Linux shuts down after compiling basic children process - c

In this simple C code, I am trying to create 10 children. Then do some work (such as printing the time) in them individually. Then I try to kill all of them in parent process. You will easily understand the code below. The problem is that, whenever I run this, first it gives the various outputs from children then Linux shuts down. Then I start from passing user password and everything is closed. Why this happens?
#include <stdio.h>
#include <unistd.h>
#include <sys/time.h>
#include <signal.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <signal.h>
#include <stdlib.h>
#include <time.h>
int main() {
pid_t pids[10];
int i;
int n= 10;
for (i= 0; i<n; ++i) {
if ((pids[i] = fork()) <0) {
perror("fork");
abort();
}
else if (pids[i] == 0) {
struct timeval tv;
time_t t;
struct tm*info;
char buffer[64];
gettimeofday(&tv,NULL);
t = tv.tv_sec;
info = localtime(&t);
sleep(1);
printf("CHILD PID: %d and the time is %s\n",getpid(),asctime(info));
}
}
int status;
pid_t pid;
sleep(5);
while (n >0) {
pid = wait(&status);
kill((long)pid, SIGTERM);
printf("CHILD %d killed.",pid);
--n;
}
}

In process created by fork() all variables have the same value as before fork. After fork in this your code
for (i= 0; i<n; ++i) {
if ((pids[i] = fork()) <0) {
perror("fork");
abort();
}
else if (pids[i] == 0) {
...
}
}
i in child process is the same as it was in parent before fork, so for loop continue to execute and spawn a lot of grand children processes.
After loop is executed all spawned processes call wait(). Processes which are spawned on last iteration (with i==9) have no children, so wait() indicates error by returning -1 (and errno==ECHILD). Then you call kill() with pid==-1, which is:
If pid equals -1, then sig is sent to every process for which the calling process has permission to send signals, except for process 1 (init)
If you want child processes to terminate by themself then you should exit explicitly, e.g. with _exit() function. In this case you don't need to send TERM signal:
int main(void)
{
pid_t pids[10];
int i;
int n = 10;
for (i = 0; i<n; ++i)
{
if ((pids[i] = fork()) < 0)
{
perror("fork");
abort();
// abort() never return, "else" is not needed
}
if (pids[i] == 0)
{
struct timeval tv;
time_t t;
struct tm*info;
gettimeofday(&tv,NULL);
t = tv.tv_sec;
info = localtime(&t);
sleep(1);
printf("CHILD PID: %d and the time is %s\n",getpid(),asctime(info));
_exit(0); // terminate process explicitly
}
}
int status;
pid_t pid;
sleep(5);
while (n > 0)
{
pid = wait(&status);
// No kill needed for already exited process
// kill((long)pid, SIGTERM);
if (pid == -1)
{
perror("wait");
abort();
} else {
printf("CHILD %d killed.\n", pid);
}
--n;
}
}
If you want to terminate child processes from parent process then children should wait until terminated, but you should send signal before waiting for child process termination:
int main(void)
{
pid_t pids[10];
int i;
int n = 10;
for (i = 0; i<n; ++i)
{
if ((pids[i] = fork()) < 0)
{
perror("fork");
abort();
// abort() never return, "else" is not needed
}
if (pids[i] == 0)
{
struct timeval tv;
time_t t;
struct tm*info;
gettimeofday(&tv,NULL);
t = tv.tv_sec;
info = localtime(&t);
sleep(1);
printf("CHILD PID: %d and the time is %s\n",getpid(),asctime(info));
// wait until terminated
for (;;)
pause();
}
}
int status;
pid_t pid;
sleep(5);
for (i = 0; i<n; ++i) {
if (kill(pids[i], SIGTERM) == -1) {
perror("kill");
}
}
while (n--)
{
pid = wait(&status);
if (pid == -1)
{
perror("wait");
abort();
} else {
printf("CHILD %d killed.\n", pid);
}
}
}

Related

How do I make it so that processes are created parallel to each other rather than one after another?

I need help in modifying this code. Right now, it creates a process, and then waits for its termination. After which, another process is created, and then it waits for its termination. I want to modify it so that it creates both processes at the same time and executes them parallel to each other. The code is:
#include <sys/types.h>
#include <stdio.h>
int main(int argc, char * argv[]) {
pid_t pid;
int status;
pid = fork();
if (pid != 0) {
while (pid != wait( & status));
} else {
sleep(5);
exit(5);
}
pid = fork();
if (pid != 0) {
while (pid != wait( & status));
} else {
sleep(1);
exit(1);
}
}
Here's code that should do the job:
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <unistd.h>
int main(void)
{
pid_t pid = fork();
if (pid != 0)
printf("Child 1 PID = %d\n", pid);
else
{
sleep(5);
exit(5);
}
pid = fork();
if (pid != 0)
{
printf("Child 2 PID = %d\n", pid);
int corpse;
int status;
while ((corpse = wait(&status)) > 0)
printf("Child %d exited with status 0x%.4X\n", corpse, status);
}
else
{
sleep(1);
exit(1);
}
return 0;
}
One time when I ran it, I got the output:
Child 1 PID = 49582
Child 2 PID = 49583
Child 49583 exited with status 0x0100
Child 49582 exited with status 0x0500
If you preferred, you could move the wait() loop and its variable declarations after the if structures and immediately before the return 0; at the end. That would give you better symmetry. You could even wrap up the child creation phase into a function called twice:
static void procreate(int kidnum, int naptime)
{
int pid = fork();
if (pid != 0)
printf("Child %d PID = %d (nap time = %d)\n", kidnum, pid, naptime);
else
{
sleep(naptime);
exit(naptime);
}
}
and then in main() you'd just have two calls to procreate() and the wait loop:
int main(void)
{
procreate(1, 5);
procreate(2, 1);
int corpse;
int status;
while ((corpse = wait(&status)) > 0)
printf("Child PID %d exited with status 0x%.4X\n", corpse, status);
return 0;
}

fork() 4 children in a loop

The goal is to try and fork 4 children in a loop, but I'm not sure how to properly do that. This is what I have so far. I tried to draw it out and I think I'm not waiting to reap the child properly. And I create like 2 children every iteration. So, 8 children in total.
void main() {
int i = 0;
pid_t pid;
int status;
for(i = 0; i < 4; i++) {
pid = fork();
if(pid == 0) {
/* Child Process */
fork();
exit(0);
} else {
/* Parent Process */
wait(&status);
printf("At i = %d, process %d is terminated.\n", i, pid);
}
}
}
Creating four children processes from the same parent process can be achieved by forking once on each iteration of the for loop:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
int main() {
for (int i = 0; i < 4; i++) {
pid_t pid = fork();
if (pid == 0)
exit(0); // child process
// parent process
wait(NULL);
printf("At i = %d, process %d is terminated.\n", i, pid);
}
}
However, you probably want the parent process to wait for the children after it has created all of the four children, because you usually want the children to do something before exiting and concurrently with the other children:
int main() {
// create the four children processes
for (int i = 0; i < 4; i++) {
pid_t pid = fork();
if (pid == 0) {
// child process
// ... do some stuff ...
exit(0);
}
}
// wait for the four children processes to finish
for (int i = 0; i < 4; i++) {
pid_t pid = wait(NULL);
printf("Process %d is terminated.\n", pid);
}
}

Lost signals from child to parent

I'm creating several child processes which send a signal to their parent process and die. I simply count them. But I never get the right count. Some signals never get caught by the handler.
How should I code this?
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
int ended = 0;
void handler(int sig){
ended++;
}
int main(int argc, char **argv){
int i;
pid_t pid, ppid;
if (signal(SIGUSR1, handler) < 0) {
fprintf(stderr, "signal failed.\n");
exit (-1);
}
ppid = getpid();
for (i = 0; i < 50; i++){
if ((pid = fork()) < 0){
fprintf(stderr, "fork failed.\n");
exit(-1);
}
if (pid == 0){
kill(ppid, SIGUSR1);
exit(0);
}
}
while (wait(NULL) > 0);
printf("ended = %d\n", ended);
return 0;
}
The output for this program is sometimes 47, others 39... but never 50
The problem here is that a signal acts as a hardware interruption where your handler function would be the ISR (Interrupt Service Routine). Then if multiple signals of the same value happens "at the same time" linux kernel treat them as only one signal. Signal are not designed to be used in this manner. A signal should be used to inform of the state of a process to another. To achieve communications between processes you should use IPC (InterProcess Communications) mechanisms such as queue, sockets, or pipes.
Thanks,
I found the problem can be solved using Real Time Signals. Just changing SIGUSR1 with SIGRTMIN. Real Time Signals are queued (http://man7.org/linux/man-pages/man7/signal.7.html).
Are there any negative side effects in this solution?
it was working..
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
int ended = 0;
void handler(int sig)
{
ended++;
}
int main(int argc, char **argv)
{
int i;
pid_t pid, ppid;
if (signal(SIGUSR1, handler) < 0)
{
fprintf(stderr, "signal failed.\n");
exit (-1);
}
ppid = getpid();
for (i = 0; i < 50; i++)
{
if ((pid = fork()) < 0)
{
fprintf(stderr, "fork failed.\n");
exit(-1);
}
if (pid == 0)
{
kill(ppid, SIGUSR1);
exit(0);
}
}
while (wait(NULL) > 0);
printf("ended = %d\n", ended);
return 0;
}

SIGUSR1 - kill sigaction in C

In the C language create a program that creates two processes and connects them via pipe.
The first descendant redirects its' stdout into the pipe and writes (space separated) pairs of random numbers into it (function rand). Delay the output of the numbers by 1 second.
The second descendant redirects the pipe output to it's stdin, redirects it's stdout into a file called out.txt in the current directory.
The parent process waits 5 seconds and then sends SIGUSR1 to the first process (number generator). This should perform a correct termination of both processes. It waits for the sub-processes to terminate (wait function) and terminates itself.
I really need help with:
The first descendant has to treat the SIGUSR1 signal (sigaction function) and in case of receiving such signal it prints a string “TERMINATED” to it's stderr and terminates.
FILE *file;
file = fopen(NAZEV, "a+");
int pipefd[2];
pipe(pipefd);
pid_t pid1;
int retcode;
pid1=fork();
if(pid1 == 0) // child 1
{
close(roura[0]);
printf("child1...\n");
dup2(roura[1], STDOUT_FILENO);
int i = 0;
while(i < 6)
{
i++;
int a = rand();
int b = rand();
sleep(1);
printf("%d %d\n", a, b);
}
close(roura[1]);
exit(45);
}
else if (pid1 < 0)
{
printf("Fork selhal\n");
exit(2);
}
else
{
pid_t pid2;
pid2 = fork();
if (pid2 == 0) //child 2
{
close(roura[1]);
dup2(roura[0], STDIN_FILENO);
printf("child2...\n");
int i = 0;
while(i < 5)
{
i++;
int c;
int d;
scanf("%d %d", &c, &d);
printf("%d %d\n", c, d);
fprintf(file,"%d %d\n", c, d);
}
printf("child2 end\n");
exit(0);
}
else if (pid2 < 0)
{
printf("Fork error\n");
exit(2);
}else
{
sleep(5);
kill(pid1, SIGUSR1);
wait(&pid1); //wait for child 1
wait(&pid2); //wait for child 2
printf("parent end\n");
exit(0);
}
}
exit(0);
}
Adda signal handler to sigusr1 that prints to stderr and exits.
Try this, adapted to compile in cygwin:
#include <stdio.h>
#include <signal.h>
#include <stdio.h>
#include <stdlib.h>
#ifndef STDIN_FILENO
# define STDIN_FILENO 0
#endif
#ifndef STDOUT_FILENO
# define STDOUT_FILENO 1
#endif
void sig_handler(){
fprintf(stderr,"TERMINATED");
exit(0);
}
void main(int argc, char ** argv){
FILE *file;
file = fopen("NAZEV", "a+");
int pipefd[2];
int roura[2] ;
pipe(pipefd);
pid_t pid1;
int retcode;
pid1=fork();
if(pid1 == 0) // child 1
{
close(roura[0]);
printf("child1...\n");
dup2(roura[1], STDOUT_FILENO);
if (signal(SIGUSR1, sig_handler) == SIG_ERR){
printf("\ncan't catch SIGUSR1\n");
exit(13);
}
int i = 0;
while(i < 6)
{
i++;
int a = rand();
int b = rand();
sleep(1);
printf("%d %d\n", a, b);
}
close(roura[1]);
exit(45);
}
else if (pid1 < 0)
{
printf("Fork selhal\n");
exit(2);
}
else
{
pid_t pid2;
pid2 = fork();
if (pid2 == 0) //child 2
{
close(roura[1]);
dup2(roura[0], STDIN_FILENO);
printf("child2...\n");
int i = 0;
while(i < 5)
{
i++;
int c;
int d;
scanf("%d %d", &c, &d);
printf("%d %d\n", c, d);
fprintf(file,"%d %d\n", c, d);
}
printf("child2 end\n");
exit(0);
}
else if (pid2 < 0)
{
printf("Fork error\n");
exit(2);
}else
{
sleep(5);
kill(pid1, SIGUSR1);
wait(&pid1); //wait for child 1
wait(&pid2); //wait for child 2
printf("parent end\n");
exit(0);
}
}
exit(0);
}
You need to register a signal handler using sigaction if you want to override the default action. For SIGUSR1, the default action is to terminate the process.

Controlling multiple children, handling sigchld

Let's say i have a main C program that has to wait for sigchld of two children, and that these two sons have to do two separate task, for example one should write "1", and the other
one should write "2" ,wait 2 seconds and then terminate, now how should I write the code so that the father write his children's pid only after the two sons ends with sigchld? It's obvious that i'm missing some theory, if you look at my code you will understand what my issue is.
After that i'll have to force the execution of the second son before the first son, suggestion?
#include <stdio.h>
#include <signal.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, char **argv)
{
int pids[2], cpid, i, status;
char buff[200];
for(i=0; i < 2; i++)
{
if ((pids[i] = fork()) < 0)
perror("errno");
else
{
//child
if (pids[i] == 0)
{
if(i == 0)
write(1,"1\n", 2);
else
{
sleep(2);
write(1,"2\n", 2);
}
return 0;
}
}
}
for(i = 0; i < 2; i++)
{
cpid = waitpid(pids[i], &status, 0);
if (WTERMSIG(status))
printf("status:%d , pid terminated:\n", status,cpid);
else
printf("error: not exited with a signal\n");
}
return 0;
}
If the last for loop is changed as:
for(i = 0; i < 2; i++)
{
cpid = waitpid(pids[i], &status, 0);
if (WIFEXITED(status))
printf("status:%d , pid %d terminated normally :\n", status,cpid);
else if (WTERMSIG(status))
printf("status:%d , pid %d terminated by signal:\n", status,cpid);
else
printf("error: not exited with a signal\n");
}
Then the thing works better, as there is no signal to terminate the childs.

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