I want to pull data for the last hour or two from a table but the data field and time field are separate fields.
The field "date_stamp" is a Date/Time field but the "time_stamp" field is short text. I cannot find a way to combine these to grab my data for the last hour.
Thank you!
You must convert your text time to true time.
Then you can filter like this:
Select *
From table
Where
date_stamp + TimeValue(time_stamp) Between DateAdd("h", -1, Now()) And Now()
Related
I need to get all the values from a SQL Server database by day (24 hours). I have timestamps column in TestAllData table and I want to select the data which only corresponds to a specific day.
For instance, there are timestamps of DateTime type like '2019-03-19 12:26:03.002', '2019-03-19 17:31:09.024' and '2019-04-10 14:45:12.015' so I want to load the data for the day 2019-03-19 and separately for the day 2019-04-10. Basically, it is needed to get DateTime values with the same date.
Is this possible to use some functions like DatePart or DateDiff for that?
And how can I solve such problem overall?
As in this case, I do not know the exact difference in hours between a timestamp and the end of the day (because there are various timestamps for 1 day) and I need to extract the day itself from the timestamp. After that, I need to group the data by days or something like this and get block by block. For example:
'2019-03-19' - 1200 records
'2019-04-10' - 3500 records
'2019-05-12' - 10000 records and so on
I'm looking for a more generic solution not supplying a timestamp (like '2019-03-19') as a boundary or in a where clause because the problem is not about simply filtering the data by some date!!
UPDATE: In my dataset, I have about 1,000,000 records and more than 100 unique dates. I was thinking about extracting the set of unique dates and then kind of run a query in the loop where the data would be filtered by the provided day. It would look in such a way:
select * from TestAllData where dayColumn = '2019-03-19'
select * from TestAllData where dayColumn = '2019-04-10'
select * from TestAllData where dayColumn = '2019-05-12'
...
I might use this query in my code, so I may run it in the loop from Scala function. However, I am not sure that in terms of performance it would be ok to run separate unique dates extraction query.
Depending on whether you want to be able to work with all the dates (rather than just a subset), one of the easiest ways to achieve this is with a cast:
;with cte as (SELECT cast(my_datetime as date) as my_date, * from TestAllData)
SELECT * FROM cte where my_date = '2019-02-14'
Note when casting datetime to date, times are truncated, ie just the date part is extracted.
As I say though, whether this is efficient, depends on your needs, as all datetime values from all records will be cast to date, before the data is filtered. If you want to select several dates (as opposed to just one or two), however, it may prove overall quicker, as it reads the whole table once and then gives you a column upon which you can much more efficiently filter.
If this is a permanent requirement, though, I would probably use a persisted computed column, which effectively would mean that the casting is done once initially and then only again if the corresponding value changed. For a large table I would also strongly consider an index on the computed column.
I have ran into a problem recently. One of the tables I have in MS Access database contains multiple fields but the main focus is on an autonumber field and date field. When I try to apply Select query with Max(autonumber) function and where clause containing date field, the wrong value or rather empty column is shown. as soon as i remove the date field from the where clause, the value is returned fine. My query is attached. Any help would be appreciated.
SELECT MAX(serial) AS Expr1
FROM coaDetails
WHERE (((coaDetails.[title])='CLAIMS')AND ((coaDetails.[dates])=#04/08/2018#));
The above query, serial is autonumber while dates is date/time with format as dd/mm/yyyy
There is no error in the query but it just gives wrong value. as soon as date condition is removed it gives results.
Use the mm/dd/yyyy or yyyy/mm/dd format for the string expression for the date value:
WHERE (((coaDetails.[title])='CLAIMS')AND ((coaDetails.[dates])=#2018/08/04#));
In the SQL code, the dates have to be formatted the american way: #mm/dd/yyyy#. In the query design grid, which is a user-friendly, graphical view of the SQL code in the back, the format depends on your regional settings.
Therefore, just use the month first:
SELECT MAX(serial) AS Expr1
FROM coaDetails
WHERE (((coaDetails.[title])='CLAIMS')AND ((coaDetails.[dates])=#08/04/2018#));
I've had a similar problem with dates before.
I'm querying a proprietary CMS database that stores dates as a string 'YYYYMMDD'.
I'm using...
convert(varchar(10),right(VarCompletionDate,2)+'/'+substring(VarCompletionDate,5,2)+'/'+left(varCompletionDate,4), 103)
to convert to 'DD/MM/YYYY' format. On the SQL side this appears to work but in Excel, the date is treated like a string rather than a date and I'm not getting the date filters that you would get with a proper date field...
what am I doing wrong here? is the convertconverting to a varchar rather than a date? ...if I do Convert(date,... I get conversion errors.
In excel, you can select a data cell and confirm that the data does not have an apostrophe sign as suffix.
This forces excel to treat the data as text. If you do find it, please do a find and replace all in your selected data range.
If there is no apostrophe, select your data and go to Home>Number>format dropdown and then select long date or short date as the format type.
This will then bring up the date filters.
Managed to find the answer!
Convert(date,....)
Was the correct treatment to output a date format from SQL.
The Pivot table wouldn't recognise the field as a date after a refresh unless I recreated the pivot table - there must be some kind of data type persistence going on in Excel.
I have a table like the next one and I would like to obtain the last "measure date" for every "Work date" of a same "ID".
At the end I would like to have this result:
In that example, the last two rows of the initial table disappears in the final one because I just want the last "To do" measure entered in the table for every work date of a same ID.
As you see in the first table, for a same ID I can have 2 differents measure_date for a same work date. However I need only the last measure date a same work date by ID. In that case, I need to get the last measure date to get the good "To Do" to achieve my job .
The table can have a lot of different Work Date and 100 of ID, which are the same for every Work date.
How can I do that?
From what I read the query should go something like this,
SELECT id, work_date, max(measure_date), todo FROM tablename GROUP BY id, work_date;
But notice that the todo value will be quite random (or can have unexpected results) so leave it out from the query. But like with the comments, there is not enough information and it does look like excel.
I have a daily record table where records are stored date wise. I am using hibernate criteria to access data. How do i get the last date till which records are present continuously (date wise continuity) by providing a date range. For example, say records are there from 21-09-2012 to 25-09-2012 , again from 27-09-2012 to 31-09-2012. I want to form a query using criteria to get record of date 25-09-2012 because for 26-09-2012 there are no records (by passing date ge 21-09-2012 and date le 31-09-2012) . I want to know the last date till which records are present continuously. Say the table has three fields - 1.recordId (AI) 2.date 3.Integer record.
Its not a proper solution to your question. But it may be scenario specific.
How about getting the data for a date range and show then on a calender. Change the color of date if the corresponding value is null.
I think HQL will be better way to this in Hibernate:
http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/queryhql.html