convert decimal(letters) to binary - c

Question

I have to convert a letter to binary number. All work but with one problem - I don`t understand why after my binary number it still prints some other numbers... Can someone help, please?
Here is my code. Thank you in advance!
#include <stdio.h>
#include <stdbool.h>
void convert(const char char, bool bits[8]) {
char c = char;
for (int j = 7; j+1 > 0; j--){
if(c>=(1<<j)){
c=c-(1<<j);
printf("1");
}else{
printf("0");
}
}
//here start to prints other numbers
printf("\n");
printf("\n");
}
int main(){
bool bits1[8];
encode_char('A', bits1);
for(int i = 0; i < 8; i++)
{
printf("%d", bits1[i]);
}
printf("\n");
return0;
}

Answer 1

There are 3 problems making your sample code unable to compile:
You tried to declare the first argument to your function as const char char, but char is a type and is not valid variable name.
You tried to call encode_char in main, but you defined convert
return0 should be return 0
After fixing those, there will still be a problem with garbage values.
Because even though you passed bits, the function never does anything with it (so it remains with garbage values).
So your printf("%d", bits1[i]); will be just a bunch of "random" numbers. The extra numbers are not from what you marked with //here....
Here is an example that assigns useful values to bits:
#include <stdio.h>
#include <stdbool.h>
void encode_char(const char input_char, bool bits[8]) {
char c = input_char;
for (int j = 7; j >= 0; j--){
if(c>=(1<<j)){
c=c-(1<<j);
bits[7-j] = 1;
}else{
bits[7-j] = 0;
}
}
}
int main(){
bool bits1[8];
encode_char('A', bits1);
for(int i = 0; i < 8; i++)
{
printf("%d", bits1[i]);
}
printf("\n");
return 0;
}