I am looking to left join another table because there are two columns in that table that I need to add to my query..how can I left join onto my existing query? For example the query I am using is similar to the one below..
select subject, sum(cnt_daily) as cnt,
min(cnt_daily) as min_cnt_daily, max(cnt_daily) as max_cnt_daily
from (
select study_date, subject, count(*) as cnt_daily
from mytable
where study_date >= '2022-01-01'
group by study_date, subject
) t
group by subject
I tried
select *
from mytable
left join table2
on mytable.id= table1.id
order by table1.id;
But i know this isnt right
You may use CTE:
WITH t AS (
select study_date, subject, count(*) as cnt_daily
from mytable
where study_date >= '2022-01-01'
group by study_date, subject
)
select subject, sum(cnt_daily) as cnt,
min(cnt_daily) as min_cnt_daily, max(cnt_daily) as max_cnt_daily
from t
group by subject
This could encourage reuse of the query inside CTE.
Related
I have the following code:
IF (OBJECT_ID('tempdb..#Data') IS NOT NULL)
BEGIN
DROP TABLE #Data
END
SELECT
t.Name, x.Time, x.Date, x.Total,
xo.DrvCommTotal, x.Name2, x.Street, x.Zip,
r.Route1
INTO
#Data
FROM
table1 xo WITH(NOLOCK)
LEFT JOIN
Table2 t WITH(NOLOCK) ON t.ID = x.ID
LEFT JOIN
Route1 r ON r.RouteID = x.RouteID
WHERE
x.Client = 1
AND x.Date = '9/13/2018'
GROUP BY
t.Name, x.Time, x.Date, x.Total, xo.DrvCommTotal, x.Name2,
x.Street, x.Zip, r.Route1
ORDER BY
Route1
SELECT DISTINCT
F.*, F2.NumOrders
FROM
#Data F
LEFT JOIN
(SELECT
Route1, COUNT(*) NumOrders
FROM
#Data
GROUP BY
Route1) F2 ON F2.Route1 = F.Route1
LEFT OUTER JOIN
(SELECT
Street + ',' + Zip Stops, Time, RouteN1
FROM
#Data
GROUP BY
RouteNo1, street, Zip) F3 ON F3.Route1 = F.Route1
WHERE
F.Route1 IS NOT NULL
ORDER BY
F.Route1
and it provides me with a list of routes and stops. The column NumOrders lets me know how many orders are on each route. I need the stops to become individual columns I will label Stop1, Stop2, etc. so that each route is only one row and all the information is contained on the row for one route.
I'm currently using the temp table because the data is so large. I can play with my SELECT statement without having to re-run the entire code.
How do I move the stops for each route into columns?
Hum.. Not quite sure I understand the question but it sounds that you want to pivot the data so that the routes break into columns. If so, I would use a sql Pivot. Here is an example from the documentation:
USE AdventureWorks2014;
GO
SELECT VendorID, [250] AS Emp1, [251] AS Emp2, [256] AS Emp3, [257] AS Emp4, [260] AS Emp5
FROM
(SELECT PurchaseOrderID, EmployeeID, VendorID
FROM Purchasing.PurchaseOrderHeader) p
PIVOT
(
COUNT (PurchaseOrderID)
FOR EmployeeID IN
( [250], [251], [256], [257], [260] )
) AS pvt
ORDER BY pvt.VendorID;
Also, here is the link to how to use pivot: https://learn.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot?view=sql-server-2017
Since you already have all the data in your temp table, you could pivot that on the way out.
I have been trying to filter one table by two dates with an order of importance (date2 > date1) as follows:
SELECT
t1.customer, t1.weights, t1.max(t1.date1) as date1, t1.date2
FROM
(SELECT *
FROM table
WHERE CAST(date2 AS smalldatetime) = '10/29/2017') t2
INNER JOIN
table t1 ON t1.customer = t2.customer
AND t1.date2 = t2.date2
GROUP BY
t1.customer, t1.date2
ORDER BY
t1.customer;
It filters the table correctly by date2 first, the max(t1.date1) doesn't what I want it to do though. I get duplicate customers, that share the same (and correct) date2, but show different date1's. These duplicate records have the following in common: The weight row is different. What would I need to do to output just the the customer records connected to the most current date1 without taking other columns into consideration?
I am still a noob, help would be greatly appreciated!
Solution for t-sql (all based on the accepted answer):
SELECT * FROM (
SELECT row_number() over(partition by t1.customer order by t1.date1 desc) as rownum, t1.customer, t1.weights, t1.date1 , t1.date2
FROM
(SELECT *
FROM table
WHERE CAST(date2 AS smalldatetime) = '10/29/2017') t2
INNER JOIN
table t1 ON t1.customer = t2.customer
AND t1.date2 = t2.date2
)t3
where rownum = 1;
If I understood correctly, then instead of a group by logic, I would just use a qualify row statement :)
Try the code below and tell me if it's what you needed - what I'm telling it to do is to bring back only one row per customer ID....but where we select the row based on the dates (by sorting them in ascending order) - however, I'm unclear of what you mean by importance of the 2 dates so I may be completely off base here...can you please give an example of input and desired output?
SELECT t1.customer, t1.weights, t1.date1, t1.date2
FROM
(
Select *
FROM table
WHERE Cast(date2 as smalldatetime)='10/29/2017'
) t2
Inner Join table t1
ON t1.customer = t2.customer
AND t1.date2 = t2.date2
Qualify row_number() over(partition by t1.customer order by date2 , date1)=1
Order By t1.customer;
This query is fine works.
SELECT * FROM TABLE WHERE 330110042 IN (iItem01,iItem02,iItem03,iItem04,iItem05,iItem_1,iItem_2,iItem_3,iItem_4,iItem_5,iItem_6,iItem_7,iItem_8,iItem_9,iItem_10,iItem_11,iItem_12,iItem_13,iItem_14,iItem_15,iItem_16,iItem_17,iItem_18,iItem_19,iItem_20,iItem_21,iItem_22,iItem_23,iItem_24,iItem_25,iItem_26,iItem_27,iItem_28,iItem_29,iItem_30)
But this query didnt work.
SELECT * FROM TABLE WHERE 330110042, 330110002, 330110002 IN (iItem01,iItem02,iItem03,iItem04,iItem05,iItem_1,iItem_2,iItem_3,iItem_4,iItem_5,iItem_6,iItem_7,iItem_8,iItem_9,iItem_10,iItem_11,iItem_12,iItem_13,iItem_14,iItem_15,iItem_16,iItem_17,iItem_18,iItem_19,iItem_20,iItem_21,iItem_22,iItem_23,iItem_24,iItem_25,iItem_26,iItem_27,iItem_28,iItem_29,iItem_30)
How i work in SQL Server?
It's difficult to tell your exact goal here, but one possibility would be to turn the list of values into a table structure of its own. A Common Table Expression might work:
;WITH Ids AS
(
SELECT 330110042 AS Id
UNION ALL
SELECT 330110002
)
SELECT t.*
FROM [Table] t
INNER JOIN Ids i ON t.iItem01 = i.Id OR t.iItem02 = i.Id OR...
But, maybe a solution with UNPIVOT would be more elegant. I presume that your table has a primary key column called Id:
;WITH Unpivoted AS
(
SELECT Id, ColName, ColValue
FROM (SELECT Id, iItem01, iItem02, iItem03
FROM [Table] t) p
UNPIVOT
(ColValue FOR ColName IN (iItem01, iItem02, iItem03)) AS unpvt
)
SELECT t.*
FROM [Table] t
WHERE EXISTS (SELECT 1 FROM Unpivoted u
WHERE t.Id = u.Id
AND u.ColValue IN (330110042, 330110002))
Of course, you would add all the necessary columns. I added only the first three for this example.
In a single database, I have three tables as below:
I want to concatenate them in some single table, any suggestion?
If I am understanding correctly your answer you want something like this:
CREATE TABLE COMBINED (/*Insert the set of fields here*/);
GO
INSERT INTO COMBINED
SELECT Table1.ProposalId
, /*all other Table1 fields*/
, Table2.ProposalId
/*all other Table2 fields*/
, Table3.ProposalId
, /*all other Table2 fields*/
FROM Table1
FULL JOIN Table2
ON Table1.ProposalId = Table2.ProposalId
FULL JOIN Table3
ON Table1.ProposalId = Table3.ProposalId;
This will match the rows with the same proposal id (but keep the all the its values as proposalid_1,proposalid_2... and for those that do not match will bring the full row and NULL for every other fields of the rest of the tables.
Thanks for your help the issue has been solved.
SELECT mtlreq.proposalid, mtlreq.prp_mtlreq_taskgrp,mtlreq.prp_mtlreq_taskcode,mtlreq.prp_mtlreq_itemcode,mtlreq.prp_mtlreq_rateper,mtlreq.prp_mtlreq_qty,mtlreq.prp_mtlreq_Inter_MaterCost,mtlreq.prp_mtlreq_UOM,mtlreq.item_short_desc, resreq.proposalid,resreq.prp_resreq_taskcode ,resreq.prp_resreq_resource,resreq.prp_resreq_usage,resreq.prp_resreq_uom,resreq.prp_resreq_rate,resreq.prp_resreq_overhd_pers
FROM (
SELECT proposalid,prp_mtlreq_taskgrp,prp_mtlreq_taskcode,prp_mtlreq_itemcode,prp_mtlreq_rateper,prp_mtlreq_qty,prp_mtlreq_Inter_MaterCost,prp_mtlreq_UOM,item_short_desc,
ROW_NUMBER() OVER (ORDER BY proposalid) AS rn
FROM prjdet_prp_taskwork_mtlreq ) AS mtlreq
FULL OUTER JOIN (
SELECT proposalid,prp_resreq_taskcode ,prp_resreq_resource,prp_resreq_usage,prp_resreq_uom,prp_resreq_rate,prp_resreq_overhd_pers,
ROW_NUMBER() OVER (ORDER BY proposalid) AS rn
FROM prjdet_prp_taskwork_resreq) AS resreq
ON mtlreq.rn = resreq.rn
FULL OUTER JOIN (
SELECT proposalid,mtprp_delv_lineno,mtprp_delv_itemcode,mtprp_delv_cost,mtprp_delv_linelevelmrg,mtprp_delv_proposedamt,
ROW_NUMBER() OVER (ORDER BY proposalid) AS rn
FROM prjproposal_delidtl ) AS delidtl
on mtlreq.rn = delidtl.rn and resreq.rn=delidtl.rn
I'm having trouble with a query I'm trying to write in oracle.
Basically I want to get the count of two tables that have the same provider list. I can run the query individually but not sure how to do it in one shot.
Here's a example:
SELECT name, COUNT(name)
FROM table1
group by name
This gives me a list of names and a count beside them. If I run the same command but on table2(changing the from statement), it works fine. What I want to do is have a query that takes count from table1 and substracts it from count from table2.
How can I do it? I have tried to do nested selects and so on but can't seem to get it to work.
One option assuming that the name values in both tables are identical would be
SELECT t1.name, t2.cnt - t1.cnt diff
FROM( SELECT name, COUNT(name) cnt
FROM table1
group by name ) t1,
( SELECT name, COUNT(name) cnt
FROM table2
group by name ) t2
WHERE t1.name = t2.name
If you want to handle the case where one table has a name that the other doesn't but you don't know which table has the extra name (and assuming that you want to say that the other table has a cnt of 0 for that name)
SELECT coalesce(t1.name, t2.name) name,
nvl(t1.cnt, 0 ) t1_cnt,
nvl(t2.cnt, 0 ) t2_cnt,
nvl(t2.cnt,0) - nvl(t1.cnt,0) diff
FROM( SELECT name, COUNT(name) AS cnt
FROM table1
group by table1.name ) t1
full outer join
( SELECT name, COUNT(name) AS cnt
FROM table2
group by table2.name ) t2
on( t1.name = t2.name )
which you can see in this SQLFiddle