Why is the 2nd while-do loop not running in my function - c

Question

I am working on CS50 and learning C. I am getting myself confused about utilizing while-do loops to ensure that the user puts in an integer. I am trying to create a function that prompts for your age and then your friend's age. However, after the first while-do loop returns false, shouldn't it move to the 2nd while-do loop in my get_ages() function? I would love some help on this.
#include <cs50.h>
#include <stdio.h>
int get_ages();
int main(void)
{
printf("%i\n", get_ages());
}
//Get your age function
int get_ages(int your_age, int friend_age)
{
do
{
your_age = get_int("What is your age: ");
return your_age;
}
while (your_age < 1);
do
{
friend_age = get_int("What is your friends age: ");
return friend_age;
}
while (friend_age < 1);
}

Answer 1

Your declaration int get_ages(); and your definition of the function int get_ages(int your_age, int friend_age) do not match. In main() you call get_ages() without arguments. If you want to pass data to caller via an argument (sometimes referred to as an out parameter) then you need to pass in the address of said variables:
int your_age;
int friend_age;
get_ages(&your_age, &friend_age);
The declaration would then be void get_ages(int *your_age, int &friend_age) you in the function you would set the value like this *your_age = get_int(...) etc.
return terminates a function and pass the optional value to caller. This means you will only ever execute a single return statement within a function.
In c, you can only return 1 value, so you need to return a struct or array if you have multiple things you want to return.
I suggest you change the function to just return a single value, pass in a prompt, then call the function twice:
#include <cs50.h>
#include <stdio.h>
int get_age(const char *prompt) {
int age;
do {
age = get_int(prompt);
} while (age < 1);
return age;
}
int main(void) {
printf("%i\n", get_age("What is your age? "));
printf("%i\n", get_age("What is your friend's age? "));
}