I am using SQL and I would like this number '1000' to appear once per month. I have a record set which has the first of every month appearing multiple times. I would like the number '1000' to appear once only and then '0' for the remaining records until the next month appears. I would like the below please- maybe a case type statement/order parition by? I am using SQL Server 2018 ##SQLSERVER. Please see table below of how i would like the data to appear.
Many Thanks :)
Date
Amount
01/01/2022
1000
01/01/2022
0
01/01/2022
0
01/02/2022
1000
01/02/2022
0
01/02/2022
0
01/03/2022
1000
01/03/2022
0
Solution for your problem:
WITH CT1 AS
(
SELECT *,
ROW_NUMBER() OVER(PARTITION BY CONCAT(MONTH([Date]),YEAR([Date])) ORDER BY [Date]) as rn
FROM your_table
)
SELECT [Date],
CASE WHEN rn = 1 THEN 1000 ELSE 0 END AS Amount
FROM CT1;
Working Example: DB<>Fiddle Link
Given just a list of dates you could use row_number and a conditional expression to arbitrarily assign one row of each month a value of 1000
select *,
Iif(Row_Number() over(partition by Month(date) order by (select null)) = 1, 1000, 0) Amount
from t
order by [date], Amount desc;
Related
Is there a relatively simple way to create rows in a table based on a range of dates?
For example; given:
ID
Date_min
Date_max
1
2022-02-01
2022-20-05
2
2022-02-09
2022-02-12
I want to output:
ID
Date_in_Range
1
2022-02-01
1
2022-02-02
1
2022-02-03
1
2022-02-04
1
2022-02-05
2
2022-02-09
2
2022-02-10
2
2022-02-11
2
2022-02-12
I saw a solution when the range is integer based (How to create rows based on the range of all values between min and max in Snowflake (SQL)?)
But in order to use that approach GENERATOR(ROWCOUNT => 1000) I have to convert my dates to integers and back, and it just gets very messy very quick, especially since I need to apply this to millions of rows.
So, I was wondering if there is a simpler way to do it when dealing with dates instead of integers? Any hints anyone can provide?
Another one without using generator -
with data (ID,Date_min,Date_max) as (
select * from values
(1,to_date('2022-02-01','YYYY-DD-MM'),to_date('2022-20-05','YYYY-DD-MM')),
(2,to_date('2022-02-09','YYYY-DD-MM'),to_date('2022-02-12','YYYY-DD-MM'))
)
select id,
Date_min,
Date_max,
dateadd(day, index, Date_min) day_slots from data,
table(split_to_table(repeat(',',datediff(day, Date_min, Date_max)-1),','));
SQL with first date -
with data (ID,Date_min,Date_max) as (
select * from values
(1,to_date('2022-02-01','YYYY-DD-MM'),to_date('2022-20-05','YYYY-DD-MM')),
(2,to_date('2022-02-09','YYYY-DD-MM'),to_date('2022-02-12','YYYY-DD-MM'))
)
select id,
dateadd(month, index-1, Date_min) day_slots from data,
table(split_to_table(repeat(',',datediff(month, Date_min, Date_max)),','));
But in order to use that approach GENERATOR(ROWCOUNT => 1000) I have to convert my dates to integers and back, and it just gets very messy very quick, especially since I need to apply this to millions of rows.
There is no need to convert date to int back and forth, just simple DATEADD('day', num, start_date)
Pseudocode:
WITH sample_data(id, date_min, date_max) AS (
SELECT 1, '2022-02-01'::DATE, '2022-02-05'::DATE
UNION
SELECT 2, '2022-02-09'::DATE, '2022-02-12'::DATE
) , numbers AS (
SELECT ROW_NUMBER() OVER(ORDER BY SEQ4())-1 AS num -- 0 based
FROM TABLE(GENERATOR(ROWCOUNT => 1000)) -- should match max anticipated span
)
SELECT s.id, DATEADD(DAY, n.num, s.date_min) AS calculated_date
FROM sample_data AS s
JOIN numbers AS n
ON DATEADD('DAY', n.num, s.date_min) BETWEEN s.date_min AND s.date_max
ORDER BY s.id, calculated_date;
Ouptut:
I have a table that contains Transactions of Customers.
I should Find Customers That had have at least 2 transaction with amount>20000 in Three consecutive days each month.
For example , Today is 2022/03/12 , I should Gather Data Of Transactions From 2022/02/13 To 2022/03/12, Then check These Data and See If a Customer had at least 2 Transaction With Amount>=20000 in Three consecutive days.
For Example, Consider Below Table:
Id
CustomerId
Transactiondate
Amount
1
1
2022-01-01
50000
2
2
2022_02_01
20000
3
3
2022_03_05
30000
4
3
2022_03_07
40000
5
2
2022_03_07
20000
6
4
2022_03_07
30000
7
4
2022_03_07
30000
The Out Put Should be : CustomerId =3 and CustomerId=4
I write query that Find Customer For Special day , but i don't know how to find these customers in one month with out using loop.
the query for special day is:
With cte (select customerid, amount, TransactionDate,Dateadd(day,-2,TransactionDate) as PrevDate
From Transaction
Where TransactionDate=2022-03-12)
Select CustomerId,Count(*)
From Cte
Where
TransactionDate>=Prevdate and TransactionDate<=TransactionDate
And Amount>=20000
Group By CustomerId
Having count(*)>=2
Hi there are many options how to achieve this.
I think that easies (from perfomance maybe not) is using LAG function:
WITH lagged_days AS (
SELECT
ISNULL(LAG(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id),
LEAD(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id)) lagged_dt
,*
FROM Transaction
), valid_cust_base as (
SELECT
*
FROM lagged_days
WHERE DATEPART(MONTH, lagged) = DATEPART(MONTH, Transactiondate)
AND datediff(day, Transactiondate, lagged_dt) <= 3
AND Amount >= 20000
)
SELECT
CustomerID
FROM valid_cust_base
GROUP BY CustomerID
HAVING COUNT(*) >= 2
First I have created lagged TransactionDate over customer (I assume that id is incremental). Then I have Selected only transactions within one month, with amount >= 20000 and where date difference between transaction is less then 4 days. Then just select customers who had more than 1 transaction.
In LAG First value is always missing per Customer missing, but you still need to be able say: 1st and 2nd transaction are within 3 days. Thats why I am replacing first NULL value with LEAD. It doesn't matter if you use:
ISNULL(LAG(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id),
LEAD(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id)) lagged_dt
OR
ISNULL(LEAD(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id),
LAG(Transactiondate) OVER(PARTITION BY CustomerID ORDER BY id)) lagged_dt
The main goal is to have for each transaction closest TransactionDate.
Lets say I have this query:
SELECT id, date, amount, cancelled
FROM transactions
Which gives me the following results:
id date amount cancelled
1 01/2019 25.10 0
1 02/2019 19.55 1
1 06/2019 20.33 0
2 10/2019 11.00 0
If there are duplicate IDs, how can I get the one with the latest date? So it would look like this:
id date amount cancelled
1 06/2019 20.33 0
2 10/2019 11.00 0
One method is with ROW_NUMBER and a common table expression like this example. In a multi-statement batch, be mindful to terminate the preceding statement with a semi-colon to avoid parsing errors.
WITH data_with_date_sequence AS (
SELECT
id
, date
, amount
, cancelled
, ROW_NUMBER() OVER(PARTITION BY id ORDER BY date DESC) AS seq
FROM dbo.SomeTable
)
SELECT
id
, date
, amount
, cancelled
FROM data_with_date_sequence
WHERE seq = 1;
One option could be to use ROW_NUMBER function, which will group rows by id and order them by date within same id.
;WITH max_dates AS (
SELECT id,
, date
, amount
, cancelled
, ROW_NUMBER() OVER (PARTITION BY id ORDER BY date DESC) AS Position
FROM transactions
)
SELECT * FROM max_dates WHERE Position = 1
I need a query that returns all the hours of the day in 12 hour format
ex: 12:00 am, 1:00am, 2:00am etc. This is going to be used in SSRS as a selection field for a parameter for time. I need to select records within a date range and then from a time range in that date range. I have this query which returns the time in 24 hour format but it is not working properly in SSRS:
With CTE(N)
AS
(
SELECT 0
UNION ALL
SELECT N+30
FROM CTE
WHERE N+5<24*60
)
SELECT CONVERT(TIME,DATEADD(minute,N,0) ,108)
FROM CTE
OPTION (MAXRECURSION 0)
This is how I would do it:
DECLARE #t time(1) = '00:00'; --I use 1 as when I use REPLACE later it means that I can "identify" the correct :00 to remove
WITH N AS(
SELECT N
FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL)) N(N)),
Tally AS(
SELECT TOP 24 ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I
FROM N N1, N N2),
Times AS(
SELECT DATEADD(HOUR, I,#t) AS [Time]
FROM Tally)
SELECT T.[Time],
REPLACE(CONVERT(varchar(12),T.Time,9),':00.0',' ') AS TimeString
FROM Times T
ORDER BY T.[Time] ASC;
Note that I return both a time and varchar datatype; both are important as the ordering of the data for a varchar would be quite different to start with and if you are using SSRS, I suspect you want the value of TimeString as a presentation thing and not the actual value.
I have following data in my table activity_count
Activitydate |count
2013-12-20:18:25:45 10
2013-12-20:18:23:40 20
2013-12-20:17:25:45 5
2013-12-20:17:25:45 10
2013-12-20:17:25:45 10
I want to get the total counts for each hour,ie the result should be following
Activitydate |count
2013-12-20:18:00:00 30
2013-12-20:17:00:00 25
If you're using mySQL try below:
SELECT CONCAT(LEFT(DATE(activitydate),10),' ',HOUR(activitydate),':00:00') as DateHour,
SUM(count) as TotalCount
FROM activity_count
GROUP BY DATE(activitydate),HOUR(activitydate)
See my Demo.
However, if MSSQL try this one:
SELECT CAST(CAST(activitydate as DATE) AS nvarchar(15))+' '+CAST(datepart(HOUR,activitydate) as CHAR(2))+':00:00' as DateHour,
SUM([count]) as TotalCount
FROM activity_count
GROUP BY CAST(CAST(activitydate as DATE) AS nvarchar(15)),DATEPART(HOUR, activitydate)
See MSSQL Demo
please try this
select cast(cast(Activitydate as date) as datetime)+cast(datepart(hour,Activitydate),
count(*)
from activity_count
group by cast(cast(Activitydate as date) as datetime)+cast(datepart(hour,Activitydate)
Try HOUR function
select
Activitydate,
count(*) as 'count'
from activity_count
GROUP BY HOUR(Activitydate)
HOUR(time)
HOUR(time)
Returns the hour for time. The range of the return value is 0 to 23 for time-of-day values. However, the range of TIME values actually is much larger, so HOUR can return values greater than 23.