all functions being skipped and code is running without them - c

Question

I have fixed my code style and have updated what it looks like, but it's skipping all the rounds and inputs I want to make
If I formatted the returns wrong(Which is what I'm thinking), or I didn't nest my functions properly, those are the only issues I can imagine would be wrong
#define ROUNDS 3
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
int main()
{
//Greets the user at the start of the round
void greeting();{
printf("Welcome to the Toothpick Game!\n");
printf("Here are the rules.\n");
printf("There are currently 31 toothpicks on the table.\n");
printf("You and I will each get a turn to pick either 1, 2, or 3 toothpick off the table.\n");
printf("The player that gets to puck the last toothpicks looses the game!\n");
printf("Sounds easy right? Well lets see if you can beat me!\n");
printf("Ready to play?... Here we go!\n");
} //display welcome message to user
for(int x = 0; x < ROUNDS; ++x)
{
int result = playRound(x + 1); //call playRound and assign result the value function returns
void winnerAnnouncment(int user);{//overall winner of round announcement
}
}
printf("********************************************************\n");
printf("Thank you for playing!\n");
return 0;
}
int playRound(int round)
{
int toothpicks = 31; //number of toothpicks to start with
int winner, taken, choice, leftover;
printf("Welcome to a new round %d!\n", round);
printf("You may go first!\n");
int leftOnTable(int toothpicks, int taken);{ //calculate number of toothpicks left
toothpicks = toothpicks - taken;
while(toothpicks != 0)//loop to control playing of the game
{
int humanPick();{ //retrieve the user's guess
int userchoice;
printf("How many toothpicks do you want to take? ");
scanf("%d", &taken);
printf("Okay... You took %d off the table", taken);
if (toothpicks = 1)
winner = 0;
int computerPick(int choice, int leftover);{ //computer makes its pick
if (toothpicks > 4){//Caculates what the computer will take based off of the users choice
choice = 4 - userchoice;
toothpicks = toothpicks - choice;
leftover = choice;
printf("I am taking %d toothpicks off the table.", choice);
}
if(toothpicks = 2 || 3 || 4)//calculates how many toothpicks the computer will take to leave one left on the table
if (toothpicks == 2){
choice = toothpicks - 1;
leftover = 1;
printf("I am taking %d toothpicks off the table.", choice);
}
if (toothpicks == 3){
choice = toothpicks - 1;
printf("I am taking %d toothpicks off the table.", choice);
}
if (toothpicks == 4){
choice = toothpicks - 1;
leftover = 1;
printf("I am taking %d toothpicks off the table.", choice);
}
if (toothpicks = 1){
choice = 1;
leftover = 0;
toothpicks = leftover;
winner = 1;
printf("I will take the last toothpick.");
}
}
}
return toothpicks;
}
}
return round;
}

Answer 1

Multiple times throughout the code used is an assignment operator = instead of the == likely intended.
In addition, the following:
userchoice is never initialized to a value.
Nested functions aren't supported by the C standard.
Numerous semicolons are found before the function definitions (e.g. void greeting();{...}).
This declares, but doesn't define the function. The following is code that executes in a new code block (new scope).
Incorrect || operator usage in conditionals (Broken:toothpicks == 2 || 3 || 4 Fixed: toothpicks == 2 || toothpicks == 3 || toothpicks == 4).
This condition would always be true. The conditional toothpicks == 2 is tested, if this proves untrue the conditional 3 is tested. 3 is true, and so this condition is always true.
The functions leftOnTable and greeting are never called.
Additional unused variables include: result and winner
Other logical errors may exist.
This should answer, if only partially, why the program isn't working as expected. Perhaps with more information about why nested functions are being used and the intended functionality of the program, I could provide a working code fix to every present issue.