Running bash in interactive mode stops my own shell - c

Question

I'm writing a shell as a hobby and more specifically because I'm bored but passionate. My shell works great, I even implemented pipelines. But there is one thing that keeps my shell crashing or entering in a for loop and it's only happening when I run bash through my shell.
So I'm in trouble when I issue this command bash -ic <some_command>. If my shell is the default one and I launch an instance and I issue this command above, my shell gets in an infinite loop. Whereas if the default shell is bash and I launch an instance then I run my shell through the first bash prompt and THEN run bash -ic <some_command> through my shell, it gets stopped and I'm back to bash.
Here is a minimal example of the main issue:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
void loop_pipe(char ***cmd)
{
pid_t pid, wpid;
int status;
pid = fork();
if (pid == 0)
{
// Child process
if (execvp((*cmd)[0],*cmd) == -1)
perror("Command error");
exit(EXIT_FAILURE);
}
else if (pid < 0)
{
// Error forking
perror("Fork error");
}
else
{
// Parent process
do {
wpid = waitpid(pid, &status, WUNTRACED);
} while (!WIFEXITED(status) && !WIFSIGNALED(status));
}
}
int main()
{
char *ls[] = {"bash", "-ic", "uname", NULL};
char **cmd[] = {ls, NULL};
while (1)
{
loop_pipe(cmd);
}
}
The problem here is that after running the command, the process gets stopped so the output is this:
./a.out
Linux
[4]+ Stopped ./a.out
I really don't now what's causing this, but it has to do with bash conflicting with my shell. I also tried to ignore SIGINT and SIGSTOP But it still gets stopped (by bash i guess ?) If someone could help the situation that would be great.
Because my project has more than one source file, I link it not sure if it's right way to do it.