printf is not showing before scanf [duplicate] - c

This question already has answers here:
C/C++ printf() before scanf() issue
(2 answers)
Why does printf not flush after the call unless a newline is in the format string?
(10 answers)
Closed 6 months ago.
I'm using Eclipse IDE
I have the following simple code in C language:
#include <stdio.h>
#include <stdlib.h>
int main(void) {
int a;
printf("Enter a number");
scanf("%d",&a);
printf("You have entered %d",a);
return EXIT_SUCCESS;
}
So as you can see, there are two printf's.
but if i run the code on console My scanf is running before my first printf displays.
And all output printed together after the execution of scanf.
Then the result will be like this (This is what I'm getting in my console):
6
Enter a numberYou have entered 6
What i really wanted is:
Enter a number
6
You have entered 6
I tried adding fflush(stdout) but the broblem still exists.
is there any working solution to fix this?

Related

c program in eclipse, first printf function is not showing in console, after i entered 2 values it is showing 2 printf out in same line [duplicate]

This question already has answers here:
C/C++ printf() before scanf() issue
(2 answers)
Closed 7 months ago.
I was doing c program in eclipse, first printf function is not showing in console, after I entered 2 values it is showing 2 printf out in same line, how to clear this problem
#include <stdio.h>
#include <stdlib.h>
int main(void) {
int a,b,c;
printf("enter two numbers");
scanf("%d%d",&a,&b);
c=a+b;
printf("total is %d",c);
return EXIT_SUCCESS;
}
This is my code
the problem seems to be that the print isn't flushed to the terminal.
when you use printf you actually are writing to a buffer that will be flushed to the terminal after one of the following:
the buffer is full
enough time has passed
you ended your print with '\n'
you give a flush command
I recommend just finishing your print with the '\n'
printf("enter two numbers\n");

When i run a program on eclipse, the console shows nothing until I type in something, then takes that as the first input (for scanf for example) [duplicate]

This question already has an answer here:
printf not print on the console in eclipse?
(1 answer)
Closed 12 months ago.
So I just installed eclipse on windows after having too many problems with my old installation on a vm running Ubuntu.
All problems gone except for what I wrote in the title. Scanf text never comes up first, no matter which program I'm running. It shows text when I have entered all that I can enter. Let me give you an example:
#include <stdio.h>
#include <stdlib.h>
int main() {
int number1;
int number2;
printf ("Type in a number \n");
scanf ("%d", &number1);
printf ("Type in a number \n");
scanf ("%d", &number2);
int number3 = number1 * number2;
printf ("%d", number3);
return 0;
}
Console looks like this:
2
3
Type in a number
Type in a number
6
2 and 3 I had to type in first, then the last three lines showed up. That's not how it's supposed to be is it?
Thanks for any help!
What seems to work is writing
setbuf(stdout, NULL);
into every main of every program. It does fix the problem, yet there's maybe another fix that's not so annoying as doing that everytime. It's not bad, but I don't get why it simply worked on another instance of eclipse but here not.

Console exits on enter [duplicate]

This question already has answers here:
scanf() leaves the newline character in the buffer
(7 answers)
How to read / parse input in C? The FAQ
(1 answer)
Closed 2 years ago.
So, i just want to know how to deal with this, the code doesnt have a purpose besides testing.
why does the the enter i press go to the getchar()command?
or is that the case to begin with? i assume it is.
here is the code
#include<stdio.h>
int main(){
int x,y,z;
printf("Enter two nums\n");
scanf("%d %d", &x, &y);
z=x/y;
printf("%d is answ\n", z);
puts("Press enter to exit");
getchar();
return 0;
}

my c program for factorial is not giving any value in the output box though it shows no errors [duplicate]

This question already has answers here:
When should I use ampersand with scanf()
(3 answers)
Closed 3 years ago.
c program
my c program for factorial is not giving any value in the output box though it shows no errors
#include<stdio.h>
main()
{
int a,n,t=1;
printf("enter the number\n");
scanf("%d",a);
for(n=1;n<=a;n++)
{
t*=n;
}
printf("the factorial is %d",t);
}
You'll have to pass address of variable a like this..
scanf("%d", &a);

date or time change.reload from disk error in c [duplicate]

This question already has answers here:
scanf() leaves the newline character in the buffer
(7 answers)
Closed 3 years ago.
I use emulated Turbo C++ IDE 3.0 for development in C. I get the above mentioned error on when I run the following program:
#include<stdio.h>
#include<conio.h>
main()
{
int i,j,k;
char x;
do
{
printf("enter the number i: ");
scanf("%d",&i );
printf("enter the number j: ");
scanf("%d",&j);
k=i+j;
printf("Addition of given numbers :%d ",k);
printf("\n Do you to continue : ");
scanf("%c",&x);
} while(x=='y'||x=='Y');
getch();
}
It was successfully compiled without errors or warnings. At run time, the problem arises after the statement printf("\n Do you to continue : ");.
When I enter a value for this, the error shows up. I tried in dev C++ but the problem prevails. I am using Windows 7 Ultimate.
Suggestion
change
scanf("%c",&x);
to
scanf(" %c",&x);

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