Passing 2D Array As Formal Parameter, Getting Single String - c

I'm passing a 2D array as an argument. Reviewing the array in main shows that I have 4 separate strings of words each being stored in words[1][], words[2][], etc. However, when I pass that array to the function I am using to append plural endings, I only seem to be able to access the first string in the array.
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#define ROWS 50
#define COLS 50
void readFileFormat(char words[ROWS][COLS]);
void determinePlurals(char words[ROWS][COLS]);
int main()
{
char words[ROWS][COLS];
readFileFormat(words);
determinePlurals(words);
return 0;
}
void readFileFormat(char words[ROWS][COLS])
{
int cols = 0;//consistent cols for 2d array
FILE* nounFile;
fopen_s(&nounFile, "plural.txt", "r");
if (nounFile == NULL)
{
printf("Error reading file; try again.");
return 1;
}
while (!feof(nounFile))
{
for (int rows = 0; rows < ROWS; ++rows)
{
fgets(&words[rows][cols], 50, nounFile);
words[rows][strcspn(words[rows], "\n")] = 0;
}
}
fclose(nounFile);
}
void determinePlurals(char words[ROWS][COLS])
{
char* iesEnd = "ies";
char* esEnd = "es";
char* sEnd = "s";
for (int rows = 0; rows < ROWS; ++rows)
{
if (strcmp(words[rows] + strlen(words[rows]) - 1, "y") == 0)
{
printf("%s: ", words);
words[rows][strlen(words[rows]) - 1] = '\0';
strncat(words[rows], iesEnd, 3);
printf("%s\n", words);
rows++;
}
else if (strcmp(words[rows] + strlen(words[rows]) - 2, "ch") == 0
|| strcmp(words[rows] + strlen(words[rows]) - 2, "ss") == 0
|| strcmp(words[rows] + strlen(words[rows]) - 2, "x") == 0
|| strcmp(words[rows] + strlen(words[rows]) - 2, "sh") == 0)
{
printf("%s: ", words);
strncat(words[rows], esEnd, 2);
printf("%s\n", words);
rows++;
}
else
{
printf("%s: ", words);
strncat(words[rows], sEnd, 1);
printf("%s\n", words);
rows++;
}
}
}
I've tried iterating through each row, but don't seem to have acccess to the rest of words[][]. I've struggled with multidimensional arrays so I'm looking for a bit of assistance.

Related

Sorting an array of strings loaded from a text file

I have problem to sort an array of string by length loaded from txt file.
So I read from the file line by line and put the strings into an array, after that I sort that array by the length of the string, but I get a strange output of the array stream.
The problem is that the program is sorting an array of strings, but one of the strings is pasted on top of another.
Example:
The data in the file I'm reading from:
X&Y
X|Y
!X
(X|Y)|Z
(X&Y)|Z
(X&Y)&Z
(X&Y)|Z&(A|B
((X|Y)|Z)&((A|B)|(C&D))
(X&Y)|(Z&(A|B))
(A|B)&(!C)
A|(B&(C&(D|E)))
((X|Y)|(Z&(A|B)))|((C&D)&(D|E))
(A|B)|(C&D)&(D|E)
!A&(B|C)
(A|B)|(C|D)&(D
Content of the array after sorting in ascending order:
!X
X|Y
X&Y
(X|Y)|Z
(X&Y)|Z
(X&Y)&Z
!A&(B|C)
(A|B)&(!C)
(X&Y)|Z&(A|B
(A|B)|(C|D)&(DA|(B&(C&(D|E))) //Here' is problem ! (A|B)|(C|D)&(D and A|(B&(C&(D|E))) are concatenated?
(X&Y)|(Z&(A|B))
(A|B)|(C&D)&(D|E)
((X|Y)|Z)&((A|B)|(C&D))
((X|Y)|(Z&(A|B)))|((C&D)&(D|E))
Here is the code:
//Sort function
void sort(char str[][MAXLEN], int number_of_elements) {
int d, j;
char temp[100];
for (d = 0; d < number_of_elements - 1; d++) {
for (j = 0; j < number_of_elements - d - 1; j++) {
if (strlen(str[j]) < strlen(str[j + 1])) {
strcpy(temp, str[j]);
strcpy(str[j], str[j + 1]);
strcpy(str[j + 1], temp);
}
}
}
}
int main() {
FILE *dat;
int number_of_elements;
char str[MAX][MAXLEN];
int i = 0;
dat = fopen("ulaz.txt", "r");
if (dat == NULL) {
printf("Error");
}
while (!feof(dat) && !ferror(dat)) {
if (fgets(str[i], 100, dat) != NULL)
i++;
}
number_of_elements = i;
fclose(dat);
sort(str, number_of_elements);
for (int d = 0; d < i; d++) {
printf("%s", str[d]);
}
return 0;
}
Thanks in advance !
Your observations is consistent with the last line of the source file having no trailing newline: (A|B)|(C|D)&(D
You can correct the problem by stripping the newline after fgets() and always appending one in the output phase.
Also make sure that the temporary array used for swapping the strings is long enough: instead of 100 bytes, it should have a length of MAXLEN. Also stop reading from the file when i reaches MAX.
Here is a modified version:
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXLEN 200
#define MAX 100
//Sort function by decreasing string lengths
void sort(char str[][MAXLEN], int number_of_elements) {
int d, j;
for (d = 0; d < number_of_elements - 1; d++) {
for (j = 0; j < number_of_elements - d - 1; j++) {
if (strlen(str[j]) < strlen(str[j + 1])) {
char temp[MAXLEN];
strcpy(temp, str[j]);
strcpy(str[j], str[j + 1]);
strcpy(str[j + 1], temp);
}
}
}
}
int main() {
int number_of_elements;
char str[MAX][MAXLEN];
int i;
FILE *dat = fopen("ulaz.txt", "r");
if (dat == NULL) {
fprintf(stderr, "Cannot open %s: %s\n", "ulaz.txt", strerror(errno));
return 1;
}
for (i = 0; i < MAX && fgets(str[i], MAXLEN, dat) != NULL; i++) {
/* strip the trailing newline if any */
str[i][strcspn(str[i], "\n")] = '\0';
}
number_of_elements = i;
fclose(dat);
sort(str, number_of_elements);
for (int d = 0; d < number_of_elements; d++) {
printf("%s\n", str[d]);
}
return 0;
}

C program to compare each word of a 2D array to all words of the order 2D array

I created 2 2D arrays containing words. For example:
loadKey[25][30] =
{
{'J','a','v','a','\0'},
{'P','y','t','h','o','n','\0'},
{'C','+','+','\0'},
{'H','T','M','L','\0'},
{'S','Q','L','\0'}
// ... 20 other words here
};
resume[189][30] =
{
{'L','a','l','a','\0'},
{'H','i','h','i','h','i','\0'},
{'C','+','+','\0'},
{'Y','o','Y','o','\0'},
{'S','Q','L','\0'}
// ... 184 other words here
};
I would like to compare each word of a loadKey[] to all words of resume[] to count how many times 25 words of loadKey[] matched of words of resume[]. I tried the strcmp(loadKey[i], resume[j]) but it's pointer of array.
Anyone can help me to solve this problem? Thanks so much!
My program code:
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define PAUSE myPause()
#define KEYWORD 25
#define WORDS 250
#define MAX_LETTER 30
//*********************************************
// FUNCTION PROTOTYPES
void compAndCount(char loadKey[][MAX_LETTER], char resume[][MAX_LETTER]);
void myPause();
void readAndLoadKeyword(char loadKey[][MAX_LETTER]);
// MAIN FUNCTION
int main() {
char loadKey[KEYWORD][MAX_LETTER];
char resume[WORDS][MAX_LETTER];
// load keywords from keywords file into array loadKey[]
readAndLoadKeyword(loadKey);
for (int j = 0; j < KEYWORD; j++)
{
puts(loadKey[j]);
}
puts("\n");
// compare and count the occurrences of keyword in resumes file
compAndCount(loadKey, resume);
}
// FUNTIONS
void compAndCount(char loadKey[][MAX_LETTER], char resume[][MAX_LETTER]) {
FILE* fpr;
fpr = fopen("resumes.txt", "r");
int r = 0, count = 0, num = 0, res = 0;
char temp;
while ((temp = fgetc(fpr)) != EOF) {
if (temp != ' ' && temp != '\n') {
resume[res][r] = temp;
r++;
}
else
{
resume[res][r] = '\0';
r = 0;
res++;
}
}
printf("words in resume file %i\n", res);
for (int j = 0; j < res; j++)
{
puts(resume[j]);
}
puts("\n");
/*
// way 1 to compare and count (WRONG?)
for (int i = 0; i < res; i++) {
if (i < KEYWORD) {
scanf(" %[^\n]", loadKey[i]);
}
scanf(" %[^\n]", resume[i]);
}
for (int k = 0; k < KEYWORD; k++) {
for (int l = 0; l < res; l++) {
if (strcmp(loadKey[k], resume[l]) == 0)
count++;
}
}*/
/*
// way 2 to compare and count (WRONG?)
char key[MAX_LETTER] = {'\0'}, r[MAX_LETTER] = {'\0'};
for (int i = 0; i < KEYWORD; i++) {
strcpy(key, loadKey[i]);
for (int l = 0; l < res; l++) {
strcpy(r, resume[l]);
if (strcmp(key, r) == 0)
count++;
}
}
*/
printf("Resume Rating: %i\n", count);
fclose(fpr);
} // end compAndCount
void myPause() {
puts("\nPress ENTER to continue\n");
exit(0);
}
void readAndLoadKeyword(char loadKey[][MAX_LETTER]) {
FILE* fp;
fp = fopen("keywords.txt", "r");
char ch;
int row = 0, col = 0;
if (fp == NULL) {
puts("Not able to open keyword file!");
PAUSE;
}
// load 25 keywords and ',' into an array line[]
char line[181]; // 180 characters + '\0'
fgets(line, 181, fp);
puts(line);
puts("\n");
// load 25 words in array line[] into array loadKey[]
for (int i = 0; i < 180; i++) {
ch = line[i];
if (ch != ',') {
loadKey[row][col] = ch;
col++;
}
else {
loadKey[row][col] = '\0';
col = 0;
row++;
}
}
fclose(fp);
} // end readAndLoadKeyword
You can use string literals instead of {} of chars
Arrays can have a different number of columns and rows.
char loadKey[25][30] =
{
"Java",
"Python",
// ... more words here
};
char resume[189][30] =
{
"Lala",
"Hihihi",
"C++",
// more
};
//lkr - number of loadKer rows
//lkr - number of loadKer columns
//rr - number of resume rows
//rc - number of resume columns
//rep - count duplicates
size_t count(size_t lkr, size_t lkc, size_t rr, size_t rc, char (*loadKey)[lkc], char (*resume)[rc], int rep)
{
size_t result = 0;
for(size_t lkrow = 0; lkrow < lkr; lkrow++)
{
for(size_t rrow = 0; rrow < rr; lrow++)
{
if(!strcmp(loadKey[lkrow], resume[rrow]))
{
result++;
if(!rep) break;
}
}
}
return result;
}
If the same string can be present in the resume array more than once and oyu want to count duplicates as well rep parameter should be non-zero.
Example usage:
int main(void)
{
size_t cnt = count(25, 30, 189, 30, loadKey, resume, 0);
printf("%zu\n", count);
}

Spaces shouldn't be counted to string length

This code gets user input then 256 % length of string is used. If the result is 3 and the input is abc the output is bcd. This works fine. However if the input is for example "hey whatsup" the length is 11 and it should be 10 because the space shouldn't be included for the length.
How can I programm this code so it dosen't count space to the length?
Is it even possible to implement it while using fgets?
Thank you in advance.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main() {
char array[20];
int length = 0;
int i;
int key = 256;
printf("input: ");
fgets(array, 20, stdin);
length = strlen(array) - 1;
key = key % length;
if (key > 0) {
for (i = 0; i < length; i++) {
if (array[i] == ' ') {
printf("%c", array[i]);
continue;
}
array[i] = array[i] + key;
printf("%c", array[i]);
}
}
return 0;
}
1) If you don't want to include the spaces in the calculation of the key, you have to make your own function to calculate the number of spaces.
2) The code length = strlen(array) - 1; seems to "take care" of a '\n' in the end of the string. However, you can't be sure that there is a '\n'. You need to check for that first.
3) Doing key % 0 will be "bad" so check for that as well
The code could look something like:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int cnt_spaces(char* arr)
{
int res = 0;
while(*arr)
{
if (*arr == ' ')
{
++res;
}
++arr;
}
return res;
}
int main() {
char array[20];
int length = 0;
int i;
int key = 256;
printf("input: ");
fgets(array, 20, stdin);
length = strlen(array);
if (strlen(array) == 0) return 0; // or add error handling
// Remove \n if present
if (array[length-1] == '\n')
{
array[length-1] = '\0';
--length;
}
printf("len = %d\n", length);
int spaces = cnt_spaces(array);
printf("spaces = %d\n", spaces);
if (length == spaces) return 0; // or add error handling
key = key % (length - spaces);
printf("key = %d\n", key);
if (key > 0) {
for (i = 0; i < length; i++) {
if (array[i] != ' ') {
array[i] = array[i] + key;
}
printf("%c", array[i]);
}
}
return 0;
}
Example:
input: a b c
len = 5
spaces = 2
key = 1
b c d

how to scanf unknown amount of integer numbers into array in C?

I know that I can scanf certain amount of numbers with scanf for example for 3 numbers
scanf("%d %d %d",array[0],array[1],array[2]);
but how can I scan it if I didn't know how many numbers (integer, not float) I would input into an array before enter (NOT EOF)? for example
input : 12 43 23(enter) --> array[0]=12, array[1]=43, array[2]=23
input : 10 20 30 40 50(enter) --> array[0]=10, array[1]=20, array[2]=30, array[3]=40, array[4]= 50
etc..
It's about how to input the numbers into an integer array.
And if it's possible, I want to save it into an 2 dimensions array, for example
input : 12 43 23(enter) --> array[0][0]=12, array[0][1]=43, array[0][2]=23
input : 10 20 30 40 50(enter) --> array[1][0]=10, array[1][1]=20, array[1][2]=30, array[1][3]=40, array[1][4]= 50
Here is come code showing how to scan the integers into a 2D array:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define INITSIZE 5
#define BUFFSIZE 1000
void print_and_free(int **array, int rowsize, int colsize);
void check_ptr(void *ptr, const char *msg);
int
main(void) {
int **array;
size_t rowsize = INITSIZE, colsize = INITSIZE;
int row = 0, col, numdigits;
char buffer[BUFFSIZE];
char *number;
array = malloc(rowsize * sizeof(*array));
check_ptr(array, "Allocation");
printf("Enter digits(Enter blank line to end):\n");
while (fgets(buffer, BUFFSIZE, stdin) != NULL && strlen(buffer) != 1) {
col = 0;
numdigits = 0;
if (rowsize == row) {
rowsize *= 2;
array = realloc(array, rowsize * sizeof(*array));
check_ptr(array, "Reallocation");
}
array[row] = malloc(colsize *sizeof(int));
check_ptr(array[row], "Allocation");
number = strtok(buffer, " ");
while (number != NULL) {
numdigits++;
if (colsize == numdigits) {
colsize *= 2;
array[row] = realloc(array[row], colsize * sizeof(int));
check_ptr(array[row], "Reallocation");
}
array[row][col] = atoi(number);
col++;
number = strtok(NULL, " ");
}
row++;
}
print_and_free(array, row, col);
return 0;
}
void
print_and_free(int **array, int rowsize, int colsize) {
int row, col;
printf("Your numbers:\n");
for (row = 0; row < rowsize; row++) {
for (col = 0; col < colsize; col++) {
printf("array[%d][%d] = %d", row, col, array[row][col]);
if (col != colsize - 1) {
printf(", ");
}
}
free(array[row]);
array[row] = NULL;
printf("\n");
}
free(array);
}
void
check_ptr(void *ptr, const char *msg) {
if (!ptr) {
printf("Unexpected null pointer: %s\n", msg);
exit(EXIT_FAILURE);
}
}
Here's how you can store things in a (dynamically allocated) array. This does assume that the line length is limited to 1000 chars though. (Code adapted from How do I use scanf() to take an arbitrary amount of integers?)
#include <stdio.h>
#include <stdlib.h>
int main() {
int val_size = 2;
int* vals = (int*)malloc(val_size * sizeof(int)); // initial array size
char buffer[1000]; // for reading in the line
int pos, bytes_read, num;
int num_read = 0;
if (fgets(buffer, sizeof(buffer), stdin) != 0) {
for (pos = 0; sscanf(buffer+pos, "%d%n", &num, &bytes_read) != EOF; pos += bytes_read) {
// resize the array if needed
if (num_read >= val_size) {
val_size *= 2;
vals = (int*)realloc(vals, val_size * sizeof(int));
}
// store the value in the array
vals[num_read] = num;
num_read++;
}
}
// print the values to prove it works
for (int i = 0; i < num_read; i++) {
printf("%d ", vals[i]);
}
printf("\n");
free(vals); // important after you're done with it
}
You can wrap a while around the if to get multiple lines.
You may use a while loop and check for the return value of scanf. For example:
int num = 0;
int idx = 0;
int arr[100] = { 0 };
while( scanf( "%d", &num ) == 1 )
{
arr[idx++] = num;
if( idx == 99 ) // protect from array overflow
{
break;
}
}
for( int i = 0; i < idx; i++ )
{
printf( "%d\n", arr[i] );
}

how to find duplicate string in an array of strings

I have an array of string from which i have to find duplicate string and then remove that duplicate string like i have string
char aa[50]="Amit Hanish Mahesh Amit"
Now Amit is duplicate and have to remove it from string .
#include "string.h"
main()
{
char x[100] = "Amit Hanish Mahesh Amit";
char y[3][100];
int i = 0, k = 0, j = 0, c = 0, end, t;
int current = 1;
while (x[i] != '\0') {
if (x[i] != ' ') {
y[k][j] = x[i];
j++;
i++;
} else {
// c = c + 1;
i++;
k++;
j = 0;
}
y[k][j] = '\0';
}
for (end = 1; end <= 3; end++) {
for (t = 0; t < end; t++) {
if (strcmp(y[end], y[t]) == 0) break;
}
if (end == t) {
strcpy(y[current],y[t]);
current++;
}
}
y[current] = 0;
printf("%s",y);
}
I have written a smalll routine for it .Does not seems to be worked .Any one have any suggestion where i am going wrong?
The other answers you got work fine for a small number strings (your example code only has 4). But, if you're comparing a large number this will be quite slow since you're doing n^2 comparisons. I'd suggest first splitting the string into an array of strings, then sorting the array using qsort(). In a sorted array all duplicates are guaranteed to be adjacent. This reduces the time from n^2 to n log n -- the time required to sort.
I would split the string array using strtok (see the man page).
So I would have something like this
char x[100]="Amit Hanish Mahesh Amit";
/* Preparing the result string */
size_t sz_result = sizeof(char) * (strlen(x) + 1);
char* result = (char*) malloc( sz_result );
result[0] = '\0';
/* Parsing the string from one element to the other */
char* elm = strtok(x, " ");
while( (elm = strtok(NULL, " ")) != NULL )
{
...
You will have each element of the string to verify if they are unique.
Then I would use something like a hashmap (you can use the one from the glib) or I would put the read string element in a new string only if it is not already in.
Here is an example for the second solution:
...
/* Is the element already in the result string? */
if ( strstr(result, elm) == NULL )
{
/* Then we should add it */
snprintf( result, sz_result - 1, "%s %s", result, elm );
}
}
In the end if you want x to be modified, you simply copy result in x:
strncpy( x, result, 99 );
Here is a sample code (not optimised, not using the strn* primitives, etc.)
#include <unistd.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
char x[100]="Amit Hanish Mahesh Amit";
/* Preparing the result string */
size_t sz_result = sizeof(char) * (strlen(x) + 1);
char* result = (char*) malloc( sz_result );
result[0] = '\0';
/* Parsing the string from one element to the other */
char* elm = strtok(x, " ");
if (elm != NULL) strcpy(result, elm);
while( (elm = strtok(NULL, " ")) != NULL )
{
/* Is the element already in the result string? */
if ( strstr(result, elm) == NULL )
{
/* Then we should add it */
strcat( result, " " );
strcat( result, elm );
}
}
strcpy( x, result );
fprintf( stdout, "Result: %s\n", x );
}
To remove duplicates from an array without preserving the order of elements:
sort the array
copy unique elements to the beginning of the array
remove the tail with duplicate elements
int remove_duplicates(StringArray array) {
if (! (array and array->items)) return 0; // empty array or NULL
StringArray_sort(array); // sort
// unique_copy()
String result = array->items, last = array->items + array->size;
for (String first = array->items; first != last; ++result) {
String_copy(result, first); // copy first to result
for (String prev = first; ++first != last and String_cmp(prev, first) == 0;)
{ /* skip adjacent equal items */ }
}
// shrink
return StringArray_remove(array, result, last);
}
Example
int main() {
char text[] = "Mahesh Amit Hanish Amit";
StringArray array = split(text, sizeof(text));
StringArray_dump(array, "<"); // print array before removing duplicates
if (remove_duplicates(array) < 0)
perror("error remove_duplicates(), OS error if any");
StringArray_dump(array, ">"); // print it after
StringArray_destroy(array);
return 0;
}
Where split() is:
StringArray split(const char* text, size_t size) {
if (! (text and text[size-1] == '\0')) return NULL;
StringArray array = StringArray_create();
if (! array) return NULL;
size_t n = -1;
for (const char* p = text; p != text+size; p += n+1) {
n = strcspn(p, " \t\n"); // find index of the next whitespace
if (n == 0) continue; // skip consecutive whitespace
// append characters in range [p, p+n)
// as a string to the array
const String string = String_create(p, n);
if (StringArray_append(array, string) < 0) {
String_destroy(string);
StringArray_destroy(array);
return NULL;
}
String_destroy(string);
}
return array;
}
Output
Mahesh<Amit<Hanish<Amit<
Amit>Hanish>Mahesh>
Full source code
I'm pretty sure, that the following line is not intended (assignment, not comparison)
if (end = t) {
See what happens, if you code a == and come back, if you still have problems.
Hint: Always code blanks around operators, so expressions are easier to read.
It's always fun to try to solve this kind of simple problems in C as exercise. Here's my take.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
char* strstrn(const char *haystack, const char *needle, size_t needle_len)
{
while((haystack = strchr(haystack, *needle)))
{
if (strncmp(haystack, needle, needle_len) == 0)
return (char *) haystack;
haystack++;
}
return NULL;
}
char* find_duplicate(const char* str, size_t len, size_t dup_len)
{
for(size_t i = 0; i < (len - dup_len); i++)
{
char* r = strstrn(str + i + 1, str + i, dup_len);
if(r) return r;
}
return NULL;
}
int main(int argc, char** argv)
{
if(argc < 3)
{
fprintf(stderr, "Usage: %s haystack dup_size\n", argv[0]);
return 1;
}
char* haystack = argv[1];
size_t len = atoi(argv[2]);
char* r;
while((r = find_duplicate(haystack, strlen(haystack), len)))
{
strcpy(r, r + len);
}
puts(haystack);
return 0;
}
/*
* C Program to Find the Frequency of Every Word in a
* given String
*/
#include <stdio.h>
#include <string.h>
void main()
{
int count = 0, c = 0, i, j = 0, k, space = 0;
char str[100], p[50][100], str1[20], ptr1[50][100];
printf("Enter the string\n");
scanf(" %[^\n]s", str);
printf("string length is %d\n", strlen(str));
for (i = 0;i<strlen(str);i++)
{
if ((str[i] == ' ')||(str[i] == ', ')||(str[i] == '.'))
{
space++;
}
}
for (i = 0, j = 0, k = 0;j < strlen(str);j++)
{
if ((str[j] == ' ')||(str[j] == 44)||(str[j] == 46))
{
p[i][k] = '\0';
i++;
k = 0;
}
else
p[i][k++] = str[j];
}
k = 0;
for (i = 0;i <= space;i++)
{
for (j = 0;j <= space;j++)
{
if (i == j)
{
strcpy(ptr1[k], p[i]);
k++;
count++;
break;
}
else
{
if (strcmp(ptr1[j], p[i]) != 0)
continue;
else
break;
}
}
}
for (i = 0;i < count;i++)
{
for (j = 0;j <= space;j++)
{
if (strcmp(ptr1[i], p[j]) == 0)
c++;
}
printf("%s -> %d times\n", ptr1[i], c);
c = 0;
}
}

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