Can anyone provide a sample code to zip a file in codename one with zipme?
I checked the sample on zipme webpage but only have the unzip sample code.
zipme project
Thank you.
I didn't try this but I guess it would look pretty close to this:
try(ZipOutputStream output = new ZipOutputStream(destinationOutputStream)) {
output.putNextEntry(new ZipEntry("NameOfFileInZip"));
output.write(byteArrayContentOfFileInZip);
}
Check out ZipOutputStream samples for further guidance. Should be pretty similar to standard JavaSE only with different packages and more limited API.
I have done a procedure to zip a file. But I can't unzip the zip file by 7-zip.
public static void zipFile(String zipFile, String srcFile) throws IOException {
InputStream i = FileSystemStorage.getInstance().openInputStream(srcFile);
OutputStream o = FileSystemStorage.getInstance().openOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(o);
zos.putNextEntry(new ZipEntry(srcFile));
int len;
byte[] buffer = new byte[1024];
while ((len = i.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
zos.closeEntry();
}
Related
Is there anyway I can get the last downloaded file using selenium. Currently I am downloading an Excel file using selenium, I need to get that file and read it. the reading part is covered, but I need the downloaded file path and file name in order to read it. So far i haven't found anything which can help. I am looking mainly for a google chrome solution, but firefox works too.
Thanks in advance
You can save your download to a fix location by using the profile. Check these discussions:
Downloading file to specified location with Selenium and python
Access to file download dialog in Firefox
As you have mentioned that you have covered the reading part. You can read it from that fixed location.
Below is the code snippet that can help resolve the above query:
**Changes in driver file:**
protected File downloadsDir = new File("");
if (browser.equalsIgnoreCase("firefox"))
{
downloadsDir = new File(System.getProperty("user.dir") + File.separatorChar + "downloads");
if (!downloadsDir.exists())
{
boolean ddCreated = downloadsDir.mkdir();
if (!ddCreated) {
System.exit(1);
}
}
}
/*Firefox browser profile*/
FirefoxProfile firefoxProfile = new FirefoxProfile();
firefoxProfile.setPreference("browser.download.folderList", 2);
firefoxProfile.setPreference("browser.download.manager.showWhenStarting", false);
firefoxProfile.setPreference("browser.download.dir", downloadsDir.getAbsolutePath());
firefoxProfile.setPreference("browser.helperApps.neverAsk.saveToDisk", "text/plain,application/octet-stream");
**Empty the download directory[Can be implemented as #BeforeClass]:**
public void emptyDownloadsDir()
{
// Verify downloads dir is empty, if not remove all files.
File[] downloadDirFiles = downloadsDir.listFiles();
if (downloadDirFiles != null) {
for (File f : downloadDirFiles) {
if (f.exists()) {
boolean deleted = FileUtility.delete(f);
assertTrue(deleted, "Files are not deleted from system local directory" + downloadsDir + ", skipping the download tests.");
}
}
}
}
**Check the Latest downloaded file:**
/*Test file*/
protected static String EXCEL_FILE_NAME= Test_Excel_File.xls;
protected static int WAIT_IN_SECONDS_DOWNLOAD = 60;
// Wait for File download.
int counter = 0;
while (counter++ < WAIT_IN_SECONDS_DOWNLOAD && (downloadsDir.listFiles().length != 1 || downloadsDir.listFiles()[0].getName().matches(EXCEL_FILE_NAME))) {
this.wait(2);
}
// Verify the downloaded File by comparing name.
File[] downloadDirFiles = downloadsDir.listFiles();
String actualName = null;
for (File file : downloadDirFiles) {
actualName = file.getName();
if (actualName.equals(EXCEL_FILE_NAME)) {
break;
}
}
assertEquals(actualName, EXCEL_FILE_NAME, "Last Downloaded File name does not matches.");
import os
import glob
home = os.path.expanduser("~")
downloadspath=os.path.join(home, "Downloads")
list_of_files = glob.glob(downloadspath+"\*.pptx") # * means all if need specific format then *.csv
latest_file = max(list_of_files, key=os.path.getctime)
Simplified solution to get the path to last file in Downloads folder. The above code will get path of the latest .pptx file in Downlodas. Change the extension as required. Or else you can chose not to specify the extension
Note, Shared answer is specific to Chrome Browser and will ONLY return LATEST downloaded file. But we can modify accordingly it for other browsers and for all files as well.
Let say, how we test latest downloaded file in browser.
In existing test browser Open NewTab Window
Go to
downloads (chrome://downloads/)
Check if expected file is there
or not
Now same thing in selenium using java
driver.get("chrome://downloads/");
JavascriptExecutor js = (JavascriptExecutor) driver;
WebElement element = (WebElement) js.executeScript("return document.querySelector('downloads-manager').shadowRoot.querySelector('#mainContainer > iron-list > downloads-item').shadowRoot.querySelector('#content')");
String latestFileName= element.getText();
Given a simple route like this
route.from("direct:foo")
.split()
.tokenize("\n")
.streaming()
.to("stream:file?fileName=target/streaming${header.count}.txt&closeOnDone=true");
which I then trigger with this
#Test
public void splitAndStreamToFile() {
StringBuilder builder = new StringBuilder();
for(int i = 0; i < 500; i++) {
builder.append(i);
builder.append("\n");
}
for(int i = 0; i < 10; i++) {
template.sendBodyAndHeader(builder.toString(), "count", i);
}
}
I get one big file that contains 10 times 500 lines, where I would have hoped to have 10 files that contain 500 lines each.
In other words, it seems that the fileName in the stream:file endpoint is not dynamic. I am wondering if this is at all possible? My google-fu turned up nothing so far.
EDIT:
With Claus' answer, I got it to work like this:
route.from("direct:foo")
.split()
.tokenize("\n")
.streaming()
.recipientList(route.simple("stream:file?fileName=target/streaming${header.count}.txt&closeOnDone=true"));
Its a dynamic to which there is an EIP pattern for:
http://camel.apache.org/how-to-use-a-dynamic-uri-in-to.html
But it could be a good idea to support the file/simple language on the fileName option as the regular file component does. Fell free to log a JIRA ticket about this improvement.
Sourcecode of the StreamProducer looks like it does not support any of the expression languages of Camel yet:
private OutputStream resolveStreamFromFile() throws IOException {
String fileName = endpoint.getFileName();
ObjectHelper.notEmpty(fileName, "fileName");
LOG.debug("About to write to file: {}", fileName);
File f = new File(fileName);
// will create a new file if missing or append to existing
f.getParentFile().mkdirs();
f.createNewFile();
return new FileOutputStream(f, true);
}
See sourecode.
If you need dynamic filenames, you should take a look at the file component, which supports the file language and the CamelFileName header.
In short,
toD uri=stream:file...
will do it.
The "toD" basically translates the "simple" or "file language" before it hits the stream component code...so that works for "fileName=..."
We're using "Google Cloud Storage Client Library" for app engine, with simply "GcsFileOptions.Builder.contentEncoding("gzip")" at file creation time, we got the following problem when reading the file:
com.google.appengine.tools.cloudstorage.NonRetriableException: java.lang.RuntimeException: com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl$1#1c07d21: Unexpected cause of ExecutionException
at com.google.appengine.tools.cloudstorage.RetryHelper.doRetry(RetryHelper.java:87)
at com.google.appengine.tools.cloudstorage.RetryHelper.runWithRetries(RetryHelper.java:129)
at com.google.appengine.tools.cloudstorage.RetryHelper.runWithRetries(RetryHelper.java:123)
at com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl.read(SimpleGcsInputChannelImpl.java:81)
...
Caused by: java.lang.RuntimeException: com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl$1#1c07d21: Unexpected cause of ExecutionException
at com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl$1.call(SimpleGcsInputChannelImpl.java:101)
at com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl$1.call(SimpleGcsInputChannelImpl.java:81)
at com.google.appengine.tools.cloudstorage.RetryHelper.doRetry(RetryHelper.java:75)
... 56 more
Caused by: java.lang.IllegalStateException: com.google.appengine.tools.cloudstorage.oauth.OauthRawGcsService$2#1d8c25d: got 46483 > wanted 19823
at com.google.common.base.Preconditions.checkState(Preconditions.java:177)
at com.google.appengine.tools.cloudstorage.oauth.OauthRawGcsService$2.wrap(OauthRawGcsService.java:418)
at com.google.appengine.tools.cloudstorage.oauth.OauthRawGcsService$2.wrap(OauthRawGcsService.java:398)
at com.google.appengine.api.utils.FutureWrapper.wrapAndCache(FutureWrapper.java:53)
at com.google.appengine.api.utils.FutureWrapper.get(FutureWrapper.java:90)
at com.google.appengine.tools.cloudstorage.SimpleGcsInputChannelImpl$1.call(SimpleGcsInputChannelImpl.java:86)
... 58 more
What else should be added to read files with "gzip" compression to be able to read the content in app engine? ( curl cloud storage URL from client side works fine for both compressed and uncompressed file )
This is the code that works for uncompressed object:
byte[] blobContent = new byte[0];
try
{
GcsFileMetadata metaData = gcsService.getMetadata(fileName);
int fileSize = (int) metaData.getLength();
final int chunkSize = BlobstoreService.MAX_BLOB_FETCH_SIZE;
LOG.info("content encoding: " + metaData.getOptions().getContentEncoding()); // "gzip" here
LOG.info("input size " + fileSize); // the size is obviously the compressed size!
for (long offset = 0; offset < fileSize;)
{
if (offset != 0)
{
LOG.info("Handling extra size for " + filePath + " at " + offset);
}
final int size = Math.min(chunkSize, fileSize);
ByteBuffer result = ByteBuffer.allocate(size);
GcsInputChannel readChannel = gcsService.openReadChannel(fileName, offset);
try
{
readChannel.read(result); <<<< here the exception was thrown
}
finally
{
......
It is now compressed by:
GcsFilename filename = new GcsFilename(bucketName, filePath);
GcsFileOptions.Builder builder = new GcsFileOptions.Builder().mimeType(image_type);
builder = builder.contentEncoding("gzip");
GcsOutputChannel writeChannel = gcsService.createOrReplace(filename, builder.build());
ByteArrayOutputStream byteStream = new ByteArrayOutputStream(blob_content.length);
try
{
GZIPOutputStream zipStream = new GZIPOutputStream(byteStream);
try
{
zipStream.write(blob_content);
}
finally
{
zipStream.close();
}
}
finally
{
byteStream.close();
}
byte[] compressedData = byteStream.toByteArray();
writeChannel.write(ByteBuffer.wrap(compressedData));
the blob_content is compressed from 46483 bytes to 19823 bytes.
I think it is the google code's bug
https://code.google.com/p/appengine-gcs-client/source/browse/trunk/java/src/main/java/com/google/appengine/tools/cloudstorage/oauth/OauthRawGcsService.java, L418:
Preconditions.checkState(content.length <= want, "%s: got %s > wanted %s", this, content.length, want);
the HTTPResponse has decoded the blob, so the Precondition is wrong here.
If I good understand you have to set mineType:
GcsFileOptions options = new GcsFileOptions.Builder().mimeType("text/html")
Google Cloud Storage does not compress or decompress objects:
https://developers.google.com/storage/docs/reference-headers?csw=1#contentencoding
I hope that's what you want to do .
Looking at your code it seems like there is a mismatch between what is stored and what is read. The documentation specifies that compression is not done for you (https://developers.google.com/storage/docs/reference-headers?csw=1#contentencoding). You will need to do the actual compression manually.
Also if you look at the implementation of the class that throws the exception (https://code.google.com/p/appengine-gcs-client/source/browse/trunk/java/src/main/java/com/google/appengine/tools/cloudstorage/oauth/OauthRawGcsService.java?r=81&spec=svn134) you will notice that you get the original contents back but you're actually expecting compressed content. Check the method readObjectAsync in the above mentioned class.
It looks like the content persisted might not be gzipped or the content-length is not set properly. What you should do is verify length of the compressed stream just before writing it into the channel. You should also verify that the content length is set correctly when doing the http request. It would be useful to see the actual http request headers and make sure that content length header matches the actual content length in the http response.
Also it looks like contentEncoding could be set incorrectly. Try using:.contentEncoding("Content-Encoding: gzip") as used in this TCK test. Although still the best thing to do is inspect the HTTP request and response. You can use wireshark to do that easily.
Also you need to make sure that GCSOutputChannel is closed as that's when the file is finalized.
Hope this puts you on the right track. To gzip your contents you can use java GZIPInputStream.
I'm seeing the same issue, easily reproducable by uploading a file with "gsutil cp -Z", then trying to open it with the following
ByteArrayOutputStream output = new ByteArrayOutputStream();
try (GcsInputChannel readChannel = svc.openReadChannel(filename, 0)) {
try (InputStream input = Channels.newInputStream(readChannel))
{
IOUtils.copy(input, output);
}
}
This causes an exception like this:
java.lang.IllegalStateException:
....oauth.OauthRawGcsService$2#1883798: got 64303 > wanted 4096
at ....Preconditions.checkState(Preconditions.java:199)
at ....oauth.OauthRawGcsService$2.wrap(OauthRawGcsService.java:519)
at ....oauth.OauthRawGcsService$2.wrap(OauthRawGcsService.java:499)
The only work around I've found is to read the entire file into memory using readChannel.read:
int fileSize = 64303;
ByteBuffer result = ByteBuffer.allocate(fileSize);
try (GcsInputChannel readChannel = gcs.openReadChannel(new GcsFilename("mybucket", "mygzippedfile.xml"), 0)) {
readChannel.read(result);
}
Unfortunately, this only works if the size of the bytebuffer is greater or equal to the uncompressed size of the file, which is not possible to get via the api.
I've also posted my comment to an issue registered with google: https://code.google.com/p/googleappengine/issues/detail?id=10445
This is my function for reading compressed gzip files
public byte[] getUpdate(String fileName) throws IOException
{
GcsFilename fileNameObj = new GcsFilename(defaultBucketName, fileName);
try (GcsInputChannel readChannel = gcsService.openReadChannel(fileNameObj, 0))
{
maxSizeBuffer.clear();
readChannel.read(maxSizeBuffer);
}
byte[] result = maxSizeBuffer.array();
return result;
}
The core is that you cannot use the size of the saved file cause Google Storage will give it to you with the original size, so it checks the sizes you expected and the real size and these are differents:
Preconditions.checkState(content.length <= want, "%s: got %s > wanted
%s", this, content.length, want);
So i solved it allocating the biggest amount possible for these files using BlobstoreService.MAX_BLOB_FETCH_SIZE. Actually maxSizeBuffer is only allocated once outsize of the function
ByteBuffer maxSizeBuffer = ByteBuffer.allocate(BlobstoreService.MAX_BLOB_FETCH_SIZE);
And with maxSizeBuffer.clear(); all data is flushed again.
In my app I tried to pass the file path from one activity to another activity using intent.In my receiving activity I got the file path as "null".But when I print the file in first activity it prints the path.From my second activity I attach that file to mail using Gmailsender.This was the code I tried,
private void startRecord()
{
File file = new File(Environment.getExternalStorageDirectory(), "test.pcm");
try
{
file.createNewFile();
OutputStream outputStream = new FileOutputStream(file);
BufferedOutputStream bufferedOutputStream = new BufferedOutputStream(outputStream);
DataOutputStream dataOutputStream = new DataOutputStream(bufferedOutputStream);
int minBufferSize = AudioRecord.getMinBufferSize(8000,
AudioFormat.CHANNEL_IN_MONO,
AudioFormat.ENCODING_PCM_16BIT);
short[] audioData = new short[minBufferSize];
AudioRecord audioRecord = new AudioRecord(MediaRecorder.AudioSource.MIC,
8000,
AudioFormat.CHANNEL_IN_MONO,
AudioFormat.ENCODING_PCM_16BIT,
minBufferSize);
audioRecord.startRecording();
while(recording)
{
int numberOfShort = audioRecord.read(audioData, 0, minBufferSize);
for(int i = 0; i < numberOfShort; i++)
{
dataOutputStream.writeShort(audioData[i]);
}
}
audioRecord.stop();
audioRecord.release();
dataOutputStream.close();
}
catch (IOException e)
{
e.printStackTrace();
}
String audiofile;
audiofile=file.getAbsolutePath();
System.out.println("File Path::::"+audiofile);
}
Intent is,
Intent sigout=new Intent(getApplicationContext(),WeeklyendActivity.class);
sigout.putExtra("mnt/sdcard-test.pcm",audiofile);
startActivity(sigout);
In my receiving activity,
String patty=getIntent().getStringExtra("mnt/sdcard-text.pcm");
System.out.println("paathhhy frfom ::"+patty);
It prints null.Can anyone help me how to get the file path.And more thing I am not sure whether the audio would save in that file correctly?
Please anyone help me!!!Thanks in advance!
Based on your information that audioFile is a variable of type File, when you do this:
sigout.putExtra("mnt/sdcard-test.pcm",audiofile);
you are putting a File object in the extras Bundle. Then, when you try to get the extra from the Bundle you do this:
String patty=getIntent().getStringExtra("mnt/sdcard-text.pcm");
However, the object in this extra is of type File, not type String. This is why you are getting null.
If you only want to pass the name of the file, then put the extra like this:
sigout.putExtra("mnt/sdcard-test.pcm",audiofile.getAbsolutePath());
/*
*This program checks type casting from String to int/double from a file
*/
import java.io.*;
import java.lang.String;
public class ConvertingStringsToNums {
public static void main (String[] args){
File dataFile = new File("/files/scores.dat");
FileReader in;
BufferedReader readFile;
String score;
double avgScore, totalScores = 0;
int numScores = 0;
//------------------------------------------------------------
try {
in = new FileReader(dataFile);
readFile = new BufferedReader(in);
while((score = readFile.readLine()) != null) {
numScores += 1;
System.out.println(score);
totalScores += Double.parseDouble(score);
}
avgScore = totalScores / numScores;
readFile.close();
in.close();
} catch(FileNotFoundException e) {
System.err.println("FileNotFoundException: " + e.getMessage());
} catch (IOException e) {
System.err.println("IOException: " + e.getMessage());
} //end try/catch
}
}
1) If you wish to open a file at an absolute file path on your hard drive:
br = new BufferedReader (
new FileReader(
new File ("/files/scores.dat")));
2) If you wish to open a file at an relative path relative to where you started your app:
br = new BufferedReader (
new FileReader(
new File ("files/scores.dat")));
3) If you wish to open a file at an relative path relative to your class files (particularly relevant for packages and/or for executing from a .jar or a .war):
this.getClass().getResourceAsStream ("files/scores.dat");
'Hope that helps
The reason is can be that you wont be having permission to open the file.
try chmod 755 scores.dat from terminal in order to change the permissions and see if the error still exist.
The answer to this problem exists in the javadocs for the File class:
For UNIX platforms, the prefix of an absolute pathname is always "/". Relative pathnames have no prefix. The abstract pathname denoting the root directory has the prefix "/" and an empty name sequence.
In your code, you have the following:
File dataFile = new File("/files/scores.dat");
According to the documentation, this is an absolute path, which means Java is looking for a folder at the root of the filesystem called "files" and then looking for scores.dat in that folder.
If you instead expect to search for a files directory that is relative to the current directory, you'd need to omit the first /:
File dataFile = new File("files/scores.dat");
The other option is to use an absolute path to your data file, but you may run into problems if you change the location of your project or put the class files in a JAR file.
Try turning up your logging level to DEBUG or ALL so that you can see exactly where the program is trying to look. This will help you adjust your code to target the right folder.