Can't run basic PyFlink example - apache-flink

Question

I have this toy pipeline
from pyflink.datastream import StreamExecutionEnvironment
def pipeline():
# Create environment
env = StreamExecutionEnvironment.get_execution_environment()
env.set_parallelism(1)
ds = env.read_text_file('file:///home/user/myfile.json')
# ds.map(lambda i: i)
ds.print()
# Execute job
env.execute('DynamicStockpilePipeline')
if __name__ == '__main__':
pipeline()
That runs just fine, but everytime I try to uncomment the mapping stage, be it a dummy inline lambda or a MapFunction, it explodes saying:
Caused by: java.io.IOException: Failed to execute the command: python
-c import pyflink;import os;print(os.path.join(os.path.abspath(os.path.dirname(pyflink.__file__)), 'bin')) output: Traceback (most recent call last): File "<string>",line 1, in <module> ModuleNotFoundError: No module named 'pyflink'
I'm using a pyenv 3.8 interpreter, would anyone know how come the basic datasource and outputting runs, but the maps says the pyflink module is missing?
Addendum: this only happens on PyCharm, it does not happen when I run the script on the console, so I'm wary it is something between PyCharm and pyenv

Answer 1

I got rid of this error by assigning a the pyenv 3.8 as virtual environment instead of assigning the pyenv 3.8 from system interpreters option in PyCharm.
I guess something about the pythonpath gets broken with the previous option

Answer 2

Maybe you can post the code when the error is reported.
According to the context, the error reported here may be a usage error，the print function needs to follow the map function
from pyflink.datastream import StreamExecutionEnvironment
def pipeline():
# Create environment
env = StreamExecutionEnvironment.get_execution_environment()
env.set_parallelism(1)
ds = env.read_text_file('file:///home/user/myfile.json')
ds.map(lambda i: i).print()
# Execute job
env.execute('DynamicStockpilePipeline')
if __name__ == '__main__':
pipeline()