how to display the table in c? [closed] - c

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#include <stdio.h>
#include <math.h>
int main(void)
{
// input value
int num, lower, upper;
double squareroot;
int square;
int cube;
printf("enter your number:\n");
scanf_s("%d", &num);
do
{
printf("the lower value limit is ");
scanf_s("%d", &lower);
} while (lower < 0 || lower > 50);
do
{
printf("the upper value limit is ");
scanf_s("%d", &upper);
} while (upper < 0 || upper > 50);
// the formular to find the squareroot, square, cube
squareroot = sqrt(num);
square = num * num;
cube = num * num * num;
//a for loop
for (num = 0; num <= upper; num++) {
printf("*base number* || *square root* || *square* || *cube*\n");
printf("*%d* || *%f* || *%ld* || *%ld*\n",
lower, squareroot, square, cube);
}
return 0;
}
i try to make a table to display the base number, square root, square, and cube
and set a limit for the table.
for example, if I input the lower number is 1 and the upper number is 5 then the table will stop at 5 then display the square root, square, and cube

Answer 1

At least this problem:
Mismatched specifiers/type
int square;
int cube;
...
printf("*%d* || *%f* || *%ld* || *%ld*\n",
lower, squareroot, square, cube);
Use "%d" with int, not "%ld".
Move assignments
Following assignments need to be inside the loop.
for (num = 0; num <= upper; num++) {
square = num * num;
cube = num * num * num;
Save time. Enable all compiler warnings

Answer 2

Try the Below Code Make all Changes I have added Comments to Clarify why I made The
#include <stdio.h>
#include <math.h>
int main(void)
{
// input value
int lower, upper;
double squareroot;
int square;
int cube;
//Read the Limits First
printf("Enter the Lower Limit: ");
scanf("%d", &lower);
printf("Enter the Upper Limit: ");
scanf("%d", &upper);
//Instead of Declaring an Entire Loop You Can Just Use an If Statement this Reduces Code Complexity
//You can also Set Your Limits
if(upper > 0 && upper < 50 && lower > 0 && lower < 50)
{
//THen Enter Actual Code
//Also Dont Set Lower to 0 It will Change Your Actual Value Instead Take another Loop Var
for (int i = lower; i <= upper; i++)
{
//Then Perform all Functions on i
squareroot = sqrt(i);
square = i * i;
cube = i * i * i;
printf("*base number* || *square root* || *square* || *cube*\n");
printf("*%d* || *%f* || *%d* || *%d*\n", i, squareroot, square, cube);
}
}
return 0;
}

Answer 3

Several issues:
You go to the trouble of asking for lower, but you don't use it to control your loop - your loop should befor( int num = lower; num <= upper; num++)
{
...
}
Put another way, if you always intend for your loop to start from zero, then you don't need lower at all.
You need compute the square root, square, and cube of num for each iteration of the loop. Instead, you're doing it once before the loop and just printing those same values over and over again;
You only need to print your table header once, outside the body of the loop;
You can compute your square root, square, and cube all as part of the printf statement:
printf( "%d %f %d %d\n", num, sqrt((double) num), num * num, num * num * num );
Field width specifiers are your friends - you can tell printf exactly how wide you want each column to be. Example:
printf( "%6d%12.2f%12d%12d", num, sqrt((double) num), num * num, num * num * num );
This means the column for num is 6 characters wide, the column for square root is 12 characters wide, with 3 characters reserved for the decimal point and two following digits, and the columns for square and cube are 12 characters wide. Example:
printf( "%6s%12s%12s%12s\n", "base", "root", "square", "cube" );
printf( "%6s%12s%12s%12s\n", "----", "----", "------", "----" );
for (int i = lower; i <= upper; i++ )
printf( "%6d%12.2f%12d%12d\n", i, sqrt( (double) i ), i*i, i*i*i );
Which gives output like this (lower == 1, upper == 10):
base root square cube
---- ---- ------ ----
1 1.00 1 1
2 1.41 4 8
3 1.73 9 27
4 2.00 16 64
5 2.24 25 125
6 2.45 36 216
7 2.65 49 343
8 2.83 64 512
9 3.00 81 729
10 3.16 100 1000
Full example:
#include <stdio.h>
#include <math.h>
int main( void )
{
int lower = 0, upper = 0;
printf( "Gimme a lower value: " );
while ( scanf( "%d", &lower ) != 1 || (lower < 0 || lower > 50 ))
{
/**
* Clear any non-numeric characters from the input stream
*/
while ( getchar() != '\n' )
; // empty loop
printf( "Nope, try again: " );
}
printf( "Gimme an upper value: " );
while ( scanf( "%d", &upper ) != 1 || (upper < lower || upper > 50 ))
{
while( getchar() != '\n' )
; // empty loop
printf( "Nope, try again: " );
}
printf( "%6s%12s%12s%12s\n", "base", "root", "square", "cube" );
printf( "%6s%12s%12s%12s\n", "----", "----", "------", "----" );
for (int i = lower; i <= upper; i++ )
printf( "%6d%12.2f%12d%12d\n", i, sqrt( (double) i ), i*i, i*i*i );
return 0;
}
I've written the input section such that it will reject inputs like foo or a123. It will not properly handle inputs like 12w4, but that would make the example more complicated than it needs to be (you're not asking about input validation, you're asking about computation and formatting). Example run:
$ ./table
Gimme a lower value: foo
Nope, try again: a123
Nope, try again: 123
Nope, try again: 1
Gimme an upper value: 100
Nope, try again: 50
base root square cube
---- ---- ------ ----
1 1.00 1 1
2 1.41 4 8
3 1.73 9 27
4 2.00 16 64
5 2.24 25 125
6 2.45 36 216
7 2.65 49 343
8 2.83 64 512
9 3.00 81 729
10 3.16 100 1000
11 3.32 121 1331
12 3.46 144 1728
13 3.61 169 2197
14 3.74 196 2744
15 3.87 225 3375
16 4.00 256 4096
17 4.12 289 4913
18 4.24 324 5832
19 4.36 361 6859
20 4.47 400 8000
21 4.58 441 9261
22 4.69 484 10648
23 4.80 529 12167
24 4.90 576 13824
25 5.00 625 15625
26 5.10 676 17576
27 5.20 729 19683
28 5.29 784 21952
29 5.39 841 24389
30 5.48 900 27000
31 5.57 961 29791
32 5.66 1024 32768
33 5.74 1089 35937
34 5.83 1156 39304
35 5.92 1225 42875
36 6.00 1296 46656
37 6.08 1369 50653
38 6.16 1444 54872
39 6.24 1521 59319
40 6.32 1600 64000
41 6.40 1681 68921
42 6.48 1764 74088
43 6.56 1849 79507
44 6.63 1936 85184
45 6.71 2025 91125
46 6.78 2116 97336
47 6.86 2209 103823
48 6.93 2304 110592
49 7.00 2401 117649
50 7.07 2500 125000