This might be a silly question; for all of you who have been in this field for a while, nevertheless, I would still appreciate your insight on the matter - why does an array need to be sorted, and in what scenario would we need to sort an array?
So far it is clear to me that the whole purpose of sorting is to organize the data in such a way that will minimize the searching complexity and improve the overall efficiency of our program, though I would appreciate it if someone could describe a scenario in which it would be most useful to sort an array? If we are searching for something specific like a number wouldn't the process of sorting an array be equally demanding as the process of just iterating through the array until we find what we are looking for? I hope that made sense.
Thanks.
This is just a general question for my coursework.
A lot of different algorithms work much faster with sorted array, including searching, comparing and merging arrays.
For one time operation, you're right, it is easier and faster to use unsorted array. But as soon as you need to repeat the operation multiple times on the same array, it is much faster to sort the array one time, and then use its benefits.
Even if you are going to change array, you can keep it sorted, again it improves performance of all other operations.
Sorting brings useful structure in a list of values.
In raw data, reading a value tells you absolutely nothing about the other values in the list. In a sorted list, when you read a value, you know that all preceding elements are not larger, and following elements are not smaller.
So to search a raw list, you have no other choice than exhaustive comparison, while when searching a sorted list, comparing to the middle element tells you in which half the searched value can be found and this drastically reduces the number of tests to be performed.
When the list is given in sorted order, you can benefit from this. When it is given in no known order, you have to ponder if it is worth affording the cost of the sort to accelerate the searches.
Sorting has other algorithmic uses than search in a list, but it is always the ordering property which is exploited.
Related
First of all let me start off by saying that I read this question.
So as I was strolling through the internet and I came across that algorithm and I was wondering how it worked. After reading about it I did understand how it counts the views by hashing and using bits.
What I haven't quite understand yet, is how can be sure to avoid counting the same view again. Do we store each hashed value we come across and before incrementing the count check if it already exists in our array or whatever?
Doesn't that make it a lot less efficient if we have 1000k+ items?
The cool thing about HyperLogLog is that you do not have to store the entire array you have seen which would be O(n), and not even the unique values. What you do need to store is of oreder O(log(log(n)) which is much lower.
Basically, if two objects have the same value, then their hash will be the same. This means that the leading bits will also be the same. So having multiple objects with the same value won't affect the computation at all.
This fact also allows easy parallelism - you can divide your population, and calculate the max separately, combining them later by calculating the maximum of your separate maxes.
I have four sorted lists and I want to merge them into one sorted list.
What is the most efficient way to do that? If the implementation can be done in parallel, it's a plus.
This is the merge part of merge sort.
Just take the minimum of the four elements at the head of each list and dump it into the output one. Repeat until all lists are empty. Assuming that min4 is a fixed cost, then this is just going to be O(N).
If you have more information (such as the range of the list) you can probably improve things a little, but I don't think these affect the asymptotic complexity.
I'm scanning a large data source, currently about 8 million entries, extracting on string per entry, which I want in alphabetical order.
Currenlty I put them in an array then sort an index to them using qsort() which works fine.
But out of curiosity I'm thinking of instead inserting each string into a data structure that maintains them in alphabetical order as I scan them from the data source, partly for the experience of emlplementing one, partly because it will feel faster without the wait for the sort to complete after the scan has completed (-:
What data structure would be the most straightforward to implement in C?
UPDATE
To clarify, the only operations I need to perform are inserting an item and dumping the index when it's done, by which I mean for each item in the original order dump an integer representing the order it is in after sorting.
SUMMARY
The easiest to implement are binary search trees.
Self balancing binary trees are much better but nontrivial to implement.
Insertion can be done iteratively but in-order traversal for dumping the results and post-order traversal for deleting the tree when done both require either recursion or an explicit stack.
Without implementing balancing, runs of ordered input will result in the degenerate worst case which is a linked list. This means deep trees which severely impact the speed of the insert operation.
Shuffling the input slightly can break up ordered input significantly and is easier to implement that balancing.
Binary search trees. Or self-balancing search trees. But don't expect those to be faster than a properly implemented dynamic array, since arrays have much better locality of reference than pointer structures. Also, unbalanced BSTs may "go linear", so your entire algorithm becomes O(n²), just like quicksort.
You are already using the optimal approach. Sort at the end will be much cheaper than maintaining an online sorted data structure. You can get the same O(logN) with a rb-tree but the constant will be much worse, not to mention significant space overhead.
That said, AVL trees and rb-trees are much simpler to implement if you don't need to support deletion. Left-leaning rb tree can fit in 50 or so lines of code. See http://www.cs.princeton.edu/~rs/talks/LLRB/ (by Sedgewick)
You could implement a faster sorting algorithm such us Timsort or other sorting algorithms with a nlog(n) worst case and just search it using Binary search since its faster if the list is sorted.
you should take a look at Trie datastructure wikilink
i think this will serve what you want
I am on a system with only about 512kb available to my application (the rest is used for buffers). I need to be as efficient as possible.
I have about 100 items that are rapidly added/deleted from a list. What is an efficient way to store these in C and is there a library (with a good license) that will help? The list never grows above 256 items and its average size is 15 items.
Should I use a Binary Search Tree?
Red Black Tree
With an average size of 15, all these other solutions are unnecessary overkill; a simple dynamic array is best here. Searching is a linear pass over the array and insertion and deletion requires moving all elements behind the insertion point. But still this moving around will be offset by the lack of overhead for so few elements.
Even better, since you’re doing a linear search anyway, deleting at arbitrary points can be done by swapping the last element to the deleted position so no further moving around of elements is required – yielding O(1) for insertion and deletion and O(very small n) for lookup.
If your list is no longer then 256, the best option will be to hold a hash table and add/remove each new element with hash function. this way each add/remove will take you only O(1), and the size of the used memory doesn't need to be large.
I would use a doubly-linked-list. When dealing with tens or hundreds of items, its not terribly slower to search than an array, and it has the advantage of only taking up as much space as it absolutely needs. Adding and removing elements is very simple, and incurs very little additional overhead.
A tree structure is faster for searching, but has more overhead when adding or removing elements. That said, when dealing with tens or hundreds of items, the difference probably isn't significant. If I were you, I'd build an implementation of each and see which one is faster in actual usage.
15 items, BST should be fine if you can keep them sorted, not sure if the overhead will be much better than a linked list or an array if the items are rather small. For a lot of insertions/deletions I recommend a linked list because the only thing you have to do is patch pointers.
What's wrong with a plain old array? You said "list" so presumably order is important, so you can't use a hash set (if you do use a hash set, use probing, not chaining).
You can't use a linked list because it would double your memory requirements. A tree would have the same problem, and it would be much more difficult to implement.
I have a linked list of around 5000 entries ("NOT" inserted simultaneously), and I am traversing the list, looking for a particular entry on occasions (though this is not very often), should I consider Hash Table as a more optimum choice for this case, replacing the linked list (which is doubly-linked & linear) ?? Using C in Linux.
If you have not found the code to be the slow part of the application via a profiler then you shouldn't do anything about it yet.
If it is slow, but the code is tested, works, and is clear, and there are other slower areas that you can work on speeding up do those first.
If it is buggy then you need to fix it anyways, go for the hash table as it will be faster than the list. This assumes that the order that the data is traversed does not matter, if you care about what the insertion order is then stick with the list (you can do things with a hash table and keep the order, but that will make the code much tricker).
Given that you need to search the list only on occasion the odds of this being a significant bottleneck in your code is small.
Another data structure to look at is a "skip list" which basically lets you skip over a large portion of the list. This requires that the list be sorted however, which, depending on what you are doing, may make the code slower overall.
Whether using hash table is more optimum or not depends on the use case, which you have not described in detail. But more importantly, make sure the bottleneck of performance is in this part of the code. If this code is called only once in a while and not in a critical path, no use bothering to change the code.
Have you measured and found a performance hit with the lookup? A hash_map or hash table should be good.
If you need to traverse the list in order (not as a part of searching for elements, but say for displaying them) then a linked list is a good choice. If you're only storing them so that you can look up elements then a hash table will greatly outperform a linked list (for all but the worst possible hash function).
If your application calls for both types of operations, you might consider keeping both, and using whichever one is appropriate for a particular task. The memory overhead would be small, since you'd only need to keep one copy of each element in memory and have the data structures store pointers to these objects.
As with any optimization step that you take, make sure you measure your code to find the real bottleneck before you make any changes.
If you care about performance, you definitely should. If you're iterating through the thing to find a certain element with any regularity, it's going to be worth it to use a hash table. If it's a rare case, though, and the ordinary use of the list is not a search, then there's no reason to worry about it.
If you only traverse the collection I don't see any advantages of using a hashmap.
I advise against hashes in almost all cases.
There are two reasons; firstly, the size of the hash is fixed.
Second and much more importantly; the hashing algorithm. How do you know you've got it right? how will it behave with real data rather than test data?
I suggest a balanced b-tree. Always O(log n), no uncertainty with regard to a hash algorithm and no size limits.