I would like to start 3 commands in the same window.
For now I have this batch but there are 3 different windows at each command.
start /d "c:\Program Files\myfolder" cmd /k cscript A
timeout /t 6 >nul
start /d "c:\Program Files\myfolder" cmd /k cscript B
timeout /t 6 >nul
start /wait /d "c:\PProgram Files\myfolder" cmd /k cscript C
What should I modify to have only one window? thanks
I think you can run a .bat file by changing the directory like so, cd C:\PATH\TO\DIRECTORY\WITH\FILE, then use call (file name here). This should work assuming that all the files are in the same directory, if not you'll just have to change the directory for each call method. If my code doesn't seem very helpful, check this page out https://superuser.com/a/1062322
Example Code
#echo off
cd PATH\TO\FILE\DIRECTORY
call FILE NAME
echo The file (file name here) has run!
pause
this code will make a call to the file and pause the terminal to keep it opened. You can take this code and make as many calls/cd's as you like. I hope this helped, If it doesn't work, please tell me what doesn't work and I'll try to fix it. Have a nice day :)
Related
So...I have "launcher"..
Its .bat file and i want it to start /ffa/server.exe
but..In ffa/ i have config file.
When i start server via launcher it starts server but it makes new config file
in directory of launcher..How can i fix this?
And "server" its: https://github.com/OgarProject/Ogar
start cmd /k %~dp0\ffa\server.exe
Please help me, its really frustrating..Thanks <3!
You can use pushd to move to the correct directory, start the server, and then pop back:
pushd %~dp0\ffa
start cmd /k server.exe
popd
I'm not familiar with the exact folder structure you're working with, and exactly how you call the script, but you definitely could use push/popd for this.
There are more possible solutions to change working directory of started command prompt window:
In calling script
pushd %~dp0\ffa
start "" cmd /k server.exe
popd
In started cmd itself: note properly escaped & character (see redirection)
start "" cmd /k pushd %~dp0\ffa^&server.exe
Using /D parameter of start command
start "" /D "%~dp0\ffa" cmd /k server.exe
So now i have 2 .bat files. one copies some file if it was updated ( robocopy C:\location C:\destination) and another one that executes a some kind of .exe file (start c:\BAT\fraps.exe) , now what i need is maybe a one file, so that WHEN a file was copied using "robocopy" the executive file would run automaticaly. So maybe there is a way to merge them into one or smth.
Errorlevels are set by robocopy: errorlevel 1 means that a file was successfully copied.
robocopy C:\location C:\destination
if errorlevel 1 if not errorlevel 2 start c:\BAT\fraps.exe
Here is proof of concept code - following extended comments:
#echo off
md test1
:loop
>test1\testfile.txt echo aaa
robocopy test1 test2
if errorlevel 1 if not errorlevel 2 pause
del test1\testfile.txt
goto :loop
Use /WAIT option, when the application is stared then it will wait until it terminates.
Use /B option, when application is started then it will not create a new window.
Example:
start /wait Command CALL D:\YourFirstScript.bat
start /wait program.exe
start /wait Command CALL X:\YourSecondScript.bat
It's a good idea to print a message before and after.
Example:
ECHO Starting program.
start /wait program.exe
ECHO Finished.
See below link for more details.
How do I launch multiple batch files from one batch file with dependency?
Note: When you run script as administrator then you need to set full path as the default is set to "C:\Windows\System32".
The easiest way to set is
start %~dp0Directory\program.exe
See for details about "%~dp0" here
What does %~dp0 mean, and how does it work?
This is my first post and I hope that this will help you.
I have a handful of batch files running at users' login via GPOs and a couple of them that create text/batch files with various info are exhibiting odd behavior. Specifically, these batches run at login are echoing the same value(s) multiple times into the target files. As an example:
ECHO #echo off > \\server\share$\%username%.bat
ECHO set minimized=true >> \\server\share$\%username%.bat
ECHO start /min cmd /C "path-to-program" %computername% >> \\server\share$\%username%.bat
Seems pretty straightforward, right? Yet this batch is producing a file that contains:
#echo off
set minimized=true
start /min cmd /C "path-to-program" computer
start /min cmd /C "path-to-program" computer
This isn't my only .bat doing this, but it's all the same concept - echoing a bunch of info into a file and somewhere along the way it's as if parts of it are getting run multiple times.
Has anyone seen this before and/or have any suggestions as to what could be going on?
Try like this :
(ECHO #echo off
ECHO set minimized=true
ECHO start /min cmd /C "path-to-program" %computername%)>"\\server\share$\%username%.bat"
I wrote a batch file for open a specific program but it is not working.I wrote this :
#echo off
C:\Windows\System32\cmd.exe /K "cd /d C:\Program Files (x86)\HTC\HTC Sync Manager\"
start HTCSyncManager.exe
When I run the batch file only this window come, program do not start. How to fix this
#echo off
For /r c: %%f in (path goes here /HTCsyncmanager.exe) do (
start "%%f"
"%%f"
)
Remove the invoking of cmd.exe. All that's doing is starting a new instance of the command processor, which is not what you need at all. (You probably don't need the start, either.)
#echo off
cd /d "C:\Program Files (x86)\HTC\HTC Sync Manager\"
HTCSyncManager.exe
#echo off
start "HTCSyncManager" "C:\Program Files\(x86)\HTC\HTC Sync Manager\HTCSyncManager.exe"
This will open HTCSyncManager.
I want to write a batch file that will do following things in given order:
Open cmd
Run cmd command cd c:\Program files\IIS Express
Run cmd command iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
Open Internet Explorer 8 with URL= http://localhost:8088/default.aspx
Note: The cmd window should not be closed after executing the commands.
I tried start cmd.exe /k "cd\ & cd ProgramFiles\IIS Express", but it is not solving my purpose.
So, make an actual batch file: open up notepad, type the commands you want to run, and save as a .bat file. Then double click the .bat file to run it.
Try something like this for a start:
c:\
cd c:\Program files\IIS Express
start iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
start http://localhost:8088/default.aspx
pause
I think the correct syntax is:
cmd /k "cd c:\<folder name>"
This fixes some issues with Blorgbeard's answer (but is untested):
#echo off
cd /d "c:\Program files\IIS Express"
start "" iisexpress /path:"C:\FormsAdmin.Site" /port:8088 /clr:v2.0
timeout 10
start http://localhost:8088/default.aspx
pause
cmd /c "command" syntax works well. Also, if you want to include an executable that contains a space in the path, you will need two sets of quotes.
cmd /c ""path to executable""
and if your executable needs a file input with a space in the path a another set
cmd /c ""path to executable" -f "path to file""
#echo off
title Command Executer
color 1b
echo Command Executer by: YourNameHere
echo #################################
: execute
echo Please Type A Command Here:
set /p cmd=Command:
%cmd%
goto execute
start cmd /k "your cmd command1"
start cmd /k "your cmd command2"
It works in Windows server2012 while I use these command in one batch file.
cmd /k cd c:\
is the right answer
I was trying to run a couple of batch files parallely at startup, if a condition was true.
For this I made a parent batch file which should have checked for the condition and invoke the other child batch files if the condition was true.
I tried to achieve it via START but it gave me an empty black command prompt running in the directory of children batch files, instead of running the children batch files themselves
The thing which worked for me was by using a combination of START and CALL
As an example
condition ...
start call "C:\Users\Amd\conn\wsl_setup - conn1.bat"
start call "C:\Users\Amd\conn\wsl_setup - conn2.bat"
start call "C:\Users\Amd\conn\wsl_setup - conn3.bat"
I know DOS and cmd prompt DOES NOT LIKE spaces in folder names. Your code starts with
cd c:\Program files\IIS Express
and it's trying to go to c:\Program in stead of C:\"Program Files"
Change the folder name and *.exe name. Hope this helps