Count Category From Column [duplicate] - sql-server

Question

This question already has answers here:
Conditional Count on a field
(8 answers)
Closed last year.
I have some table, which I want count column that column have 2 category, the explain table like this:
I have query with union like this:
select CLASS, BRANCH, COUNT(STATUS) as STATUS
from dwh.Table a
where STATUS = 'INCLUDE'
group by CLASS, BRANCH, STATUS
order by CLASS
union
select CLASS, BRANCH, COUNT(STATUS) as STATUS
from dwh.Table a
where STATUS = 'NOT INCLUDE'
group by CLASS, BRANCH, STATUS
order by CLASS
but I have got some error.

Answer 1

I think you want conditional aggregation here:
SELECT
CLASS,
BRANCH,
COUNT(CASE WHEN STATUS = 'INCLUDE' THEN 1 END) AS [INCLUDE],
COUNT(CASE WHEN STATUS = 'NOT INCLUDE' THEN 1 END) AS [NOT INCLUDE]
FROM dwh.Table
GROUP BY
CLASS,
BRANCH;
If you just want to report classes only, then simply group by the class by itself (and also select only the class):
SELECT
CLASS,
COUNT(CASE WHEN STATUS = 'INCLUDE' THEN 1 END) AS [INCLUDE],
COUNT(CASE WHEN STATUS = 'NOT INCLUDE' THEN 1 END) AS [NOT INCLUDE]
FROM dwh.Table
GROUP BY
CLASS;

Answer 2

A simple group by and count can do that
select t.class,
count(case when t.status = 'INCLUDE' then 1 end) as INCLUDE,
count(case when t.status = 'NOT INCLUDE' then 1 end) as [NOT INCLUDE]
from test t
group by t.class
Test it yourself in this DBFiddle
That will leave a warning though
Warning: Null value is eliminated by an aggregate or other SET
operation.
So another way to do it is group by and sum and this way you will not get a warning anymore
select t.class,
sum(case when t.status = 'INCLUDE' then 1 else 0 end),
sum(case when t.status = 'NOT INCLUDE' then 1 else 0 end)
from test t
group by t.class
See the altered DBFiddle