VBA: populate a 2dim array from another 2dim array without nested loop - arrays

very new to VBA.
Suppose I have a 6 by 2 array with values shown on right, and I have an empty 2 by 3 array (excluding the header). My goal is to get the array on the left looks as how it is shown.
(Header) 1 2 3 1 a
a c e 1 b
b d f 2 c
2 d
3 e
3 f
Since the array on the right is already sorted, I noticed that it can be faster if I just let the 1st column of the 2 by 3 array take the first 2 values (a and b), the 2nd column takes the following 2 values (c and d), and so on. This way, it can avoid using a nested for loop to populate the left array.
However, I was unable to find a way to populate a specific column of an array. Another way to describe my question is: Is there a way in VBA to replicate this code from python, which directly modifies a specific column of an array? Thanks!
array[:, 0] = [a, b]

Populate Array With Values From Another Array
It is always a nested loop, but in Python, it is obviously 'under the hood' i.e. not seen to the end-user. They have integrated this possibility (written some code) into the language.
The following is a simplified version of what you could do in VBA since there is just too much hard-coded data with 'convenient' numbers in your question.
The line of your interest is:
PopulateColumn dData, c, sData, SourceColumn
to populate column c in the destination array (dData) using one line of code. It's just shorter, not faster.
Sure, it has no loop but if you look at the called procedure, PopulateColumn, you'll see that there actually is one (For dr = 1 To drCount).
You can even go further with simplifying the life of the end-user by using classes but that's 'above my paygrade', and yours at the moment since you're saying you're a noob.
Copy the code into a standard module, e.g. Module1, and run the PopulateColumnTEST procedure.
Note that there are results written to the Visual Basic's Immediate window (Ctrl+G).
The Code
Option Explicit
Sub PopulateColumnTEST()
Const SourceColumn As Long = 2
' Populate the source array.
Dim sData As Variant: ReDim sData(1 To 6, 1 To 2)
Dim r As Long
For r = 1 To 6
sData(r, 1) = Int((r + 1) / 2) ' kind of irrelevant
sData(r, 2) = Chr(96 + r)
Next r
' Print source values.
DebugPrintCharData sData, "Source:" & vbLf & "R 1 2"
' Populate the destination array.
Dim dData As Variant: ReDim dData(1 To 2, 1 To 3)
Dim c As Long
' Loop through the columns of the destination array.
For c = 1 To 3
' Populate the current column of the destination array
' with the data from the source column of the source array
' by calling the 'PopulateColumn' procedure.
PopulateColumn dData, c, sData, SourceColumn
Next c
' Print destination values.
DebugPrintCharData dData, "Destination:" & vbLf & "R 1 2 3"
End Sub
Sub PopulateColumn( _
ByRef dData As Variant, _
ByVal dDataCol As Long, _
ByVal sData As Variant, _
ByVal sDataCol As Long)
Dim drCount As Long: drCount = UBound(dData, 1)
Dim dr As Long
For dr = 1 To drCount
dData(dr, dDataCol) = sData(drCount * (dDataCol - 1) + dr, sDataCol)
Next dr
End Sub
Sub DebugPrintCharData( _
ByVal Data As Variant, _
Optional Title As String = "", _
Optional ByVal ColumnDelimiter As String = " ")
If Len(Title) > 0 Then Debug.Print Title
Dim r As Long
Dim c As Long
Dim rString As String
For r = LBound(Data, 1) To UBound(Data, 1)
For c = LBound(Data, 2) To UBound(Data, 2)
rString = rString & ColumnDelimiter & Data(r, c)
Next c
rString = r & rString
Debug.Print rString
rString = vbNullString
Next r
End Sub
The Results
Source:
R 1 2
1 1 a
2 1 b
3 2 c
4 2 d
5 3 e
6 3 f
Destination:
R 1 2 3
1 a c e
2 b d f

Alternative avoiding loops
For the sake of the art and in order to approximate your requirement to find a way replicating Python's code
array[:, 0] = [a, b]
in VBA without nested loops, you could try the following function combining several column value inputs (via a ParamArray)
returning a combined 2-dim array.
Note that the function
will return a 1-based array by using Application.Index and
will be slower than any combination of array loops.
Function JoinColumnValues(ParamArray cols()) As Variant
'Purp: change ParamArray containing "flat" 1-dim column values to 2-dim array !!
'Note: Assumes 1-dim arrays (!) as column value inputs into ParamArray
' returns a 1-based 2-dim array
Dim tmp As Variant
tmp = cols
With Application
tmp = .Transpose(.Index(tmp, 0, 0))
End With
JoinColumnValues = tmp
End Function
Example call
Assumes "flat" 1-dim array inputs with identical element boundaries
Dim arr
arr = JoinColumnValues(Array("a", "b"), Array("c", "d"), Array("e", "f"))

Related

Store data by using FILTER Function within VBA [duplicate]

I'm trying to make a function MonstersInLevel() that filters the second column of my "LevelMonsters" named range based on the value of the first column. The range's first column represents a game level ID and the second column represents a monster ID that appears in that level. Here's what my range looks like.
If I call MonstersInLevel(2) I expect the function to return a range consisting of "2", "3" and "4".
Function MonstersInLevel(level As Integer) As Range
MonstersInLevel = Application.WorksheetFunction.Filter(Range("LevelMonsters").Columns(2), Range("LevelMonsters").Columns(1) = level)
End Function
I get:
A value used in the formula is of the wrong data type
I'm using the FILTER function as I would as an Excel formula. I assume there's some difference in the Excel and VBA syntax for FILTER's criteria.
Just encountered this problem myself and wanted to post my workaround.
We need to return an array of True/False to the worksheet function. To do this I created a Function that takes a 2D array, the column wanted and the value to compare. It then returns a 2d single column array of the necessary True/False.
Function myeval(arr() As Variant, clm As Long, vl As Variant) As Variant()
Dim temp() As Variant
ReDim temp(1 To UBound(arr, 1), 1 To 1)
Dim i As Long
For i = 1 To UBound(arr, 1)
temp(i, 1) = arr(i, clm) = vl
Next i
myeval = temp
End Function
So in this particular case it would be called:
Function MonstersInLevel(level As Integer) As Variant
MonstersInLevel = Application.WorksheetFunction.Filter(Range("LevelMonsters").Columns(2), myeval(Range("LevelMonsters").Value, 1, level),"""")
End Function
Avoid type mismatch in Worksheetfunction via VBA
Keeping in mind that the 2nd argument reflects a dynamic matrix condition
based entirely on â–ºworksheet logic (returning an array of 0 or 1 cell values /False or True])
it seems that you have
to execute an evaluation at least within this argument and
declare the function type (explicitly or implicitly) as Variant
Function MonstersInLevel(level As Integer) As Variant
'' Failing assignment:
' MonstersInLevel = Application.WorksheetFunction.Filter(Range("LevelMonsters").Columns(2), _
' Range("LevelMonsters").Columns(1) = level _
' )
MonstersInLevel = Application.WorksheetFunction.Filter( _
Range("LevelMonsters").Columns(2), _
Evaluate(Range("LevelMonsters").Columns(1).Address & "=" & level) _
)
End Function
...or to evaluate the complete function
Function MonstersInLevel(level As Integer) As Variant
Dim expr As String
expr = "=Filter(" & _
Range("LevelMonsters").Columns(2).Address & "," & _
Range("LevelMonsters").Columns(1).Address & "=" & level & _
")"
'Debug.Print expr
MonstersInLevel = Evaluate(expr)
End Function
Example call writing results to any target
Dim v
v = MonstersInLevel(2)
Sheet1.Range("D2").Resize(UBound(v), UBound(v, 2)) = v
Of course it would be possible as well to write .Formula2 expressions programmatically, even splitting into spill range references.
Addendum ........... //as of Jan 10th
Backwards compatible workaround via VBA.Filter()
"If you guys know any other VBA function that would be more appropriate
than Application.WorksheetFunction.Filter I'd be ok."
In order to provide also a backwards compatible alternative,
I demonstrate the following approach using the classic (VBA.)Filter() function (see section [3]) based upon
prior matching results (see [1]).
Note that Application.Match() comparing two (!) array inputs
delivers a whole array of possible findings (instead of a single result as most frequently executed).
Non findings are identified by IsError() values of -1; adding +1 results in a set
of zeros and ones. Section [2] enters corresponding data for positive findings.
Eventually non-findings (i.e. 0or zero) are removed by a tricky negative filtering.
Function getLevels()
Function getLevels(rng As Range, ByVal level As Long)
'Site: https://stackoverflow.com/questions/65630126/how-to-remove-only-the-duplicate-row-instead-of-removing-all-the-rows-that-follo
'[0] get datafield array
Dim v, v2
v = Application.Index(rng.Value2, 0, 1) ' 1st column
v2 = Application.Index(rng.Value2, 0, 2) ' 2nd column
'[1] check data (with Match comparing 2 arrays :-)
Dim results
results = Application.Transpose(Application.Match(v, Array(level), 0))
'[2] rebuild with False/True entries
Dim i As Long
For i = 1 To UBound(results)
results(i) = IsError(results(i)) + 1 ' 0 or 1-values
If results(i) Then results(i) = v2(i, 1) ' get current value if true
Next i
'[3] remove zeros (negative filtering)
results = Filter(results, "0", False)
'[4] return results as vertical 1-based array
getLevels = Application.Transpose(results)
End Function
Example call
Const LVL = 2 ' define level
With Sheet1 ' change to project's sheet Code(Name)
'define data range (assuming columns A:B)
Dim rng As Range
Set rng = .UsedRange.Resize(, 2)
'function call getLevels()
Dim levels
levels = getLevels(rng, level:=LVL)
'write to target
.Columns("I:I").Clear
.Range("I2").Resize(UBound(levels), 1) = levels
End With
Solution without any supporting VBA function:
Function MonstersInLevel(level As Integer) As Variant
With Application.WorksheetFunction
MonstersInLevel = .Filter(Range("LevelMonsters").Columns(2), _
.IfError(.XLookup(Range("LevelMonsters").Columns(1), level, True), False))
End With
End Function
XLookup returns an array of #N/A or True. IfError replaces errors with False. Finally, the Filter function receives an array of booleans as the second parameter.
EDIT
Removed the IfError function thanks to #ScottCraner:
Function MonstersInLevel(level As Integer) As Variant
With Application.WorksheetFunction
MonstersInLevel = .Filter(Range("LevelMonsters").Columns(2), _
.XLookup(Range("LevelMonsters").Columns(1), level, True, False))
End With
End Function
I couldn't resolve your question but as I did some testing on the subject trying to do so, I thought I'd share my findings:
Based on this Microsoft community post, or at least the answers there, it seems you will need to loop through the output in one way or another...
That question seems to want to achieve the same as what you are wanting to do (I think?).
On the other hand, I have never used the WorksheetFunction.Filter method, and the closest I could get it to working was like so:
Here is my sample data - RangeOne is Column A and RangeTwo is Column B. I have used the =FILTER() function in cell C1 evaluating the input in D1 for reference of expected results. Naturally this function is working as expected! The VBA routine is outputting to Columns E, F and G.
Sub TestFilterFunction()
Dim TestArray As Variant
Range("E1:E3") = Application.Filter(Range("RangeTwo"), Range("RangeOne"), Range("D1"))
Range("F1:F3") = Application.Filter(Range("RangeTwo"), Range("RangeOne") = Range("D1")) 'Runtime Error 13
Range("G1:G3") = Application.Filter(Range("RangeTwo"), Range("RangeOne"))
TestArray = Application.Filter(Range("RangeTwo"), Range("RangeOne"), Range("D1"))
TestArray = Application.Filter(Range("RangeTwo"), Range("RangeOne") = Range("D1")) 'Runtime Error 13
TestArray = Application.Filter(Range("RangeTwo"), Range("RangeOne"))
Range("H1:H3") = Application.Filter(Range("RangeTwo", "RangeOne"), Range("RangeOne"), Range("D1"))
TestArray = Application.Filter(Range("A1:B9"), Range("RangeOne"), "2")
End Sub
Column E returned the first 3 values from RangeTwo.
Column F has not been populated - This is because that line threw the Runtime error 13 - Type Mismatch
Column G returned the first 3 values from RangeTwo.
Column H returned the first 3 values from "A1:B9" (both ranges together) - specifically the first 3 values of column A.
I thought this was odd so I threw in an array to assign the values to rather than directly to the worksheet;
The first TestArray line and the third TestArray line both populated the array with the entire RangeTwo values;
I realised with the syntax of the first and third attempt at the WorksheetFunction.Filter, the entire range is returned (that being the first argument - Arg1 - range), but when trying to include the = Range("D1") , it returns the Type Mismatch error.
The final TestArray attempt being the same syntax as the Column H test, returned both columns in a 2D array (now TestArray(1 To 9, 1 To 2)).
I should note I couldn't find any documentation at all on WorksheetFunction.Filter so I'm assuming it does follow the same syntax as the Excel Sheet Function has.
If I find anything more on this topic I'll come back and edit it in, but for now it's looking like perhaps a solution using either loops or Index/Match functions also will need to happen to have the data returned in VBA.
I thought about perhaps writing the sheet formula to a cell and then grab that into an array or something but Excel inserts # into it now which only returns a single cell result, i.e.
Range("J1").Formula = "=FILTER(B1:B9, A1:A9 = D1)"
Would return in J1:
=#FILTER(B1:B9, A1:A9 = D1)
Which with our sample data, would only return 2 in J1 as opposed to the expected/desired 2, 3 and 4 in J1:J3.
I can't work out a way to remove the # as it is applied when the function is written to the cell unfortunately, but hopefully any of the above helps someone find a solution.
Just some comments to help you out.
If you are using the new FILTER() function from either a worksheet cell or within some VBA code, the first argument should be a range and the second argument should a a Boolean array. (if you don't enter something that can evaluate to a Boolean array, VBA may complain the the data type is wrong)
You would be best served (in VBA) if you:
explicitly declared a 2 dimensional, column-compatible, Boolean array
filled the array
used the array in the function call
Here is a super simple example. Say we want to filter the data from A1 to A6 to remove blanks. We could pick a cell and enter:
=FILTER(A1:A6,A1:A6<>"")
Looks like:
Now we want to perform the same activities with a VBA sub and put the result in a block starting with B9. The code:
Sub SingleColumn()
Dim r As Range, wf As WorksheetFunction, i As Long
Dim arr, s As String, dq As String, boo, rc As Long
Set wf = Application.WorksheetFunction
Set r = Range("A1:A6")
rc = r.Rows.Count
ReDim boo(1 To r.Rows.Count, 1 To 1) As Boolean
i = 1
For Each rr In r
If rr.Value = "" Then
boo(i, 1) = False
Else
boo(i, 1) = True
End If
i = i + 1
Next rr
arr = wf.Filter(r, boo)
MsgBox LBound(arr, 1) & "-" & UBound(arr, 1) & vbCrLf & LBound(arr, 2) & "-" & UBound(arr, 2)
Range("B9").Resize(UBound(arr, 1), UBound(arr, 2)) = arr
End Sub
Result:
On Excel version 15.0 (2013), I don't see Application.WorksheetFunction.Filter (tried with Show Hidden Members):
So maybe this is a newer function in later versions ?
My top Google search directs me to this question ;)
So, my answer is to avoid the function primarily from the point of view of backwards compatibility.
Alternate code options presented below returning e.g. a Range and a Variant.
Input:
Code:
Option Explicit
Sub Test()
Dim rngInput As Range
Dim rngFiltered As Range
Dim varFiltered As Variant
Dim varItem As Variant
Set rngInput = ThisWorkbook.Worksheets("Sheet1").Range("A2:B10")
' as range
Debug.Print "' Output as Range"
Set rngFiltered = MonstersInLevel_AsRange(rngInput, 2, 1, 2)
Debug.Print "' " & rngFiltered.Address ' expect B5, B6, B8
Debug.Print "' ---------------"
' as variant
Debug.Print "' Output as Variant"
varFiltered = MonstersInLevel_AsVariant(rngInput, 2, 1, 2)
For Each varItem In varFiltered
Debug.Print "' " & varItem ' expect 3, 4, 5
Next varItem
Debug.Print "' ---------------"
End Sub
Function MonstersInLevel_AsRange(rngToFilter As Range, _
ByVal lngLevel As Long, _
ByVal lngColIxToFilter As Long, _
ByVal lngColIxForValue As Long) As Range
Dim rngResult As Range
Dim lngRowIndex As Long
Dim lngResultIndex As Long
Set rngResult = Nothing
For lngRowIndex = 1 To rngToFilter.Rows.Count
If rngToFilter.Cells(lngRowIndex, lngColIxToFilter) = lngLevel Then
If rngResult Is Nothing Then
Set rngResult = rngToFilter.Cells(lngRowIndex, lngColIxForValue)
Else
Set rngResult = Union(rngResult, rngToFilter.Cells(lngRowIndex, lngColIxForValue))
End If
End If
Next lngRowIndex
Set MonstersInLevel_AsRange = rngResult
End Function
Function MonstersInLevel_AsVariant(rngToFilter As Range, _
ByVal lngLevel As Long, _
ByVal lngColIxToFilter As Long, _
ByVal lngColIxForValue As Long) As Variant
Dim varResult As Variant
Dim lngRowIndex As Long
Dim lngResultIndex As Long
lngResultIndex = 0
ReDim varResult(0)
For lngRowIndex = 1 To rngToFilter.Rows.Count
If rngToFilter.Cells(lngRowIndex, lngColIxToFilter) = lngLevel Then
lngResultIndex = lngResultIndex + 1
ReDim Preserve varResult(1 To lngResultIndex)
varResult(lngResultIndex) = rngToFilter.Cells(lngRowIndex, lngColIxForValue)
End If
Next lngRowIndex
MonstersInLevel_AsVariant = varResult
End Function
Test output:
' Output as Range
' $B$5:$B$6,$B$8
' ---------------
' Output as Variant
' 3
' 5
' 4
' ---------------
Based on Christian Buses answer (https://stackoverflow.com/a/65671334/16578424) I wrote a generic function to use the FILTER-function.
It returns a one-dimensional array with the filtered values.
Public Function getFILTERValuesFromRange(rgResult As Range, rgFilter As Range, varValue As Variant) As Variant
If rgResult.Columns.count > 1 Or rgFilter.Columns.count > 1 Then
Err.Raise vbObjectError + 512, , "Only ranges with one column are allowed."
ElseIf rgResult.Rows.count <> rgFilter.Rows.count Then
Err.Raise vbObjectError + 512, , "Both ranges have to be of the same size."
End If
Dim arr1 As Variant
With Application.WorksheetFunction
arr1 = .filter(rgResult, .XLookup(rgFilter, varValue, True, False))
End With
getFILTERValuesFromRange = getOneDimensionalArrayFromRangeArray(arr1)
End Function
Private Function getOneDimensionalArrayFromRangeArray(arr1 As Variant) As Variant
Dim arr2 As Variant
ReDim arr2(LBound(arr1, 1) To UBound(arr1, 1))
Dim i As Long
For i = 1 To UBound(arr1, 1)
arr2(i) = arr1(i, 1)
Next
getOneDimensionalArrayFromRangeArray = arr2
End Function

How to join returned values from named range separated by comma

I've spent hours trying to find out how to join returned values from a named range, but the result is a
run-time error 32 - Type mismatch.
As a newbie I'm still struggling with arrays, so maybe I've overlooked some detail. Thank you for helping me out.
Example: (B1)Benzine, (B2)Diesel, (B3)Hybride -> (E1)Gasoline, (E2)Diesel, (E3)Hybrid
This is the named range:
Another example (to be more clear):
Example 2: (B1)Benzine, (B3)Hybride -> (E1)Gasoline, (E3)Hybrid
Option Explicit
Sub splitter()
Dim i As Long
Dim w As Long
'Dim oWB As Workbook
Dim oWS As Worksheet
Dim oWS9 As Worksheet
Dim rngMOTOR As Range
Dim rngMOTOR2 As Range
Dim arrMOTOR() As Variant
Dim LastRow As Long
'Set oWB = Workbooks("BRONBESTAND.xlsm")
Set oWS = Sheets("ONDERDELEN")
Set oWS9 = Sheets("MOTOR") '5 columns: 1 Short & LONG + 1 NL + 3 Languages !!!!! WARNING
LastRow = oWS.Range("A" & Rows.Count).End(xlUp).Row
For i = 2 To LastRow 'Starting below headers
Set rngMOTOR = oWS.Cells(i, "M") 'MOTOR ...
Set rngMOTOR2 = oWS9.Range("MOTOR") 'MOTOR2: MOTOR - Bronbestand arrPOS = rngPOS2.Value
arrMOTOR = rngMOTOR2.Value
'*********
Dim txt As String
Dim j As Integer
Dim Splitted As Variant
Dim arrMOTORall As Variant
Dim arrMOTORsplit As Variant
Dim Motor3 As String
txt = oWS.Cells(i, "M") 'MOTOR ...
Debug.Print ("txt : ") & i & ": "; txt
If Not IsEmpty(txt) Then
Splitted = Split(txt, ", ")
For j = 0 To UBound(Splitted)
Cells(1, j + 1).Value = Splitted(j)
Debug.Print (" ---> Splitted: ") & Splitted(j)
'**** INSERT *****
For w = LBound(arrMOTOR) To UBound(arrMOTOR)
If arrMOTOR(w, 1) = Splitted(j) Then 'EX: B - Benzine
arrMOTORsplit = (arrMOTOR(w, 4)) '(arrMOTOR(y, 2)) -> 1=SHORT+LONG , 2=NL, 3=FR, 4=EN
Debug.Print (" ---> arrMOTORsplit: ") & i & ": " & arrMOTORsplit
'**** JOIN ****
arrMOTORall = Join(arrMOTORsplit, ", ")
Debug.Print ("arrMOTORall: ") & arrMOTORall
End If
Next w
Next j
End If
Next i
End Sub
Get comma separated strings for each column in named range
I didn't analyze your code, but this should work to receive the first three values joined
"Benzine, Diesel, Hybride" ' e.g. from first column
or
"Gasoline, Diesel, Hybrid" ' e.g. from the fourth column
from a named range "Motor" via the Application.Index function.
Notes
The parameter 0 in this Index function indicates to not choose a specific row, the Parameter ColNo chooses each of your columns in a Loop. A subsequent transposition allows to change the 2 dimensioned array values to a 1-dim array. The Join function needs a 1-dim array and concatenates the chosen column items therein.
Hint: The following sample code uses a fully qualified range reference assuming that you don't call the TestMe procedure from your Personal Macro Library. In the latter case you'd have to change references and workbook identification (not using ThisWorkbook!).
Example code
Option Explicit ' declaration head of your code module
Sub TestMe()
Dim v As Variant, ColNo As Long
' assign first three rows to variant 1-based 2-dim datafield array
v = ThisWorkbook.Worksheets("Motor").[Motor].Resize(3, 4) ' Named range value
' write comma separated list for each column
For ColNo = 1 To 4
Debug.Print Join(Application.Transpose(Application.Index(v, 0, ColNo)), ", ")
Next ColNo
End Sub
EDIT - Flexible Search in ANY ORDER to translate joined lists
This solution allows to return joined search words in any combination using the Application.Index function in an advanced way using row and column arrays as parameters. The main function getSplitters() creates a variant 2-dim array in only three steps without loops and redims and uses two language constants (Const DUTCH and Const ENGLISH).:
assigns data to variant 1-based 2-dim datafield array
gets only the selected rows based on comma separated string values
reduces the same array to Dutch and English columns
Calling Code
Due to your OP the calling code anylyzes all comma separated strings in Column M in your sheet "ONDERDELEN" as far as there are values in column A. This is made by passing these found string values to the main function getSplitters with an innovative approach to get results in only three steps without Loops (see function code below).
Translation is based on values in the named range Motor "B1:E4" in sheet "Motor" where rows comprise different sort of fuel with neighbouring columns for different languages (starting with Dutch in the first column and English in the fourth col).
Note that using VBA it is faster to loop through an array to get values than through a range.
Option Explicit ' declaration head of your code module
Const DUTCH As Integer = 1
Const ENGLISH As Integer = 4
Sub TranslateAnyFuelCombination()
' Purpose: returns comma separated lists in column "M" and translates from Dutch to English
' Example: "Benzine, Hybride, Diesel" (Dutch) gets to "Gasoline, Hybrid, Diesel" in English
Dim s As String
Dim oWS As Worksheet, i&, LastRow&, vMOTOR As Variant
Set oWS = Thisworkbook.Worksheets("ONDERDELEN") ' fully qualified reference
' Get last row of wanted data
LastRow = oWS.Range("A" & Rows.Count).End(xlUp).Row
vMOTOR = oWS.Range("M1:M" & LastRow)
For i = 2 To LastRow 'Starting below headers
Debug.Print getSplitters(vMOTOR(i, 1))
Next i
End Sub
Main function
Function getSplitters(ByVal sRows As String) As String
Dim i As Long, j As Long
Dim v As Variant, a As Variant
' [0] analyze selected rows string, e.g. "Benzine, Hybride, Diesel"
a = getRowAr(sRows) ' -> assign 1-dim Rows Array(1, 3, 2)
' [1] assign data to variant 1-based 2-dim datafield array
v = Application.Transpose(ThisWorkbook.Worksheets("Motor").[Motor]) ' Named range value
' [2] get only selected rows, e.g. 1st, 3rd and 2nd -> in free order (!) Benzine, Hybride, Diesel
v = Application.Transpose(Application.Index(v, _
Application.Evaluate("row(1:" & UBound(v, 2) & ")"), _
a)) ' transposed columns array = selected rows
' [3] reduce to Dutch and English columns
v = Application.Transpose(Application.Index(v, _
Application.Evaluate("row(1:" & (UBound(a) + 1) & ")"), _
Array(DUTCH, ENGLISH))) ' selected columns array (above array retransposed)
' [4] return concatenated strings
getSplitters = Join(Application.Transpose(Application.Transpose(Application.Index(v, 1, 0))), ", ") & " -> " & _
Join(Application.Transpose(Application.Transpose(Application.Index(v, 2, 0))), ", ")
End Function
Two helper functions
Function getRowAr(ByVal sList As String) As Variant
' Purpose: split comma separated list into 1-dim number array in FREE ORDER
' Example: "Benzine, Hybride, Diesel" -> Array(1, 3, 2)
Dim ar, i&
' change words in comma separated list to numbers
ar = Split(Replace(sList, " ", ""), ",")
For i = LBound(ar) To UBound(ar)
ar(i) = val(getNumber(ar(i))) ' change to numbers
Next i
getRowAr = ar ' return
End Function
Function getNumber(ByVal s As String) As Long
' Purpose: replaces dutch search words with corresponding row number
Dim arFuel
' get search words to 1-dim array
arFuel = Application.Index(ThisWorkbook.Worksheets("Motor").[Motor], 0, DUTCH)
' return corresponding number
getNumber = Application.Match(s, arFuel)
End Function
Addendum (Edit due to comment)
The above code works as intended if you are sure that the concatenated search words (or starting parts) actually match else an Error 13 is raised. You can solve this issue in two steps:
Insert an empty first row into your named range Motor (or fill it e.g. with ?, #N/A etc.)
Change the 2nd helper function as follows:
Edited function getNumber()
Function getNumber(ByVal s As String) As Long
' Purpose: replaces dutch search words with corresponding row number
Dim arFuel
' get search words to 1-dim array
arFuel = Application.Index(ThisWorkbook.Worksheets("Motor").[Motor], 0, DUTCH)
' return corresponding number
On Error Resume Next ' provide for not found case
getNumber = Application.Match(s, arFuel, 0) ' find only exact matches
If Err.Number <> 0 Then getNumber = 0 ' could be omitted in case of a zero return
End Function
With 2 arrays this is a possible solution:
Sub TestMe()
Dim inputString As String
Dim arrString As Variant
Dim arrResult As Variant
inputString = "Benzine, Diesel, Hybride"
arrString = Split(inputString, ",")
Dim total As Long: total = UBound(arrString)
ReDim arrResult(total)
Dim i As Long
For i = LBound(arrString) To UBound(arrString)
arrResult(total - i) = Trim(arrString(i))
Next i
Debug.Print Join(arrResult, " ,")
End Sub
However, there is a classic solution of this problem, reversing everything twice:
Sub TestMe()
Dim inputString As String
inputString = "Benzine, Diesel, Hybride"
inputString = StrReverse(inputString)
Dim arr As Variant: arr = Split(inputString, ",")
Dim i As Long
For i = LBound(arr) To UBound(arr)
arr(i) = Trim(StrReverse(arr(i)))
Next i
Debug.Print Join(arr, ", ")
End Sub

Cleaning up an array

I have a very large array in VBA which includes a lot of 0 values that I'd like to remove. Something like this:
A B C 12345
D E F 848349
G H I 0
J K L 0
M N O 0
P Q R 4352
S T U 0
V W X 0
I would like to be able to quickly/easily strip out all rows from this array that have a zero in the 4th column, resulting in something like this:
A B C 12345
D E F 848349
P Q R 4352
This array has 100,000 or so rows, that hopefully gets down to a number closer to 20,000 or 30,000 rows instead after processing.
I assume iterating through every entry will prove very time-consuming.
Is there another way that is faster?
I'm not aware of any other way in VBA than to loop through the array and write another array/list.
What makes it trickier is that your array looks to be two-dimensional and VBA will only allow you to redim the last dimension. From the look of your data, you'd want to redim the first dimension as you iterate through your array.
There are several solutions:
Iterate your data twice - once to get the array size (and probably to store the relevant row numbers) and a second time to transfer the raw data into your new data.
Iterate once and just reverse your dimensions (ie row is last).
Use an array of arrays, so that each array only has one dimension).
Use a Collection which doesn't need to be dimensioned - this would be my preferred option.
Option 4 would look like this (I've assumed your array is zero based):
Dim resultList As Collection
Dim r As Long
Set resultList = New Collection
For r = 0 To UBound(raw, 1)
If raw(r, 3) <> 0 Then
resultList.Add Array(raw(r, 0), raw(r, 1), raw(r, 2), raw(r, 3))
End If
Next
If you have to write to a new array, then here's an example of Option 1:
Dim rowList As Collection
Dim result() As Variant
Dim r As Long
Dim c As Long
Dim v As Variant
Set rowList = New Collection
For r = 0 To UBound(raw, 1)
If raw(r, 3) <> 0 Then
rowList.Add r
End If
Next
ReDim result(rowList.Count - 1, 3) As Variant
c = 0
For Each v In rowList
result(c, 0) = raw(v, 0)
result(c, 1) = raw(v, 1)
result(c, 2) = raw(v, 2)
result(c, 3) = raw(v, 3)
c = c + 1
Next
Okay, it's all off-sheet, so all the arrays are zero-based. To test this set-up, I created a worksheet with four columns, as per your data and using random numbers in the fourth column. I saved this to a text file (TestFile.txt), then read it in to be able to get a zero-based array (Excel ranges are 1-based when you take them into an array). I saved 150000 rows to the text file to properly stress the routine. Yes, I have an SSD and that would affect the 2s run time, but I'd still expect it to run in <10s on a spinning HDD, I think.
Anyway, here's the code (requires a VBA reference to Microsoft Scripting Runtime purely to read in the file):
Public Function ReturnFilteredArray(arrSource As Variant, _
strValueToFilterOut As String) As Variant
Dim arrDestination As Variant
Dim lngSrcCounter As Long
Dim lngDestCounter As Long
ReDim arrDestination(UBound(arrSource, 1) + 1, UBound(arrSource, 2) + 1)
lngDestCounter = 1
For lngSrcCounter = LBound(arrSource, 1) To UBound(arrSource, 1)
' Assuming the array dimensions are (100000, 3)
If CStr(arrSource(lngSrcCounter, 3)) <> strValueToFilterOut Then
' Hit an element we want to include
arrDestination(lngDestCounter, 1) = arrSource(lngSrcCounter, 0)
arrDestination(lngDestCounter, 2) = arrSource(lngSrcCounter, 1)
arrDestination(lngDestCounter, 3) = arrSource(lngSrcCounter, 2)
arrDestination(lngDestCounter, 4) = arrSource(lngSrcCounter, 3)
lngDestCounter = lngDestCounter + 1
End If
Next
ReturnFilteredArray = arrDestination
End Function
Sub TestRun()
Dim fso As FileSystemObject
Dim txs As TextStream
Dim arr As Variant
Dim arr2 As Variant
Dim lngCounter As Long
Debug.Print Now()
Set fso = New FileSystemObject
Set txs = fso.OpenTextFile("E:\Users\Thingy\Desktop\TestFile.txt", ForReading)
arr = Split(txs.ReadAll, vbNewLine)
ReDim arr2(UBound(arr), 3)
For lngCounter = 0 To UBound(arr) - 1
arr2(lngCounter, 0) = Split(arr(lngCounter), vbTab)(0)
arr2(lngCounter, 1) = Split(arr(lngCounter), vbTab)(1)
arr2(lngCounter, 2) = Split(arr(lngCounter), vbTab)(2)
arr2(lngCounter, 3) = Split(arr(lngCounter), vbTab)(3)
Next
arr2 = ReturnFilteredArray(arr2, "0")
Range("L2").Resize(UBound(arr2, 1), 5) = arr2
Debug.Print Now()
End Sub
There are a number of assumptions in there, not least the dimensions. Note the difference in the second dimension counter between arrDestination and arrSource. That's to do with Excel being 1-based and normal arrays being 0-based.
Also, when I'm writing out the array, I needed to bump up the second dimension to 5 in order to get all of the array out to the sheet. I wasn't able to trim off the empty elements since ReDim Preserve only works on the uppermost dimension (columns) and it's the first dimension (rows) that's changing here.
Anywho, this should serve as a reminder that despite its faults Excel is pretty amazing.

Comparing 2-dimension arrays in VB Excel

I'm trying to compare two 2d arrays in VBA Excel.
Source:
1 2 3 4
4 5 6 2
3 3 4 4
Target:
4 5 3 2
1 2 3 4
3 7 7 5
Given the above two 2-d arrays which I will call source and target I want to compare each row from source with entire target and check if it exists in target. For
Example row 1 from source (1 2 3 4) would be considered a match as it would found in target (at row 2). So I need to compare each row in target for a given row from source. If row in source does not exist in target then I will need to make note of this some how in order to mark as not existing in target.
Something on the lines of (not actual code just idea):
For i to ubound(srcArray)
isFound = False
For j To ubound(trgArray)
If srcArray(i) = trgArray(j) Then
isFound = True
If Not isFound Then
//make note of some sort
I know approach worked ok for single dim. array. But trying to do this for 2d arrays in some sort of loop in VB or other method. Not too familiar with VB in Excel. I would also like to look at each row as entire array if possible rather than comparing each element for each array individually.
Here is an example of how to loop and compare the elements of a 2D array:
Sub ArrayCompare()
Dim MyArr1 As Variant, MyArr2 As Variant, X as long, Y as long
MyArr1 = [{1,2,3,4;4,5,6,2;3,3,4,4}]: MyArr2 = [{4,5,3,2;1,2,3,4;3,7,7,5}]
For X = LBound(MyArr1) To UBound(MyArr1)
For Y = LBound(MyArr1, 1) To UBound(MyArr1, 1)
If MyArr1(X, Y) = MyArr2(X, Y) Then MsgBox X & ":" & Y & ":" & MyArr1(X, Y)
Next
Next
End Sub
Here is my updated code to compare each row as a string (Thanks #Tim Williams :)):
Sub ArrayCompare()
Dim MyArr1 As Variant, MyArr2 As Variant, X As Long, Y As Long
MyArr1 = [{1,2,3,4;4,5,6,2;3,3,4,4}]: MyArr2 = [{4,5,3,2;1,2,3,4;3,7,7,5}]
For X = LBound(MyArr1) To UBound(MyArr1)
For Y = LBound(MyArr2) To UBound(MyArr2)
If Join(Application.Transpose(Application.Transpose(Application.Index(MyArr1, X, 0))), "|") = Join(Application.Transpose(Application.Transpose(Application.Index(MyArr2, Y, 0))), "|") Then MsgBox "Found a match at MyArr1 index:" & X & " and MyArr2 index:" & Y
Next
Next
End Sub
If you really want to avoid loops then you use this approach to extract a single "row" out of your 2-d array for comparison purposes, but it might be faster to loop.
Sub Tester()
Dim arr, rw
arr = Range("A1:J10").Value 'get 2-d array from worksheet
'get a 1-d array "row" out of the 2-d array
rw = Application.Transpose( _
Application.Transpose(Application.Index(arr, 1, 0)))
'then you can (eg) create a string for comparison purposes
Debug.Print Join(rw, Chr(0))
End Sub

ReDim Preserve to a multi-dimensional array in VB6

I'm using VB6 and I need to do a ReDim Preserve to a Multi-Dimensional Array:
Dim n, m As Integer
n = 1
m = 0
Dim arrCity() As String
ReDim arrCity(n, m)
n = n + 1
m = m + 1
ReDim Preserve arrCity(n, m)
Whenever I do it as I have written it, I get the following error:
runtime error 9: subscript out of range
Because I can only change the last array dimension, well in my task I have to change the whole array (2 dimensions in my example) !
Is there any workaround or another solution for this?
As you correctly point out, one can ReDim Preserve only the last dimension of an array (ReDim Statement on MSDN):
If you use the Preserve keyword, you can resize only the last array
dimension and you can't change the number of dimensions at all. For
example, if your array has only one dimension, you can resize that
dimension because it is the last and only dimension. However, if your
array has two or more dimensions, you can change the size of only the
last dimension and still preserve the contents of the array
Hence, the first issue to decide is whether 2-dimensional array is the best data structure for the job. Maybe, 1-dimensional array is a better fit as you need to do ReDim Preserve?
Another way is to use jagged array as per Pieter Geerkens's suggestion. There is no direct support for jagged arrays in VB6. One way to code "array of arrays" in VB6 is to declare an array of Variant and make each element an array of desired type (String in your case). Demo code is below.
Yet another option is to implement Preserve part on your own. For that you'll need to create a copy of data to be preserved and then fill redimensioned array with it.
Option Explicit
Public Sub TestMatrixResize()
Const MAX_D1 As Long = 2
Const MAX_D2 As Long = 3
Dim arr() As Variant
InitMatrix arr, MAX_D1, MAX_D2
PrintMatrix "Original array:", arr
ResizeMatrix arr, MAX_D1 + 1, MAX_D2 + 1
PrintMatrix "Resized array:", arr
End Sub
Private Sub InitMatrix(a() As Variant, n As Long, m As Long)
Dim i As Long, j As Long
Dim StringArray() As String
ReDim a(n)
For i = 0 To n
ReDim StringArray(m)
For j = 0 To m
StringArray(j) = i * (m + 1) + j
Next j
a(i) = StringArray
Next i
End Sub
Private Sub PrintMatrix(heading As String, a() As Variant)
Dim i As Long, j As Long
Dim s As String
Debug.Print heading
For i = 0 To UBound(a)
s = ""
For j = 0 To UBound(a(i))
s = s & a(i)(j) & "; "
Next j
Debug.Print s
Next i
End Sub
Private Sub ResizeMatrix(a() As Variant, n As Long, m As Long)
Dim i As Long
Dim StringArray() As String
ReDim Preserve a(n)
For i = 0 To n - 1
StringArray = a(i)
ReDim Preserve StringArray(m)
a(i) = StringArray
Next i
ReDim StringArray(m)
a(n) = StringArray
End Sub
Since VB6 is very similar to VBA, I think I might have a solution which does not require this much code to ReDim a 2-dimensional array - using Transpose, if you are working in Excel.
The solution (Excel VBA):
Dim n, m As Integer
n = 2
m = 1
Dim arrCity() As Variant
ReDim arrCity(1 To n, 1 To m)
m = m + 1
ReDim Preserve arrCity(1 To n, 1 To m)
arrCity = Application.Transpose(arrCity)
n = n + 1
ReDim Preserve arrCity(1 To m, 1 To n)
arrCity = Application.Transpose(arrCity)
What is different from OP's question: the lower bound of arrCity array is not 0, but 1. This is in order to let Application.Transpose do it's job.
Note that Transpose is a method of the Excel Application object (which in actuality is a shortcut to Application.WorksheetFunction.Transpose). And in VBA, one must take care when using Transpose as it has two significant limitations: If the array has more than 65536 elements, it will fail. If ANY element's length exceed 256 characters, it will fail. If neither of these is an issue, then Transpose will nicely convert the rank of an array form 1D to 2D or vice-versa.
Unfortunately there is nothing like 'Transpose' build into VB6.
In regards to this:
"in my task I have to change the whole array (2 dimensions"
Just use a "jagged" array (ie an array of arrays of values). Then you can change the dimensions as you wish. You can have a 1-D array of variants, and the variants can contain arrays.
A bit more work perhaps, but a solution.
I haven't tested every single one of these answers but you don't need to use complicated functions to accomplish this. It's so much easier than that! My code below will work in any office VBA application (Word, Access, Excel, Outlook, etc.) and is very simple. Hope this helps:
''Dimension 2 Arrays
Dim InnerArray(1 To 3) As Variant ''The inner is for storing each column value of the current row
Dim OuterArray() As Variant ''The outer is for storing each row in
Dim i As Byte
i = 1
Do While i <= 5
''Enlarging our outer array to store a/another row
ReDim Preserve OuterArray(1 To i)
''Loading the current row column data in
InnerArray(1) = "My First Column in Row " & i
InnerArray(2) = "My Second Column in Row " & i
InnerArray(3) = "My Third Column in Row " & i
''Loading the entire row into our array
OuterArray(i) = InnerArray
i = i + 1
Loop
''Example print out of the array to the Intermediate Window
Debug.Print OuterArray(1)(1)
Debug.Print OuterArray(1)(2)
Debug.Print OuterArray(2)(1)
Debug.Print OuterArray(2)(2)
I know this is a bit old but I think there might be a much simpler solution that requires no additional coding:
Instead of transposing, redimming and transposing again, and if we talk about a two dimensional array, why not just store the values transposed to begin with. In that case redim preserve actually increases the right (second) dimension from the start. Or in other words, to visualise it, why not store in two rows instead of two columns if only the nr of columns can be increased with redim preserve.
the indexes would than be 00-01, 01-11, 02-12, 03-13, 04-14, 05-15 ... 0 25-1 25 etcetera instead of 00-01, 10-11, 20-21, 30-31, 40-41 etcetera.
As long as there is only one dimension that needs to be redimmed-preserved the approach would still work: just put that dimension last.
As only the second (or last) dimension can be preserved while redimming, one could maybe argue that this is how arrays are supposed to be used to begin with.
I have not seen this solution anywhere so maybe I'm overlooking something?
(Posted earlier on similar question regarding two dimensions, extended answer here for more dimensions)
You can use a user defined type containing an array of strings which will be the inner array. Then you can use an array of this user defined type as your outer array.
Have a look at the following test project:
'1 form with:
' command button: name=Command1
' command button: name=Command2
Option Explicit
Private Type MyArray
strInner() As String
End Type
Private mudtOuter() As MyArray
Private Sub Command1_Click()
'change the dimensens of the outer array, and fill the extra elements with "1"
Dim intOuter As Integer
Dim intInner As Integer
Dim intOldOuter As Integer
intOldOuter = UBound(mudtOuter)
ReDim Preserve mudtOuter(intOldOuter + 2) As MyArray
For intOuter = intOldOuter + 1 To UBound(mudtOuter)
ReDim mudtOuter(intOuter).strInner(intOuter) As String
For intInner = 0 To UBound(mudtOuter(intOuter).strInner)
mudtOuter(intOuter).strInner(intInner) = "1"
Next intInner
Next intOuter
End Sub
Private Sub Command2_Click()
'change the dimensions of the middle inner array, and fill the extra elements with "2"
Dim intOuter As Integer
Dim intInner As Integer
Dim intOldInner As Integer
intOuter = UBound(mudtOuter) / 2
intOldInner = UBound(mudtOuter(intOuter).strInner)
ReDim Preserve mudtOuter(intOuter).strInner(intOldInner + 5) As String
For intInner = intOldInner + 1 To UBound(mudtOuter(intOuter).strInner)
mudtOuter(intOuter).strInner(intInner) = "2"
Next intInner
End Sub
Private Sub Form_Click()
'clear the form and print the outer,inner arrays
Dim intOuter As Integer
Dim intInner As Integer
Cls
For intOuter = 0 To UBound(mudtOuter)
For intInner = 0 To UBound(mudtOuter(intOuter).strInner)
Print CStr(intOuter) & "," & CStr(intInner) & " = " & mudtOuter(intOuter).strInner(intInner)
Next intInner
Print "" 'add an empty line between the outer array elements
Next intOuter
End Sub
Private Sub Form_Load()
'init the arrays
Dim intOuter As Integer
Dim intInner As Integer
ReDim mudtOuter(5) As MyArray
For intOuter = 0 To UBound(mudtOuter)
ReDim mudtOuter(intOuter).strInner(intOuter) As String
For intInner = 0 To UBound(mudtOuter(intOuter).strInner)
mudtOuter(intOuter).strInner(intInner) = CStr((intOuter + 1) * (intInner + 1))
Next intInner
Next intOuter
WindowState = vbMaximized
End Sub
Run the project, and click on the form to display the contents of the arrays.
Click on Command1 to enlarge the outer array, and click on the form again to show the results.
Click on Command2 to enlarge an inner array, and click on the form again to show the results.
Be careful though: when you redim the outer array, you also have to redim the inner arrays for all the new elements of the outer array
I stumbled across this question while hitting this road block myself. I ended up writing a piece of code real quick to handle this ReDim Preserve on a new sized array (first or last dimension). Maybe it will help others who face the same issue.
So for the usage, lets say you have your array originally set as MyArray(3,5), and you want to make the dimensions (first too!) larger, lets just say to MyArray(10,20). You would be used to doing something like this right?
ReDim Preserve MyArray(10,20) '<-- Returns Error
But unfortunately that returns an error because you tried to change the size of the first dimension. So with my function, you would just do something like this instead:
MyArray = ReDimPreserve(MyArray,10,20)
Now the array is larger, and the data is preserved. Your ReDim Preserve for a Multi-Dimension array is complete. :)
And last but not least, the miraculous function: ReDimPreserve()
'redim preserve both dimensions for a multidimension array *ONLY
Public Function ReDimPreserve(aArrayToPreserve,nNewFirstUBound,nNewLastUBound)
ReDimPreserve = False
'check if its in array first
If IsArray(aArrayToPreserve) Then
'create new array
ReDim aPreservedArray(nNewFirstUBound,nNewLastUBound)
'get old lBound/uBound
nOldFirstUBound = uBound(aArrayToPreserve,1)
nOldLastUBound = uBound(aArrayToPreserve,2)
'loop through first
For nFirst = lBound(aArrayToPreserve,1) to nNewFirstUBound
For nLast = lBound(aArrayToPreserve,2) to nNewLastUBound
'if its in range, then append to new array the same way
If nOldFirstUBound >= nFirst And nOldLastUBound >= nLast Then
aPreservedArray(nFirst,nLast) = aArrayToPreserve(nFirst,nLast)
End If
Next
Next
'return the array redimmed
If IsArray(aPreservedArray) Then ReDimPreserve = aPreservedArray
End If
End Function
I wrote this in like 20 minutes, so there's no guarantees. But if you would like to use or extend it, feel free. I would've thought that someone would've had some code like this up here already, well apparently not. So here ya go fellow gearheads.
This is more compact and respect the intial first position in array and just use the inital bound to add old value.
Public Sub ReDimPreserve(ByRef arr, ByVal size1 As Long, ByVal size2 As Long)
Dim arr2 As Variant
Dim x As Long, y As Long
'Check if it's an array first
If Not IsArray(arr) Then Exit Sub
'create new array with initial start
ReDim arr2(LBound(arr, 1) To size1, LBound(arr, 2) To size2)
'loop through first
For x = LBound(arr, 1) To UBound(arr, 1)
For y = LBound(arr, 2) To UBound(arr, 2)
'if its in range, then append to new array the same way
arr2(x, y) = arr(x, y)
Next
Next
'return byref
arr = arr2
End Sub
I call this sub with this line to resize the first dimension
ReDimPreserve arr2, UBound(arr2, 1) + 1, UBound(arr2, 2)
You can add an other test to verify if the initial size is not upper than new array. In my case it's not necessary
Easiest way to do this in VBA is to create a function that takes in an array, your new amount of rows, and new amount of columns.
Run the below function to copy in all of the old data back to the array after it has been resized.
function dynamic_preserve(array1, num_rows, num_cols)
dim array2 as variant
array2 = array1
reDim array1(1 to num_rows, 1 to num_cols)
for i = lbound(array2, 1) to ubound(array2, 2)
for j = lbound(array2,2) to ubound(array2,2)
array1(i,j) = array2(i,j)
next j
next i
dynamic_preserve = array1
end function
Function Redim2d(ByRef Mtx As Variant, ByVal QtyColumnToAdd As Integer)
ReDim Preserve Mtx(LBound(Mtx, 1) To UBound(Mtx, 1), LBound(Mtx, 2) To UBound(Mtx, 2) + QtyColumnToAdd)
End Function
'Main Code
sub Main ()
Call Redim2d(MtxR8Strat, 1) 'Add one column
end sub
'OR
sub main2()
QtyColumnToAdd = 1 'Add one column
ReDim Preserve Mtx(LBound(Mtx, 1) To UBound(Mtx, 1), LBound(Mtx, 2) To UBound(Mtx, 2) + QtyColumnToAdd)
end sub
If you not want include other function like 'ReDimPreserve' could use temporal matrix for resizing. On based to your code:
Dim n As Integer, m As Integer, i as Long, j as Long
Dim arrTemporal() as Variant
n = 1
m = 0
Dim arrCity() As String
ReDim arrCity(n, m)
n = n + 1
m = m + 1
'VBA automatically adapts the size of the receiving matrix.
arrTemporal = arrCity
ReDim arrCity(n, m)
'Loop for assign values to arrCity
For i = 1 To UBound(arrTemporal , 1)
For j = 1 To UBound(arrTemporal , 2)
arrCity(i, j) = arrTemporal (i, j)
Next
Next
If you not declare of type VBA assume that is Variant.
Dim n as Integer, m As Integer

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