, U(:));
[m mi] = min(abs(d),[],2);
answer = RR(:,mi);
first - put the three vectors into a single matrix:
RR = [R1(:) R2(:) R3(:)];
next, take the difference with U: bsxfun is ideal for this kind of thing
d = bsxfun(#minus,RR, U(:));
Now find the minimum absolute difference for each row:
[m mi] = min(abs(d),[],2);
The corresponding indices should allow you to find the "best fit"
answer = RR(:,mi);
I had to do some mind reading to get to this 'answer', so feel free to correct my misunderstanding of your problem!
update if you just need the highest of the three values, then
val = max([R1(:) R2(:) R3(:)]');
plot(U, val);
should be all you need...

Advice for Object Detection on Embedded System with no non-standard libraries

I am looking for some advice for a good way to detect either square or circular objects in an image. I currently have a canny edge algorithm running on the original greyscale and I can produce this output:
Now I can see that there is a cubesat in this picture, but what is a good computationally efficient way that the program can see that aswell? I have looked at houghs transform but that seems to be very computation heavy. I have also looked at Harris corner detect, but I feel I would get to many false positives, for I am essentially looking to isolate pictures that contain said cube satellite.
Anyone have any thoughts on some good algorithms to pursue? I am very limited on space so I cannot use any large external libraries like opencv. (This is all in C btw)
Many Thanks!
I would into what is called mathematical morphology
Basically you operate on binary images, so you must find a clever way to threshold them first , the you do operations such as erosion and dilation with some well selected structuring element to extract areas of interest in your image.

AI Minesweeper project

I need to implement Minesweeper solver. I have started to implement rule based agent.
I have implemented certain rules. I have a heuristic function for choosing best matching rule for current cell (with info about surrounding cells) being treated. So for each chosen cell it can decide for 8 surroundings cells to open them, to mark them or to do nothing. I mean. at the moment, the agent gets as an input some revealed cell and decides what to do with surrounding cells (at the moment, the agent do not know, how to decide which cell to treat).
My question is, what algorithm to implement for deciding which cell to treat?
Suppose, for, the first move, the agent will reveal a corner cell (or some other, according to some rule for the first move). What to do after that?
I understand that I need to implement some kind of search. I know many search algorithms (BFS, DFS, A-STAR and others), that is not the problem, I just do not understand how can I use here these searches.
I need to implement it in a principles of Artificial Intelligence: A modern approach.
BFS, DFS, and A* are probably not appropriate here. Those algorithms are good if you are trying to plan out a course of action when you have complete knowledge of the world. In Minesweeper, you don't have such knowledge.
Instead, I would suggest trying to use some of the logical inference techniques from Section III of the book, particularly using SAT or the techniques from Chapter 10. This will let you draw conclusions about where the mines are using facts like "one of the following eight squares is a mine, and exactly two of the following eight squares is a mine." Doing this at each step will help you identify where the mines are, or realize that you must guess before continuing.
Hope this helps!
I ported this (with a bit of help). Here is the link to it working: . Here is the project:
Have fun!

ANTLR and arrays

I have question relating to implementation of arrays with Java+ANTLR combo. (I'm mainly talking about java/c style arrays).
So basically I'm asking how do you implement such feature, if there is such example already available or if someone could point me to anything that may point to solve it.
On other hand, I've searched a bit how would possible solution be. Main problem that I see
is that user may create arrays of various dimensions, even go crazy if he or she wants (like creating 5 dimension arrays or worse).
While grammar for something like this is fairly simple, like
new ID (INT (',' INT)* )
back end really gets involved a bit. As I said, user may input any number of dimensions, so array dimensions should be dynamically created. (at least as I see it, maybe I'm over complicating things?)
After searching I did found something that pretty much solves this problem perfectly, here is link to the question:
Is it possible to dynamically build a multi-dimensional array in Java?
Of course, my question is, is this viable example, it is a bit (to say at least), complicated? Is there more elegant solution to it?
Having that in mind, I was thinking maybe answer might be in the grounds of somehow transforming multidimensions
into more linear structure ? Could something like that be useful ? Simple search on stackoverflow pointed many solutions
to this, like:
Algorithm to convert a multi-dimensional array to a one-dimensional array
Would it be worth to search in that direction ?
Now, at the end, having in mind that arrays are really common feature in many languages, I must find it surprising that after searching ANTLR mailing list there is no similar question, which as I previously said leads me to believe that I'm maybe over complicating things ? (Unless I really suck at search?) I would really appreciate feedback.
Your syntax, if I'm not mistaken, corresponds to something like
new char 4,5,6,7
which is kind of strange. I expect that you really meant
new char[4,5,6,7]
However from a purely syntactic point of view, there's no reason not to just store the indices in an array and let the semantic analysis pass worry about it.

Dynamic Programming resources in C?

I'll be writing the online Google test tomorrow as a fresher. Apparently, they definitely ask one problem on Dynamic Programming?
Does anyone know of a good resource for collection of DP problems in C along with solutions? I know what DP is & have used it on an occasion or twice. However I feel to crack a DP problem in test, prior practice of typical problems will make it easier to approach.
Any good resources or problem sets with solutions in C will be highly appreciated. Thanks.
Okay, so I really hope this doesn't count as "shameless self-promotion," since all of these links are to code snippets I've posted on my personal site. If this is inappropriate, please let me know and I can take them down.
Here are a few fun DP problems that are pretty much classics:
Minimum edit distance: Given two strings A and B, find the shortest number of edits (insertions, deletions, or substitutions) necessary to convert A into B. This is called the Levenshtein distance. (My solution)
Optimal sequence alignment: Given two strings A and B, find the minimum number of gaps that must be inserted into the sequence to align A and B. This is called the Needleman-Wunsch algorithm. (My solution)
Single-source shortest paths: Given a directed graph G and a single node s, find the lengths of the shortest paths from s to each other node in the graph, assuming edges can be positive or negative but that no cycles exist. This is the Bellman-Ford algorithm. (My solution)
All-pairs shortest paths: Given a directed graph G, find the minimum distances between all pairs of nodes. This is the Floyd-Warshall algorithm. (My solution)
Hopefully this is somewhat useful, and best of luck tomorrow!
The Topcoder website is amazing. Not all of the problems use DP, but many do. Free full access to all problems from past competitions, which are at 3 different difficulty levels, as well as after-match explanations of every single problem from the problem author. Not only that, but you can quickly dig up the source code solution submitted by any coder in the competition.
Haven't been back there for a while, but they allow at least C++, Java, C# and I believe several other languages now.
I suggest u,collect a book "An Introduction to Bioinformatics Algorithms".This has a chapter fully on DP.As #templatetypedef mentioned Minimum edit distance,Optimal sequence alignment it has other problem with them.Though there is no implementation in it.You have to do it on your own.But you will find pretty interesting reading them.
To practice you can take one of the available problems at SPOJ. To recognize DP ones easily you can check at Problems Classifier (keyword: dp).