#define new macros inside the #define macro function - c

#define RB3_SetHigh() do { LATBbits.LATB3 = 1; } while(0)
#define RB3_SetLow() do { LATBbits.LATB3 = 0; } while(0)
#define SET_ALIAS(new_name, old_name) { \
#define new_name##_SetHigh() old_name##_SetHigh() \
#define new_name##_SetLow() old_name##_SetLow() \
}
SET_ALIAS(MOTOR,RB3)
I am trying to change the prefix of an already-defined function macro. I want to rename the MACRO Function in C.
I thought I will use another MACRO Function and will use the MACRO concatenation to achieve this. But it is not allowed. There are my functions that I want to change in the code.

Related

Prepend/append string to each element in C preprocessor list?

Ultimately, what I want is this: first, have a list of variable names declared as a C preprocessor macro; say, in test_cpp.c:
#define VARLIST \
var_one, \
var_two, \
var_three, \
var_four
These would eventually be actual variable names in code - but, of course, the preprocessor does not know (or even has a concept of) that at this time.
To make sure the macro has been parsed correctly, I use this command (awk to get rid of the preamble defines in the gcc -E preprocessor output):
$ gcc -E -dD test_cpp.c | awk 'BEGIN{prn=0} /# 1 "test_cpp.c"/ {prn=1} prn==1 {print}'
# 1 "test_cpp.c"
#define VARLIST var_one, var_two, var_three, var_four
So far, so good.
Now: second, I'd like to use this list - that is, I'd like to (pre)process it - and prepend and append characters to each element (token) of the VARLIST, so that I end up with the equivalent of the following macros:
#define VARLIST_QUOTED "var_one", "var_two", "var_three", "var_four"
#define VARLIST_PTR &var_one, &var_two, &var_three, &var_four
... which I could ultimately use in code as, say:
char varnames[][16] = { VARLIST_QUOTED };
( ... which then would end up like this in compiled code, inspected in debugger:
(gdb) p varnames
$1 = {"var_one\000\000\000\000\000\000\000\000",
"var_two\000\000\000\000\000\000\000\000",
"var_three\000\000\000\000\000\000",
"var_four\000\000\000\000\000\000\000"}
)
I'm guessing, at this time the preprocessor wouldn't know & is intended to be an "address-of" operator, although I think it has special handling for double quotes.
In any case, I think that such "lists" in the preprocessor are handled via Variadic Macros (The C Preprocessor), where there is an identifier __VA_ARGS__. Unfortunately, I do not understand this very well: I tried the first thing that came to mind - again, test_cpp.c:
#define VARLIST \
var_one, \
var_two, \
var_three, \
var_four
#define do_prepend(...) &##__VA_ARGS__
#define VARLIST_PTR do_prepend(VARLIST)
void* vars_ptr[] = { VARLIST_PTR };
Then if I run the preprocessor, I get this:
$ gcc -E -dD test_cpp.c | awk 'BEGIN{prn=0} /# 1 "test_cpp.c"/ {prn=1} prn==1 {print}' | sed '/^$/d;G'
test_cpp.c:8:25: error: pasting "&" and "VARLIST" does not give a valid preprocessing token
8 | #define do_prepend(...) &##__VA_ARGS__
| ^
test_cpp.c:9:21: note: in expansion of macro 'do_prepend'
9 | #define VARLIST_PTR do_prepend(VARLIST)
| ^~~~~~~~~~
test_cpp.c:11:22: note: in expansion of macro 'VARLIST_PTR'
11 | void* vars_ptr[] = { VARLIST_PTR };
| ^~~~~~~~~~~
# 1 "test_cpp.c"
#define VARLIST var_one, var_two, var_three, var_four
#define do_prepend(...) & ##__VA_ARGS__
#define VARLIST_PTR do_prepend(VARLIST)
void* vars_ptr[] = { &var_one, var_two, var_three, var_four };
It does show an error - but ultimately, the preprocessor did prepend a single ampersand & to the first variable in the array vars_ptr, as I wanted it to ...
The question is, then: can it prepend an ampersand & to all the entries in the list VARLIST without errors (and likewise, can it both prepend and append a double quote " to all the entries in the list VARLIST without errors) - and if so, how?
Sounds like a job for X macros:
#include <stdio.h>
#define VARS \
X(var_one) \
X(var_two) \
X(var_three) \
X(var_four)
// Define all the variables as ints (just for the example)
#define X(V) int V=0;
VARS
#undef X
// Define the array of variable pointers
#define X(V) &V,
void* vars_ptr[] = { VARS };
#undef X
// Define the array of variable name strings
#define X(V) #V,
const char *var_names[] = { VARS };
#undef X
// Set a few variable values and print out the name/value of all variables
int main()
{
var_one = 9;
var_two = 2;
for(unsigned i = 0; i < sizeof(var_names)/sizeof(var_names[0]); i++)
{
printf("%s=%d\n", var_names[i], *(int *)vars_ptr[i]);
}
return 0;
}
Ok, seems I found an answer, mostly thanks to Is it possible to iterate over arguments in variadic macros? (see also Expand a macro in a macro); this is test_cpp.c:
#define VARLIST \
var_one, \
var_two, \
var_three, \
var_four
// Make a FOREACH macro
#define FE_0(WHAT)
#define FE_1(WHAT, X) WHAT(X)
#define FE_2(WHAT, X, ...) WHAT(X)FE_1(WHAT, __VA_ARGS__)
#define FE_3(WHAT, X, ...) WHAT(X)FE_2(WHAT, __VA_ARGS__)
#define FE_4(WHAT, X, ...) WHAT(X)FE_3(WHAT, __VA_ARGS__)
#define FE_5(WHAT, X, ...) WHAT(X)FE_4(WHAT, __VA_ARGS__)
//... repeat as needed
#define GET_MACRO(_0,_1,_2,_3,_4,_5,NAME,...) NAME
#define FOR_EACH(action,...) \
GET_MACRO(_0,__VA_ARGS__,FE_5,FE_4,FE_3,FE_2,FE_1,FE_0)(action,__VA_ARGS__)
#define XSTR(x) STR(x)
#define STR(x) #x
// original: https://stackoverflow.com/a/11994395
//#define QUALIFIER(X) X::
//#define QUALIFIED(NAME,...) FOR_EACH(QUALIFIER,__VA_ARGS__)NAME
#define POINTERER(X) &X,
#define POINTERIFIED(NAME,...) FOR_EACH(POINTERER,__VA_ARGS__)NAME
// leave first argument (from original QUALIFIED) empty here!
#define vptrs POINTERIFIED(,VARLIST)
void* vars_ptr[] = { vptrs };
//#define DQUOTE " // no need for DQUOTE;
// if we just use the number/hash sign, X gets automatically quoted with double quotes!
// (don't forget the comma at the end!)
#define DQUOTERER(X) #X,
#define DQUOTERIFIED(NAME,...) FOR_EACH(DQUOTERER,__VA_ARGS__)NAME
// leave first argument (from original QUALIFIED) empty here!
#define vnames DQUOTERIFIED(,VARLIST)
char vars_names[][16] = { vnames };
... and this is the output of the preprocessor:
$ gcc -E -dD test_cpp.c | awk 'BEGIN{prn=0} /# 1 "test_cpp.c"/ {prn=1} prn==1 {print}' | sed '/^$/d;G'
# 1 "test_cpp.c"
#define VARLIST var_one, var_two, var_three, var_four
#define FE_0(WHAT)
#define FE_1(WHAT,X) WHAT(X)
#define FE_2(WHAT,X,...) WHAT(X)FE_1(WHAT, __VA_ARGS__)
#define FE_3(WHAT,X,...) WHAT(X)FE_2(WHAT, __VA_ARGS__)
#define FE_4(WHAT,X,...) WHAT(X)FE_3(WHAT, __VA_ARGS__)
#define FE_5(WHAT,X,...) WHAT(X)FE_4(WHAT, __VA_ARGS__)
#define GET_MACRO(_0,_1,_2,_3,_4,_5,NAME,...) NAME
#define FOR_EACH(action,...) GET_MACRO(_0,__VA_ARGS__,FE_5,FE_4,FE_3,FE_2,FE_1,FE_0)(action,__VA_ARGS__)
#define XSTR(x) STR(x)
#define STR(x) #x
#define POINTERER(X) &X,
#define POINTERIFIED(NAME,...) FOR_EACH(POINTERER,__VA_ARGS__)NAME
#define vptrs POINTERIFIED(,VARLIST)
void* vars_ptr[] = { &var_one,&var_two,&var_three,&var_four, };
#define DQUOTERER(X) #X,
#define DQUOTERIFIED(NAME,...) FOR_EACH(DQUOTERER,__VA_ARGS__)NAME
#define vnames DQUOTERIFIED(,VARLIST)
char vars_names[][16] = { "var_one","var_two","var_three","var_four", };
So, ultimately, I got my output as desired - and no preprocessor errors/warnings, as far as I can tell:
void* vars_ptr[] = { &var_one,&var_two,&var_three,&var_four, };
char vars_names[][16] = { "var_one","var_two","var_three","var_four", };
As already mentioned, you are more or less literally describing the purpose of "X macros".
An alternative, arguably somewhat more readable way of writing them is to first declare a macro list, then pass a macro to that list. As in
"here is a function-like macro, run it with all the arguments listed", rather than
"here is the function-like macro X, run macro X with all the arguments listed".
This allows you to give macros meaningful names, optionally group all macros belonging to the list somewhere, and it eliminates the need to #undef.
#include <stdio.h>
// note the absence of commas
#define VARLIST(X) \
X(var_one) \
X(var_two) \
X(var_three) \
X(var_four) \
int main (void)
{
char varnames[][16] =
{
#define VARLIST_QUOTED(name) #name, /* "stringification operator" */
VARLIST(VARLIST_QUOTED) /* no semicolon or comma here */
};
#define VARLIST_DECL_VARS(name) int name; /* declare a bunch of int */
VARLIST(VARLIST_DECL_VARS)
int* const pointers[] =
{
#define VARLIST_PTR(name) &name, /* declare an array of pointers to previous ints */
VARLIST(VARLIST_PTR)
};
var_two = 123;
printf("%s has value %d and address %p\n",
varnames[1],
var_two,
pointers[1]);
}

Variable in Macros

I am writing a program in c language. So, suppose I have defined a macro in c as follows :
#define TEST_MACRO(type, name) \
{ \
int testVar = 0; \
}
#define TEST_MACRO_TWO(type, name) \
{ \
}
How can I use the testVar variable from the first macro in the second macro?

What is the best way to mark macro as deprecated?

I know how to mark enums/functions as deprecated by using
__attribute__ ((deprecated)). But how can I mark constant macro
as deprecated?
#define MACRO1 4 //This is deprecated macro
GCC (and possibly others)
__attribute__((deprecated))
For your particular example with just a constant expression, you can use this:
Change
#define X (4)
to
#define X_old (4)
and then add
const int dep __attribute__((deprecated)) = 0;
#define X ((void)dep, X_old)
Addition also works:
#define X (X_old + dep)
For a procedure macro you can do this:
#define P_old do { ... } while(0)
#define P do { (void)dep; P_old; } while(0)
The only function of (void) is to suppress warnings. Thanks Kevin.
#pragma message
Another solution is to put all deprecated macros in a separate header file and use pragma. You could combine this with #ifdef and such:
#pragma message ("This header contains deprecated macros")
All compilers
Unreferenced label
Use an unreferenced label:
#define P_old do { ... } while(0)
#define P do { P_IS_DEPRECATED: P_old; } while(0)
This does not work for constant expression macros and requires you to compile with -Wall to get a warning. Will trigger error if used more than once.
Unused variable:
#define P_old do { ... } while(0)
#define P do { int P_IS_DEPRECATED; P_old; } while(0)
Does not work on constant expressions either. Also requires -Wall but can be used more than once.
Sidenote
Remember to encapsulate constant expression macros in parentheses. The macro #define X 2+3 would make an expression like 2*X to expand to 2*2+3 instead of 2*(2+3).

Enable/Disable LOG levels using C Macro

#include <stdio.h>
#define LOG_D(x) { printf("D:"); printf(x);}
#define LOG_E(x) { printf("E:"); printf(x);}
void test(void)
{
LOG_D("ALL is well " );
}
I have a very huge code it has different levels of log, like above code.
In the final tested library I just need only one error logs in order to reduce the code size .
so I want something like this
#define ENABLE_DEBUG_LOG 0
#define ENABLE_ERROR_LOG 1
#define LOG_D(x) {#if(ENABLE_DEBUG_LOG==1) printf("D:"); printf(x); #endif}
#define LOG_E(x) {#if(ENABLE_ERROR_LOG==1) printf("E:"); printf(x);#endif}
I added this #if(ENABLE_DEBUG_LOG==1) just for explaining, I need some solution which can compile.
Another option - you can just comment / uncomment ENABLE_DEBUG_LOG and ENABLE_ERROR_LOG to disable / enable corresponding log level.
// #define ENABLE_DEBUG_LOG // disable DEBUG_LOG
#define ENABLE_ERROR_LOG // enable ERROR_LOG
#ifdef ENABLE_DEBUG_LOG
#define LOG_D(x) { printf("D:"); printf(x);}
#else
#define LOG_D(x) // nothing
#endif
#ifdef ENABLE_ERROR_LOG
#define LOG_E(x) { printf("E:"); printf(x);}
#else
#define LOG_E(x) // nothing
#endif
You cannot nest preprocessor directives. But you can make two versions of your macro and define them in exclusive parts of an #if or #ifdef:
#define ENABLE_DEBUG_LOG 0
#if ENABLE_DEBUG_LOG != 0
#define LOG_D(...) printf("D: " __VA_ARGS__)
#else
#define LOG_D(...) // Do nothing
#endif
Here, the disabled version just "eats" the LOG_D macro and doesn't do anything. (Note that undefined macros are treated as the value 0 in #if conditionals.)
You should be able to do something like this:
#if ENABLE_DEBUG_LOG == 1
# define LOG_D(x) { printf("D:"); printf(x);}
#else
# define LOG_D(x)
#end
That way the debug log statements will just disappear if ENABLE_DEBUG_LOG is undefined or has a different value.
Regarding the other answers, it is not good idea to define the macros completely empty when they are not enabled, as this would go wrong when error logging is enabled:
if (some_error)
LOG_E("Oops...");
do_something();
If LOG_E(x) expands to nothing, then do_something() would only be called if some_error is true, which is probably not what you want!
So you could define the "do nothing" variant of LOG_E(x) like this:
#define LOG_E(x) { }
Rather than starting and ending with braces, I tend to use the do { blah; } while (0) construct as it forces you to put a semicolon on the end when you use it. Something like this:
#if ENABLE_ERROR_LOG
#define LOG_E(x) do { printf("E:"); printf(x); } while (0)
#else
#define LOG_E(x) do ; while (0)
#endif
Then,
if (some_error)
LOG_E("Oops")
would result in a syntax error because of the missing semicolon, forcing you to write it as
if (some_error)
LOG_E("Oops");
Another thing you can do is concatenate the "E:" or "D:" tag with the passed in string, although this requires the parameter to be a string literal, rather than a general char *:
#define LOG_E(x) printf("E:" x)
Another thing you can do is to define the macro with a variable number of parameters (a variadic macro) to increase your options:
#define LOG_E(...) printf("E:" __VA_ARGS__)
Then you can do:
if (some_error)
LOG_E("Oops, got error: %d\n", some_error);
Another thing you can do is let the compiler optimize out the call to printf and define it like this:
#define LOG_E(...) do if (ENABLE_ERROR_LOG) printf("E:" __VA_ARGS__); while (0)
A decent compiler will notice that the if condition is constant and either optimize out the call to printf completely (if the constant condition is false), or include it (if the constant condition is true). For some compilers, you might need to suppress warnings about constant conditions in an if statement.
I am not sure if this is what you want, but you could check the #ifdef directive.
#include <stdio.h>
/* #define DEBUG */
#ifdef DEBUG
#define LOG_D(x) { printf("D: %s\n",x); }
#define LOG_E(x) { printf("E: %s\n",x); }
#else
#define LOG_D(x)
#define LOG_E(x)
#endif
int main() {
LOG_D("blah...");
return 0;
}
If you uncomment the #define DEBUG line, the program will print D: blah...

How can I generate a list via the C preprocessor (cpp)?

I would like to do something like the following:
F_BEGIN
F(f1) {some code}
F(f2) {some code}
...
F(fn) {some code}
F_END
and have it generate the following
int f1() {some code}
int f2() {some code}
...
int fn() {some code}
int (*function_table)(void)[] = { f1, f2, ..., fn };
The functions themselves are easy. What I can't seem to do is to keep track of all of the names until the end for the function_table.
I looked at this question and this question but I couldn't get anything to work for me.
Any ideas?
The normal way of doing this with the preprocessor is to define all the functions in a macro that takes another macro as an argument, and then use other macros to extract what you want. For your example:
#define FUNCTION_TABLE(F) \
F(f1, { some code }) \
F(f2, { some code }) \
F(f3, { some code }) \
:
F(f99, { some code }) \
F(f100, { some code })
#define DEFINE_FUNCTIONS(NAME, CODE) int NAME() CODE
#define FUNCTION_NAME_LIST(NAME, CODE) NAME,
FUNCTION_TABLE(DEFINE_FUNCTIONS)
int (*function_table)(void)[] = { FUNCTION_TABLE(FUNCTION_NAME_LIST) };
If you have a C99 complying compiler, the preprocessor has variable length argument lists. P99 has a preprocessor P99_FOR that can do "code unrolling" like the one you want to achieve. To stay close to your example
#define MYFUNC(DUMMY, FN, I) int FN(void) { return I; }
#define GENFUNCS(...) \
P99_FOR(, P99_NARG(__VA_ARGS__), P00_IGN, MYFUNC, __VA_ARGS__) \
int (*function_table)(void)[] = { __VA_ARGS__ }
GENFUNCS(toto, hui, gogo);
would expand to the following (untested)
int toto(void) { return 0; }
int hui(void) { return 1; }
int gogo(void) { return 2; }
int (*function_table)(void)[] = { toto, hui, gogo };
This is sort of abuse of CPP but a common type of abuse. I handle situations
like this by defining dummy macros
#define FUNCTIONS \
foo(a,b,c,d) \
foo(a,b,c,d) \
foo(a,b,c,d)
now,
#define foo(a,b,c,d) \
a+b ;
FUNCTIONS
#undef foo
later, when you want something different done with the same list
#define foo(a,b,c,d) \
a: c+d ;
FUNCTIONS
#undef foo
It's a bit ugly and cumbersome, but it works.
There's this thing called X Macro which is used as:
a technique for reliable maintenance of parallel lists, of code or data, whose corresponding items must appear in the same order
This is how it works:
#include <stdio.h>
//you create macro that contains your values and place them in (yet) not defined macro
#define COLORS\
X(red, 91)\
X(green, 92)\
X(blue, 94)\
//you can name that macro however you like but conventional way is just an "X"
//and then you will be able to define a format for your values in that macro
#define X(name, value) name = value,
typedef enum { COLORS } Color;
#undef X //so you redefine it below
int main(void)
{
#define X(name, value) printf("%d, ", name);
COLORS
#undef X
return 0;
}
Solution for your problem would be:
#define FUNCTIONS \
F(f1, code1)\
F(f2, code2)\
F(f3, code3)
#define F(name, code) int name(void){code}
FUNCTIONS
#undef F
#define F(name, code) &name,
int (*function_table[])(void) = { FUNCTIONS };
#undef F
Boost is a C++ library, but it's Preprocessor module should still be good for use in C. It offers some surprisingly advanced data types and functionality for use in the preprocessor. You could check it out.

Resources