const dayone = [{ name: 1, uid: 1 }, { name: 2, uid: 2 }, { name: 3, uid: 3 },
{ name: "ball", uid: 100 }, { name: "lina", uid: 200 }, { name: "ppp", uid: 700 }]
const daytwo = [{ name: "ball", uid: 100 }, { name: "lina", uid: 200 }, { name: "ppp", uid: 700 }, { name: 7, uid: 7 }]
const total = dayone.concat(daytwo)
i want to omit the duplicate objects..
{ name: "ball", uid: 100 }, { name: "lina", uid: 200 }, { name: "ppp", uid: 700 }
what i really want to get is,
Newtotal = [{ name: 1, uid: 1 }, { name: 2, uid: 2 }, { name: 3, uid: 3 },{ name: 7, uid: 7 }]
how can i solve this problem? help!
i am trying to omit the data which is duplicate in array.
i already used filter, map, reduce.. and other friends told me about omit.
but i couldn't find the way how to resolve problem yet.
I hope this one helps you.
[...new Map(total.map((item) => [item["uid"], item])).values(),];
const dayone = [{ name: 1, uid: 1 }, { name: 2, uid: 2 }, { name: 3, uid: 3 },
{ name: "ball", uid: 100 }, { name: "lina", uid: 200 }, { name: "ppp", uid: 700 }]
const daytwo = [{ name: "ball", uid: 100 }, { name: "lina", uid: 200 }, { name: "ppp", uid: 700 }, { name: 7, uid: 7 }]
const total = dayone.concat(daytwo)
const unique = [
...new Map(total.map((item) => [item["uid"], item])).values(),
];
console.log("original items",total.length,total)
console.log("unique items",unique.length,unique)
Thanks.
Related
I am trying to get collections using selectors. Here is my code:
Selectors
import { createSelector } from "reselect";
export const selectShop = state => state.shop;
export const selectCollections = createSelector(
[selectShop],
shop => shop.collections
)
export const selectCollectionForPreview = createSelector(
[selectCollections],
collections => Object.keys(collections).map(key => collections[key])
)
export const selectCollectionItem = collectionUrl =>
createSelector(
[selectCollections],
collections => collections[collectionUrl]
//It seems that the selector above is returning collections as an array instead of object, so collections[collectionUrl] is returning undefined
)
Component
const CollectionPage = ({collections}) => {
// const {title, items} = Object.keys(collections)
const {title, items} = collections
console.log('collection', collections);
return(
// <></>
<div className="collection-page">
<h2 className='title'>{title}</h2>
<div className='items'>
{items.map( item =>
<CollectionItem key={item.id} item={item}/>
)}
</div>
</div>
)
}
const mapStateToProps = (state,ownProps) => ({
collections: selectCollectionItem(ownProps.match.params.collectionId)(state)
})
export default connect(mapStateToProps)(CollectionPage);
SHOP_DATA
const SHOP_DATA = {
hats:{
id: 1,
title: 'Hats',
routeName: 'hats',
items: [
{
id: 1,
name: 'Brown Brim',
imageUrl: 'https://i.ibb.co/ZYW3VTp/brown-brim.png',
price: 25
},
{
id: 2,
name: 'Blue Beanie',
imageUrl: 'https://i.ibb.co/ypkgK0X/blue-beanie.png',
price: 18
},
{
id: 3,
name: 'Brown Cowboy',
imageUrl: 'https://i.ibb.co/QdJwgmp/brown-cowboy.png',
price: 35
},
{
id: 4,
name: 'Grey Brim',
imageUrl: 'https://i.ibb.co/RjBLWxB/grey-brim.png',
price: 25
},
{
id: 5,
name: 'Green Beanie',
imageUrl: 'https://i.ibb.co/YTjW3vF/green-beanie.png',
price: 18
},
{
id: 6,
name: 'Palm Tree Cap',
imageUrl: 'https://i.ibb.co/rKBDvJX/palm-tree-cap.png',
price: 14
},
{
id: 7,
name: 'Red Beanie',
imageUrl: 'https://i.ibb.co/bLB646Z/red-beanie.png',
price: 18
},
{
id: 8,
name: 'Wolf Cap',
imageUrl: 'https://i.ibb.co/1f2nWMM/wolf-cap.png',
price: 14
},
{
id: 9,
name: 'Blue Snapback',
imageUrl: 'https://i.ibb.co/X2VJP2W/blue-snapback.png',
price: 16
}
]
},
sneakers:{
id: 2,
title: 'Sneakers',
routeName: 'sneakers',
items: [
{
id: 10,
name: 'Adidas NMD',
imageUrl: 'https://i.ibb.co/0s3pdnc/adidas-nmd.png',
price: 220
},
{
id: 11,
name: 'Adidas Yeezy',
imageUrl: 'https://i.ibb.co/dJbG1cT/yeezy.png',
price: 280
},
{
id: 12,
name: 'Black Converse',
imageUrl: 'https://i.ibb.co/bPmVXyP/black-converse.png',
price: 110
},
{
id: 13,
name: 'Nike White AirForce',
imageUrl: 'https://i.ibb.co/1RcFPk0/white-nike-high-tops.png',
price: 160
},
{
id: 14,
name: 'Nike Red High Tops',
imageUrl: 'https://i.ibb.co/QcvzydB/nikes-red.png',
price: 160
},
{
id: 15,
name: 'Nike Brown High Tops',
imageUrl: 'https://i.ibb.co/fMTV342/nike-brown.png',
price: 160
},
{
id: 16,
name: 'Air Jordan Limited',
imageUrl: 'https://i.ibb.co/w4k6Ws9/nike-funky.png',
price: 190
},
{
id: 17,
name: 'Timberlands',
imageUrl: 'https://i.ibb.co/Mhh6wBg/timberlands.png',
price: 200
}
]
},
jackets:{
id: 3,
title: 'Jackets',
routeName: 'jackets',
items: [
{
id: 18,
name: 'Black Jean Shearling',
imageUrl: 'https://i.ibb.co/XzcwL5s/black-shearling.png',
price: 125
},
{
id: 19,
name: 'Blue Jean Jacket',
imageUrl: 'https://i.ibb.co/mJS6vz0/blue-jean-jacket.png',
price: 90
},
{
id: 20,
name: 'Grey Jean Jacket',
imageUrl: 'https://i.ibb.co/N71k1ML/grey-jean-jacket.png',
price: 90
},
{
id: 21,
name: 'Brown Shearling',
imageUrl: 'https://i.ibb.co/s96FpdP/brown-shearling.png',
price: 165
},
{
id: 22,
name: 'Tan Trench',
imageUrl: 'https://i.ibb.co/M6hHc3F/brown-trench.png',
price: 185
}
]
},
womens:{
id: 4,
title: 'Womens',
routeName: 'womens',
items: [
{
id: 23,
name: 'Blue Tanktop',
imageUrl: 'https://i.ibb.co/7CQVJNm/blue-tank.png',
price: 25
},
{
id: 24,
name: 'Floral Blouse',
imageUrl: 'https://i.ibb.co/4W2DGKm/floral-blouse.png',
price: 20
},
{
id: 25,
name: 'Floral Dress',
imageUrl: 'https://i.ibb.co/KV18Ysr/floral-skirt.png',
price: 80
},
{
id: 26,
name: 'Red Dots Dress',
imageUrl: 'https://i.ibb.co/N3BN1bh/red-polka-dot-dress.png',
price: 80
},
{
id: 27,
name: 'Striped Sweater',
imageUrl: 'https://i.ibb.co/KmSkMbH/striped-sweater.png',
price: 45
},
{
id: 28,
name: 'Yellow Track Suit',
imageUrl: 'https://i.ibb.co/v1cvwNf/yellow-track-suit.png',
price: 135
},
{
id: 29,
name: 'White Blouse',
imageUrl: 'https://i.ibb.co/qBcrsJg/white-vest.png',
price: 20
}
]
},
mens:{
id: 5,
title: 'Mens',
routeName: 'mens',
items: [
{
id: 30,
name: 'Camo Down Vest',
imageUrl: 'https://i.ibb.co/xJS0T3Y/camo-vest.png',
price: 325
},
{
id: 31,
name: 'Floral T-shirt',
imageUrl: 'https://i.ibb.co/qMQ75QZ/floral-shirt.png',
price: 20
},
{
id: 32,
name: 'Black & White Longsleeve',
imageUrl: 'https://i.ibb.co/55z32tw/long-sleeve.png',
price: 25
},
{
id: 33,
name: 'Pink T-shirt',
imageUrl: 'https://i.ibb.co/RvwnBL8/pink-shirt.png',
price: 25
},
{
id: 34,
name: 'Jean Long Sleeve',
imageUrl: 'https://i.ibb.co/VpW4x5t/roll-up-jean-shirt.png',
price: 40
},
{
id: 35,
name: 'Burgundy T-shirt',
imageUrl: 'https://i.ibb.co/mh3VM1f/polka-dot-shirt.png',
price: 25
}
]
}
};
export default SHOP_DATA;
Please provide any pointers or advice on what am I doing wrong? I keep getting the error. It seems that the collection is undefined. I don't understand why. Ideally it should return an object.
You are exporting the component like this
const mapStateToProps = (state,ownProps) => ({
collections: selectCollectionItem(ownProps.match.params.collectionId)(state)
})
export default connect(mapStateToProps)(CollectionPage);
The ownProps.match.params.collectionId might be undefined.
Add this at the top of your file
import { withRouter} from 'react-router-dom'
and export your component like
export default connect(mapStateToProps)(withRouter(CollectionPage));
var arr = [
{ id: 1, name: 'Ahmed Malick', school: 'TEWGS' },
{ id: 2, name: 'Tehmeed Anwar', school: 'DGS' },
{ id: 3, name: 'Azhar Yameen', school: 'DGS' }
]
I want this output:
The student name is his id is and he studies in
Can you please show me what kind of output you expect. Then i will try to solve it.
I'm not sure if this is what you want
var arr = [
{ id: 1, name: "Ahmed Malick", school: "TEWGS" },
{ id: 2, name: "Tehmeed Anwar", school: "DGS" },
{ id: 3, name: "Azhar Yameen", school: "DGS" },
];
arr.map((student) => {
return `Name: ${student.name}, id: ${student.id}, he studies in: ${student.school}`;
}).forEach((output) => {
console.log(output);
});
If you want it in the DOM do this
let html = arr.map((student) => {
return `<p><strong>Name</strong>: ${student.name}, <strong>id</strong>: ${student.id},<strong> he studies in</strong> ${student.school}</p>`;
}).join("")
document.createElement("div").innerHTML = html
Try thatGood luck
The arrays I have
const users = [
{ id: 1, name: "field 1" },
{ id: 2, name: "field 2" },
{ id: 3, name: "field 3" },
{ id: 4, name: "field 4" },
];
const onlineUsers = [
{ id: 1, name: "field 1" },
{ id: 3, name: "field 3" }
];
I would like to find the online and offline ones by comparing the two series
I want to do:
const userLists = [
{ id: 1, name: "field 1", online: true },
{ id: 2, name: "field 2", online: false },
{ id: 3, name: "field 3", online: true },
{ id: 4, name: "field 4", online: false },
];
Using Array.map and Array.some
const users = [
{ id: 1, name: "field 1" },
{ id: 2, name: "field 2" },
{ id: 3, name: "field 3" },
{ id: 4, name: "field 4" },
];
const onlineUsers = [
{ id: 1, name: "field 1" },
{ id: 3, name: "field 3" }
];
var retVal=users.map(u=>{
var isOnline=onlineUsers.some(ou=> ou.id==u.id);//this will check if onlineUsers have some record with given userid
return {...u,online:isOnline}
})
console.log(retVal)
You can just traverse through the user list and you can find out the onlineuser using find and just push it in the onlineuserList.
const users = [
{ id: 1, name: "field 1" },
{ id: 2, name: "field 2" },
{ id: 3, name: "field 3" },
{ id: 4, name: "field 4" },
];
const onlineUsers = [
{ id: 1, name: "field 1" },
{ id: 3, name: "field 3" }
];
const userLists = [];
users.forEach(user => {
if(onlineUsers.find(q => q.id == user.id)){
userLists.push({
id: user.id,
name: user.name,
online: "true"
})
}
else{
userLists.push({
id: user.id,
name: user.name,
online: "false"
})
}
})
console.log(userLists);
a bit faster approach using Array.indexOf() and JSON.strigify()
const onlineUsers = JSON.stringify([
{ id: 1, name: "field 1" },
{ id: 3, name: "field 3" }
]);
const userList = users.map(user =>
({
...user,
online: onlineUsers.indexOf(JSON.stringify(user)) > -1
})
);
OR if you neither want to change original onlineUsers array nor declare another variable:
const userList = users.map(user =>
({ ...user, online: JSON.stringify(onlineUsers).indexOf(JSON.stringify(user)) > -1 })
);
This question already has answers here:
JavaScript closure inside loops – simple practical example
(44 answers)
Closed 7 years ago.
I have angular ui grid that I am trying to get values from its cells. Here is my list in table
id name
1 AUSTRIA
2 BELGIUM
3 BULGARIA
4 CROATIA
5 CZECH REPUBLIC
This is code I run:
element(by.id('grid1')).all(by.repeater('(rowRenderIndex, row) in rowContainer.renderedRows track by $index')).then(function (items) {
for (var i = 0; i < items.length; i++) {
var country = <any>{}; //typescript code
self.gridTestUtils.dataCell('grid1', i, 0).getText().then(
function (valueId) {
country.id = valueId
});
self.gridTestUtils.dataCell('grid1', i, 1).getText().then(
function (valueName) {
country.name = valueName;
self.countryList.push(country)
console.log(self.countryList)
});
}
});
And this is result
[ { id: 1, name: 'AUSTRIA' }]
[ { id: 1, name: 'BELGIUM' },
{ id: 1, name: 'BELGIUM' }]
[ { id: 1, name: 'BULGARIA' },
{ id: 1, name: 'BULGARIA' },
{ id: 1, name: 'BULGARIA' } ]
[ { id: 1, name: 'CROATIA' },
{ id: 1, name: 'CROATIA' },
{ id: 1, name: 'CROATIA' },
{ id: 1, name: 'CROATIA' } ]
[ { id: 1, name: 'CZECH REPUBLIC' },
{ id: 1, name: 'CZECH REPUBLIC' },
{ id: 1, name: 'CZECH REPUBLIC' },
{ id: 1, name: 'CZECH REPUBLIC' },
{ id: 1, name: 'CZECH REPUBLIC' } ]
I expect result would look like:
[ { id: 1, name: 'AUSTRIA' }]
[ { id: 1, name: 'AUSTRIA' },
{ id: 1, name: 'BELGIUM' }]
[ { id: 1, name: 'AUSTRIA' },
{ id: 1, name: 'BELGIUM' },
{ id: 1, name: 'BULGARIA' } ]
[ { id: 1, name: 'AUSTRIA' },
{ id: 1, name: 'BELGIUM' },
{ id: 1, name: 'BULGARIA' },
{ id: 1, name: 'CROATIA' } ]
[ { id: 1, name: 'AUSTRIA' },
{ id: 1, name: 'BELGIUM' },
{ id: 1, name: 'BULGARIA' },
{ id: 1, name: 'CROATIA' },
{ id: 1, name: 'CZECH REPUBLIC' } ]
What is wrong with my code? What should I do that I have expected array
The problem is that i in your loop changes as the loops goes through, and in your async calls you are using i and getting a promise, but it's only a reference, so at the time the promises get resolved, the will have the reference to the variable with the last value of the loop. A workaround is to create an IIFE:
element(by.id('grid1')).all(by.repeater('(rowRenderIndex, row) in rowContainer.renderedRows track by $index')).then(function (items) {
for (var i = 0; i < items.length; i++) {
var country = <any>{}; //typescript code
(function (i, country) {
self.gridTestUtils.dataCell('grid1', i, 0).getText().then(function (valueId) {
country.id = valueId;
});
self.gridTestUtils.dataCell('grid1', i, 1).getText().then(function (valueName) {
country.name = valueName;
self.countryList.push(country)
console.log(self.countryList)
});
})(i, country);
}
});
So I'm looking to write an AngularJS function that performs a COUNT of how many activities each user has performed.
Ideally: What I'd like to be able to return is (by looking at the data model below):
John Wilson - 2 Deals
Robin Wilson - 3 Deals
Garry Wilson - 3 Deals & 1 Meeting
My question is, how can I conduct a count of each activity using angularJS? What I would like to is create an element that looks like:
<div class="countArea" ng-repeat="activity in selectedUser.activities"
{{activity.count}}
</div>
The code I have so far:
$scope.competitionDetails = {
organisationId: 1,
competitionId: "52eabcf0f3672",
currentUser: 2,
title: "Challenge #1",
description: "Challenge description goes here",
end_date: "2014-03-01",
users: [{
id: 2,
name: "John Wilson",
totalPoints: 40,
activities: [{
id: 6431,
points: 20
}, {
id: 6431,
points: 20
}]
}, {
id: 3,
name: "Robin Wilson",
totalPoints: 60,
activities: [{
id: 6431,
points: 20
}, {
id: 6431,
points: 20
}, {
id: 6431,
points: 20
}]
}, {
id: 1,
name: "Garry Wilson",
totalPoints: 140,
activities: [{
id: 6431,
points: 20
}, {
id: 6431,
points: 20
}, {
id: 6432,
points: 100
}]
}]
};
$scope.activities = [{
id: 6431,
name: "Deal",
points: 20
}, {
id: 6432,
name: "Meeting",
points: 100
}];