How do I share state between routes in React-Router? - reactjs

Question

I've seen a few questions similar to this on SO but none that quite matched my needs. I'm using React and Material-UI to make a dashboard. I'm using Material-UI's mini variant drawer as a sidebar, with links that should display routes when clicked. The sidebar can be opened by clicking a button, which updates a state variable and adjusts the CSS className of the sidebar. This causes the sidebar/drawer to "slide" open.
If I click a link on the sidebar, I can easily display a desired route. However, I can't get the route to also "slide" to the side when the sidebar/drawer opens. It will probably be easier to understand by looking at the code, so I've included a link to a codesandbox below:
https://codesandbox.io/s/appbar-with-react-router-bkogj?file=/src/App.js
I basically copy and pasted everything from the Material-UI website (using v4 I believe), then added the route myself. Would appreciate any feedback on how to solve this issue.

Answer 1

For this I think the MiniDrawer component needs to render the content since it necessarily is aware of the space the appbar and drawer components occupy.
MiniDrawer
Take and render a children prop.
export default function MiniDrawer({ children }) {
...
return (
<div className={classes.root}>
<CssBaseline />
<AppBar
...
>
...
</AppBar>
<Drawer
...
>
...
</Drawer>
<main className={classes.content}>{children}</main>
</div>
);
}
App
Render the Outlet as a child component.
export default function App() {
return (
<div className="App">
<AppBar>
<Outlet />
</AppBar>
</div>
);
}
RejectTable
Remove the excess margin so it fills the content area the parent component allows.
const useStyles = makeStyles((theme) => ({
content: {
flexGrow: 1,
padding: theme.spacing(3),
height: "100%",
// marginLeft: "4em" // <-- remove
}
}));