Get the rank of each string extracted from split_string - sql-server

Question

I have a TABLE with STR DNA DATA the following Table [DYS]
Id
DYS385
3
10-19
4
13-16
5
13-18
6
13-19
7
13-17
8
13-18
9
13-18
10
14-19
11
13-19
12
13-18
I am USING the following script to split the values of [DYS385]
select top 10 id,[DYS385],t.Value
from dys
OUTER APPLY(select * from string_split([DYS385],'-')) t
where dys385 is not null
Output
Id
DYS385
VALUE
3
10-19
10
3
10-19
19
4
13-16
13
4
13-16
16
5
13-18
13
5
13-18
18
6
13-19
13
6
13-19
19
7
13-17
13
7
13-17
17
I want to get for each Value, the Rank
example
10-19 => 10: Rank 1, 19: Rank 2
Desired results:
Id
DYS385
VALUE
RANK
3
10-19
10
1
3
10-19
19
2
4
13-16
13
1
4
13-16
16
2
5
13-18
13
1
5
13-18
18
2
6
13-19
13
1
6
13-19
19
2
7
13-17
13
1
7
13-17
17
2

Answer 1

Use an alternative string-split method, such as XML or Json that can return an ordinal position, such as:
create function dbo.SplitString(#string varchar(1000), #Delimiter varchar(10))
returns table
as
return(
select j.[value], 1 + Convert(tinyint,j.[key]) Seq
from OpenJson(Concat('["',replace(#string,#delimiter, '","'),'"]')) j
);
select value, Seq as [Rank]
from dbo.SplitString('10-19','-')
order by [Rank];
Example fiddle

Answer 2

Given this data:
CREATE TABLE dbo.Something(Id int, DYS385 varchar(10));
INSERT dbo.Something(Id, DYS385) VALUES (3 , '10-19'),
(4 , '13-16'), (5 , '13-18'), (6 , '13-19'),
(7 , '13-17'), (8 , '13-18'), (9 , '13-18'),
(10, '14-19'), (11, '13-19'), (12, '13-18');
Another way to make sure you rank the broken-up strings in the right order could be to use tricks like PARSENAME(), though this can be sensitive to strings lengths and whether a dot is valid within the data:
SELECT s.Id, s.DYS385, value = v.v, [rank] = ROW_NUMBER() OVER
(PARTITION BY s.Id ORDER BY c.c DESC)
FROM dbo.Something AS s
CROSS APPLY (VALUES(1),(2)) AS c(c)
CROSS APPLY (VALUES(PARSENAME(REPLACE(s.DYS385,'-','.'),c.c))) AS v(v)
ORDER BY s.Id, [rank];
Output:
Id
DYS385
value
rank
3
10-19
10
1
3
10-19
19
2
4
13-16
13
1
4
13-16
16
2
5
13-18
13
1
5
13-18
18
2
6
13-19
13
1
6
13-19
19
2
7
13-17
13
1
7
13-17
17
2
8
13-18
13
1
8
13-18
18
2
9
13-18
13
1
9
13-18
18
2
10
14-19
14
1
10
14-19
19
2
11
13-19
13
1
11
13-19
19
2
12
13-18
13
1
12
13-18
18
2
Example db<>fiddle

Answer 3

Split_string has an option to output this rank, called ordinal. Just add an extra parameter with the value of 1:
SELECT *FROM STRING_SPLIT('Lorem ipsum dolor sit amet.', ' ', 1);
That returns:
value ordinal
Lorem 1
ipsum 2
dolor 3
sit 4
amet. 5
In your case the query would be:
select top 10 id,[DYS385],t.* from dys OUTER APPLY(select * from string_split([DYS385],'-',1)) t where dys385 is not null

Answer 4

We can also make recursive split_string function which returns the rank of each item as follows
Link dbfiddle
Create function Split_Recursive(#string nvarchar(max),#delimiter as varchar(1)) returns Table
as
return(
with cte as(
select 1 N,
case when charindex(#delimiter,#string,1) =0 then #string else
substring(#string,1,-1+charindex(#delimiter,#string,1)) end [Found],
case when charindex(#delimiter,#string,1)=0 then #string else substring(#string,1+charindex(#delimiter,#string,1) ,len(#string))
end [MYSTRING]
union all
select 1+n,
case when charindex(#delimiter,[MYSTRING],1)=0 then [MYSTRING] else
substring([MYSTRING],1,-1+charindex(#delimiter,[MYSTRING],1)) end,substring([MYSTRING],1+charindex(#delimiter,[MYSTRING]),len([MYSTRING])) from cte
where charindex(#delimiter,[MYSTRING],1)>0),
cte2 as (select N,Found from cte
union select 1+t.N,Mystring from cte OUTER APPLY(select top 1 N from cte order by n desc)t where t.n=cte.n
)
select N Rank,Found from cte2
)
go
select * from dbo.Split_Recursive('12-16','-')
Output
Rank
Found
1
12
2
16