Create a new array of objects in a aggregate query in Mongodb - arrays

Question

I'm running a query on Mongodb to get the combine data from two different collections: User and Store.
User collection has a property named as store_ids, which is an array that contains a list of ObjectIds of each store that the User has access to.
I'm trying to add the name of each store in the query result.
Example:
User Document:
{
_id: '58ebf8f24d52e9ab59b5538b',
store_ids: [
ObjectId("58dd4bb10e2898b0057be648"),
ObjectId("58ecd57d1a2f48e408ea2a30"),
ObjectId("58e7a0766de7403f5118afea"),
]
}
Store Documents:
{
_id: "58dd4bb10e2898b0057be648",
name: "Store A",
},
{
_id: "58ecd57d1a2f48e408ea2a30",
name: "Store B",
},
{
_id: "58e7a0766de7403f5118afea",
name: "Store C"
}
I'm looking for a query that returns an output like this:
{
_id: '58ebf8f24d52e9ab59b5538b',
stores: [
{
_id: ObjectId("58dd4bb10e2898b0057be648"),
name: "Store A"
},
{
id: ObjectId("58ecd57d1a2f48e408ea2a30"),
name: "Store B"
},
{
_id: ObjectId("58e7a0766de7403f5118afea"),
name: "Store C"
}
]
}
I've already tried operations like $map and $set. I don't know if I'm applying them in the right way because they didn't work for my case.

Answer 1

You can use an aggregate query:
db.users.aggregate([
{
$lookup: {
from: "stores", //Your store collection
localField: "store_ids",
foreignField: "_id",
as: "stores"
}
},
{
$project: {
store_ids: 0
}
}
])
You can see a working example here: https://mongoplayground.net/p/ICsEEsmRcg0

Answer 2

We can achieve this with a simple $lookup and with $project.
db.user.aggregate({
"$lookup": {
"from": "store",
"localField": "store_ids",
"foreignField": "_id",
"as": "stores"
}
},
{
"$project": {
store_ids: 0
}
})
$lookup will join with store table on with the store_ids array where the _id matches
$project removes the store_ids array from the resulting objects
Playground