Use of "while" instead of "for" in C - c

Question

Hello I'm new to programming, and would want to return an array in a "while" condition (not use "for"), any tips to make my program working please? Thanks
int numberPlayer=0;
int *listPlayers= NULL;
int i;
printf("How many players");
scanf("%d",&numberPlayer);
listPlayers= malloc(sizeof(int) * numberPlayer);
if (listPlayers==NULL){
exit(1);
}
i=0;
while(i<numberPlayer){
printf("Joueur n° %d", i*3);
listPlayers[i]= i*3;
i++;
}
while(i<numberPlayer){
printf("%d", listPlayers[i]);
i++;
}

Answer 1

I think you should learn how to use function. return array pointer is available for function not for commands like while, for.
you can check this https://www.tutorialspoint.com/cprogramming/c_return_arrays_from_function.htm

Answer 2

Your example is a perfect illustration of the superiority of the for loop over the while loop. It is a shame some schools insist on students using only while loops (42, Epita, Epitech...)
You forgot to initialize i = 0 before the second while loop. A classical for loop combines initialization, test and increment in the for clauses, making it easy to read and verify.
For proper output, you should use a separator between the numbers and output a newline.
Here is a modified version:
#include <stdio.h>
#include <stdlib.h>
int main() {
int numberPlayers = 0;
int *listPlayers = NULL;
int i;
printf("How many players? ");
if (scanf("%d", &numberPlayers) != 1) {
return 1;
}
listPlayers = malloc(sizeof(int) * numberPlayers);
if (listPlayers == NULL) {
return 1;
}
i = 0;
while (i < numberPlayers) {
printf("Joueur n° %d? ", i * 3);
if (scanf("%d", &listPlayers[i]) != 1)
return 1;
i++;
}
printf("Liste des joueurs: ");
i = 0;
while (i < numberPlayers) {
printf("[%d]", numberPlayers[i]);
i++;
}
printf("\n");
free(listPlayers);
return 0;
}