The last cycle in the code doesn't see printf - c

Question

I need to convert the entered number into a five-digit system. But the last cycle in the code does not see printf regardless of what you want to output, but in any other part of the code everything works fine. Does anyone know how to fix this?
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define MAX_NUM 6
#define MAX_ARR 20
int main()
{
system("chcp 1251");
printf("\n\n");
unsigned long long n;
int numArray[MAX_ARR];
int count = 0, i, j;
printf("Введіть довге ціле число: ");
scanf_s("%llu", &n);
while (n != 0)
{
n /= 10;
count++;
}
if (count > MAX_NUM)
{
printf("\nЧисло занадто велике. Введіть число менше або рівне 6: ");
scanf_s("%llu", &n);
count = 0;
while (n != 0)
{
n /= 10;
count++;
}
while (count > MAX_NUM)
{
printf("\nЧисло занадто велике. Введіть число менше або рівне 6: ");
scanf_s("%llu", &n);
count = 0;
while (n != 0)
{
n /= 10;
count++;
}
}
}
for (i = 0; n > 0; i++)
{
numArray[i] = n % 5;
n /= 5;
printf(" %d ", numArray[i]);
}
}

Answer 1

After while loops as for example the first while loop
while (n != 0)
{
n /= 10;
count++;
}
n is equal to 0.
So the following for loop
for (i = 0; n > 0; i++)
will be skipped.
You need to use an intermediate variable in loops like this
while (n != 0)
{
n /= 10;
count++;
}
the following way
unsigned long long tmp = n;
do
{
++count;
} while ( tmp /= 10 );
Pay attention to that 0 is a valid number. You should not ignore it.
Also the array numArray is redundant because it is not used in the program apart from this assignment
numArray[i] = n % 5;
You could use it like
i = 0;
do
{
numArray[i++] = n % 5;
} while ( n /= 5 );
Then you could output the array in the reverse order like
while ( i )
{
printf( "%d", numArray[--i] );
}