I'm not sure why this is throwing and exception - c

Question

`
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
int main(void)
{
int charCounter = 0;
int intCounter = 0;
int otherCounter = 0;
int ch;
FILE* fp;
fp = fopen("infile.txt", "r");
while ((ch = getc(fp)) != EOF) {
if (isalpha(ch)) {
charCounter += 1;
}
else if (isdigit(ch))
{
intCounter += 1;
}
else
{
otherCounter += 1;
}
}
printf("There were %d char values \n there were %d int values \n there were %d other values ", charCounter, intCounter, otherCounter);
close(fp);
}
`
My code throws an exception after the while statement, and I'm not sure why
I'm new to C so im not sure where to start on this

Answer 1

Not sure what "throwing an exception" means in C. Here are the changes I made:
Added missing include files.
Add error check for fopen().
Used fclose() instead of the incorrect close(). Your compiler should have complained.
Added a newline to printf().
#define _CRT_SECURE_NO_WARNINGS
#include <ctype.h>
#include <errno.h>
#include <string.h>
#include <stdio.h>
int main(void) {
FILE* fp = fopen("infile.txt", "r");
if(!fp) {
printf("%s\n", strerror(errno));
return 1;
}
int charCounter = 0;
int intCounter = 0;
int otherCounter = 0;
int ch;
while ((ch = getc(fp)) != EOF) {
if (isalpha(ch)) {
charCounter += 1;
} else if (isdigit(ch)) {
intCounter += 1;
} else {
otherCounter += 1;
}
}
printf("There were %d char values \n there were %d int values \n there were %d other values\n",
charCounter, intCounter, otherCounter);
fclose(fp);
}
and here is the output with a copy of the above program as "infile.txt":
There were 375 char values
there were 7 int values
there were 232 other values