pallindrome is not copied to next file but printed on output screen - c

Question

I have a file named fp1 containing different names, some being palindromes, and have to read all names from fp1 and check if each name is a palindrome or not. If it's a palindrome the I need to print the name to screen and copy it to another file named fp.
Here's my program:
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
void main() {
FILE *fp, *fp1;
char m, y[100];
int k = 0, i = 0, t = 1, p = 0;
fp = fopen("C:\\Users\\HP\\Desktop\\New folder\\file 2.txt", "w");
fp1 = fopen("C:\\Users\\HP\\Desktop\\New folder\\file4.txt", "r");
if (fp == NULL) {
printf("error ");
exit(1);
}
if (fp1 == NULL) {
printf("error");
exit(1);
}
k = 0;
m = fgetc(fp1);
while (m != EOF) {
k = 0;
i = 0;
t = 1;
p = 0;
while (m != ' ') {
y[k] = m;
k = k + 1;
m = fgetc(fp1);
}
p = k - 1;
for (i = 0; i <= k - 1; i++) {
if (y[i] != y[p]) t = 0;
p = p - 1;
}
if (t == 1) {
fputs(y, fp);
printf("%s is a pallindrome\n", y);
}
m = fgetc(fp1);
}
fclose(fp);
fclose(fp1);
}
coping pallindrome from one file to next file

Answer 1

You are not null terminating your buffer before attempting to use the contents as a string. After placing the last valid character read by fgetc into the buffer, you must place a null terminating character (\0).
A character buffer without a null terminating byte is not a string. Passing such a buffer to fputs, or the printf specifier %s without a length bound, will invoke Undefined Behaviour.
fgetc returns an int, not a char. On systems where char is unsigned, you will not be able to reliably test against the negative value of EOF.
The inner while loop is not checking for EOF. When the file is exhausted, it will repeatedly assign EOF to the buffer, until the buffer overflows.
To that end, in general, the inner while loop does nothing to prevent a buffer overflow for longer inputs.
In a hosted environment, void main() is never the correct signature for main. Use int main(void) or int main(int argc, char **argv).
Note that fputs does not print a trailing newline. As is, you would fill the output file full of strings with no delineation.
The nested while loops are fairly clumsy, and I would suggest moving your palindrome logic to its own function.
Here is a refactored version of your program. This program discards the tails of overly long words ... but the buffer is reasonably large.
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#define BUFFER_SIZE 1024
FILE *open_file_or_die(const char *path, const char *mode)
{
FILE *file = fopen(path, mode);
if (!path) {
perror(path);
exit(EXIT_FAILURE);
}
return file;
}
int is_palindrome(const char *word, size_t len)
{
for (size_t i = 0; i < len / 2; i++)
if (word[i] != word[len - i - 1])
return 0;
return 1;
}
int main(void)
{
/*
FILE *input = open_file_or_die("C:\\Users\\HP\\Desktop\\New folder\\file4.txt", "r");
FILE *output = open_file_or_die("C:\\Users\\HP\\Desktop\\New folder\\file 2.txt", "w");
*/
FILE *input = stdin;
FILE *output = stdout;
char buffer[BUFFER_SIZE];
size_t length = 0;
int ch = 0;
while (EOF != ch) {
ch = fgetc(input);
if (isspace(ch) || EOF == ch) {
buffer[length] = '\0';
if (length && is_palindrome(buffer, length)) {
fputs(buffer, output);
fputc('\n', output);
printf("<%s> is a palindrome.\n", buffer);
}
length = 0;
} else if (length < BUFFER_SIZE - 1)
buffer[length++] = ch;
}
/*
fclose(input);
fclose(output);
*/
}