How to encrypt a String in C - c

I am kind of new to coding and in this particular situation I am trying to change each character in a string.
My first attempt is to use a pointer to access each character (since I think it is some sort of an array so I won´t need an index for loop) and change it to '%'
Else I want to change the current location of the pointer to be +5 letters in the alphabet.
At the ende the pointer should move one forward.
So this string = "This is confidential information"
should look like this = "Ymnx%nx%htsknijsynfq%nsktwrfynts"
There is an Error at line 22 at the "if" statement where i want change the empty char to %
#include <stdio.h>
#include <ctype.h>
void encryptString(char *sPtr);
int main(void)
{
char string[] = "This is confidential information"; //given string to encrypt
printf("The string before encrypting is: %s", string);
encryptString(string);
printf("\nThe string after encrypting is: %s\n", string);
}
void encryptString(char *sPtr)
{
while(*sPtr != '\0'){ //loop is running until end of string
if(*sPtr == ''){ // should convert space char into a '%')
char *sPtr = '%';
}
else{ //should shift the output of character +5 in the alphabet
char *sPtr =+ 5;
}
++sPtr; //make sPtr point to the next character
}
}

There were some issues in your code, especially the way your have written x =+ 5. Also, I don't understand why you added the char in front of the assignment char *sPtr =+ 5. As it is written C interprets this as a cast to char, but dereferencing a pointer to char already has the char type, so it is useless at least and dangerous at most.. It actually creates a new variable that shadows the outer sPtr, sets it to point to some weird low memory location, then doesn't dereference it
Lastly you can think about what happen when the alphabet is finished, for instance when there is a z character. I have here your code fixed with an idea on how to wrap around with a ASCII table. Please mind that the C standard does not HAVE TO use ASCII, so this implementation won't work everywhere, it's more of an idea for you.
#include <stdio.h>
#include <ctype.h>
#define START_ALPHABET_ASCII 65
#define ALPHABET_LENGTH_ASCII (123-START_ALPHABET_ASCII)
void encryptString(char *sPtr);
int main(void)
{
char string[] = "This is confidential information zzz"; //given string to encrypt
printf("The string before encrypting is: %s", string);
encryptString(string);
printf("\nThe string after encrypting is: %s\n", string);
}
void encryptString(char *sPtr)
{
while(*sPtr != '\0'){ //loop is running until end of string
if(*sPtr == ' '){ // should convert space char into a '%')
*sPtr = '%';
}
else{ //should shift the output of character +5 in the alphabet
*sPtr = ((*sPtr)+5 - START_ALPHABET_ASCII)%(ALPHABET_LENGTH_ASCII) + START_ALPHABET_ASCII ;
}
++sPtr; //make sPtr point to the next character
}
}
Which prints
The string before encrypting is: This is confidential information zzz
The string after encrypting is: Ymnx%nx%htsknijsynfq%nsktwrfynts%EEE

Related

warning: incompatible pointer to integer conversion

I am attempting to change the last character in a word to make it the plural version of that word. For example bus to buses or penny to pennies. I get a warning when I try to set the last character equal to the plural ending. Please let me know what I need to change in order to fix this problem. Thank you.
#include <stdio.h>
#include <string.h>
int main(void) {
char word[50];
char *last_char;
printf("Enter a word: ");
scanf("%[^\t\n]", word);
last_char = &word[(strlen(word)-1)];
if(*last_char == 'y')
{
*last_char = "ies";
printf("\nthis does not work %s", word);
}
else if(*last_char == 's')
{
*last_char = "es";
printf("\nthis is working %s", word);
}
else if(*last_char == 'h')
{
*last_char = 'es';
printf("\nPlural: %s", word);
}
else
{
last_char = &word[(strlen(word))];
*last_char = 's';
printf("\nPlural: %s", word);
}
return 0;
}
Just look at what you said yourself:
I get a warning when I try to set the last character equal to the plural ending.
You've got a memory slot for one character at that position and you're trying to squeeze many at that one slot. Isn't going to work.
"ies"; is not a single character, it is a string - an array of characters that decays to a pointer to the first character. A single char is of integer type; you cannot convert a pointer to character (well you can, but it does not make sense).
In this case the simple solution would be to strcpy the ending to the subarray starting from last_character, i.e.:
strcpy(last_char, "ies");
As for
last_char = &word[(strlen(word))];
*last_char = 's';
that is not correct because the string would not be null-terminated!
remember that last_char was already pointing to the last character, and the null terminator after that is at address last_char + 1; you can replace these two lines with
strcpy(last_char + 1, "s");

Why following code snippets assignment gives confusing output?

I'm studying C. I came across with string arrays. I'm bit confused about the following codes. I was anticipating one kind of output; however, getting completely different kind of output or program crush due to read access violation.
I've run this code on visual studio 2017, with _CRT_SECURE_NO_WARNINGS
// case 1
char* name[2];
//name[0] = (char*)malloc(sizeof(char*) * 10);
//name[1] = (char*)malloc(sizeof(char*) * 10);
name[0] = "john";
name[1] = 'doe';
printf("%s\n", name[0]); // prints john
//printf("%s\n", name[1]); // gives read access violation exception, why??? even with dynamically allocated memory
// case 2
char* name2[2] = { "emma", "olsson" };
printf("%s\n", name2[0]); // prints emma
printf("%s\n", name2[1]); // prints olsson, why no error???
// case 3
for (int i = 0; i < 2; i++)
{
name[i] = name2[i];
}
printf("%s\n", name[0]); // prints emma
printf("%s\n", name[1]); // prints olsson, why no error???
// case 4
char inputName[10];
int i = 0;
while (i < 2)
{
fgets(inputName, sizeof(inputName), stdin); // first input: Max second input: Payne
char* pos = strchr(inputName, '\n');
if (pos != NULL)
*pos = '\0';
name[i++] = inputName;
}
printf("%s\n", name[0]); // prints Payne, why not Max???
printf("%s\n", name[1]); // prints Payne
For case 1, 'doe' is not a string.
Case 2 works because you are initializing you pointers with string literals.
Case 3 works too because you assign the same initialized pointer in case 2 to case 1 pointers. Your name array pointers are basically set to point to where name2 ones are pointing.
In case 4, you declared inputName which points to a set of 10 chars. Then each time you get a new input you are writing it to the same memory section. And by doing this:name[i++] = inputName;
you are not copying a new char array to name[i] as you might think. Instead, you are telling name[i] char pointer to point to inputName. So it is normal that name prints last input twice, because that's what inputName points to, as well as both name char pointers.
It is unclear whether OP's code runs within main() or a user-defined function and what kind of value returns. That said, after removing superfluous variable redeclarations, here's how I achieved working code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void) {
char * name[2];
char * name2[2]={ "emma", "olsson" };
char inputName[10];
char names[BUFSIZ];
int i = 0;
// case 1
name[0] = "john";
name[1] = "doe";
printf("%s %s\n", name[0],name[1]); //john doe
// case 2
printf("%s %s\n", name2[0],name2[1]);//emma olsson
// case 3
for (i = 0; i < 2; i++){
name[i] = name2[i];
}
printf("%s %s\n", name[0],name[1]);//emma olsson
// case 4
i=0;
while (fgets(inputName, sizeof(inputName), stdin) != NULL && (i < 2) ){
strcat(names,inputName);
i++;
}
printf("\n%s\n",names);
return 0;
}
See live code here
OP should replace the single quotes around doe with double quotes which denote a null-terminated string. Single quotes are meant for a single character, i.e. 'a' refers to a byte value while "a" signifies a string containing two characters, an 'a' and a '\0'.
Also, OP should include two other libraries to facilitate execution. In particular, string.h is needed for the built-in string functions to execute properly.
Case 2 and Case 3 work because strings are encompassed by double quotes instead of single quotes. Note that in each case the "%s" format specifier for the printf() indicates that a string needs to be displayed.
In last case, fgets() with respect to stdin, upon success returns user input as a string. But that input will be overridden in the while loop, unless in each iteration you concatenate the old input with the new. Otherwise, when the inputName element values change because its address remains constant, only the latest input string displays. Here's some code that illustrates this point:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void) {
char * name[2];
char inputName[10];
int i = 0;
while (fgets(inputName, sizeof(inputName), stdin) != NULL && (i < 2) ){
printf("inputName: %p points to: %s",inputName,inputName);
name[i++] = inputName;
}
printf("\n name[0]: %p points to: %s\n name[1]: %p points to: %s",name[0],name[0],name[1],name[1]);
return 0;
}
Output:
inputName: 0x7fff8a511a50 points to: Maxine
inputName: 0x7fff8a511a50 points to: Pauline
name[0]: 0x7fff8a511a50 points to: Pauline
name[1]: 0x7fff8a511a50 points to: Pauline
See live code.
Incidentally, you don't need an array to display the names and indeed one may display the names outside of the loop as long as within the loop the code concatenates user input.

Using Pointers and strtok()

I'm building a linked list and need your assistance please as I'm new to C.
I need to input a string that looks like this: (word)_#_(year)_#_(DEFINITION(UPPER CASE))
Ex: Enter a string
Input: invest_#_1945_#_TRADE
Basically I'm looking to build a function that scans the DEFINITION and give's me back the word it relates to.
Enter a word to search in the dictionary
Input: TRADE
Output: Found "TREADE" in the word "invest"
So far I managed to come up using the strtok() function but right now I'm not sure what to do about printing the first word then.
Here's what I could come up with:
char split(char words[99],char *p)
{
p=strtok(words, "_#_");
while (p!=NULL)
{
printf("%s\n",p);
p = strtok(NULL, "_#_");
}
return 0;
}
int main()
{
char hello[99];
char *s = NULL;
printf("Enter a string you want to split\n");
scanf("%s", hello);
split(hello,s);
return 0;
}
Any ideas on what should I do?
I reckon that your problem is how to extract the three bits of information from your formatted string.
The function strtok does not work as you think it does: The second argument is not a literal delimiting string, but a string that serves as a set of characters that are delimiters.
In your case, sscanf seems to be the better choice:
#include <stdlib.h>
#include <stdio.h>
int main()
{
const char *line = "invest_#_1945 _#_TRADE ";
char word[40];
int year;
char def[40];
int n;
n = sscanf(line, "%40[^_]_#_%d_#_%40s", word, &year, def);
if (n == 3) {
printf("word: %s\n", word);
printf("year: %d\n", year);
printf("def'n: %s\n", def);
} else {
printf("Unrecognized line.\n");
}
return 0;
}
The function sscanf examines a given string according to a given pattern. Roughly, that pattern consists of format specifiers that begin with a percent sign, of spaces which denote any amount of white-space characters (including none) and of other characters that have to be matched varbatim. The format specifiers yield a result, which has to be stored. Therefore, for each specifier, a result variable must be given after the format string.
In this case, there are several chunks:
%40[^_] reads up to 40 characters that are not the underscore into a char array. This is a special case of reading a string. Strings in sscanf are really words and may not contain white space. The underscore, however, would be part of a string, so in order not to eat up the underscore of the first delimiter, you have to use the notation [^(chars)], which means: Any sequence of chars that do not contain the given chars. (The caret does the negation here, [(chars)] would mean any sequence of the given chars.)
_#_ matches the first delimiter literally, i.e. only if the next chars are underscore hash mark, underscore.
%d reads a decimal number into an integer. Note that the adress of the integer has to be given here with &.
_#_ matches the second delimiter.
%40s reads a string of up to 40 non-whitespace characters into a char array.
The function returns the number of matched results, which should be three if the line is valid. The function sscanf can be cumbersome, but is probably your best bet here for quick and dirty input.
#include <stdio.h>
#include <string.h>
char *strtokByWord_r(char *str, const char *word, char **store){
char *p, *ret;
if(str != NULL){
*store = str;
}
if(*store == NULL) return NULL;
p = strstr(ret=*store, word);
if(p){
*p='\0';
*store = p + strlen(word);
} else {
*store = NULL;
}
return ret;
}
char *strtokByWord(char *str, const char *word){
static char *store = NULL;
return strtokByWord_r(str, word, &store);
}
int main(){
char input[]="invest_#_1945_#_TRADE";
char *array[3];
char *p;
int i, size = sizeof(array)/sizeof(char*);
for(i=0, p=input;i<size;++i){
if(NULL!=(p=strtokByWord(p, "_#_"))){
array[i]=p;//strdup(p);
p=NULL;
} else {
array[i]=NULL;
break;
}
}
for(i = 0;i<size;++i)
printf("array[%d]=\"%s\"\n", i, array[i]);
/* result
array[0]="invest"
array[1]="1945"
array[2]="TRADE"
*/
return 0;
}

How to extract a substring from a string in C?

I tried using strncmp but it only works if I give it a specific number of bytes I want to extract.
char line[256] = This "is" an example. //I want to extract "is"
char line[256] = This is "also" an example. // I want to extract "also"
char line[256] = This is the final "example". // I want to extract "example"
char substring[256]
How would I extract all the elements in between the ""? and put it in the variable substring?
Note: I edited this answer after I realized that as written the code would cause a problem as strtok doesn't like to operate on const char* variables. This was more an artifact of how I wrote the example than a problem with the underlying principle - but apparently it deserved a double downvote. So I fixed it.
The following works (tested on Mac OS 10.7 using gcc):
#include <stdio.h>
#include <string.h>
int main(void) {
const char* lineConst = "This \"is\" an example"; // the "input string"
char line[256]; // where we will put a copy of the input
char *subString; // the "result"
strcpy(line, lineConst);
subString = strtok(line,"\""); // find the first double quote
subString=strtok(NULL,"\""); // find the second double quote
printf("the thing in between quotes is '%s'\n", subString);
}
Here is how it works: strtok looks for "delimiters" (second argument) - in this case, the first ". Internally, it knows "how far it got", and if you call it again with NULL as the first argument (instead of a char*), it will start again from there. Thus, on the second call it returns "exactly the string between the first and second double quote". Which is what you wanted.
Warning: strtok typically replaces delimiters with '\0' as it "eats" the input. You must therefore count on your input string getting modified by this approach. If that is not acceptable you have to make a local copy first. In essence I do that in the above when I copy the string constant to a variable. It would be cleaner to do this with a call to line=malloc(strlen(lineConst)+1); and a free(line); afterwards - but if you intend to wrap this inside a function you have to consider that the return value has to remain valid after the function returns... Because strtok returns a pointer to the right place inside the string, it doesn't make a copy of the token. Passing a pointer to the space where you want the result to end up, and creating that space inside the function (with the correct size), then copying the result into it, would be the right thing to do. All this is quite subtle. Let me know if this is not clear!
if you want to do it with no library support...
void extract_between_quotes(char* s, char* dest)
{
int in_quotes = 0;
*dest = 0;
while(*s != 0)
{
if(in_quotes)
{
if(*s == '"') return;
dest[0]=*s;
dest[1]=0;
dest++;
}
else if(*s == '"') in_quotes=1;
s++;
}
}
then call it
extract_between_quotes(line, substring);
#include <string.h>
...
substring[0] = '\0';
const char *start = strchr(line, '"') + 1;
strncat(substring, start, strcspn(start, "\""));
Bounds and error checking omitted. Avoid strtok because it has side effects.
Here is a long way to do this: Assuming string to be extracted will be in quotation marks
(Fixed for error check suggested by kieth in comments below)
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char input[100];
char extract[100];
int i=0,j=0,k=0,endFlag=0;
printf("Input string: ");
fgets(input,sizeof(input),stdin);
input[strlen(input)-1] = '\0';
for(i=0;i<strlen(input);i++){
if(input[i] == '"'){
j =i+1;
while(input[j]!='"'){
if(input[j] == '\0'){
endFlag++;
break;
}
extract[k] = input[j];
k++;
j++;
}
}
}
extract[k] = '\0';
if(endFlag==1){
printf("1.Your code only had one quotation mark.\n");
printf("2.So the code extracted everything after that quotation mark\n");
printf("3.To make sure buffer overflow doesn't happen in this case:\n");
printf("4.Modify the extract buffer size to be the same as input buffer size\n");
printf("\nextracted string: %s\n",extract);
}else{
printf("Extract = %s\n",extract);
}
return 0;
}
Output(1):
$ ./test
Input string: extract "this" from this string
Extract = this
Output(2):
$ ./test
Input string: Another example to extract "this gibberish" from this string
Extract = this gibberish
Output(3):(Error check suggested by Kieth)
$ ./test
Input string: are you "happy now Kieth ?
1.Your code only had one quotation mark.
2.So the code extracted everything after that quotation mark
3.To make sure buffer overflow doesn't happen in this case:
4.Modify the extract buffer size to be the same as input buffer size
extracted string: happy now Kieth ?
--------------------------------------------------------------------------------------------------------------------------------
Although not asked for it -- The following code extracts multiple words from input string as long as they are in quotation marks:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char input[100];
char extract[50];
int i=0,j=0,k=0,endFlag=0;
printf("Input string: ");
fgets(input,sizeof(input),stdin);
input[strlen(input)-1] = '\0';
for(i=0;i<strlen(input);i++){
if(input[i] == '"'){
if(endFlag==0){
j =i+1;
while(input[j]!='"'){
extract[k] = input[j];
k++;
j++;
}
endFlag = 1;
}else{
endFlag =0;
}
//break;
}
}
extract[k] = '\0';
printf("Extract = %s\n",extract);
return 0;
}
Output:
$ ./test
Input string: extract "multiple" words "from" this "string"
Extract = multiplefromstring
Have you tried looking at the strchr function? You should be able to call that function twice to get pointers to the first and second instances of the " character and use a combination of memcpy and pointer arithmetic to get what you want.

Strings in C Language

How can you code this in C language if the output is like this? I need strings format of the code because our topic is strings.
#include <stdio.h>
#include <stdlib.h>
void main()
{
char my_string[50];
printf("Enter a word:");
scanf("%s", my_string);
printf("Enter a word:");
scanf("%s", my_string);
// Some unknown code here...
// this part is my only problem to solve this.
getch();
}
Output:
Hello -> (user input)
World -> (user input)
HWeolrllod -> (result)
Okay, you need to do some investigating. We don't, as a general rule, do people's homework for them since:
it's cheating.
you'll probably get caught out if you copy verbatim.
it won't help you in the long run at all.
The C library call for user input that you should use is fgets, along the line of:
char buffer[100];
fgets (buffer, sizeof(buffer), stdin);
This will input a string into the character array called buffer.
If you do that with two different buffers, you'll have the strings in memory.
Then you need to create pointers to them and walk through the two strings outputting alternating characters. Pointers are not an easy subject but the following pseudo-code may help:
set p1 to address of first character in string s1
set p1 to address of first character in string s1
while contents of p1 are not end of string marker:
output contents of p1
add 1 to p1 (move to next character)
if contents of p2 are not end of string marker:
output contents of p2
add 1 to p2 (move to next character)
while contents of p2 are not end of string marker:
output contents of p2
add 1 to p2 (move to next character)
Translating that into C will take some work but the algorithm is solid. You just need to be aware that a character pointer can be defined with char *p1;, getting the contents of it is done with *p1 and advancing it is p = p + 1; or p1++;.
Short of writing the code for you (which I'm not going to do), there's probably not much else you need.
void main()
{
char my_string1[50],my_string2[50]; int ptr;
ptr=0;
printf("Enter a word : ");
scanf("%s",my_string1);
printf("enter a word");
scanf("%s",my_string2);
while(my_string1[ptr]!='\0' && my_string2[ptr]!='\0')
{
printf("%c%c",my_string1[ptr],my_string2[ptr]);
ptr++;
}
if(my_string1[ptr]!='\0')
{
while(my_string1[ptr]!='\0')
{ printf("%c",my_string1[ptr]);
ptr++;
}
}
else
{
while(my_string2[ptr]!='\0')
{printf("%c",my_string2[ptr]);
ptr++;
}
}
}
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void main()
{
char my_string1[50],my_string2[50];
int i,l1=1,l2=0;
printf("Enter a word:");
scanf("%s", my_string1);
printf("Enter a word:");
scanf("%s", my_string2);
l1=strlen(my_string1); /* Length of 1st string */
l2=strlen(my_string2); /* Length of 2nd string */
if(l1==l2)
{
for(i=0;i<l1;i++)
{
printf("%c%c",my_string1[i],my_string2[i]);
}
}
else
{
printf("Length of the entered strings do not match");
}
}
This is your required code.
You can see that output needs to be a String containing all chars of User String1 and User String2 one by one...
You can do this like...
//add #include<String.h>
int l1=strlen(s1);
int l2=strlen(s2);
if(l1!=l2)
{
printf("length do not match");
return 0;
}
char ansstr[l1+l2];
int i,j=0,k=0;
for(i=0;i<l1+l2;i=i+2)
{
ansstr[i]=s1[j];
ansstr[i+1]=s2[k];
j++;
k++;``
}
//ansstr is your answer
Ok, here's your code. Come on guys, if he asked here it means he can't solve this.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
char str1[] = "abcdefghijklmopq";
char str2[] = "jklm";
int len1 = strlen(str1);
int len2 = strlen(str2);
int c1 = 0, c2 = 0;
int max = (len1 > len2) ? len1 : len2 ;
char *result = malloc(len1 + len2);
for(c1 = 0; c1 <= max; c1++) {
if(c1 < len1)
result[c2++] = str1[c1];
if(c1 < len2)
result[c2++] = str2[c1];
}
result[c2] = 0;
printf("\n%s\n", result);
return 0;
}
Basically the loop picks up a character from str1 and appends it to result. Then it picks a character, which stands in the same position as the first from str2 and appends it to result, just as before. I increment c2 by 2 every time because I'm adding 2 chars to result. I check if c1 is bigger that the length of the strings because I want to copy only the characters in the string without the terminating \0. If you know that your strings have the same length you can omit these ifs.

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