how to get different array in for loop every time? - arrays

Question

#include<stdio.h>
#include<time.h>
int main(void)
{
srand(time(NULL));
int answer;
int treatment = rand() % 4;
printf("###발모제 찾기###\n\n");
int cntShowBottle = 0;
int prevCntShowBottle = 0;
int ptr[4] = { 0,0,0,0 };
int bottle[4] = { 0, 0, 0, 0 };
int isincluded = 0;
for (int i = 1; i <= 3; i++)
{
do {
cntShowBottle = rand() % 2 + 2;
} while (cntShowBottle == prevCntShowBottle);
prevCntShowBottle = cntShowBottle;
printf(" %d 번째 시도 : ", i);
for (int j = 0; j < cntShowBottle; j++)
{
int randBottle = rand() % 4;
if (bottle[randBottle] == 0)
{
bottle[randBottle] = 1;
if (randBottle == treatment)
{
isincluded = 1;
}
}
else
{
j--;
}
}
}
if (bottle[0] == ptr[0] && bottle[1] == ptr[1] && bottle[2] == ptr[2] && bottle[3] == ptr[3])
{
int bottle[4] = { 0,0,0,0 };
for (int j = 0; j < cntShowBottle; j++)
{
int randBottle = rand() % 4;
if (bottle[randBottle] == 0)
{
bottle[randBottle] = 1;
if (randBottle == treatment)
{
isincluded = 1;
}
}
else
{
j--;
}
}
}
else
{
return 0;
}
for (int i = 0; i < 4; i++)
{
ptr[i] = bottle[i];
}
for (int k = 0; k < 4; k++)
{
if (bottle[k] == 1)
printf("%d ", k + 1);
}
printf("번 물약을 머리에 바릅니다.\n\n");
if (isincluded == 1)
{
printf("성공!\n");
}
else
{
printf("실패...\n");
}
printf("\n ...계속 하려면 아무키나 누르세요...");
getchar(0);
printf("\n\n발모제는 몇 번? : ");
scanf_s("%d", &answer);
if (answer == treatment+1)
{
printf("\n 정답! \n");
}
else
{
printf("\n 실패! \n 정답은 %d 였습니다.\n", treatment+1);
}
return 0;
}
in this loop, for (int j = 0; j < cntShowBottle; j++), 'bottle' array will be [0,1,1,1] or [1,1,0,0] etc. In this loop, how to get different array without overlapping(like [0,1,1,0] and again [0,1,1,0])?? I tried comparing each elements, if it takes overlapping array, makes 'bottle' array again. but it didn't run properly. please help..