I don't know how to ask this but I'm trying to make a suggestion command that stacks reasons when a staff runs the command to deny or accept the application, this uses code in 2 different files, here's the suggestion.js file code:
https://pastebin.com/raw/4svJAuNW
Heres the index.js code:
https://pastebin.com/raw/PNMfnMdz
It would be appreciated if I could be helped out with this since it's a nice feature to have.
Thanks
What it looks like right now:
click here for the image
What I'm trying to accomplish click here for the image
you can't update fields, what you can do, is update the description
const fields = `User: test\nUser: test2`
embed.setDescription(`**Denied**\n${fields}`)
Related
I am using VS Code on a Mac to write ReactJS, however I find that I could not save my code. If I use command and s to save, then the JSX will be a mess, just like shown in the picture:
enter image description here
So how could I solve it? Thank you
I think your code is being saved, but that your code formatting is messing-up your code.
Hit the following combination : Shift+Command+P
This will open a menu on top. Inside that menu type Format Document With..., and select it. It will allow you to format your code with a different auto-format tool. Choose the one that is appropriate for your code i.e. Prettier.
Issue with JSON LD CODE
To start with I am trying to use this code in weebly, buy using embed code option and then I click on the edit custom HTML and enter this code. However, after entering this nothing shows up as in the recipe is not shown on the page and a blank page is shown.
this code is picked on schema.org, for recipes.
Could anyone please help me out in what exactly went wrong. I really appreciate your assistance. FYI- I am new to this. I am trying to set up my own food website and and wanted to schema to for SEO improvement. Any other suggestions are welcome. Thanks in advance.
Please refer this link for the JSON-LD CODE. IT WILL BE AT THE END OF THE PAGE. https://schema.org/Recipe
When you add a JSON-LD block in the HTML, it doesn’t change anything visibly on the page. The script element is hidden by default in all browsers, and you typically want to keep it like that (users typically have no interest in your JSON-LD code).
To check if adding the JSON-LD worked correctly, open the page in a browser and check the source code of the page. You should see the script element with your JSON-LD.
You have to add the content (that should be visible to your users) regularly with HTML. The JSON-LD exists next to your content (duplicating the data like name, photo URL etc.), it doesn’t replace your content.
This is my first post here, so I'm sorry if I'm not in the good section.
My "simple" question is, can we add a gage/gauge (I don't now the exact english spelling), in a Ionic project ?
A thing like that:
https://www.youtube.com/watch?v=w2qrYL0Le24
Or an other exemple:
http://crisbeto.github.io/angular-svg-round-progressbar/
I already tried to insert gauge like that in my project but the gauge never appears, so please, can you help me ?
(The goal is to show to an user a speed for exemple or the batterie life of his smartphone, any importance, juste a jauge who can be incremented or decremented)
Can you explain me please how it works, for example via a Codepen or anything else. I had already tried to search response but I solve anything on that.
I'm french and I am sorry for my language, but thanks in advance for you'r help !
Thanks.
I was able to get this to work:
https://github.com/frapontillo/angular-gage
You must also have the JustGage library and Raphael. Take a look at the example to see it in action. I was able to even make it work in the http://creator.ionic.io app by adding the scripts of angular-gage, JustGage and Raphael (just add a js and paste in the scripts).
I'm trying to convert the Adjuster example mentioned here: http://agiletoolkit.org/learn/understand/view/interactive
into a View that is able to show me the next/previous picture of a list of given images.
I guess the number in the example could be an index into an array of pictures.
I'm just not sure how to provide the list of pictures, when all the code is put in init() for the View, so no way to give it the picturelist before that...
Should I use memorize/recall for this list also to prevent it getting lost upon reload ?
is there another example that might help me?
I think you what you are doing can be much easier done with a classic JavaScript Lightbox script. You would supply it list of images and it would show one full-screen.
If not, you can use this:
https://gist.github.com/romaninsh/7217119
This will give you slides similar to the ones on http://agiletech.ie/
Be advised that this code is a little old.
First time poster here, I'm a designer not skilled at all with php and I have a small issue I don't seem to be able to solve. I'm making a site in drupal 7 using a sub theme on zen.
Btw this is a great CMS, even though people say it's really more a developers CMS. I have no trouble to do what I need using views, rules, display suite etc. So a big thank you for all the developers out there making this such a good CMS. But for this apparently simple problem... no module will help me (I think) and I'm kinda stuck.
So here it is: I'd like to add a subtitle next to the title in all my pages.
So what I did was to add a custom field into the content type basic page (machine name: field_sub_title) which is a simple text field.
I uncommented the following line in my template.php
function mytheme_preprocess_page(&$variables, $hook) {
$variables['sub_title'] = t('field_sub_title');
}
Now my question is how do I load the content of my custom field into that variable?
I know i need to change the second part, but I don't have a clue as into what I need to change this.
Displaying the variable into the the page.tpl.php is something I know about so I only need help with the first part.
{EDIT}
Ok I found how to do this :)
I was looking for a solution in the wrong place. I don't need to change any thing in the template.php file.
Just needed to add this bit of code into my page.tpl.php:
<?php
print $node->field_sub_title['und'][0]['value'];
?>
So I'm posting this here for other Drupal newbies struggling with this....
Your solution may work for now, but there may be a more Drupal-y way to handle a problem like this. If you haven't noticed any problems yet, you may find one or more of the following issues down the road:
Someone who doesn't know php or Drupal theming may need to change the way this works.
If you're like me, you may forget where exactly in code this was implemented.
You may see superfluous markup and/or errors on nodes (content) that do not have this sub-title field (ie. event content not having a sub-title field while basic pages and news articles do).
When you add a field to a content type, it will automatically appear anytime content in that content type is displayed. You should be able to add the sub-title field for your page, event or whatever else you need and have it automatically appear in the markup.
You can 'manage display' of a content type to drag and drop the order for fields to appear. You could take it a step further by using a module like Display Suite to add formatting or layout per-content type.
If you feel like this isn't good enough and the markup for the subtitle must be at the same level as the page title (which is rare), at least add an if statement to make your code check to see if the variable is present before trying to print it. I'd also add a new variable and comments for code readability.
<?php
$subtitle = $node->field_sub_title['und'][0]['value'];
if($subtitle){
print $subtitle;
}
?>
Consider using field_get_items or field_view_value, or at least use the LANGUAGE_NONE constant instead of 'und'
See https://api.drupal.org/api/drupal/modules%21field%21field.module/function/field_get_items/7 and https://api.drupal.org/api/drupal/modules!field!field.module/function/field_view_value/7
This has the added benefit of reducing the number of potential security holes you create.