I have the following code; the only issue with it is that sometimes it generates a digit alphanumeric code.
I am trying to modify it such that it always returns a 6 digit code. Any thoughts on how to tweak this?
I have another procedure the purges duplicates and it re-runs, so that is not an issue.
SET #HashCode = NULL
SELECT
#HashCode = ISNULL(#HashCode, '') + SUBSTRING('23456789ABCDEFGHJKLMNPQRSTUVWXYZ', (ABS(CHECKSUM(NEWID())) % 36) + 1, 1)
FROM
[master]..[spt_values] AS [spt_values] WITH (NOLOCK)
WHERE
[spt_values].[type] = 'P'
AND [spt_values].[number] < 6
A very simple way of achieving this is selecting the first 6 LEFT characters in the string generated by the NEWID() function:
SELECT LEFT(NEWID(), 6)
Examples:
4DF32A
DC70D5
8793B2
3D8416
EE2838
Note, because the NEWID() function generates a unique identifier (GUID), consisting of hexadecimal characters (A-F & 0-9), there is a chance the output will consist of only numbers or only letters; which may or may not fit your purpose if you require a strict alphanumeric value.
Examples:
946983
831814
DDFDBB
You can use it like this:
SET #HashCode = NULL
SELECT
#HashCode = LEFT(NEWID(), 6)
Related
I am trying to filter out some query results to where it only shows items with 6 decimal places. I don't need it to round up or add 0's to the answer, just filter out anything that is 5 decimal places or below. My current query looks like this: (ex. if item is 199.54215 i dont want to see it but if it is 145.253146 i need it returned)
select
TRA_CODPLANTA,
TRA_WO,
TRA_IMASTER,
tra_codtipotransaccion,
tra_Correlativo,
TRA_INGRESOFECHA,
abs(tra_cantidadparcial) as QTY
from mw_tra_transaccion
where FLOOR (Tra_cantidadparcial*100000) !=tra_cantidadparcial*100000
and substring(tra_imaster,1,2) not in ('CP','SG','PI','MR')
and TRA_CODPLANTA not in ('4Q' , '5C' , '5V' , '8H' , '7W' , 'BD', 'DP')
AND tra_INGRESOFECHA > #from_date
and abs(tra_cantidadparcial) > 0.00000
Any assistance would be greatly appreciated!
Here is an example with ROUND, which seems to be the ideal function to use, since it remains in the realms of numbers. If you have at most 5 decimal places, then rounding to 5 decimal places will leave the value unchanged.
create table #test (Tra_cantidadparcial decimal(20,10));
INSERT #test (Tra_cantidadparcial) VALUES (1),(99999.999999), (1.000001), (45.000001), (45.00001);
SELECT * FROM #test WHERE ROUND(Tra_cantidadparcial,5) != Tra_cantidadparcial;
drop table #test
If your database values are VARCHAR and exist in the DB like so:
100.123456
100.1
100.100
You can achieve this using a wildcard LIKE statement example
WHERE YOUR_COLUMN_NAME LIKE '%.[0-9][0-9][0-9][0-9][0-9][0-9]%'
This will being anything containing a decimal place followed by AT LEAST 6 numeric values
Here is an example using a conversion to varchar and using the LEN - the CHARINDEX of the decimal point, I'm not saying this is the best way, but you did ask for an example in syntax, so here you go:
--Temp Decimal value holding up to 10 decimal places and 10 whole number places
DECLARE #temp DECIMAL(20, 10) = 123.4565432135
--LEN returns an integer number of characters in the converted varchar
--CHARINDEX returns the integer location of the decimal where it is found in the varchar
--IF the number of characters left after subtracting the index of the decimal from the length of the varchar is greater than 5,
--you have more than 6 decimal places
IF LEN(CAST(#temp AS varchar(20))) - CHARINDEX('.', CAST(#temp AS varchar(20)), 0) > 5
SELECT 1
ELSE
SELECT 0
Here is a shorthand way.
WHERE (LEN(CONVERT(DOUBLE PRECISION, FieldName % 1)) - 2) >=5
One way would be to convert / cast that column to a lower precision. Doing this would cause automatic rounding, but that would show you if it is 6 decimals or not based on the last digit. If the last digit of the converted value is 0, then it's false, otherwise it's true.
declare #table table (v decimal(11,10))
insert into #table
values
(1.123456789),
(1.123456),
(1.123),
(1.123405678)
select
v
,cast(v as decimal(11,5)) --here, we are changing the value to have a precision of 5. Notice the rounding.
,right(cast(v as decimal(11,5)),1) --this is taking the last digit. If it's 0, we don't want it
from #table
Thus, your where clause would simply be.
where right(cast(tra_cantidadparcial as decimal(11,5)),1) > 0
I am trying to get last numeric part in the given string.
For Example, below are the given strings and the result should be last numeric part only
SB124197 --> 124197
287276ACBX92 --> 92
R009321743-16 --> 16
How to achieve this functionality. Please help.
Try this:
select right(#str, patindex('%[^0-9]%',reverse(#str)) - 1)
Explanation:
Using PATINDEX with '%[^0-9]%' as a search pattern you get the starting position of the first occurrence of a character that is not a number.
Using REVERSE you get the position of the first non numeric character starting from the back of the string.
Edit:
To handle the case of strings not containing non numeric characters you can use:
select case
when patindex(#str, '%[^0-9]%') = 0 then #str
else right(#str, patindex('%[^0-9]%',reverse(#str)) - 1)
end
If your data always contains at least one non-numeric character then you can use the first query, otherwise use the second one.
Actual query:
So, if your table is something like this:
mycol
--------------
SB124197
287276ACBX92
R009321743-16
123456
then you can use the following query (works in SQL Server 2012+):
select iif(x.i = 0, mycol, right(mycol, x.i - 1))
from mytable
cross apply (select patindex('%[^0-9]%', reverse(mycol) )) as x(i)
Output:
mynum
------
124197
92
16
123456
Demo here
Here is one way using Patindex
SELECT RIGHT(strg, COALESCE(NULLIF(Patindex('%[^0-9]%', Reverse(strg)), 0) - 1, Len(strg)))
FROM (VALUES ('SB124197'),
('287276ACBX92'),
('R009321743-16')) tc (strg)
After reversing the string, we are finding the position of first non numeric character and extracting the data from that position till the end..
Result :
-----
124197
92
16
hie am trying to select the integer value before the char C in my SQL database table which contains the information below.
240mm2 X 15C WIRING CABLE
150mm2 X 3C flex
10mm2 x 4C swa
so far i have used the query
select left ('C',CHARINDEX ('C',product_name)) from product
and i get 'C' on my results which is correct. Now am stuck does anyone know how i can modify the above select query to get a result which only lists the integers for eg
15
3
4
Two observations: the integer before "C" has a space before it and there is no space between the integer and "C".
If these are generally true, then you can do what you want using substring_index():
select substring_index(substring_index(product_name, 'C', 1), ' ', -1) + 0 as thenumber
The + 0 simply converts the value to a number.
If you're doing this in SQL Server you could try the following:
Select Substring(product_name,
PATINDEX('% [0-9]%',product_name) + 1,
PATINDEX('%[0-9]C%',product_name) - PATINDEX('% [0-9]%',product_name)
) as num
from Product
This assumes that there is a space before the number and always a C after the number with no space.
It works out the starting point and then the length based on the start and end and performs a substring with the results.
You could use a combination of instring and substring.
First get the position of the C
Then substring till C
It goes like this:
SELECT INSTR('foobarbar', 'bar');
= 4
And then you select substring from 1 to 4.
Someone asked here how to get only values which are a number :
So , if the table is :
DECLARE #Table TABLE(
Col nVARCHAR(50)
)
INSERT INTO #Table SELECT 'ABC'
INSERT INTO #Table SELECT '234.62'
INSERT INTO #Table SELECT '10:10:10:10'
INSERT INTO #Table SELECT 'France'
INSERT INTO #Table SELECT '2'
then - the desired results are :
234.62
2
But when I tested this query :
SELECT * FROM #Table WHERE Col LIKE '%[0-9.]%' --expected to see only 234.62
it showed :
234.62
10:10:10:10
2
Question #1
How come 10:10:10:10 , 2 satisfies the condition ?
Question #2
I saw this answer here which does work
SELECT * FROM #Table WHERE Col NOT LIKE '%[^0-9.]%'
But I don't understand why this works. AFAIU - it selects all values which are not like (not(has number) and not( has dot)) which is ===>(de morgan)===> not like ( has number or has dot)
Can someone please shed light ?
nb I already know that isnumeric can be used also , but it's unsafe (+). also valid wildcards are %,_,[],[^]
Any particular use of [set] within a LIKE expression is a check against one character in the target string.
So, LIKE '%[0-9.]%' says - % - match 0-to-many arbitrary characters, then [0-9.] match one character in the set 0-9., and then % match 0-to-many arbitrary characters. Paraphrased, it says "match any string that contains at least one character in the set 0-9.". So, 10:10:10:10 can be matched as 0 arbitrary characters, then 1 matches [0-9.], and then 0:10:10:10 matches the final %.
LIKE '%[^0-9.]%' says - % - match 0-to-many arbitrary characters, then [^0-9.] match one character not in the set 0-9., and then % match 0-to-many arbitrary characters. Paraphrased, it says "match any string that contains at least one character outside of the set 0-9.. So when we apply the NOT to the front of that, we are saying "match any string that doesn't contain at least one character outside of the set 0-9." or "match strings that only contain characters in the set 0-9..
Essentially, the double-negative is a way to make an assertion about all characters in the string.
I am working with a table that comes from an external source, and cannot be "cleaned". There is a column which an nvarchar(20) and contains an integer about 95% of the time, but occasionally contains an alpha. I want to use something like
select * from sch.tbl order by cast(shouldBeANumber as integer)
but this throws an error on the odd "3A" or "D" or "SUPERCEDED" value.
Is there a way to say "sort it like a number if you can, otherwise just sort by string"? I know there is some sloppiness in that statement, but that is basically what I want.
Lets say for example the values were
7,1,5A,SUPERCEDED,2,5,SECTION
I would be happy if these were sorted in any of the following ways (because I really only need to work with the numeric ones)
1,2,5,7,5A,SECTION,SUPERCEDED
1,2,5,5A,7,SECTION,SUPERCEDED
SECTION,SUPERCEDED,1,2,5,5A,7
5A,SECTION,SUPERCEDED,1,2,5,7
I really only need to work with the
numeric ones
this will give you only the numeric ones, sorted properly:
SELECT
*
FROM YourTable
WHERE ISNUMERIC(YourColumn)=1
ORDER BY YourColumn
select
*
from
sch.tbl
order by
case isnumeric(shouldBeANumber)
when 1 then cast(shouldBeANumber as integer)
else 0
end
Provided that your numbers are not more than 100 characters long:
WITH chars AS
(
SELECT 1 AS c
UNION ALL
SELECT c + 1
FROM chars
WHERE c <= 99
),
rows AS
(
SELECT '1,2,5,7,5A,SECTION,SUPERCEDED' AS mynum
UNION ALL
SELECT '1,2,5,5A,7,SECTION,SUPERCEDED'
UNION ALL
SELECT 'SECTION,SUPERCEDED,1,2,5,5A,7'
UNION ALL
SELECT '5A,SECTION,SUPERCEDED,1,2,5,7'
)
SELECT rows.*
FROM rows
ORDER BY
(
SELECT SUBSTRING(mynum, c, 1) AS [text()]
FROM chars
WHERE SUBSTRING(mynum, c, 1) BETWEEN '0' AND '9'
FOR XML PATH('')
) DESC
SELECT
(CASE ISNUMERIC(shouldBeANumber)
WHEN 1 THEN
RIGHT(CONCAT('00000000',shouldBeANumber), 8)
ELSE
shouoldBeANumber) AS stringSortSafeAlpha
ORDEER BY
stringSortSafeAlpha
This will add leading zeros to all shouldBeANumber values that truly are numbers and leave all remaining values alone. This way, when you sort, you can use an alpha sort but still get the correct values (with an alpha sort, "100" would be less than "50", but if you change "50" to "050", it works fine). Note, for this example, I added 8 leading zeros, but you only need enough leading zeros to cover the largest possible integer in your column.