I am trying to extract words from a string like this:
(octopus kitten) (game cake) (soccer football)
I attempted doing this with the help of strtok (I do strcpy just for not modifying the original token/string, also used memcpy, but it does the same in my case).
Main function:
int main(int argc, char * argv[]) {
char row[] = "(octopus kitten) (game cake) (soccer football)";
char * pch;
pch = strtok(row, "(");
while (pch != NULL) {
pch[strcspn(pch, ")")] = '\0';
print_word(pch);
pch = strtok(NULL, "(");
}
return 0;
}
Function for getting and printing each word:
void get_and_print_word(char str[]) {
char r[4000];
// for not modifying the original string
strcpy(r, str);
char * c = strtok(r, " ");
for (int i = 0; i < 2; i++) {
printf("%s\n", c);
c = strtok(NULL, " ");
}
}
It works absolutely fine with a first iteration, but after pch starts to point to another adress of memory (but it should point to the adress of letter "g").
It works absolutely fine (it's just printing string within the brackets) if we remove get_and_print_word(pch):
int main(int argc, char * argv[]) {
char row[] = "(octopus kitten) (game cake) (soccer football)";
char * pch;
pch = strtok(row, "(");
while (pch != NULL) {
pch[strcspn(pch, ")")] = '\0';
printf("%s\n", pch);
pch = strtok(NULL, "(");
}
return 0;
}
But that's not what I want to do, I need to get each word, not just a string of two words and space between them.
Using pch = strtok(NULL, " )(") is also not appropriate in my case, cause I need to store each pair of words (each word, of couse, should be a separate string) in some individual
struct, so I definitely need this function.
How to solve this issue and why it works like this?
Why not use regular expression :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <regex.h>
int main (int argc, char *argv[])
{
int err;
regex_t preg;
const char *str_request = argv[1];
const char *str_regex = argv[2];
err = regcomp (&preg, str_regex, REG_EXTENDED);
if (err == 0) {
int match;
size_t nmatch = 0;
regmatch_t *pmatch = NULL;
nmatch = preg.re_nsub;
pmatch = malloc (sizeof (*pmatch) * nmatch);
char *buffer;
if (pmatch) {
buffer = (char *) str_request;
match = regexec (&preg, buffer, nmatch, pmatch, 0);
while (match == 0) {
char *found = NULL;
size_t size ;
int start, end;
start = pmatch[0].rm_so;
end = pmatch[0].rm_eo;
size = end - start;
found = malloc (sizeof (*found) * (size + 1));
if (found) {
strncpy (found, &buffer[start], size);
found[size] = '\0';
printf ("found : %s\n", found);
free (found);
}
//searching next occurence
match = regexec (&preg, (buffer += end), nmatch, pmatch, 0);
}
regfree (&preg);
free (pmatch);
}
}
return 0;
}
[puppet#damageinc regex]$ ./regex "(octopus kitten) (game cake) (soccer football)" "([a-z]+)"
found : octopus
found : kitten
found : game
found : cake
found : soccer
found : football
Related
Situation as following:
In the first line input a string, then the following lines are 'command'. 2 types of command 'p' and 's', 'p' means printing the string, 's' means substitution.
e.g. Input a string aaabbbcccqwerdd then input sbqwerbkkk
(s means substitution, b acts as a delimiter, therefore it means replacing qwer in the string with kkk)
The expected result should be aaabbbccckkkdd, but instead I got aaabbbccckkkrdd
Any help?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXLEN 1023
int main() {
char str[MAXLEN];
scanf("%s", str);
char command[MAXLEN];
while (scanf("%s", command) != EOF) {
if (command[0] == 'p') {
printf("%s\n", str); }
else if (command[0] == 's') {
char delimiter[] = {"0"};
strncpy(delimiter, command+1, 1);
char *a = command;
a = strtok(command, delimiter);
a = strtok(NULL, delimiter);
char *b = command;
b = strtok(NULL, delimiter);
int alength = strlen(a);
int blength = strlen(b);
char *bereplaced = strstr(str, a);
if (bereplaced == NULL) {
continue; }
int aindex = bereplaced - str;
strncpy(str + aindex, b, blength);
}
}
return 0;
}
Many things can go wrong here but the main issue is copying from from source string on to itself, there can be memory overlap. Instead declare a new buffer for the result for find/replace operation.
You can define a separate find_replace function as follows:
char* find_replace(const char* src, const char* find, const char* replace)
{
if (!src) return NULL;
char* find_ptr = strstr(src, find); if (!find_ptr) return NULL;
int find_start = find_ptr - src;
int find_length = strlen(find);
char* result = malloc(strlen(src) + strlen(replace) + 1);
strncpy(result, src, find_start);
strcpy(result + find_start, replace);
strcat(result, find_ptr + find_length);
return result;
}
int main()
{
char source[] = "aaabbbcccqwerdd";
char command[] = "sbqwerbkkk";
if (command[0] != 's') return 0;
char delimiter[] = { "0" };
delimiter[0] = command[1];
char* find = strtok(command, delimiter); if (!find) return 0;
find = strtok(NULL, delimiter); if (!find) return 0;
char* replace = strtok(NULL, delimiter); if (!replace) return 0;
char* result = find_replace(source, find, replace);
if (!result) return 0;
printf("%s\n", result);
free(result);
return 0;
}
Here is another solution. It does the substitution directly into the input string by:
Use memmove to move the trailing part of the orginal string to its final location
Use strncpy to copy the substitute substring to its final location
Like:
#include <stdio.h>
#include <string.h>
#define MAXLEN 1023
int main(void)
{
char str[MAXLEN] = "aaabbbcccqwerdd";
char command[MAXLEN] = "sbqwerbkkk";
printf("COMMAND : %s\n", command);
printf("TEXT BEFORE : %s\n", str);
char* pfind = command + 2; // skip initial sb
char* psub = strchr(pfind, 'b'); // find delimiter
*psub = '\0'; // terminate replace string
++psub; // point to substitute substring
size_t flen = strlen(pfind); // calculate length
size_t slen = strlen(psub); // calculate length
char* p = strstr(str, pfind); // find location of replace string
size_t sc = strlen(p); // calculate length
memmove(p + slen, p + flen, sc - flen + 1); // Move trailing part
strncpy(p, psub, slen); // Put in substitute substring
printf("TEXT AFTER : %s\n", str);
return 0;
}
Output:
COMMAND : sbqwerbkkk
TEXT BEFORE : aaabbbcccqwerdd
TEXT AFTER : aaabbbccckkkdd
Disclamer
In order to keep the code example short, the above code blindly trust that the command and the original string form a legal substitution and that there are sufficient memory for the result.
In real code, you need to check that. For instance check that strchr and strstr doesn't return NULL.
I am getting used to writing eBPF code as of now and want to avoid using pointers in my BPF text due to how difficult it is to get a correct output out of it. Using strtok() seems to be out of the question due to all of the example codes requiring pointers. I also want to expand it to CSV files in the future since this is a means of practice for me. I was able to find another user's code here but it gives me an error with the BCC terminal due to the one pointer.
char str[256];
bpf_probe_read_user(&str, sizeof(str), (void *)PT_REGS_RC(ctx));
char token[] = strtok(str, ",");
char input[] ="first second third forth";
char delimiter[] = " ";
char firstWord, *secondWord, *remainder, *context;
int inputLength = strlen(input);
char *inputCopy = (char*) calloc(inputLength + 1, sizeof(char));
strncpy(inputCopy, input, inputLength);
str = strtok_r (inputCopy, delimiter, &context);
secondWord = strtok_r (NULL, delimiter, &context);
remainder = context;
getchar();
free(inputCopy);
Pointers are powerful, and you wont be able to avoid them for very long. The time you invest in learning them is definitively worth it.
Here is an example:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/**
Extracts the word with the index "n" in the string "str".
Words are delimited by a blank space or the end of the string.
}*/
char *getWord(char *str, int n)
{
int words = 0;
int length = 0;
int beginIndex = 0;
int endIndex = 0;
char currentchar;
while ((currentchar = str[endIndex++]) != '\0')
{
if (currentchar == ' ')
{
if (n == words)
break;
if (length > 0)
words++;
length = 0;
beginIndex = endIndex;
continue;
}
length++;
}
if (n == words)
{
char *result = malloc(sizeof(char) * length + 1);
if (result == NULL)
{
printf("Error while allocating memory!\n");
exit(1);
}
memcpy(result, str + beginIndex, length);
result[length] = '\0';
return result;
}else
return NULL;
}
You can easily use the function:
int main(int argc, char *argv[])
{
char string[] = "Pointers are cool!";
char *word = getWord(string, 2);
printf("The third word is: '%s'\n", word);
free(word); //Don't forget to de-allocate the memory!
return 0;
}
I have been trying to tokenize a string using SPACE as delimiter but it doesn't work. Does any one have suggestion on why it doesn't work?
Edit: tokenizing using:
strtok(string, " ");
The code is like the following
pch = strtok (str," ");
while (pch != NULL)
{
printf ("%s\n",pch);
pch = strtok (NULL, " ");
}
Do it like this:
char s[256];
strcpy(s, "one two three");
char* token = strtok(s, " ");
while (token) {
printf("token: %s\n", token);
token = strtok(NULL, " ");
}
Note: strtok modifies the string its tokenising, so it cannot be a const char*.
Here's an example of strtok usage, keep in mind that strtok is destructive of its input string (and therefore can't ever be used on a string constant
char *p = strtok(str, " ");
while(p != NULL) {
printf("%s\n", p);
p = strtok(NULL, " ");
}
Basically the thing to note is that passing a NULL as the first parameter to strtok tells it to get the next token from the string it was previously tokenizing.
strtok can be very dangerous. It is not thread safe. Its intended use is to be called over and over in a loop, passing in the output from the previous call. The strtok function has an internal variable that stores the state of the strtok call. This state is not unique to each thread - it is global. If any other code uses strtok in another thread, you get problems. Not the kind of problems you want to track down either!
I'd recommend looking for a regex implementation, or using sscanf to pull apart the string.
Try this:
char strprint[256];
char text[256];
strcpy(text, "My string to test");
while ( sscanf( text, "%s %s", strprint, text) > 0 ) {
printf("token: %s\n", strprint);
}
Note: The 'text' string is destroyed as it's separated. This may not be the preferred behaviour =)
You can simplify the code by introducing an extra variable.
#include <string.h>
#include <stdio.h>
int main()
{
char str[100], *s = str, *t = NULL;
strcpy(str, "a space delimited string");
while ((t = strtok(s, " ")) != NULL) {
s = NULL;
printf(":%s:\n", t);
}
return 0;
}
I've made some string functions in order to split values, by using less pointers as I could because this code is intended to run on PIC18F processors. Those processors does not handle really good with pointers when you have few free RAM available:
#include <stdio.h>
#include <string.h>
char POSTREQ[255] = "pwd=123456&apply=Apply&d1=88&d2=100&pwr=1&mpx=Internal&stmo=Stereo&proc=Processor&cmp=Compressor&ip1=192&ip2=168&ip3=10&ip4=131&gw1=192&gw2=168&gw3=10&gw4=192&pt=80&lic=&A=A";
int findchar(char *string, int Start, char C) {
while((string[Start] != 0)) { Start++; if(string[Start] == C) return Start; }
return -1;
}
int findcharn(char *string, int Times, char C) {
int i = 0, pos = 0, fnd = 0;
while(i < Times) {
fnd = findchar(string, pos, C);
if(fnd < 0) return -1;
if(fnd > 0) pos = fnd;
i++;
}
return fnd;
}
void mid(char *in, char *out, int start, int end) {
int i = 0;
int size = end - start;
for(i = 0; i < size; i++){
out[i] = in[start + i + 1];
}
out[size] = 0;
}
void getvalue(char *out, int index) {
mid(POSTREQ, out, findcharn(POSTREQ, index, '='), (findcharn(POSTREQ, index, '&') - 1));
}
void main() {
char n_pwd[7];
char n_d1[7];
getvalue(n_d1, 1);
printf("Value: %s\n", n_d1);
}
When reading the strtok documentation, I see you need to pass in a NULL pointer after the first "initializing" call. Maybe you didn't do that. Just a guess of course.
Here is another strtok() implementation, which has the ability to recognize consecutive delimiters (standard library's strtok() does not have this)
The function is a part of BSD licensed string library, called zString. You are more than welcome to contribute :)
https://github.com/fnoyanisi/zString
char *zstring_strtok(char *str, const char *delim) {
static char *static_str=0; /* var to store last address */
int index=0, strlength=0; /* integers for indexes */
int found = 0; /* check if delim is found */
/* delimiter cannot be NULL
* if no more char left, return NULL as well
*/
if (delim==0 || (str == 0 && static_str == 0))
return 0;
if (str == 0)
str = static_str;
/* get length of string */
while(str[strlength])
strlength++;
/* find the first occurance of delim */
for (index=0;index<strlength;index++)
if (str[index]==delim[0]) {
found=1;
break;
}
/* if delim is not contained in str, return str */
if (!found) {
static_str = 0;
return str;
}
/* check for consecutive delimiters
*if first char is delim, return delim
*/
if (str[0]==delim[0]) {
static_str = (str + 1);
return (char *)delim;
}
/* terminate the string
* this assignmetn requires char[], so str has to
* be char[] rather than *char
*/
str[index] = '\0';
/* save the rest of the string */
if ((str + index + 1)!=0)
static_str = (str + index + 1);
else
static_str = 0;
return str;
}
As mentioned in previous posts, since strtok(), or the one I implmented above, relies on a static *char variable to preserve the location of last delimiter between consecutive calls, extra care should be taken while dealing with multi-threaded aplications.
int not_in_delimiter(char c, char *delim){
while(*delim != '\0'){
if(c == *delim) return 0;
delim++;
}
return 1;
}
char *token_separater(char *source, char *delimiter, char **last){
char *begin, *next_token;
char *sbegin;
/*Get the start of the token */
if(source)
begin = source;
else
begin = *last;
sbegin = begin;
/*Scan through the string till we find character in delimiter. */
while(*begin != '\0' && not_in_delimiter(*begin, delimiter)){
begin++;
}
/* Check if we have reached at of the string */
if(*begin == '\0') {
/* We dont need to come further, hence return NULL*/
*last = NULL;
return sbegin;
}
/* Scan the string till we find a character which is not in delimiter */
next_token = begin;
while(next_token != '\0' && !not_in_delimiter(*next_token, delimiter)) {
next_token++;
}
/* If we have not reached at the end of the string */
if(*next_token != '\0'){
*last = next_token--;
*next_token = '\0';
return sbegin;
}
}
void main(){
char string[10] = "abcb_dccc";
char delim[10] = "_";
char *token = NULL;
char *last = "" ;
token = token_separater(string, delim, &last);
printf("%s\n", token);
while(last){
token = token_separater(NULL, delim, &last);
printf("%s\n", token);
}
}
You can read detail analysis at blog mentioned in my profile :)
Is there a better of parsing the below string instead of doing a strtok() to get each field.
"subject=what&cc=bose#yahoo.com&server=smtp.yahoo.com:8000"
Basically I want to retrieve the value for each field into another char buf's.
Here is my code. Just wanted to know if there is any other better way of doing it (any better string parsing algos)
#include <stdio.h>
#include <stdint.h>
#include <string.h>
#include <stdlib.h>
#define SUBJECT "subject="
#define CC_LIST "cc="
#define SERVER "server="
static void
get_value (const char *tok, char **rval_buf, size_t field_len)
{
size_t val_size = 0;
if (!tok || !rval_buf)
return;
val_size = strlen(tok + field_len) + 1;
*rval_buf = calloc(1, val_size);
if (*rval_buf) {
strlcpy(*rval_buf, tok + field_len, val_size);
}
}
int
main (int argc, char **argv)
{
/* hard coded buf for testing */
char buf[] = "subject=what&cc=bose#yahoo.com&server=smtp.yahoo.com:8000";
char *subject_text = NULL;
char *cc_list = NULL;
char *server_addr = NULL;
char *tok = NULL;
int field_len = 0;
int val_len = 0;
tok = strtok(buf, "&");
while(tok) {
/*
* Handle the token
*/
/* check if it is subject */
if (strstr(tok, SUBJECT)) {
get_value(tok, &subject_text, strlen(SUBJECT));
} else if (strstr(tok, CC_LIST)) { /* check if it is CC */
get_value(tok, &cc_list, strlen(CC_LIST));
} else if (strstr(tok, SERVER)) { /* check if it is server */
get_value(tok, &server_addr, strlen(SERVER));
}
tok = strtok(NULL, "&");
}
/* dump data */
fprintf(stdout, "\nSUBJECT: \"%s\"\nCC_LIST: \"%s\"\nSERVER: \"%s\" \n\n",
subject_text, cc_list, server_addr);
return EXIT_SUCCESS;
}
strstr searches for one string ("the needle") inside another ("the haystack"), but you really only want to know whether the needle is the beginning of the haystack.
Here's a small suggestion: (requires #include <stdbool> or change the booleans to ints. I like bools.)
static bool
getval(const char* haystack, const char** res, const char* needle, size_t len) {
if (haystack && 0 == strncmp(haystack, needle, len)) {
*res = strdup(haystack + len);
return true;
}
return false;
}
and later:
for (tok = strtok(buf, "&"); tok; tok = strtok(NULL, "&")) {
getval(tok, &subject_text, SUBJECT, strlen(SUBJECT)) ||
getval(tok, &cc_list, CC_LIST, strlen(CC_LIST)) ||
getval(tok, &server_addr, SERVER, strlen(SERVER));
}
You can actually get away with doing the strlen inside of getval, which cuts down a lot on the noise, because most modern compilers are clever enough to inline getval and constant-fold the length of a constant string.
Use strtok()
char *strtok(char *str, const char *delim)
You can put '&' as a delimeter
I wrote a quick-n-dirty splitter for you:
int split(char* input, char delim, char*** parts)
{
int count = 1;
char** result;
char* t = input;
while(*t != '\0')
{
if (*t++ == delim)
{
count++;
}
}
result = (char**)malloc(count * sizeof(char*));
t = input;
int i = 0;
result[i] = input;
while(*t != '\0')
{
if (*t == delim)
{
*t = '\0';
result[++i] = ++t;
}
else
{
t++;
}
}
*parts = result;
return count;
}
int main()
{
char raw[] = "subject=\"some text\"&cc=abcd&server=acd.com";
char* str = _strdup(raw);
char** parts;
char** keyval;
int cnt = split(str, '&', &parts);
for(int i=0; i<cnt; ++i)
{
split(parts[i], '=', &keyval);
printf("[%d]: %s <--> %s\n", i, keyval[0], keyval[1]);
free(keyval);
}
free(parts);
getchar();
return 0;
}
Output
[0]: subject <--> "some text"
[1]: cc <--> abcd
[2]: server <--> acd.com
I have been trying to tokenize a string using SPACE as delimiter but it doesn't work. Does any one have suggestion on why it doesn't work?
Edit: tokenizing using:
strtok(string, " ");
The code is like the following
pch = strtok (str," ");
while (pch != NULL)
{
printf ("%s\n",pch);
pch = strtok (NULL, " ");
}
Do it like this:
char s[256];
strcpy(s, "one two three");
char* token = strtok(s, " ");
while (token) {
printf("token: %s\n", token);
token = strtok(NULL, " ");
}
Note: strtok modifies the string its tokenising, so it cannot be a const char*.
Here's an example of strtok usage, keep in mind that strtok is destructive of its input string (and therefore can't ever be used on a string constant
char *p = strtok(str, " ");
while(p != NULL) {
printf("%s\n", p);
p = strtok(NULL, " ");
}
Basically the thing to note is that passing a NULL as the first parameter to strtok tells it to get the next token from the string it was previously tokenizing.
strtok can be very dangerous. It is not thread safe. Its intended use is to be called over and over in a loop, passing in the output from the previous call. The strtok function has an internal variable that stores the state of the strtok call. This state is not unique to each thread - it is global. If any other code uses strtok in another thread, you get problems. Not the kind of problems you want to track down either!
I'd recommend looking for a regex implementation, or using sscanf to pull apart the string.
Try this:
char strprint[256];
char text[256];
strcpy(text, "My string to test");
while ( sscanf( text, "%s %s", strprint, text) > 0 ) {
printf("token: %s\n", strprint);
}
Note: The 'text' string is destroyed as it's separated. This may not be the preferred behaviour =)
You can simplify the code by introducing an extra variable.
#include <string.h>
#include <stdio.h>
int main()
{
char str[100], *s = str, *t = NULL;
strcpy(str, "a space delimited string");
while ((t = strtok(s, " ")) != NULL) {
s = NULL;
printf(":%s:\n", t);
}
return 0;
}
I've made some string functions in order to split values, by using less pointers as I could because this code is intended to run on PIC18F processors. Those processors does not handle really good with pointers when you have few free RAM available:
#include <stdio.h>
#include <string.h>
char POSTREQ[255] = "pwd=123456&apply=Apply&d1=88&d2=100&pwr=1&mpx=Internal&stmo=Stereo&proc=Processor&cmp=Compressor&ip1=192&ip2=168&ip3=10&ip4=131&gw1=192&gw2=168&gw3=10&gw4=192&pt=80&lic=&A=A";
int findchar(char *string, int Start, char C) {
while((string[Start] != 0)) { Start++; if(string[Start] == C) return Start; }
return -1;
}
int findcharn(char *string, int Times, char C) {
int i = 0, pos = 0, fnd = 0;
while(i < Times) {
fnd = findchar(string, pos, C);
if(fnd < 0) return -1;
if(fnd > 0) pos = fnd;
i++;
}
return fnd;
}
void mid(char *in, char *out, int start, int end) {
int i = 0;
int size = end - start;
for(i = 0; i < size; i++){
out[i] = in[start + i + 1];
}
out[size] = 0;
}
void getvalue(char *out, int index) {
mid(POSTREQ, out, findcharn(POSTREQ, index, '='), (findcharn(POSTREQ, index, '&') - 1));
}
void main() {
char n_pwd[7];
char n_d1[7];
getvalue(n_d1, 1);
printf("Value: %s\n", n_d1);
}
When reading the strtok documentation, I see you need to pass in a NULL pointer after the first "initializing" call. Maybe you didn't do that. Just a guess of course.
Here is another strtok() implementation, which has the ability to recognize consecutive delimiters (standard library's strtok() does not have this)
The function is a part of BSD licensed string library, called zString. You are more than welcome to contribute :)
https://github.com/fnoyanisi/zString
char *zstring_strtok(char *str, const char *delim) {
static char *static_str=0; /* var to store last address */
int index=0, strlength=0; /* integers for indexes */
int found = 0; /* check if delim is found */
/* delimiter cannot be NULL
* if no more char left, return NULL as well
*/
if (delim==0 || (str == 0 && static_str == 0))
return 0;
if (str == 0)
str = static_str;
/* get length of string */
while(str[strlength])
strlength++;
/* find the first occurance of delim */
for (index=0;index<strlength;index++)
if (str[index]==delim[0]) {
found=1;
break;
}
/* if delim is not contained in str, return str */
if (!found) {
static_str = 0;
return str;
}
/* check for consecutive delimiters
*if first char is delim, return delim
*/
if (str[0]==delim[0]) {
static_str = (str + 1);
return (char *)delim;
}
/* terminate the string
* this assignmetn requires char[], so str has to
* be char[] rather than *char
*/
str[index] = '\0';
/* save the rest of the string */
if ((str + index + 1)!=0)
static_str = (str + index + 1);
else
static_str = 0;
return str;
}
As mentioned in previous posts, since strtok(), or the one I implmented above, relies on a static *char variable to preserve the location of last delimiter between consecutive calls, extra care should be taken while dealing with multi-threaded aplications.
int not_in_delimiter(char c, char *delim){
while(*delim != '\0'){
if(c == *delim) return 0;
delim++;
}
return 1;
}
char *token_separater(char *source, char *delimiter, char **last){
char *begin, *next_token;
char *sbegin;
/*Get the start of the token */
if(source)
begin = source;
else
begin = *last;
sbegin = begin;
/*Scan through the string till we find character in delimiter. */
while(*begin != '\0' && not_in_delimiter(*begin, delimiter)){
begin++;
}
/* Check if we have reached at of the string */
if(*begin == '\0') {
/* We dont need to come further, hence return NULL*/
*last = NULL;
return sbegin;
}
/* Scan the string till we find a character which is not in delimiter */
next_token = begin;
while(next_token != '\0' && !not_in_delimiter(*next_token, delimiter)) {
next_token++;
}
/* If we have not reached at the end of the string */
if(*next_token != '\0'){
*last = next_token--;
*next_token = '\0';
return sbegin;
}
}
void main(){
char string[10] = "abcb_dccc";
char delim[10] = "_";
char *token = NULL;
char *last = "" ;
token = token_separater(string, delim, &last);
printf("%s\n", token);
while(last){
token = token_separater(NULL, delim, &last);
printf("%s\n", token);
}
}
You can read detail analysis at blog mentioned in my profile :)