Reproduce the shell pipe command - c

I have a school project which consists of reproducing the shell pipe command between two commands that the operator will choose as it pleases.
./pipex infile "ls -l" "wc -l" outfile
should be equivalent to
< infile ls -l | wc -l > outfile
Roles of my find_path function:
extract the contents of PATH from the envp
use split() to delimit the paths according to ":" and store them in a double pointer
use strjoin() to append a "/" to the end of each path, and add the user command
test each path with access() then return the valid path
char *find_path(char *cmd, char **envp)
{
char **array_of_paths;
char *path_ultime;
int i;
char *temp;
i = 0;
while (ft_strnstr(envp[i], "PATH=", 5) == 0)
i++;
array_of_paths = ft_split(envp[i] + 5, ':');
i = 0;
while (array_of_paths[i])
{
temp = ft_strjoin(array_of_paths[i], "/");
path_ultime = ft_strjoin(temp, cmd);
free(temp);
if (access(path_ultime, F_OK | X_OK) == 0)
return (path_ultime);
i++;
}
return (0);
}
My main takes care of:
split the argv[2] and the argv[3] with a space as delimiter, to keep only the command "ls" or "wc", and not the options
classic stuff like pipe(), fork(), execve() …
int main(int argc, char *argv[], char **envp)
{
(void)argc;
pid_t pid1;
pid_t pid2;
int fd[2];
char **cmd_and_options1;
char **cmd_and_options2;
char *path_ultime1;
char *path_ultime2;
cmd_and_options1 = ft_split(argv[2], ' ');
cmd_and_options2 = ft_split(argv[3], ' ');
path_ultime1 = find_path(cmd_and_options1[0], envp);
path_ultime2 = find_path(cmd_and_options2[0], envp);
if (pipe(fd) == -1)
return (1);
pid1 = fork();
if (pid1 == -1)
return (1);
if (pid1 == 0) // First child
{
dup2(fd[1], STDOUT_FILENO);
close(fd[0]);
close(fd[1]);
execve(path_ultime1, cmd_and_options1, envp);
}
pid2 = fork();
if (pid2 == -1)
return (1);
if (pid2 == 0) // Second child
{
dup2(fd[0], STDIN_FILENO);
close(fd[0]);
close(fd[1]);
execve(path_ultime2, cmd_and_options2, envp);
}
close(fd[0]);
close(fd[1]);
waitpid(pid1, NULL, 0);
waitpid(pid2, NULL, 0);
return (0);
}
A friend told me that I lacked the management of the input and output file (argv[1] and argv[4]) that the operator will enter but I don't really understand what that means.
I know I have to use open() somewhere...
Can you give me some clues?

Related

Reproduce the pipe command

I have a school project which consists of reproducing the shell pipe command between two commands that the operator will choose as it pleases.
./pipex infile "ls -l" "wc -l" outfile
should be equivalent to
< infile ls -l | wc -l > outfile
Here is my way of doing it:
void first_child(char **argv, char **envp, int pipefd[2], int fd[2])
{
char **cmd_and_options1;
char *path_ultime1;
int pid1;
pipefd[0] = open(argv[1], O_RDONLY);
pid1 = fork();
if (pid1 == -1)
error();
if (pid1 == 0)
{
dup2(fd[1], STDOUT_FILENO);
dup2(pipefd[0], STDIN_FILENO);
close(pipefd[0]);
close(fd[1]);
execve(path_ultime1, cmd_and_options1, envp);
}
}
void second_child(char **argv, char **envp, int pipefd[2], int fd[2])
{
char **cmd_and_options2;
char *path_ultime2;
int pid2;
pipefd[1] = open(argv[4], O_CREAT | O_WRONLY | O_TRUNC, 0777);
pid2 = fork();
if (pid2 == -1)
error();
if (pid2 == 0)
{
dup2(fd[0], STDIN_FILENO);
dup2(pipefd[1], STDOUT_FILENO);
close(pipefd[1]);
close(fd[0]);
execve(path_ultime2, cmd_and_options2, envp);
}
}
int main(int argc, char *argv[], char **envp)
{
int pipefd[2];
int fd[2];
char **cmd_and_options1;
char **cmd_and_options2;
char *path_ultime1;
char *path_ultime2;
(void)argc;
cmd_and_options1 = ft_split(argv[2], ' ');
cmd_and_options2 = ft_split(argv[3], ' ');
path_ultime1 = find_path(cmd_and_options1[0], envp);
path_ultime2 = find_path(cmd_and_options2[0], envp);
if (pipe(fd) == -1)
error();
first_child(&argv[1], envp, &pipefd[0], &fd[0]);
second_child(&argv[4], envp, &pipefd[1], &fd[1]);
close(pipefd[0]);
close(pipefd[1]);
close(fd[0]);
close(fd[1]);
waitpid(-1, NULL, 0);
waitpid(-1, NULL, 0);
return (0);
}
Roles of my find_path function:
extract the contents of PATH from the envp
use split() to delimit the paths according to ":" and store them in a double pointer
use strjoin() to append a "/" to the end of each path, and add the user command
test each path with access() then return the valid path
char *find_path(char *cmd, char **envp)
{
char **array_of_paths;
char *path_ultime;
int i;
char *temp;
i = 0;
while (ft_strnstr(envp[i], "PATH=", 5) == 0)
i++;
array_of_paths = ft_split(envp[i] + 5, ':');
i = 0;
while (array_of_paths[i])
{
temp = ft_strjoin(array_of_paths[i], "/");
path_ultime = ft_strjoin(temp, cmd);
free(temp);
if (access(path_ultime, F_OK | X_OK) == 0)
return (path_ultime);
i++;
}
return (0);
}
When I put all my code in the main(), my program worked.
But when I try to separate it into functions it doesn't work anymore and I don't understand what the problem is.

Simulating multi pipes "|" with a loop in c

I'm trying to simulate Unix shell multi pipes in c and I found a source code of a function doing the same thing but I didn't understand it well, if you can please explaint to me how's works, I know that pipe fd[2] creates fd[0] read input, and fd[1] write input as well dup2 close selected FD and duplicate it to FD through the pipe.
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
/*
* loop over commands by sharing
* pipes.
*/
static void
pipeline(char ***cmd)
{
int fd[2];
pid_t pid;
int fdd = 0; /* Backup */
while (*cmd != NULL) {
pipe(fd); /* Sharing bidiflow */
if ((pid = fork()) == -1) {
perror("fork");
exit(1);
}
else if (pid == 0) {
dup2(fdd, 0);
if (*(cmd + 1) != NULL) {
dup2(fd[1], 1);
}
close(fd[0]);
execvp((*cmd)[0], *cmd);
exit(1);
}
else {
wait(NULL); /* Collect childs */
close(fd[1]);
fdd = fd[0];
cmd++;
}
}
}
/*
* Compute multi-pipeline based
* on a command list.
*/
int
main(int argc, char *argv[])
{
char *ls[] = {"ls", "-al", NULL};
char *rev[] = {"rev", NULL};
char *nl[] = {"nl", NULL};
char *cat[] = {"cat", "-e", NULL};
char **cmd[] = {ls, rev, nl, cat, NULL};
pipeline(cmd);
return (0);
}

Program stuck on Pipe (exec ls grep sort)

I'm trying to make a program that executes the following commands connecting the output of one to the input of the next using pipes and taking two arguments DIR (directory) and ARG (filetype, example: jpg).
ls DIR -laR | grep ARG | sort
Here's the code:
int main(int argc, char *argv[]) {
if (argc != 3) {
printf("Invalid arguments. <dir> <arg>\n");
exit(1);
}
int pipe_fd1[2];
int pipe_fd2[2];
pid_t ls_pid, grep_pid;
int status;
pipe(pipe_fd1);
pipe(pipe_fd2);
ls_pid = fork();
if (ls_pid == 0) { //first child ls DIR -laR
dup2(pipe_fd1[1], STDOUT_FILENO);
close(pipe_fd1[0]);
execlp("ls", "ls", argv[1], "-laR", NULL);
} else if (ls_pid > 0) {
grep_pid = fork();
if (grep_pid == 0) { //second child grep ARG
dup2(pipe_fd1[0], STDIN_FILENO);
dup2(pipe_fd2[1], STDOUT_FILENO);
close(pipe_fd1[1]);
close(pipe_fd2[0]);
waitpid(ls_pid, &status, 0);
execlp("grep", "grep", argv[2], NULL);
} else if (grep_pid > 0) { //parent sort
dup2(pipe_fd2[0], STDIN_FILENO);
close(pipe_fd2[1]);
waitpid(grep_pid, &status, 0);
execlp("sort", "sort", NULL);
}
}
return 0;
}
It seems to be stuck? Not sure why?
You never close pipe_fd1 on the parent, so grep and sort doen't know when to stop reading input: because the pipe read and write ends are never closed on the parent, the reader blocks waiting for more input that will never arrive. You need to close it.
Also, you don't need waitpid(): the way pipes work ensures that input flows linearly and in order throughout the pipe.
Here's the working version with these issues addressed:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, char *argv[]) {
if (argc != 3) {
printf("Invalid arguments. <dir> <arg>\n");
exit(1);
}
int pipe_fd1[2];
int pipe_fd2[2];
pid_t ls_pid, grep_pid;
pipe(pipe_fd1);
ls_pid = fork();
if (ls_pid == 0) { //first child ls DIR -laR
dup2(pipe_fd1[1], STDOUT_FILENO);
close(pipe_fd1[0]);
execlp("ls", "ls", argv[1], "-laR", NULL);
} else if (ls_pid > 0) {
dup2(pipe_fd1[0], STDIN_FILENO);
close(pipe_fd1[1]);
pipe(pipe_fd2);
grep_pid = fork();
if (grep_pid == 0) { //second child grep ARG
dup2(pipe_fd2[1], STDOUT_FILENO);
close(pipe_fd2[0]);
execlp("grep", "grep", argv[2], NULL);
} else if (grep_pid > 0) { //parent sort
dup2(pipe_fd2[0], STDIN_FILENO);
close(pipe_fd2[1]);
execlp("sort", "sort", NULL);
}
}
return 0;
}

Is there any other way to build pipe in C?

I want to know that is this possible to code this program with using write(), read() functions. It takes 2 initial arguments with argv[] then fork() and after that child process' stdout passes to parents stdin and result will be showed on screen.
when I execute the program like this ---> ./program date wc
It must show a result as same as date | wc does in shell programming.
I coded this program with dup(). it works fine but I want to other way around. Thank you and sorry for my english.
int main(int argc, char* argv[]){
char* argument1[]={argv[1], NULL};
char* argument2[]={argv[2], NULL};
int fd[2];
int d;
pid_t pid;
char buffer[30];
if(argc < 3){
printf("No parameter");
return 1;
}
if(pipe(fd)==-1){
perror("pipe failed");
exit(1);
}
else{
pid=fork();
if(pid==0){
/*child process*/
close(1);
dup(fd[1]);
close(fd[0]);
//close(fd[1]);
execvp(argument1[0], argument1);
}
else if(pid>0){
/*Parent process*/
close(0);
dup(fd[0]);
close(fd[1]);
//close(fd[0]);
execvp(argument2[0], argument2);
}
}
return 0;
}
Same code with dup2: (I let you make your m_exec function)
int m_pipe(char *cmd1, char *cmd2)
{
int fd[2];
if (pipe(fd) == -1)
{
perror("Pipe failed ");
return (-1);
}
if (fork() == 0)
{
/*Child process*/
dup2(fd[0], 0);
close(fd[1]);
m_exec(cmd2);
}
else
{
/*Parent process*/
dup2(fd[1], 1);
close(fd[0]);
m_exec(cmd1);
}
return (0);
}
int main(int argc, char* argv[])
{
if(argc != 3)
{
write(2, "Usage ./a.out cmd1 cmd2\n", strlen("Usage ./a.out cmd1 cmd2\n"));
return EXIT_FAILURE;
}
if (m_pipe(argv[1], argv[2]) == -1)
return EXIT_FAILURE;
return EXIT_SUCCESS;
}

Shell pipe system in C

I'm trying to make a pipe system for my shell, but it's not working as intended.
void pipes (char *listaCommand[], int end, char **argv)
{
int cont = end;
for (cont;listaCommand[cont]; cont++)
{
if (listaCommand[cont] != NULL)
{
if (!strcmp(listaCommand[cont],"|")){
int pid2, status;
int pipefd[2], ret;
listaCommand[cont] = NULL;
ret = pipe (pipefd);
if (ret < 0) fatal();
/* Now fork. */
pid2 = fork ();
if (pid2 <0) fatal ();
if (pid2 > 0)
{
printf ("P: waiting for child\n");
wait (&status);
close(STDIN_FILENO);
dup(pipefd[0]);
close(pipefd[0]);
close(pipefd[1]);
/*execvp (auxCommand[0], auxCommand);*/
pipes(listaCommand, cont+1, argv);
/*break;*/
}
else
{
close (STDOUT_FILENO);
dup (pipefd[1]);
close (pipefd[1]);
close (pipefd[0]);
}
}
}
}
if (end >= 3)
{
printf("%s \n", listaCommand[end-1]);
}
execvp (listaCommand[end], listaCommand);
printf ("%s: command not found.\n", listaCommand[end]); /* Exec failed. */
exit(EXIT_FAILURE);
}
If I use commands like ls | sort, it works, but if ls has any argument, it doesnt work, because for some reason, listaCommand[cont] where its == "|" is not NULL, so I just get
ls: option -- 'a' invalid.
listaCommand have
[0] = "ls"
[1] = "-al"
[2] = "|"
[3] = "sort"
You don't need to pass the end argument, instead increment the pointer to your command array. You are passing the initial array to the execvp call so it tries to execute ls multiple times. Further, you need a break statement after setting the listaCommand[cont] to NULL because after the iteration cont is incremented. Also I think you need to protect the execvp call so that the parent does not call it after the processing is done.
#include <stdio.h>
#include <string.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/wait.h>
#define fatal() exit(1)
void pipes (char *listaCommand[], char **argv)
{
printf("pipes %s\n", listaCommand[0]);
int cont = 0;
for (;listaCommand[cont]; cont++) {
if (listaCommand[cont][0] == '|'){
int pid2, status;
int pipefd[2], ret;
listaCommand[cont] = NULL;
ret = pipe (pipefd);
if (ret < 0) fatal();
/* Now fork. */
pid2 = fork ();
if (pid2 <0) fatal ();
if (pid2 > 0)
{
printf ("P: waiting for child\n");
wait (&status);
close(STDIN_FILENO);
dup(pipefd[0]);
close(pipefd[0]);
close(pipefd[1]);
/*execvp (auxCommand[0], auxCommand);*/
pipes(listaCommand + cont + 1, argv);
/*break;*/
}
else
{
close (STDOUT_FILENO);
dup (pipefd[1]);
close (pipefd[1]);
close (pipefd[0]);
break;
}
}
}
if (listaCommand[0]) {
execvp (listaCommand[0], listaCommand);
printf ("%s: command not found.\n", listaCommand[0]); /* Exec failed. */
exit(EXIT_FAILURE);
}
}
int main() {
char *args[] = { "ls", "-al", "|", "sort", "|" , "tr", "[a-z]", "[A-Z]", 0 };
pipes(args, 0);
return 0;
}

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