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Closed 11 months ago.
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#include<stdio.h>
int main() {
char l,u;
printf("Enter any lowercase number: ");
scanf(" %c",&l);
u = toupper(l);
printf("The uppercase number is: %c\n",u);
return 0;
}
The toupper() function is declared in the <ctype.h> header file. So you have to include that at the top.
#include <stdio.h>
#include <ctype.h>
int main() {
char l,u;
printf("Enter any lowercase number: ");
scanf(" %c",&l);
u = toupper(l);
printf("The uppercase number is: %c\n",u);
return 0;
}
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Closed 1 year ago.
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#include <stdio.h>
#include <stdlib.h>
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char** argv) {
int n,i;
float num[100],sum=0.0,avg;
printf("please enter a number between 1-100: ");
scanf("%d",&n);
while(n<1||n>100){
printf("wrong number, enter again: ");
scanf("%d",&n);
}
for(i=0;i<n;i++){
printf("%d. number: ",i+1);
scanf("%f",&num[i]);
sum+=num[i];
}
avg=sum/n;
printf("avarage %.2f",&avg);
return 0;
}
In last printf("...", <float>) you shold not send an adress of sum. Remove &.
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Closed 2 years ago.
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#include <stdio.h>
#include <stdlib.h>
int main(void) {
int i,limit,sum=0;
int a[100];
setbuf(stdout,NULL);
printf("enter the limit");
scanf("%d",&limit);
printf("enter the values");
for(i=0;i<limit;i++)
{
scanf("%d",&a[limit]);
}
for(i=0;i<limit;i++)
{
sum=sum+a[i];
}
printf("the sum is : %d",sum);
return 0;
}
Output:
enter the limit3
enter the values3
3
3
the sum is : 19265880
The actual output should be 9
for(i=0;i<limit;i++)
{
scanf("%d",&a[limit]); //replace limit with i
}
You can see that scanf is reading into the array a[limit] instead of a[i]. This is causing the issue.
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Closed 5 years ago.
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Why this code isn't working? After entering the value, program crashes.
I'm just learning programming btw.
#include <stdio.h>
#include <stdlib.h>
int main()
{
int* p;
p=(int*)malloc(sizeof(int));
printf("Enter a value : \n");
scanf("%d", *p);
printf("%d", *p);
}
scanf should have address, not value.
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int* p;
p=(int*)malloc(sizeof(int));
printf("Enter a value : \n");
scanf("%d", p);
printf("%d", *p);
free(p); // should free manually
}
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Closed 6 years ago.
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Im receiving warnings like this "warning: array subscript has type 'char' [-Wchar-subscripts]" in lines 11, 12 and 15. Whats wrong with my code?
#include <stdio.h>
#include <ctype.h>
int main()
{
char s[1000], i, d, a;
printf("Enter a string: ");
fgets(s, 1000, stdin );
for(i = 0; s[i] != '\0'; i++){
if (isalpha(s[i])){
a++;
}
if (isdigit(s[i])){
d++;
}
}
printf("Number of digits: %d ... Number of letters: %d ", d, a);
return 0;
}
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Closed 8 years ago.
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Please tell me, what is wrong here,it compiles but console crashes when i enter the number. I don't know what to write next, i will just write something to make my post possible.
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char *argv[])
{
unsigned int i,l,p,w;
printf("Enter natural number excluding 0: ");
scanf("%d",l);
p = 1;
for(i=1;i<=l;i++)
{
p=p*i;
}
w=p;
printf("\nFactorial of entered number %d",w);
return 0;
}
scanf("%d",l); you need to insert the address of l, which is &l.
You should also use %u for unsigned ints, not %d.