C simple queue code stuck running while inserting - c

Question

/* Queues */
/* Linear Queues */
#include <stdio.h>
#define MAX 10
int queue[MAX];
int rear=-1;front=-1;
void insert(void);
int delete_element(void);
int peek(void);
void display(void);
int main(){
int option;
printf("\n\n ***** MAIN MENU *****");
printf("\n 1. Insert an element");
printf("\n 2. Delete an element");
printf("\n 3. Peek");
printf("\n 4. Display the queue");
printf("\n 5. EXIT");
printf("\n Enter your option : ");
scanf("%d", &option);
switch(option){
case 1:
insert();
break;
case 2:
int val;
val = delete_element();
if(val != -1)
printf("\n The number deleted is :%d", val);
break;
case 3:
val = peek();
if(val != -1)
printf("\n the first value in queue is: %d", val);
break;
case 4:
display();
break;
}while(option !=5);
return 0;
}
void insert(){
int num;
printf("\n Enter the number to be inserted in the queue : ");
scanf("%d", &num);
if (rear == MAX-1){
printf("Queue is full");
}
else if(front == -1 && rear == -1){
front = rear = 0; /* If queue is empty, set front and rear to 0 */
}
else{
rear++; /* Increment rear */
queue[rear] = num;
}
}
int delete_element(){
int val;
if(front == -1 || front>rear){
printf("Queue is empty");
return -1;
}
else{
val=queue[front];
front++;
if(front>rear){
front = rear = -1; /* Front > rear = queue empty */
}
return val; /* Return popped value */
}
}
int peek(){
if(front == -1 || front>rear){
printf("Queue is empty");
return -1;
}
else{
return queue[front];
}
}
void display(){
int i;
printf("\n");
if(front == -1 || front>rear){
printf("Queue is empty");
}
else{
for(i=front;i<=rear;i++){
printf("\t %d",&queue[i]);
}
}
}
Code gets stuck while I try to insert element "3".
I am following Data Structures using C book, so I am not sure they would write a broken code to the book, but this just boggled my mind. It is running for 4 minutes, without doing literally anything. Neither deleting, peeking, inserting, displaying everything gets stuck in a loop.

Answer 1

You have the code (abbreviated):
switch(option){
...
}while(option !=5);
Slightly reformatted it's the same as:
switch(option){
...
}
while(option !=5)
{
}
That is, your switch ends and then you have an infinite loop.
I'll guess you really wanted to do an do-while loop around the menu and switch:
do
{
// Print menu
// Get input
// Switch
} while (option != 5);