How to locate the XPATH of the Continue button on LinkedIn? - selenium-webdriver

I right clicked the button, selected "Inspect" command and copied and used both XPATH and full XPATH. Neither of them worked for any of the commands below.
xpath = '//*[#id="ember949"]/footer/button[1]'
xpath_full = '/html/body/div[3]/div/div[2]/artdeco-tabs/artdeco-tabpanel[2]/form/footer/button[1]'
button = WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.XPATH, xpath)))
button = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, xpath_full)))
Can someone please explain? Thank you.

Without the HTML, I cannot give a definitive answer.
Looks like the first id may be dynamic and could change.
As for the second one, the full XPaths are brittle and I do not use them at all.
There could be an iframe that you should switch to first.

You could try searching the entire page for a button element with the continue-btn class:
//button[#class='continue-btn']

I would recommend using the Selector / CSS Selector. In the code just change
By.XPATH
to:
By.CSS_SELECTOR
and instead of copying the XPATH copy the Selector or in some cases CSS Selector.

Related

Unable to submit image button as not able to locate web element?

For the below website, html link:
http://www.travelcube.com/uk/Home.jsp;jsessionid=1520F064FE65C29BB1D9F891B8F88890.01IJW?page=CurrencyUL.jsp&siteid=viewtrip&lang=E
...can you have answer for this query?
I am unable to click the Go button, even though using classname,xpath method.
can any one help us how to click that button?
Here is the answer to your Question:
The Go button is within a frame. So first you need to switch to the frame then locate the element and perform click() as follows:
//your code lines
driver.switchTo().frame("Main");
//your code lines
driver.findElement(By.xpath("//button[#name='go']")).click();
Alternative xpath :
driver.findElement(By.xpath("//form[#name='main']//button[#name='go']")).click();
driver.findElement(By.xpath("//form[#name='main']//button[text()='GO']")).click();
Let me know if this Answers your Question.
Try with CSS instead.
driver.switchTo().frame("main");
driver.findElement(By.cssSelector("tr .buttonImage")).click();

click method is not working properly in selenium webdriver

i am trying to Automate flipkart website in which i am trying to change address but "add new adress" is not getting clicked i have attached the snapshot
my code is like driver.findElement(By.xpath("//*[#id='ng-app']/div/div[2]/ul/li[2]/div/div[2]/div[2]/div[2]/a/span")).click();
please give the appropriate help
I doesn't look that you are clicking active element, the xpath is //*[#id='ng-app']/div/div[2]/ul/li[2]/div/div[2]/div[2]/div[2]/a/span not correct it clicks on some span.
Use Firepath https://addons.mozilla.org/en-US/firefox/addon/firepath/ to get the xpath.
To ensure that button is clickable Use isDisplayed() and isEnabled() method before clicking on "Add New Address" button, this method return boolean value.
driver.findElement(By.xpath("//*[#id='ng-app']/div/div[2]/ul/li[2]/div/div[2]/div[2]/div[2]/a/span")).isDisplayed();
driver.findElement(By.xpath("//*[#id='ng-app']/div/div[2]/ul/li[2]/div/div[2]/div[2]/div[2]/a/span")).isEnabled();
Also you can verify that element is exist on page or not using below code
if(driver.findElements(byVal).size()!=0){
// Element is present.
}
hope it may helpful to identify cause of issue, why its not clickable.
First and foremost, Use a customized Xpath instead of the one you are using which is extracted directly from the browser. If no customized Xpath can be constructed then try a customized Css or any other locator if possible.
Try to go through the following attempts in order (I hope you can grasp why this is):
1- If .click() still doesn’t work, then keep on changing the values of the attributes you are using to construct your customized xpath, cssSelector, or locator.
2- Use the Actions class.
3- Use JavaScript executioner
4- instead of click(), try using any of: .sendKeys(“\n”). Or .sendKeys(keys.ENTER) or .sendKeys(keys.RETURN)

Webdriver and push button

i try to make in webdriver a test.
go to http://programyedukacyjne.pl/konkurs/galeria-prac.html
click for example first vote "GŁOSUJ [star]"
and should appear a box to put email.
But nothing happend just add to url in browser "#vote_box_22"
I tryed use click(), Action and javascript click but still there no appear a form...
here is begine:
driver.get("http://programyedukacyjne.pl/konkurs/galeria-prac.html");
WebElement location = driver.findElement(By.name("filter_miejscowosc"));
location.sendKeys("nowy sącz", Keys.ENTER);
here is where I have problem
WebElement voteBtn = driver.findElement(By.xpath("html/body/div[4]/div/div[3]/div/div[4]/div/div[1]/div[2]/div[2]/div[1]/a"));
voteBtn.click();
my secound solution
new Actions(driver).moveToElement(voteBtn).click().perform();
Try using a more specific selector that pinpoints the link more accurately in a less brittle way. The following CSS selector should select the vote link for the first result shown in the list:
WebElement voteBtn = driver.findElement(By.cssSelector("div.praca:nth-of-type(1) a[href*='vote_box']"));
voteBtn.click();

Unable to locate a web element using protractor in jasmine framework

I tried to locate an element on the page with the following but couldn't do.
element(by.css('.organizer-text.ng-binding')).click();
element(by.className('organizer-text')).click();
element(by.linkText('All Cases(1)')).click();
element(by.css('span[class="organizer-text"]')).click();
element(by.css('span[ng-class="{'folder-selected' : isSelected(node)}"]')).click();
element(by.css('span[title="All Cases (1)"')).click();
element(by.xpath('div//span[title()="All Cases(1)"]')).click();
Attaching the screenshot of the element with the DOM. Could you please help me on how to locate it?
<span class="organizer-text ng-binding"
tooltip="buildLabel(node.name, node.totalCases)"
ng-click="onLabelClick($event, node)"
ng-class="{'folder-selected' : isSelected(node)}"
ng-show="!node.showEditName" title="All Cases (1)">
All Cases (1)
</span>
The structure is div->span->multiple spans here (one of the spans here is the element)
try
element(by.xpath('//span[#title="All Cases(1)"]')).click();
I used browser.ignoreSynchronization = true; after logging into the page and it worked.
Looks like you found your answer yourself. But, this is for your own information. Just try this work flow out.
Right-click of your element and get the inspect element window.
Go to inspect element of the element and right-click
There will be a window with some options
Select copy Unique Selector option.
element(by.css('paste your Unique Selector here')).click();
Like step 5 paste your unique selector
Hope this helps. :)

Wrong button is clicked on with a page having two buttons

I'm using Selenium Webdriver to test a web page.
The web page http://www.leaseplan.nl/contact/index.asp has two buttons, one button with button text 'Zoeken' and one with button text 'Verstuur'. I want to click on the button with button text 'Verstuur' either by using XPath or CssSelector with the following code:
driver.FindElement(By.XPath("/html/body/div[3]/div[2]/div[2]/form/fieldset/a/span")).Click();
driver.FindElement(By.CssSelector("fieldset.contact_form > a.button > span.button_center")).Click();
But using the either one of the above lines of code, on the button with text 'Zoeken' is clicked on instead.
This button has quite a similar CssSelector and XPath:
fieldset.header_search a.button span.button_center
/html/body/div[3]/div/form/fieldset/a/span[2]
Does anybody know how to solve this?
Try this out with the cssSelector and tell me if it's work.
For "verstuur" :
By.cssSelector("div.content form a.button")
Solution :
Ok, i've found your problem. Your xpath is good but now, your action on the click submit the first form, so the form with "Zoeken".
onclick="document.forms[0].submit();" // submit the 1st form, the bad one !
Try this :
onclick="document.forms["form"].submit();" // submit the 2nd form, the good one !
//or
onclick="document.forms[1].submit();"
proof : Jsfiddle
xpath for ZOEKEN /html/body/div[3]/div/form/fieldset/a/span[2]
xpath for VERSTUUR /html/body/div[3]/div[2]/div[2]/form/fieldset/a/span[2]
Try this:
driver.FindElement(By.XPath("//span[text()='Verstuur']")).click();
Edit:
I think you want to learn Selenium that's why you are using 3rd party websites. If you really want to learn Selenium find some opensource applications to automate. Here is a good application to automate -
http://sourceforge.net/projects/sugarcrm/files/1%20-%20SugarCRM%206.5.X/FastStack/
Download the latest version and install.
Find more info about the website and selenium stuff here. It's so good..
http://selftechy.com/2011/02/05/introduction-to-selenium-web-application-test-automation-tool
Zoeken: driver.findElement(By.xpath("//div[1]/form/fieldset/a/span[2]")).click();
Verstuur : driver.findElement(By.xpath("//div[2]/form/fieldset/a/span[2]")).click();
Using xpath is easy but slow.

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