int main() {
char *cmd1[2] = { "ls", NULL };
char *cmd2[3] = { "grep", "a", NULL };
char *cmd3[3] = { "wc", "-l", NULL };
char *cmd4[5] = { "cat", NULL };
char *cmd5[5] = { "cat", NULL };
int pipe_count = 2;
int pid1, pid2, pid3, pid4, pid5;
int pfd1[2];
int pfd2[2];
pipe(pfd1);
pipe(pfd2);
if ((pid1 = fork()) == 0) {
close(pfd2[0]);
close(pfd2[1]);
close(pfd1[0]);
dup2(pfd1[1], 1);
if (execvp(cmd1[0], cmd1) == -1) {
exit(-1);
}
} else if (pid1 > 0) {
waitpid(pid1, NULL, 0);
}
if ((pid2 = fork()) == 0) {
if (pipe_count >= 2) {
close(pfd1[1]);
close(pfd2[0]);
dup2(pfd1[0], 0);
dup2(pfd2[1], 1);
} else {
close(pfd1[1]);
close(pfd2[0]);
close(pfd2[1]);
dup2(pfd1[0], 0);
}
if (execvp(cmd2[0], cmd2) == -1) {
exit(-1);
}
if (pipe_count == 1) {
printf("\n");
return 0;
}
} else if (pid2 > 0) {
waitpid(pid2, NULL, 0);
}
if (pipe_count >= 2) {
if ((pid3 = fork()) == 0) {
if (pipe_count >= 3) {
close(pfd1[0]);
close(pfd2[1]);
dup2(pfd2[0], 0);
dup2(pfd1[1], 1);
} else {
close(pfd1[0]);
close(pfd1[1]);
close(pfd2[1]);
dup2(pfd2[0], 0);
}
if (execvp(cmd3[0], cmd3) == -1) {
exit(-1);
}
if (pipe_count == 2) {
printf("\n");
}
} else if (pid3 > 0) {
waitpid(pid3, NULL, 0);
}
}
if (pipe_count >= 3) {
if ((pid4 = fork()) == 0) {
close(pfd1[1]);
close(pfd2[0]);
dup2(pfd1[0], 0);
if (pipe_count == 4)
dup2(pfd2[1], 1);
else
close(pfd2[1]);
if (execvp(cmd4[0], cmd4) == -1) {
exit(-1);
}
} else if (pid4 > 0) {
waitpid(pid4, NULL, 0);
}
}
if (pipe_count == 4) {
if ((pid5 = fork()) == 0) {
close(pfd1[0]);
close(pfd2[1]);
dup2(pfd2[0],0);
close(pfd1[1]);
if (execvp(cmd5[0], cmd5) == -1) {
exit(-1);
}
} else if (pid5 > 0) {
waitpid(pid5, NULL, 0);
}
}
return 0;
}
I'm trying to build a shell with piping command. When I input ls | grep a | wc -l for example, I realize that the program is stuck on grep a when I use ps f on the terminal. The shell is not responsive.
When I kill the child process for grep a, I'm again stuck on wc -l and have to kill it on the terminal again.
After killing the processes, no output is printed (My desired output is 2).
Any help would be appreciated.
As already diagnosed in the comments, there are many problems with the original code, including:
The most likely problem is that your parent process isn't closing the pipes before waiting for the child processes to die, so the child processes don't get EOF and don't terminate. (This was one of the problems, but far from the only problem.)
If you have N processes to run, you need N-1 pipes. You have only two pipes here; you've got a lot of work to do before you can make it work with just two pipes. The case of N=2 still has special cases: the first and last processes need to be treated a bit different from the way you treat processes 2..N-1.
You also need to run the processes in a pipeline concurrently. The controlling process should not wait for any of the children until the whole pipeline has been launched. This is because, for example, process P1 may generate so much data that it fills the pipe buffer connecting it to process P2, at which point it will block waiting for P2 to read some data. But if P2 hasn't been launched yet, P1 will never be unblocked, so the pipeline will make no progress. You need to rethink the waiting code as well as the piping code. You end up closing a lot of file descriptors.
You aren't closing enough file descriptors. Rule of thumb: If you dup2() one end of a pipe to standard input or standard output, close both of the original file descriptors from pipe() as soon as possible. In particular, that means before using any of the exec*() family of functions. The rule also applies with either dup() or fcntl() with F_DUPFD.
Note that there is no need to test the return value from the exec*() family of functions. If they succeed, they do not return; if they return, they failed. I think it is good practice, in most cases, to generate an error message before exiting after an exec*() call fails.
Putting those observations together leads to code like this:
/* SO 7412-0402 */
#include <stdio.h>
#include <unistd.h>
#include <sys/wait.h>
#include <stderr.h>
int main(void)
{
char *cmd1[2] = { "ls", NULL };
char *cmd2[3] = { "grep", "a", NULL };
char *cmd3[3] = { "wc", "-l", NULL };
char *cmd4[5] = { "cat", NULL };
char *cmd5[5] = { "cat", NULL };
int pid1, pid2, pid3, pid4, pid5;
int pfd1[2];
int pfd2[2];
int pfd3[2];
int pfd4[2];
err_setarg0("pipe61");
err_setlogopts(ERR_PID | ERR_MILLI);
err_remark("Parent process\n");
if (pipe(pfd1) != 0 ||
pipe(pfd2) != 0 ||
pipe(pfd3) != 0 ||
pipe(pfd4) != 0)
err_syserr("failed to create a pipe: ");
if ((pid1 = fork()) < 0)
err_syserr("failed to fork(): ");
if (pid1 == 0)
{
err_remark("Child process 1\n");
dup2(pfd1[1], 1);
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
execvp(cmd1[0], cmd1);
err_syserr("failed to execute '%s': ", cmd1[0]);
}
if ((pid2 = fork()) < 0)
err_syserr("failed to fork(): ");
else if (pid2 == 0)
{
err_remark("Child process 2\n");
dup2(pfd1[0], 0);
dup2(pfd2[1], 1);
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
execvp(cmd2[0], cmd2);
err_syserr("failed to execute '%s': ", cmd2[0]);
}
if ((pid3 = fork()) < 0)
err_syserr("failed to fork(): ");
else if (pid3 == 0)
{
err_remark("Child process 3\n");
dup2(pfd2[0], 0);
dup2(pfd3[1], 1);
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
execvp(cmd3[0], cmd3);
err_syserr("failed to execute '%s': ", cmd3[0]);
}
if ((pid4 = fork()) < 0)
err_syserr("failed to fork(): ");
else if (pid4 == 0)
{
err_remark("Child process 4\n");
dup2(pfd3[0], 0);
dup2(pfd4[1], 1);
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
execvp(cmd4[0], cmd4);
err_syserr("failed to execute '%s': ", cmd4[0]);
}
if ((pid5 = fork()) < 0)
err_syserr("failed to fork(): ");
else if (pid5 == 0)
{
err_remark("Child process 5\n");
dup2(pfd4[0], 0);
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
execvp(cmd5[0], cmd5);
err_syserr("failed to execute '%s': ", cmd5[0]);
}
close(pfd1[0]); close(pfd1[1]);
close(pfd2[0]); close(pfd2[1]);
close(pfd3[0]); close(pfd3[1]);
close(pfd4[0]); close(pfd4[1]);
int status;
int corpse;
while ((corpse = wait(&status)) > 0)
printf("%d: child %d exited with status 0x%.4X\n", getpid(), corpse, status);
return 0;
}
Notice that the blocks for pid2, pid3 and pid4 are almost the same; the block for pid1 only duplicates a pipe descriptor to stdout, while the block for pid5 only duplicates a pipe descriptor to stdin.
The code for the error reporting routines is available in my SOQ (Stack Overflow Questions) repository on GitHub as files stderr.c and stderr.h in the src/libsoq sub-directory. The err(3) functions on Linux and BSD have similar functionality but different function names.
Here is the output from a sample run (of the program pipe61 compiled from source code pipe61.c shown above.
pipe61: 2022-10-19 23:52:03.833 - pid=50391: Parent process
pipe61: 2022-10-19 23:52:03.834 - pid=50392: Child process 1
pipe61: 2022-10-19 23:52:03.834 - pid=50393: Child process 2
pipe61: 2022-10-19 23:52:03.834 - pid=50394: Child process 3
pipe61: 2022-10-19 23:52:03.834 - pid=50395: Child process 4
pipe61: 2022-10-19 23:52:03.834 - pid=50396: Child process 5
50391: child 50392 exited with status 0x0000
50391: child 50393 exited with status 0x0000
16
50391: child 50394 exited with status 0x0000
50391: child 50395 exited with status 0x0000
50391: child 50396 exited with status 0x0000
Clearly, this code is not easily configurable to deal with 6 or more stages in the pipeline except by cut'n'paste programming, nor is it trivial to remove any stages from the pipeline (variable renaming). For 'real' code, you'd need to use an array-driven approach to avoid unnecessary duplication of code. You'd have the pipe descriptors stored in an array; you'd have the PIDs stored in an array. You'd probably have an array of pointers to the lists of command arguments — three-star programming. And you'd probably use a function to launch the Nth child process.
Related
For my piping function, I am creating two child processes with fork() and attempting to pipe the contents of the first over to the second child process before calling execvp(). I am doing something wrong, as if I do ls -la | more, the output is a vertical list of the files in the directory. I am very new to piping in c (and c) so chances are that it is an overlooked mistake. Any help is appreciated!
void handle_pipe_cmds(char **args1, char **args2){
char ** word1 = parse_space(*args1);
char ** word2 = parse_space(*args2);
int p[2];
pipe(p);
pid_t pid = fork();
if (pid == -1) {
printf("CANNOT FORK!");
} else if (pid == 0) {
dup2(p[1], STDOUT_FILENO);
close(p[1]);
int status = execvp(word1[0], word1);
if (status != 0) {
printf("%s failed\n", word1[0]);
exit(1);
}
exit(0);
} else {
close(p[1]);
wait(NULL);
}
pid = fork();
if (pid == -1) {
printf("CANNOT FORK!");
} else if (pid == 0) {
dup2(p[0], STDIN_FILENO);
close(p[1]);
close(p[0]);
int status = execvp(word2[0], word2);
if (status != 0) {
printf("%s failed\n", word2[0]);
exit(1);
}
exit(0);
} else {
close(p[1]);
close(p[0]);
wait(NULL);
}
}
If I do ls -la | more, the output is a vertical list of the files in the directory.
That is because the ls program is aware of whether its output stream is a terminal or not, and acts different in both cases. On a terminal, it (may) print colorized entries, and multiple items per line; to a pipe, or a file, it will print just one entry per line with no color. See man ls for details.
I'm trying to pipe two different processes to implement the terminal's functionality "|".
I need the new child to execute a command itself, and fork another process to execute a different command using the first process's output, then output the final process's results on the terminal.
Here's my code, I keep the original parent untouched because I need to continue executing the other parts of my program afterwards.
int exec_pipe(char **args, int index, int *i, char**** jobs){
int fd1[2];
pid_t pid, wpid;
int status;
int savedStdOut = dup(1);
int savedStdIn = dup(fileno(stdin));
if (pipe(fd1)==-1)
{
fprintf(stderr, "Pipe Failed" );
return 1;
}
pid = fork();
if (pid < 0)
{
fprintf(stderr, "fork Failed" );
return 1;
}else if (pid == 0)
{
// Child process
close(fd1[0]);
dup2(fd1[1], 1);
printf("%s\n", args[index - 1]);
if (execvp(args[0], args) == -1)
{
printf("command not found\n");
}
int childId = fork();
if(childId < 0){
fprintf(stderr, "fork Failed" );
return 1;
}else if(childId == 0){
// child of child of parent
fdopen(fd1[1], "r");
dup2(fd1[1], savedStdOut);
if (execvp(args[index + 1], args) == -1)
{
printf("command not found\n");
}
exit(EXIT_FAILURE);
}else {
// parent of child of child of parent
do
{
wpid = waitpid(pid, &status, WUNTRACED);
} while (!WIFEXITED(status) && !WIFSIGNALED(status)); // wait for child until it's exited or been killed
fdopen(savedStdIn, "r");
close(fd1[0]);
close(fd1[1]);
}
}else{
// Parent process
do
{
wpid = waitpid(pid, &status, WUNTRACED);
} while (!WIFEXITED(status) && !WIFSIGNALED(status)); // wait for child until it's exited or been killed
}
return 1;
}
I'm getting a "No such file or directory" error with the program ending with exit code 9.
Solved it based on some comments, thanks all!
int fd1[2];
pid_t pid;
// allocate two pipe sets
if (pipe(fd1) < 0)
{
perror("Failed to create pipe.");
return EXIT_FAILURE;
}
// launch first child process.
if ((pid = fork()) < 0)
{
perror("Failed to fork child(1)");
return EXIT_FAILURE;
}
if (pid == 0)
{
// child
// stdout = fd1(write)
if(strcmp(args[0], args[index - 1]) == 0)
{
dup2(fd1[WRITE], STDOUT_FILENO);
close(fd1[READ]);
close(fd1[WRITE]);
execlp(args[0], args[0], (char*) NULL);
fprintf(stderr, "failed to execute '%s'\n", args[0]);
exit(1);
}else{
dup2(fd1[WRITE], STDOUT_FILENO);
close(fd1[READ]);
close(fd1[WRITE]);
execlp(args[0], args[0], args[index - 1], (char*) NULL);
fprintf(stderr, "failed to execute '%s'\n", args[0]);
exit(1);
}
}else
{
// parent
// fork once more.
if ((pid = fork()) < 0)
{
perror("Failed to fork child(2)");
return EXIT_FAILURE;
}
if (pid == 0)
{
// child of child
// stdin = fd1(read)
dup2(fd1[READ], STDIN_FILENO);
close(fd1[WRITE]);
close(fd1[READ]);
execlp(args[index + 1], args[index + 1], (char*) NULL);
fprintf(stderr, "failed to execute '%s'\n", args[index + 1]);
exit(1);
}else{
int status;
close(fd1[READ]);
close(fd1[WRITE]);
waitpid(pid, &status, 0);
}
}
I'm trying to simulate a unix shell in a C program and it's still in the beginning and working for at most two pipes. I have a vector of commands (char *com[3][3]), which were separated considering the character "|", but my question is how to proceed to more pipes in a for loop? In the follow the current implementation, I'm trying to execute 3 commands separeted by pipes:
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <sys/types.h>
int main(int argc, char **argv){
//Vector with positions of pipes found, position 0 reserved for the total amount of commands.
char* com[3][3] = { { "/bin/ls", "-la", 0 },
{ "/bin/grep", ".", 0}, { "/usr/bin/wc", "-l", 0 }};
//EXECUTE COMMANDS
pid_t fork1, fork2, fork3;
int fd1[2], fd2[2];
if(pipe(fd1) < 0){
perror("pipe1");
}
if(pipe(fd2) < 0){
perror("pipe2");
}
//COMMAND 1
fork1 = fork();
if(fork1 == 0){
dup2(fd1[1], STDOUT_FILENO);
close(fd1[0]);
close(fd2[0]);
close(fd2[1]);
execvp(com[0][0], com[0]);
perror("execvp 1");
exit(EXIT_FAILURE);
}
//COMMAND 2
fork2 = fork();
if(fork2 == 0){
dup2(fd1[0], STDIN_FILENO);
dup2(fd2[1], STDOUT_FILENO);
close(fd1[1]);
close(fd2[0]);
execvp(com[1][0], com[1]);
perror("execvp 2");
exit(EXIT_FAILURE);
}
//COMMAND 3
fork3 = fork();
if(fork3 == 0){
dup2(fd2[0], STDIN_FILENO);
close(fd2[1]);
close(fd1[0]);
close(fd1[1]);
execvp(com[2][0], com[2]);
perror("execvp 3");
exit(EXIT_FAILURE);
}
close(fd1[0]);
close(fd1[1]);
close(fd2[0]);
close(fd2[1]);
waitpid(-1, NULL, 0);
waitpid(-1, NULL, 0);
waitpid(-1, NULL, 0);
return 0;
}
How do I make to com[n][3], in a for loop?
"To iterate is human, to recurse is divine" -- Anon.
I'd attack this with a recursive approach. This is one of those very rare occasions when being a Three Star programmer is almost justified. ;)
This is completely untested, but should get you pointed in the correct direction.
// You'll need to rearrange your command strings into this three dimensional array
// of pointers, but by doing so you allow an arbitrary number of commands, each with
// an arbitrary number of arguments.
int executePipe(char ***commands, int inputfd)
{
// commands is NULL terminated
if (commands[1] == NULL)
{
// If we get here there's no further commands to execute, so run the
// current one, and send its result back.
pid_t pid;
int status;
if ((pid = fork()) == 0)
{
// Set up stdin for this process. Leave stdout alone so output goes to the
// terminal. If you want '>' / '>>' redirection to work, you'd do that here
if (inputfd != -1)
{
dup2(inputfd, STDIN_FILENO);
close(inputfd);
}
execvp(commands[0][0], commands[0]);
perror("execvp");
exit(EXIT_FAILURE);
}
else if (pid < 0)
{
perror("fork");
exit(EXIT_FAILURE);
}
waitpid(pid, &status, 0);
return status;
}
else
{
// Somewhat similar to the above, except we also redirect stdout for the
// next process in the chain
int fds[2];
if (pipe(fds) != 0)
{
perror("pipe");
exit(EXIT_FAILURE);
}
pid_t pid;
int status;
if ((pid = fork()) == 0)
{
// Redirect stdin if needed
if (inputfd != -1)
{
dup2(inputfd, STDIN_FILENO);
close(inputfd);
}
dup2(fds[1], STDOUT_FILENO);
close(fds[1]);
execvp(commands[0][0], commands[0]);
perror("execvp");
exit(EXIT_FAILURE);
}
else if (pid < 0)
{
perror("fork");
exit(EXIT_FAILURE);
}
// This is where we handle piped commands. We've just executed
// commands[0], and we know there's another command in the chain.
// We have everything needed to execute that next command, so call
// ourselves recursively to do the heavy lifting.
status = executePipe(++commands, fds[0]);
// As written, this returns the exit status of the very last command
// in the chain. If you pass &status as the second parameter here
// to waitpid, you'll get the exit status of the first command.
// It is left as an exercise to the reader to figure how to get the
// the complete list of exit statuses
waitpid(pid, NULL, 0);
return status;
}
}
To use this, call it initially with the commands array set up as described, and inputfd initially -1.
If you want to handle < type redirection, you probably want to check for inputfd == -1 at the very top, do redirection if requested and replace inputfd with the appropriate value before entering the remainder of the body.
I have written the below method to fork and execute commands separated by multiple pipes( test with : ls -lrt | grep "check" | wc -l . However it is not resulting in any output, could any one please spot my mistake. Thanks.
void execCmd (pInfo *info)
{
int i, j, k, m;
struct comType *comm, *comm1, *comm2;
if(info->noOfPipes > 2)
{
// DOES NOT WORK
printf("Start\n");
comm=&(info->cArr[0]);
comm2=&(info->cArr[(info->ppNum)-1]);
int fds[2];
pipe(fds);
pid_t pid = fork();
if(pid == -1)
{
perror("fork failed");
exit(1);
}
if(pid == 0)
{
printf("1st child execution here\n");
close(fds[0]);
dup2(fds[1], STDOUT_FILENO);
close(fds[1]);
execvp(comm->cmd,comm->parms);
}
for (k=1;k<=((info->ppNum)-1);k++)
{
printf("For loop executionn number %d",k);
comm1=&(info->cArr[k]);
printf ("comm 1 : %s\n",comm1->cmd);
pid = fork();
if(pid == -1)
{
perror("fork failed");
exit(1);
}
if(pid == 0)
{
//2nd to n-1 child process
dup2(fds[0], STDIN_FILENO);
close(fds[0]);
dup2(fds[1], STDOUT_FILENO);
close(fds[1]);
execvp(comm1->cmd,comm1->parms);
}
wait(NULL);
}
pid = fork();
if(pid == -1)
{
perror("fork failed");
exit(1);
}
if(pid == 0)
{
//nth child process
printf("Last child execution\n");
close(fds[1]);
dup2(fds[0], STDIN_FILENO);
close(fds[0]);
execvp(comm2->cmd,comm2->parms);
}
close(fds[0]);
close(fds[1]);
wait(NULL);
wait(NULL);
}
}
This following code should give you an idea how to implement the pipelining:
#define STDIN 0
#define STDOUT 1
void exec_cmd(struct comType cmd) {
execvp(cmd->cmd, cmd->params);
}
void pipeCmds(struct comType* cmds) {
int fd[cmds_length * 2] = {0};
pid_t pid = 0;
for (int i = 0; i < cmds_length; i++) {
if (pid = fork() == 0) {
//child: make this cmd's output the other cmd's input
pipe(fd + (2*i) );
close(STDOUT);
dup(fd[i]);
if(i > 0) {
close(STDIN);
dup(fd[i-1]);
}
exec_cmd(cmds[i]);
close(fd[i]);
}
}
}
Note that the main idea is that each command is executed in a separate process (via fork) and the output goes to the next command's input rather than to the default stdout(with file descriptor 1), and the same for the input - stdin (file descriptor 0).
I want to set up 2 pipes in my program. I have 1 pipe working fine, but I don't know where to place the second pipe.
The pseudo code of my setup is shown below,
Here is it with curly braces sorry about that
//the first pipe:
pipe(pipe1)
//the second pipe:
pipe(pipe2)
pid = fork()
if(pid == 0) {
dup2(pipe1[1], 1)
close(pipe1[0])
execvp(beforepipe)
}
if(pid > 0) { //everything below is in here
pid2 = fork()
if(pid2 == 0){
//pipe1
dup2(pipe1[0],0)
dup2(out,1)
close(pipe1[1])
execvp(afterpipe)
//pipe2 does not work might need to be placed in different area
dup2(pipe1[1],1)
close(pipe1[0])
execvp(beforepipe1)
}
if(pid2 > 0){
close(pipe[0])
close(pipe[1])
wait() //this is an infinite for loop
pid3 = fork()
if(pid3 == 0){
dup2(pipe2[0],0)
dup2(out,1)
close(pipe2[1])
execvp(afterpipe2)
}
if(pid3 > 0) {
close(pipe2[0])
close(pipe2[1])
wait()
}
}
The position of the second pipe is in the wrong place or the code is altogether wrong.
Any suggestions?
Your main problem is that you are not closing anywhere near enough file descriptors. Given a file input1 in the current directory containing your string "eschew obfuscation\", this code works for me (but note how many file descriptors have to be closed!).
Rule of thumb: if a pipe is dup2()d or dup()d to standard input or output, close both file pipe file descriptors.
Example code (with debug tracing in place):
#include <unistd.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
/* command pipeline: cat input1 | tr a-z A-Z | tr \\ q */
int main(void)
{
int pipe1[2];
int pipe2[2];
pid_t pid1;
char *cmd1[] = { "cat", "input1", 0 };
char *cmd2[] = { "tr", "a-z", "A-Z", 0 };
char *cmd3[] = { "tr", "\\", "q", 0 };
if (pipe(pipe1) != 0 || pipe(pipe2) != 0)
{
perror("pipe failed");
return 1;
}
pid1 = fork();
if (pid1 < 0)
{
perror("fork 1 failed");
return 1;
}
if (pid1 == 0)
{
/* Child 1 - cat */
dup2(pipe1[1], 1);
close(pipe1[0]);
close(pipe1[1]);
close(pipe2[0]);
close(pipe2[1]);
execvp(cmd1[0], cmd1);
perror("failed to execute cmd1");
return 1;
}
printf("pid 1 = %d\n", pid1);
fflush(stdout);
pid_t pid2 = fork();
if (pid2 < 0)
{
perror("fork 2 failed");
return 1;
}
if (pid2 == 0)
{
/* Child 2 - tr a-z A-Z */
dup2(pipe1[0], 0);
dup2(pipe2[1], 1);
close(pipe1[0]);
close(pipe1[1]);
close(pipe2[0]);
close(pipe2[1]);
execvp(cmd2[0], cmd2);
perror("failed to execute cmd2");
return 1;
}
printf("pid 2 = %d\n", pid2);
fflush(stdout);
pid_t pid3 = fork();
if (pid3 < 0)
{
perror("fork 3 failed");
return 1;
}
if (pid3 == 0)
{
/* Child 3 - tr \\ q */
dup2(pipe2[0], 0);
close(pipe1[0]);
close(pipe1[1]);
close(pipe2[0]);
close(pipe2[1]);
execvp(cmd3[0], cmd3);
perror("failed to execute cmd3");
return 1;
}
printf("pid 3 = %d\n", pid3);
fflush(stdout);
/* Parent - wait for the kids to all die */
close(pipe1[0]);
close(pipe1[1]);
close(pipe2[0]);
close(pipe2[1]);
pid_t corpse;
int status;
while ((corpse = wait(&status)) > 0)
printf("Child %d died status 0x%.4X\n", corpse, status);
return 0;
}
execvp(afterpipe)
//pipe2 does not work might need to be placed in different area
dup2(pipe1[1],1)
close(pipe1[0])
execvp(beforepipe1)
I think the execvp() didnot return. So the code below the execvp() is irrelevent.