Total number of rows count in SQL SERVER [duplicate] - sql-server

How to list row count of each table in the database. Some equivalent of
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
I will post a solution but other approaches are welcome

If you're using SQL Server 2005 and up, you can also use this:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
In my opinion, it's easier to handle than the sp_msforeachtable output.

A snippet I found at http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021 that helped me:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;

To get that information in SQL Management Studio, right click on the database, then select Reports --> Standard Reports --> Disk Usage by Table.

SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;

As seen here, this will return correct counts, where methods using the meta data tables will only return estimates.
CREATE PROCEDURE ListTableRowCounts
AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #TableCounts
(
TableName VARCHAR(500),
CountOf INT
)
INSERT #TableCounts
EXEC sp_msForEachTable
'SELECT PARSENAME(''?'', 1),
COUNT(*) FROM ? WITH (NOLOCK)'
SELECT TableName , CountOf
FROM #TableCounts
ORDER BY TableName
DROP TABLE #TableCounts
END
GO

sp_MSForEachTable 'DECLARE #t AS VARCHAR(MAX);
SELECT #t = CAST(COUNT(1) as VARCHAR(MAX))
+ CHAR(9) + CHAR(9) + ''?'' FROM ? ; PRINT #t'
Output:

Well luckily SQL Server management studio gives you a hint on how to do this.
Do this,
start a SQL Server trace and open the activity you are doing (filter
by your login ID if you're not alone and set the application Name
to Microsoft SQL Server Management Studio), pause the trace and discard any results you have recorded till now;
Then, right click a table and select property from the pop up menu;
start the trace again;
Now in SQL Server Management studio select the storage property item on the left;
Pause the trace and have a look at what TSQL is generated by microsoft.
In the probably last query you will see a statement starting with exec sp_executesql N'SELECT
when you copy the executed code to visual studio you will notice that this code generates all the data the engineers at microsoft used to populate the property window.
when you make moderate modifications to that query you will get to something like this:
SELECT
SCHEMA_NAME(tbl.schema_id)+'.'+tbl.name as [table], --> something I added
p.partition_number AS [PartitionNumber],
prv.value AS [RightBoundaryValue],
fg.name AS [FileGroupName],
CAST(pf.boundary_value_on_right AS int) AS [RangeType],
CAST(p.rows AS float) AS [RowCount],
p.data_compression AS [DataCompression]
FROM sys.tables AS tbl
INNER JOIN sys.indexes AS idx ON idx.object_id = tbl.object_id and idx.index_id < 2
INNER JOIN sys.partitions AS p ON p.object_id=CAST(tbl.object_id AS int) AND p.index_id=idx.index_id
LEFT OUTER JOIN sys.destination_data_spaces AS dds ON dds.partition_scheme_id = idx.data_space_id and dds.destination_id = p.partition_number
LEFT OUTER JOIN sys.partition_schemes AS ps ON ps.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_range_values AS prv ON prv.boundary_id = p.partition_number and prv.function_id = ps.function_id
LEFT OUTER JOIN sys.filegroups AS fg ON fg.data_space_id = dds.data_space_id or fg.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_functions AS pf ON pf.function_id = prv.function_id
Now the query is not perfect and you could update it to meet other questions you might have, the point is, you can use the knowledge of microsoft to get to most of the questions you have by executing the data you're interested in and trace the TSQL generated using profiler.
I kind of like to think that MS engineers know how SQL server work and, it will generate TSQL that works on all items you can work with using the version on SSMS you are using so it's quite good on a large variety releases prerviouse, current and future.
And remember, don't just copy, try to understand it as well else you might end up with the wrong solution.
Walter

This approaches uses string concatenation to produce a statement with all tables and their counts dynamically, like the example(s) given in the original question:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
Finally this is executed with EXEC:
DECLARE #cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(#cmd);

The first thing that came to mind was to use sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
that does not list the table names though, so it can be extended to
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
The problem here is that if the database has more than 100 tables you will get the following error message:
The query has exceeded the maximum
number of result sets that can be
displayed in the results grid. Only
the first 100 result sets are
displayed in the grid.
So I ended up using table variable to store the results
declare #stats table (n sysname, c int)
insert into #stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from #stats
order by c desc

Fastest way to find row count of all tables in SQL Refreence (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC

I want to share what's working for me
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
The database is hosted in Azure and the final result is:
Credit: https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/

Here is my take on this question. It contains all schemas and lists only tables with rows. YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;

If you use MySQL >4.x you can use this:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
Keep in mind that for some storage engines, TABLE_ROWS is an approximation.

The accepted answer didn't work for me on Azure SQL, here's one that did, it's super fast and did exactly what I wanted:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc

You could try this:
SELECT OBJECT_SCHEMA_NAME(ps.object_Id) AS [schemaname],
OBJECT_NAME(ps.object_id) AS [tablename],
row_count AS [rows]
FROM sys.dm_db_partition_stats ps
WHERE OBJECT_SCHEMA_NAME(ps.object_Id) <> 'sys' AND ps.index_id < 2
ORDER BY
OBJECT_SCHEMA_NAME(ps.object_Id),
OBJECT_NAME(ps.object_id)

This sql script gives the schema, table name and row count of each table in a database selected:
SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc
Ref: https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/
Another way of doing this:
SELECT o.NAME TABLENAME,
i.rowcnt
FROM sysindexes AS i
INNER JOIN sysobjects AS o ON i.id = o.id
WHERE i.indid < 2 AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc

I think that the shortest, fastest and simplest way would be:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id

USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable #command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts

From this question:
https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
I added record count to the answer provided by #Aaron Bertrand that lists all databases and all tables.
DECLARE #src NVARCHAR(MAX), #sql NVARCHAR(MAX);
SELECT #sql = N'', #src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT #sql = #sql + REPLACE(#src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET #sql = STUFF(#sql, 1, 10, CHAR(13) + CHAR(10));
PRINT #sql;
--EXEC sys.sp_executesql #sql;

You can copy, past and execute this piece of code to get all table record counts into a table. Note: Code is commented with instructions
create procedure RowCountsPro
as
begin
--drop the table if exist on each exicution
IF OBJECT_ID (N'dbo.RowCounts', N'U') IS NOT NULL
DROP TABLE dbo.RowCounts;
-- creating new table
CREATE TABLE RowCounts
( [TableName] VARCHAR(150)
, [RowCount] INT
, [Reserved] NVARCHAR(50)
, [Data] NVARCHAR(50)
, [Index_Size] NVARCHAR(50)
, [UnUsed] NVARCHAR(50))
--inserting all records
INSERT INTO RowCounts([TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed])
-- "sp_MSforeachtable" System Procedure, 'sp_spaceused "?"' param to get records and resources used
EXEC sp_MSforeachtable 'sp_spaceused "?"'
-- selecting data and returning a table of data
SELECT [TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed]
FROM RowCounts
ORDER BY [TableName]
end
I have tested this code and it works fine on SQL Server 2014.

SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO

Shnugo's answer is the ONLY one that works in Azure with Externa Tables. (1) Azure SQL doesn't support sp_MSforeachtable at all and (2) rows in sys.partitions for an External table is always 0.

select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
Here indid=1 means a CLUSTERED index and indid=0 is a HEAP

Related

number rows in table and views without select [duplicate]

How to list row count of each table in the database. Some equivalent of
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
I will post a solution but other approaches are welcome
If you're using SQL Server 2005 and up, you can also use this:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
In my opinion, it's easier to handle than the sp_msforeachtable output.
A snippet I found at http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021 that helped me:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;
To get that information in SQL Management Studio, right click on the database, then select Reports --> Standard Reports --> Disk Usage by Table.
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
As seen here, this will return correct counts, where methods using the meta data tables will only return estimates.
CREATE PROCEDURE ListTableRowCounts
AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #TableCounts
(
TableName VARCHAR(500),
CountOf INT
)
INSERT #TableCounts
EXEC sp_msForEachTable
'SELECT PARSENAME(''?'', 1),
COUNT(*) FROM ? WITH (NOLOCK)'
SELECT TableName , CountOf
FROM #TableCounts
ORDER BY TableName
DROP TABLE #TableCounts
END
GO
sp_MSForEachTable 'DECLARE #t AS VARCHAR(MAX);
SELECT #t = CAST(COUNT(1) as VARCHAR(MAX))
+ CHAR(9) + CHAR(9) + ''?'' FROM ? ; PRINT #t'
Output:
Well luckily SQL Server management studio gives you a hint on how to do this.
Do this,
start a SQL Server trace and open the activity you are doing (filter
by your login ID if you're not alone and set the application Name
to Microsoft SQL Server Management Studio), pause the trace and discard any results you have recorded till now;
Then, right click a table and select property from the pop up menu;
start the trace again;
Now in SQL Server Management studio select the storage property item on the left;
Pause the trace and have a look at what TSQL is generated by microsoft.
In the probably last query you will see a statement starting with exec sp_executesql N'SELECT
when you copy the executed code to visual studio you will notice that this code generates all the data the engineers at microsoft used to populate the property window.
when you make moderate modifications to that query you will get to something like this:
SELECT
SCHEMA_NAME(tbl.schema_id)+'.'+tbl.name as [table], --> something I added
p.partition_number AS [PartitionNumber],
prv.value AS [RightBoundaryValue],
fg.name AS [FileGroupName],
CAST(pf.boundary_value_on_right AS int) AS [RangeType],
CAST(p.rows AS float) AS [RowCount],
p.data_compression AS [DataCompression]
FROM sys.tables AS tbl
INNER JOIN sys.indexes AS idx ON idx.object_id = tbl.object_id and idx.index_id < 2
INNER JOIN sys.partitions AS p ON p.object_id=CAST(tbl.object_id AS int) AND p.index_id=idx.index_id
LEFT OUTER JOIN sys.destination_data_spaces AS dds ON dds.partition_scheme_id = idx.data_space_id and dds.destination_id = p.partition_number
LEFT OUTER JOIN sys.partition_schemes AS ps ON ps.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_range_values AS prv ON prv.boundary_id = p.partition_number and prv.function_id = ps.function_id
LEFT OUTER JOIN sys.filegroups AS fg ON fg.data_space_id = dds.data_space_id or fg.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_functions AS pf ON pf.function_id = prv.function_id
Now the query is not perfect and you could update it to meet other questions you might have, the point is, you can use the knowledge of microsoft to get to most of the questions you have by executing the data you're interested in and trace the TSQL generated using profiler.
I kind of like to think that MS engineers know how SQL server work and, it will generate TSQL that works on all items you can work with using the version on SSMS you are using so it's quite good on a large variety releases prerviouse, current and future.
And remember, don't just copy, try to understand it as well else you might end up with the wrong solution.
Walter
This approaches uses string concatenation to produce a statement with all tables and their counts dynamically, like the example(s) given in the original question:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
Finally this is executed with EXEC:
DECLARE #cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(#cmd);
The first thing that came to mind was to use sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
that does not list the table names though, so it can be extended to
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
The problem here is that if the database has more than 100 tables you will get the following error message:
The query has exceeded the maximum
number of result sets that can be
displayed in the results grid. Only
the first 100 result sets are
displayed in the grid.
So I ended up using table variable to store the results
declare #stats table (n sysname, c int)
insert into #stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from #stats
order by c desc
Fastest way to find row count of all tables in SQL Refreence (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
I want to share what's working for me
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
The database is hosted in Azure and the final result is:
Credit: https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/
Here is my take on this question. It contains all schemas and lists only tables with rows. YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;
If you use MySQL >4.x you can use this:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
Keep in mind that for some storage engines, TABLE_ROWS is an approximation.
The accepted answer didn't work for me on Azure SQL, here's one that did, it's super fast and did exactly what I wanted:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
You could try this:
SELECT OBJECT_SCHEMA_NAME(ps.object_Id) AS [schemaname],
OBJECT_NAME(ps.object_id) AS [tablename],
row_count AS [rows]
FROM sys.dm_db_partition_stats ps
WHERE OBJECT_SCHEMA_NAME(ps.object_Id) <> 'sys' AND ps.index_id < 2
ORDER BY
OBJECT_SCHEMA_NAME(ps.object_Id),
OBJECT_NAME(ps.object_id)
This sql script gives the schema, table name and row count of each table in a database selected:
SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc
Ref: https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/
Another way of doing this:
SELECT o.NAME TABLENAME,
i.rowcnt
FROM sysindexes AS i
INNER JOIN sysobjects AS o ON i.id = o.id
WHERE i.indid < 2 AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc
I think that the shortest, fastest and simplest way would be:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable #command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts
From this question:
https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
I added record count to the answer provided by #Aaron Bertrand that lists all databases and all tables.
DECLARE #src NVARCHAR(MAX), #sql NVARCHAR(MAX);
SELECT #sql = N'', #src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT #sql = #sql + REPLACE(#src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET #sql = STUFF(#sql, 1, 10, CHAR(13) + CHAR(10));
PRINT #sql;
--EXEC sys.sp_executesql #sql;
You can copy, past and execute this piece of code to get all table record counts into a table. Note: Code is commented with instructions
create procedure RowCountsPro
as
begin
--drop the table if exist on each exicution
IF OBJECT_ID (N'dbo.RowCounts', N'U') IS NOT NULL
DROP TABLE dbo.RowCounts;
-- creating new table
CREATE TABLE RowCounts
( [TableName] VARCHAR(150)
, [RowCount] INT
, [Reserved] NVARCHAR(50)
, [Data] NVARCHAR(50)
, [Index_Size] NVARCHAR(50)
, [UnUsed] NVARCHAR(50))
--inserting all records
INSERT INTO RowCounts([TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed])
-- "sp_MSforeachtable" System Procedure, 'sp_spaceused "?"' param to get records and resources used
EXEC sp_MSforeachtable 'sp_spaceused "?"'
-- selecting data and returning a table of data
SELECT [TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed]
FROM RowCounts
ORDER BY [TableName]
end
I have tested this code and it works fine on SQL Server 2014.
SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO
Shnugo's answer is the ONLY one that works in Azure with Externa Tables. (1) Azure SQL doesn't support sp_MSforeachtable at all and (2) rows in sys.partitions for an External table is always 0.
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
Here indid=1 means a CLUSTERED index and indid=0 is a HEAP

MS SQL 2008 - get all table names and their row counts in a DB

I'm trying to identify which tables are affected by a data update though an application (developed by others). There are more than 200 tables in the DB and I'd like to avoid checking each of them for changes.
Is there any other way where I can list all table names along with their row count?
select table_name from information_schema.tables
List out all the tables in my DB buy how do I include number of rows as well?
SELECT sc.name +'.'+ ta.name TableName
,SUM(pa.rows) RowCnt
FROM sys.tables ta
INNER JOIN sys.partitions pa
ON pa.OBJECT_ID = ta.OBJECT_ID
INNER JOIN sys.schemas sc
ON ta.schema_id = sc.schema_id
WHERE ta.is_ms_shipped = 0 AND pa.index_id IN (1,0)
GROUP BY sc.name,ta.name
ORDER BY SUM(pa.rows) DESC
See this:
SQL SERVER – Find Row Count in Table – Find Largest Table in Database.
to get all tables in a database:
select * from INFORMATION_SCHEMA.TABLES
to get all columns in a database:
select * from INFORMATION_SCHEMA.columns
to get all views in a db:
select * from INFORMATION_SCHEMA.TABLES where table_type = 'view'
Posted for completeness.
If you are looking for row count of all tables in all databases (which was what I was looking for) then I found this combination of this and this to work. No idea whether it is optimal or not:
SET NOCOUNT ON
DECLARE #AllTables table (DbName sysname,SchemaName sysname, TableName sysname, RowsCount int )
DECLARE
#SQL nvarchar(4000)
SET #SQL='SELECT ''?'' AS DbName, s.name AS SchemaName, t.name AS TableName, p.rows AS RowsCount FROM [?].sys.tables t INNER JOIN sys.schemas s ON t.schema_id=s.schema_id INNER JOIN [?].sys.partitions p ON p.OBJECT_ID = t.OBJECT_ID'
INSERT INTO #AllTables (DbName, SchemaName, TableName, RowsCount)
EXEC sp_msforeachdb #SQL
SET NOCOUNT OFF
SELECT DbName, SchemaName, TableName, SUM(RowsCount), MIN(RowsCount), SUM(1)
FROM #AllTables
WHERE RowsCount > 0
GROUP BY DbName, SchemaName, TableName
ORDER BY DbName, SchemaName, TableName
Try this it's simple and fast
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2 ORDER BY I.rows DESC

Get size of all tables in database

I have inherited a fairly large SQL Server database. It seems to take up more space than I would expect, given the data it contains.
Is there an easy way to determine how much space on disk each table is consuming?
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
If you are using SQL Server Management Studio (SSMS), instead of running a query (which in my case returned duplicate rows) you can run a standard report. 
Right click on the database
Navigate to Reports > Standard Reports > Disk Usage By Table
Note: The database compatibility level must be set to 90 or above for this to work correctly. See http://msdn.microsoft.com/en-gb/library/bb510680.aspx
Note: This report isn't available when working with and Azure SQL database
sp_spaceused can get you information on the disk space used by a table, indexed view, or the whole database.
For example:
USE MyDatabase; GO
EXEC sp_spaceused N'User.ContactInfo'; GO
This reports the disk usage information for the ContactInfo table.
To use this for all tables at once:
USE MyDatabase; GO
sp_msforeachtable 'EXEC sp_spaceused [?]' GO
You can also get disk usage from within the right-click Standard Reports functionality of SQL Server. To get to this report, navigate from the server object in Object Explorer, move down to the Databases object, and then right-click any database. From the menu that appears, select Reports, then Standard Reports, and then "Disk Usage by Partition: [DatabaseName]".
Here is another method: using SQL Server Management Studio, in Object Explorer, go to your database and select Tables
Then open the Object Explorer Details (either by pressing F7 or going to View->Object Explorer Details). In the object explorer details page, right click on the column header and enable the columns that you would like to see in the page. You can sort the data by any column too.
exec sp_spaceused N'dbo.MyTable'
For all tables ,use..(adding from the comments of Paul)
exec sp_MSForEachTable 'exec sp_spaceused [?]'
After some searching, I could not find an easy way to get information on all of the tables. There is a handy stored procedure named sp_spaceused that will return all of the space used by the database. If provided with a table name, it returns the space used by that table. However, the results returned by the stored procedure are not sortable, since the columns are character values.
The following script will generate the information I'm looking for.
create table #TableSize (
Name varchar(255),
[rows] int,
reserved varchar(255),
data varchar(255),
index_size varchar(255),
unused varchar(255))
create table #ConvertedSizes (
Name varchar(255),
[rows] int,
reservedKb int,
dataKb int,
reservedIndexSize int,
reservedUnused int)
EXEC sp_MSforeachtable #command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows],
SUBSTRING(reserved, 0, LEN(reserved)-2),
SUBSTRING(data, 0, LEN(data)-2),
SUBSTRING(index_size, 0, LEN(index_size)-2),
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize
select * from #ConvertedSizes
order by reservedKb desc
drop table #TableSize
drop table #ConvertedSizes
For Azure I used this:
You should have SSMS v17.x+
I used;
With this, as User Sparrow has mentioned:
Open your Databases> and select Tables,
Then press key F7
You should see the row count
as:
SSMS here is connected to Azure databases
Above queries are good for finding the amount of space used by the table (indexes included), but if you want to compare how much space is used by indexes on the table use this query:
SELECT
OBJECT_NAME(i.OBJECT_ID) AS TableName,
i.name AS IndexName,
i.index_id AS IndexID,
8 * SUM(a.used_pages) AS 'Indexsize(KB)'
FROM
sys.indexes AS i
JOIN sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id
JOIN sys.allocation_units AS a ON a.container_id = p.partition_id
WHERE
i.is_primary_key = 0 -- fix for size discrepancy
GROUP BY
i.OBJECT_ID,
i.index_id,
i.name
ORDER BY
OBJECT_NAME(i.OBJECT_ID),
i.index_id
Marc_s' answer gives incorrect results when working with multiple partitions and/or filtered indexes. It also doesn't distinguish between the size of the data and indexes, which is often very relevant. Several suggested fixes don't address the core problem or are simply wrong as well.
The following query addresses all of those issues.
SELECT
[object_id] = t.[object_id]
,[schema_name] = s.[name]
,[table_name] = t.[name]
,[index_name] = CASE WHEN i.[type] in (0,1,5) THEN null ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
,[object_type] = CASE WHEN i.[type] in (0,1,5) THEN 'TABLE' ELSE 'INDEX' END
,[index_type] = i.[type_desc]
,[partition_count] = p.partition_count
,[row_count] = p.[rows]
,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN 'Mixed'
ELSE ( SELECT DISTINCT p.data_compression_desc
FROM sys.partitions p
WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
)
END
,[total_space_MB] = cast(round(( au.total_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[used_space_MB] = cast(round(( au.used_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[unused_space_MB] = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
FROM sys.partitions
GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
FROM sys.partitions p
JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table
Extension to #xav answer that handled table partitions to get size in MB and GB.
Tested on SQL Server 2008/2012 (Commented a line where is_memory_optimized = 1)
SELECT
a2.name AS TableName,
a1.rows as [RowCount],
--(a1.reserved + ISNULL(a4.reserved,0)) * 8 AS ReservedSize_KB,
--a1.data * 8 AS DataSize_KB,
--(CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS IndexSize_KB,
--(CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS UnusedSize_KB,
CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_MB,
CAST(ROUND(a1.data * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_MB,
CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_MB,
CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_MB,
--'| |' Separator_MB_GB,
CAST(ROUND(((a1.reserved + ISNULL(a4.reserved,0)) * 8) / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS ReservedSize_GB,
CAST(ROUND(a1.data * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS DataSize_GB,
CAST(ROUND((CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS IndexSize_GB,
CAST(ROUND((CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 / 1024.00 / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSize_GB
FROM
(SELECT
ps.object_id,
SUM (CASE WHEN (ps.index_id < 2) THEN row_count ELSE 0 END) AS [rows],
SUM (ps.reserved_page_count) AS reserved,
SUM (CASE
WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
END
) AS data,
SUM (ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
--===Remove the following comment for SQL Server 2014+
--WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN
(SELECT
it.parent_id,
SUM(ps.reserved_page_count) AS reserved,
SUM(ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
WHERE it.internal_type IN (202,204)
GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2 ON ( a1.object_id = a2.object_id )
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N'S' and a2.type <> N'IT'
--AND a2.name = 'MyTable' --Filter for specific table
--ORDER BY a3.name, a2.name
ORDER BY ReservedSize_MB DESC
If you need to calculate exactly the same numbers, that are on 'table properties - storage' page in SSMS, you need to count them with the same method as it done in SSMS (works for sql server 2005 and above ... and also works correctly for tables with LOB fields - because just counting "used_pages" is not enought to show accurate index size):
;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END) as pages
FROM sys.dm_db_partition_stats AS s
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
cte.TableName,
cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB,
cast(((CASE WHEN cte.used_pages_count > cte.pages
THEN cte.used_pages_count - cte.pages
ELSE 0
END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc
We use table partitioning and had some trouble with the queries provided above due to duplicate records.
For those who need this, you can find below the query as run by SQL Server 2014 when generating the "Disk usage by table" report. I assume it also works with previous versions of SQL Server.
It works like a charm.
SELECT
a2.name AS [tablename],
a1.rows as row_count,
(a1.reserved + ISNULL(a4.reserved,0))* 8 AS reserved,
a1.data * 8 AS data,
(CASE WHEN (a1.used + ISNULL(a4.used,0)) > a1.data THEN (a1.used + ISNULL(a4.used,0)) - a1.data ELSE 0 END) * 8 AS index_size,
(CASE WHEN (a1.reserved + ISNULL(a4.reserved,0)) > a1.used THEN (a1.reserved + ISNULL(a4.reserved,0)) - a1.used ELSE 0 END) * 8 AS unused
FROM
(SELECT
ps.object_id,
SUM (
CASE
WHEN (ps.index_id < 2) THEN row_count
ELSE 0
END
) AS [rows],
SUM (ps.reserved_page_count) AS reserved,
SUM (
CASE
WHEN (ps.index_id < 2) THEN (ps.in_row_data_page_count + ps.lob_used_page_count + ps.row_overflow_used_page_count)
ELSE (ps.lob_used_page_count + ps.row_overflow_used_page_count)
END
) AS data,
SUM (ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
WHERE ps.object_id NOT IN (SELECT object_id FROM sys.tables WHERE is_memory_optimized = 1)
GROUP BY ps.object_id) AS a1
LEFT OUTER JOIN
(SELECT
it.parent_id,
SUM(ps.reserved_page_count) AS reserved,
SUM(ps.used_page_count) AS used
FROM sys.dm_db_partition_stats ps
INNER JOIN sys.internal_tables it ON (it.object_id = ps.object_id)
WHERE it.internal_type IN (202,204)
GROUP BY it.parent_id) AS a4 ON (a4.parent_id = a1.object_id)
INNER JOIN sys.all_objects a2 ON ( a1.object_id = a2.object_id )
INNER JOIN sys.schemas a3 ON (a2.schema_id = a3.schema_id)
WHERE a2.type <> N'S' and a2.type <> N'IT'
ORDER BY a3.name, a2.name
A small change from Marc_s's answer, since I have been going back to this page so often, ordered by most row's first:
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
--p.rows DESC --Uncomment to order by amount rows instead of size in KB.
SUM(a.total_pages) DESC
-- Show the size of all the tables in a database sort by data size descending
SET NOCOUNT ON
DECLARE #TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE #cmd1 varchar(500)
SET #cmd1 = 'exec sp_spaceused ''?'''
INSERT INTO #TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable #command1=#cmd1
SELECT * FROM #TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC
Here is a way to get all tables' sizes quickly with the following steps:
Write the given T-SQL commands to list all database tables:
select 'exec sp_spaceused ' + TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_TYPE = 'BASE TABLE'
Now copy the list of database tables, and copy it into a new query analyzer window
exec sp_spaceused table1
exec sp_spaceused table2
exec sp_spaceused table3
exec sp_spaceused table4
exec sp_spaceused table5
In SQL query analyzer, select from top tool bar option Results to file (Ctrl + Shift + F).
Now finally hit the Execute button red marked from the above tool bar.
The Database size of all tables is now stored in a file on your computer.
For get all table size in one database you can use this query :
Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
And you can change it to insert all of result into temp table and after that select from temp table.
Insert into #TempTable Exec sys.sp_MSforeachtable ' sp_spaceused "?" '
Select * from #TempTable
This will give you the sizes, and record counts for each table.
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
-- Get a list of tables and their sizes on disk
ALTER PROCEDURE [dbo].[sp_Table_Sizes]
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
DECLARE #table_name VARCHAR(500)
DECLARE #schema_name VARCHAR(500)
DECLARE #tab1 TABLE(
tablename VARCHAR (500) collate database_default
,schemaname VARCHAR(500) collate database_default
)
CREATE TABLE #temp_Table (
tablename sysname
,row_count INT
,reserved VARCHAR(50) collate database_default
,data VARCHAR(50) collate database_default
,index_size VARCHAR(50) collate database_default
,unused VARCHAR(50) collate database_default
)
INSERT INTO #tab1
SELECT Table_Name, Table_Schema
FROM information_schema.tables
WHERE TABLE_TYPE = 'BASE TABLE'
DECLARE c1 CURSOR FOR
SELECT Table_Schema + '.' + Table_Name
FROM information_schema.tables t1
WHERE TABLE_TYPE = 'BASE TABLE'
OPEN c1
FETCH NEXT FROM c1 INTO #table_name
WHILE ##FETCH_STATUS = 0
BEGIN
SET #table_name = REPLACE(#table_name, '[','');
SET #table_name = REPLACE(#table_name, ']','');
-- make sure the object exists before calling sp_spacedused
IF EXISTS(SELECT id FROM sysobjects WHERE id = OBJECT_ID(#table_name))
BEGIN
INSERT INTO #temp_Table EXEC sp_spaceused #table_name, false;
END
FETCH NEXT FROM c1 INTO #table_name
END
CLOSE c1
DEALLOCATE c1
SELECT t1.*
,t2.schemaname
FROM #temp_Table t1
INNER JOIN #tab1 t2 ON (t1.tablename = t2.tablename )
ORDER BY schemaname,t1.tablename;
DROP TABLE #temp_Table
END
I would like to thank Mr. Greg Low for this query:
SELECT o.name AS ObjectName,
SUM(reserved_page_count) * 8.0 / 1024 AS SizeinMB
FROM sys.dm_db_partition_stats AS ps
INNER JOIN sys.sysobjects AS o
ON ps.object_id = o.id
GROUP BY o.name
ORDER BY SizeinMB DESC;
From a command prompt using OSQL:
OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt
I added a few more columns on top of marc_s answer:
with fs
as
(
select i.object_id,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKb
from sys.indexes i INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.OBJECT_ID > 255
GROUP BY
i.object_id,
p.rows
)
SELECT
t.NAME AS TableName,
fs.RowCounts,
fs.TotalSpaceKb,
t.create_date,
t.modify_date,
( select COUNT(1)
from sys.columns c
where c.object_id = t.object_id ) TotalColumns
FROM
sys.tables t INNER JOIN
fs ON t.OBJECT_ID = fs.object_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
ORDER BY
t.Name
Maybe the Tables have a more partion file & must show the file order
SELECT
T1.Name AS TableName,
T5.Name AS SchemaName,
T3.partition_number AS PartionNumber,
T3.Rows AS RowsCount,
SUM(T4.total_pages) * 8 AS TotalSpaceKB,
SUM(T4.used_pages) * 8 AS UsedSpaceKB,
(SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.objects T1 INNER JOIN
sys.indexes T2 ON T1.object_id = T2.object_id INNER JOIN
sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id INNER JOIN
sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
T1.type='U'
GROUP BY
T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
T1.Name,T3.partition_number;
My post is only relevant for SQL Server 2000 and has been tested to work in my environment.
This code accesses All possible databases of a single instance, not just a single database.
I use two temp tables to help collect the appropriate data and then dump the results into one 'Live' table.
Returned data is: DatabaseName, DatabaseTableName, Rows (in the Table), data (size of the table in KB it would seem), entry data (I find this useful for knowing when I last ran the script).
Downfall to this code is the 'data' field is not stored as an int (The chars 'KB' are kept in that field), and that would be useful (but not totally necessary) for sorting.
Hopefully this code helps someone out there and saves them some time!
CREATE PROCEDURE [dbo].[usp_getAllDBTableSizes]
AS
BEGIN
SET NOCOUNT OFF
CREATE TABLE #DatabaseTables([dbname] sysname,TableName sysname)
CREATE TABLE #AllDatabaseTableSizes(Name sysname,[rows] VARCHAR(18), reserved VARCHAR(18), data VARCHAR(18), index_size VARCHAR(18), unused VARCHAR(18))
DECLARE #SQL nvarchar(4000)
SET #SQL='select ''?'' AS [Database], Table_Name from [?].information_schema.tables WHERE TABLE_TYPE = ''BASE TABLE'' '
INSERT INTO #DatabaseTables(DbName, TableName)
EXECUTE sp_msforeachdb #Command1=#SQL
DECLARE AllDatabaseTables CURSOR LOCAL READ_ONLY FOR
SELECT TableName FROM #DatabaseTables
DECLARE AllDatabaseNames CURSOR LOCAL READ_ONLY FOR
SELECT DBName FROM #DatabaseTables
DECLARE #DBName sysname
OPEN AllDatabaseNames
DECLARE #TName sysname
OPEN AllDatabaseTables
WHILE 1=1 BEGIN
FETCH NEXT FROM AllDatabaseNames INTO #DBName
FETCH NEXT FROM AllDatabaseTables INTO #TName
IF ##FETCH_STATUS<>0 BREAK
INSERT INTO #AllDatabaseTableSizes
EXEC ( 'EXEC ' + #DBName + '.dbo.sp_spaceused ' + #TName)
END
--http://msdn.microsoft.com/en-us/library/aa175920(v=sql.80).aspx
INSERT INTO rsp_DatabaseTableSizes (DatabaseName, name, [rows], data)
SELECT [dbname], name, [rows], data FROM #DatabaseTables
INNER JOIN #AllDatabaseTableSizes
ON #DatabaseTables.TableName = #AllDatabaseTableSizes.Name
GROUP BY [dbname] , name, [rows], data
ORDER BY [dbname]
--To be honest, I have no idea what exact duplicates we are dropping
-- but in my case a near enough approach has been good enough.
DELETE FROM [rsp_DatabaseTableSizes]
WHERE name IN
(
SELECT name
FROM [rsp_DatabaseTableSizes]
GROUP BY name
HAVING COUNT(*) > 1
)
DROP TABLE #DatabaseTables
DROP TABLE #AllDatabaseTableSizes
CLOSE AllDatabaseTables
DEALLOCATE AllDatabaseTables
CLOSE AllDatabaseNames
DEALLOCATE AllDatabaseNames
END
--EXEC [dbo].[usp_getAllDBTableSizes]
In case you need to know, the rsp_DatabaseTableSizes table was created through:
CREATE TABLE [dbo].[rsp_DatabaseSizes](
[DatabaseName] [varchar](1000) NULL,
[dbSize] [decimal](15, 2) NULL,
[DateUpdated] [smalldatetime] NULL
) ON [PRIMARY]
GO
Riffing on #Mark answer above, added the #updateusage='true' to force the latest size stats (https://msdn.microsoft.com/en-us/library/ms188776.aspx):
SET NOCOUNT ON
DECLARE #TableInfo TABLE (tablename varchar(255), rowcounts int, reserved varchar(255), DATA varchar(255), index_size varchar(255), unused varchar(255))
DECLARE #cmd1 varchar(500)
SET #cmd1 = 'exec sp_spaceused #objname =''?'', #updateusage =''true'' '
INSERT INTO #TableInfo (tablename,rowcounts,reserved,DATA,index_size,unused)
EXEC sp_msforeachtable #command1=#cmd1
SELECT * FROM #TableInfo ORDER BY Convert(int,Replace(DATA,' KB','')) DESC
Here is a sample query to get tables larger than 1GB ordered by size descending.
USE YourDB
GO
DECLARE #Mult float = 8
SET #Mult = #Mult / POWER(2, 20) -- Use POWER(2, 10) for MBs
; WITH CTE AS
(
SELECT
i.object_id,
Rows = MAX(p.rows),
TotalSpaceGB = ROUND(SUM(a.total_pages) * #Mult, 0),
UsedSpaceGB = ROUND(SUM(a.used_pages) * #Mult, 0)
FROM
sys.indexes i
JOIN
sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
i.object_id > 255
GROUP BY
i.object_id
HAVING
SUM(a.total_pages) * #Mult > 1
)
SELECT
SchemaName = s.name,
TableName = t.name,
c.TotalSpaceGB,
c.UsedSpaceGB,
UnusedSpaceGB = c.TotalSpaceGB - c.UsedSpaceGB,
[RowCount] = c.Rows
FROM
CTE c
JOIN
sys.tables t ON t.object_id = c.object_id
JOIN
sys.schemas s ON t.schema_id = s.schema_id
ORDER BY
c.TotalSpaceGB DESC
As a simple extension to marc_s's answer (the one that has been accepted), this is adjusted to return column count and allow for filtering:
SELECT *
FROM
(
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
(SUM(a.used_pages) * 8) AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
) AS Result
WHERE
RowCounts > 1000
AND ColumnCount > 10
ORDER BY
UsedSpaceKB DESC
I found this query to be easy to use & quick.
select schema_name(tab.schema_id) + '.' + tab.name as [table],
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind
on tab.object_id = ind.object_id
inner join sys.partitions (nolock) part
on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
IF you only care about the empty wasted space in the database and not the individual tables you can consider the following:
If the database experiences large amount of data insertion and then deletions, maybe like in an ETL situation, this will cause too much unused space in the database as the file groups auto-grows but never auto-shrinks back.
You can see if this is the case by using the Properties page of your database. You can shrink (right click on the database > Tasks > Shrink) and claim some space back. But, if the underlying reason is still there, the database will grow back (and consume extra time trying to grow back and things gets slowed down until it grows enough - so don't do it in that case)
CREATE TABLE #tmp_table_info
(
id int identity(1,1),
tblname varchar(200)
);
CREATE TABLE #SpaceUsed
(
TableName sysname
,NumRows BIGINT
,ReservedSpace VARCHAR(50)
,DataSpace VARCHAR(50)
,IndexSize VARCHAR(50)
,UnusedSpace VARCHAR(50)
)
insert into #tmp_table_info
select s.name+'.'+t.name
from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
where t.type = 'U';
declare #min int =1,#max int = 0
select #max = count(*)
from #tmp_table_info
while(#min<=#max)
begin
declare #tablename varchar(200)
select #tablename=tblname
from #tmp_table_info
where id =#min
DECLARE #str VARCHAR(500)
SET #str = 'sp_spaceused '''+#tablename+''''
INSERT INTO #SpaceUsed
EXEC (#str)
set #min =#min + 1
end;
select ##SERVERNAME as servername,DB_NAME() as DatabaseName,CONVERT(numeric(18,0),REPLACE(ReservedSpace,' KB','')) / 1024 as ReservedSpace_MB,
CONVERT(numeric(18,0),REPLACE(DataSpace,' KB','')) / 1024 as DataSpace_MB,
CONVERT(numeric(18,0),REPLACE(IndexSize,' KB','')) / 1024 as IndexSpace_MB,
CONVERT(numeric(18,0),REPLACE(UnusedSpace,' KB','')) / 1024 as UnusedSpace_MB from #SpaceUsed
drop table #tmp_table_info
drop table #SpaceUsed

Query to list number of records in each table in a database

How to list row count of each table in the database. Some equivalent of
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
I will post a solution but other approaches are welcome
If you're using SQL Server 2005 and up, you can also use this:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
In my opinion, it's easier to handle than the sp_msforeachtable output.
A snippet I found at http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021 that helped me:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;
To get that information in SQL Management Studio, right click on the database, then select Reports --> Standard Reports --> Disk Usage by Table.
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
As seen here, this will return correct counts, where methods using the meta data tables will only return estimates.
CREATE PROCEDURE ListTableRowCounts
AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #TableCounts
(
TableName VARCHAR(500),
CountOf INT
)
INSERT #TableCounts
EXEC sp_msForEachTable
'SELECT PARSENAME(''?'', 1),
COUNT(*) FROM ? WITH (NOLOCK)'
SELECT TableName , CountOf
FROM #TableCounts
ORDER BY TableName
DROP TABLE #TableCounts
END
GO
sp_MSForEachTable 'DECLARE #t AS VARCHAR(MAX);
SELECT #t = CAST(COUNT(1) as VARCHAR(MAX))
+ CHAR(9) + CHAR(9) + ''?'' FROM ? ; PRINT #t'
Output:
Well luckily SQL Server management studio gives you a hint on how to do this.
Do this,
start a SQL Server trace and open the activity you are doing (filter
by your login ID if you're not alone and set the application Name
to Microsoft SQL Server Management Studio), pause the trace and discard any results you have recorded till now;
Then, right click a table and select property from the pop up menu;
start the trace again;
Now in SQL Server Management studio select the storage property item on the left;
Pause the trace and have a look at what TSQL is generated by microsoft.
In the probably last query you will see a statement starting with exec sp_executesql N'SELECT
when you copy the executed code to visual studio you will notice that this code generates all the data the engineers at microsoft used to populate the property window.
when you make moderate modifications to that query you will get to something like this:
SELECT
SCHEMA_NAME(tbl.schema_id)+'.'+tbl.name as [table], --> something I added
p.partition_number AS [PartitionNumber],
prv.value AS [RightBoundaryValue],
fg.name AS [FileGroupName],
CAST(pf.boundary_value_on_right AS int) AS [RangeType],
CAST(p.rows AS float) AS [RowCount],
p.data_compression AS [DataCompression]
FROM sys.tables AS tbl
INNER JOIN sys.indexes AS idx ON idx.object_id = tbl.object_id and idx.index_id < 2
INNER JOIN sys.partitions AS p ON p.object_id=CAST(tbl.object_id AS int) AND p.index_id=idx.index_id
LEFT OUTER JOIN sys.destination_data_spaces AS dds ON dds.partition_scheme_id = idx.data_space_id and dds.destination_id = p.partition_number
LEFT OUTER JOIN sys.partition_schemes AS ps ON ps.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_range_values AS prv ON prv.boundary_id = p.partition_number and prv.function_id = ps.function_id
LEFT OUTER JOIN sys.filegroups AS fg ON fg.data_space_id = dds.data_space_id or fg.data_space_id = idx.data_space_id
LEFT OUTER JOIN sys.partition_functions AS pf ON pf.function_id = prv.function_id
Now the query is not perfect and you could update it to meet other questions you might have, the point is, you can use the knowledge of microsoft to get to most of the questions you have by executing the data you're interested in and trace the TSQL generated using profiler.
I kind of like to think that MS engineers know how SQL server work and, it will generate TSQL that works on all items you can work with using the version on SSMS you are using so it's quite good on a large variety releases prerviouse, current and future.
And remember, don't just copy, try to understand it as well else you might end up with the wrong solution.
Walter
This approaches uses string concatenation to produce a statement with all tables and their counts dynamically, like the example(s) given in the original question:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
Finally this is executed with EXEC:
DECLARE #cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(#cmd);
The first thing that came to mind was to use sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
that does not list the table names though, so it can be extended to
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
The problem here is that if the database has more than 100 tables you will get the following error message:
The query has exceeded the maximum
number of result sets that can be
displayed in the results grid. Only
the first 100 result sets are
displayed in the grid.
So I ended up using table variable to store the results
declare #stats table (n sysname, c int)
insert into #stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from #stats
order by c desc
Fastest way to find row count of all tables in SQL Refreence (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
I want to share what's working for me
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
The database is hosted in Azure and the final result is:
Credit: https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/
Here is my take on this question. It contains all schemas and lists only tables with rows. YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;
If you use MySQL >4.x you can use this:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
Keep in mind that for some storage engines, TABLE_ROWS is an approximation.
The accepted answer didn't work for me on Azure SQL, here's one that did, it's super fast and did exactly what I wanted:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
You could try this:
SELECT OBJECT_SCHEMA_NAME(ps.object_Id) AS [schemaname],
OBJECT_NAME(ps.object_id) AS [tablename],
row_count AS [rows]
FROM sys.dm_db_partition_stats ps
WHERE OBJECT_SCHEMA_NAME(ps.object_Id) <> 'sys' AND ps.index_id < 2
ORDER BY
OBJECT_SCHEMA_NAME(ps.object_Id),
OBJECT_NAME(ps.object_id)
This sql script gives the schema, table name and row count of each table in a database selected:
SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc
Ref: https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/
Another way of doing this:
SELECT o.NAME TABLENAME,
i.rowcnt
FROM sysindexes AS i
INNER JOIN sysobjects AS o ON i.id = o.id
WHERE i.indid < 2 AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc
I think that the shortest, fastest and simplest way would be:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable #command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts
From this question:
https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
I added record count to the answer provided by #Aaron Bertrand that lists all databases and all tables.
DECLARE #src NVARCHAR(MAX), #sql NVARCHAR(MAX);
SELECT #sql = N'', #src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT #sql = #sql + REPLACE(#src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET #sql = STUFF(#sql, 1, 10, CHAR(13) + CHAR(10));
PRINT #sql;
--EXEC sys.sp_executesql #sql;
You can copy, past and execute this piece of code to get all table record counts into a table. Note: Code is commented with instructions
create procedure RowCountsPro
as
begin
--drop the table if exist on each exicution
IF OBJECT_ID (N'dbo.RowCounts', N'U') IS NOT NULL
DROP TABLE dbo.RowCounts;
-- creating new table
CREATE TABLE RowCounts
( [TableName] VARCHAR(150)
, [RowCount] INT
, [Reserved] NVARCHAR(50)
, [Data] NVARCHAR(50)
, [Index_Size] NVARCHAR(50)
, [UnUsed] NVARCHAR(50))
--inserting all records
INSERT INTO RowCounts([TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed])
-- "sp_MSforeachtable" System Procedure, 'sp_spaceused "?"' param to get records and resources used
EXEC sp_MSforeachtable 'sp_spaceused "?"'
-- selecting data and returning a table of data
SELECT [TableName], [RowCount],[Reserved],[Data],[Index_Size],[UnUsed]
FROM RowCounts
ORDER BY [TableName]
end
I have tested this code and it works fine on SQL Server 2014.
SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO
Shnugo's answer is the ONLY one that works in Azure with Externa Tables. (1) Azure SQL doesn't support sp_MSforeachtable at all and (2) rows in sys.partitions for an External table is always 0.
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
Here indid=1 means a CLUSTERED index and indid=0 is a HEAP

Table and Index size in SQL Server

Can we have a SQL query which will basically help in viewing table and index sizes in SQl Server.
How SQL server maintains memory usage for tables/indexes?
sp_spaceused gives you the size of all the indexes combined.
If you want the size of each index for a table, use one of these two queries:
SELECT
i.name AS IndexName,
SUM(s.used_page_count) * 8 AS IndexSizeKB
FROM sys.dm_db_partition_stats AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
WHERE s.[object_id] = object_id('dbo.TableName')
GROUP BY i.name
ORDER BY i.name
SELECT
i.name AS IndexName,
SUM(page_count * 8) AS IndexSizeKB
FROM sys.dm_db_index_physical_stats(
db_id(), object_id('dbo.TableName'), NULL, NULL, 'DETAILED') AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
GROUP BY i.name
ORDER BY i.name
The results are usually slightly different but within 1%.
The exec sp_spaceused without parameter shows the summary for the whole database. The foreachtable solution generates one result set per table - which SSMS might not be able to handle if you have too many tables.
I created a script which collects the table infos via sp_spaceused and displays a summary in a single record set, sorted by size.
create table #t
(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
declare #id nvarchar(128)
declare c cursor for
select '[' + sc.name + '].[' + s.name + ']' FROM sysobjects s INNER JOIN sys.schemas sc ON s.uid = sc.schema_id where s.xtype='U'
open c
fetch c into #id
while ##fetch_status = 0 begin
insert into #t
exec sp_spaceused #id
fetch c into #id
end
close c
deallocate c
select * from #t
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #t
On SQL 2012 getting this information on a table level has become deliciously simple:
SQL Management Studio -> Right click on Db -> Reports -> Standard Reports -> Disk usage by table !
Enjoy
EXEC sp_MSforeachtable #command1="EXEC sp_spaceused '?'"
It’s been a long time since the creation of this post, but I wanted to share my script:
WITH CteIndex
AS
(
SELECT
reservedpages = (reserved_page_count)
,usedpages = (used_page_count)
,pages = (
CASE
WHEN (s.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END
)
,s.object_id
,i.index_id
,i.type_desc AS IndexType
,i.name AS indexname
FROM sys.dm_db_partition_stats s
INNER JOIN sys.indexes i ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
)
SELECT DISTINCT
DB_NAME(DB_ID()) AS DatabaseName
,o.name AS TableName
,o.object_id
,ct.indexname
,ct.IndexType
,ct.index_id
, IndexSpace = LTRIM (STR ((CASE WHEN usedpages > pages THEN CASE WHEN ct.index_id < 2 THEN pages ELSE (usedpages - pages) END ELSE 0 END) * 8, 15, 0) + ' KB')
FROM CteIndex ct
INNER JOIN sys.objects o ON o.object_id = ct.object_id
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL , NULL) ps ON ps.object_id = o.object_id
AND ps.index_id = ct.index_id
ORDER BY name ASC
This works for :
SQL Server (starting with 2008)
Includes info for all tables per current database
--Gets the size of each index for the specified table
DECLARE #TableName sysname = N'SomeTable';
SELECT i.name AS IndexName
,8 * SUM(s.used_page_count) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.dm_db_partition_stats AS s
ON i.[object_id] = s.[object_id] AND i.index_id = s.index_id
WHERE s.[object_id] = OBJECT_ID(#TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
SELECT i.name AS IndexName
,8 * SUM(a.used_pages) AS IndexSizeKB
FROM sys.indexes AS i
INNER JOIN sys.partitions AS p
ON i.[object_id] = p.[object_id] AND i.index_id = p.index_id
INNER JOIN sys.allocation_units AS a
ON p.partition_id = a.container_id
WHERE i.[object_id] = OBJECT_ID(#TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
Here is more compact version of the most successful answer:
create table #tbl(
name nvarchar(128),
rows varchar(50),
reserved varchar(50),
data varchar(50),
index_size varchar(50),
unused varchar(50)
)
exec sp_msforeachtable 'insert into #tbl exec sp_spaceused [?]'
select * from #tbl
order by convert(int, substring(data, 1, len(data)-3)) desc
drop table #tbl
This query comes from two other answers:
Get size of all tables in database
How to find largest objects in a SQL Server database?
, but I enhanced this to be universal. It uses sys.objects dictionary:
SELECT
s.NAME as SCHEMA_NAME,
t.NAME AS OBJ_NAME,
t.type_desc as OBJ_TYPE,
i.name as indexName,
sum(p.rows) as RowCounts,
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.objects t
INNER JOIN
sys.schemas s ON t.SCHEMA_ID = s.SCHEMA_ID
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
s.NAME, t.NAME, t.type_desc, i.object_id, i.index_id, i.name
ORDER BY
sum(a.total_pages) DESC
;
There is an extended stored procedure sp_spaceused that gets this information out. It's fairly convoluted to do it from the data dictionary, but This link fans out to a script that does it. This stackoverflow question has some fan-out to information on the underlying data structures that you can use to construct estimates of table and index sizes for capcity planning.
To see a single table's (and its indexes) storage data:
exec sp_spaceused MyTable

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